Ngā mara hiko - ngā raruraru me ngā otinga

Ngā mara hiko - ngā raruraru me ngā otinga

1. Kei waenganui i ngā utu e rua te Pūwāhi A. He rite te rahi o ngā utu e rua engari he rerekē te tohu, ā, he tawhiti a te a kei waenganui i a rāua. Ko te rahi o te āpure hiko i te pūwāhi A he 36 N/C. Mena ka neke te pūwāhi A i te 1/2a tata ki tētahi o ngā utu e rua , he aha te rahi o te āpure hiko i te pūwāhi A?

Mōhiotia:

Utu 1 (q 1 ) = +Q

Utu 2 (q 2 ) = -Q

Ko te tawhiti i waenganui i te utunga 1 me te pūwāhi A (r 1A ) = ½ a

Ko te tawhiti i waenganui i te utunga 2 me te pūwāhi A (r 2A ) = ½ a

Ko te rahi o te papa hiko i te pūwāhi A (E A ) = 36 NC -1

E hiahiatia ana: Te rahi o te mara hiko

Rongoā:

Hipanga 1.

Ka puta te āpure hiko i te utu +Q i te pūwāhi A :

Ngā mara hiko – ngā raruraru me ngā otinga 1

He pai te utu whakamātautau, ā, he pai te utu 1, kia anga ai te ahunga o te mara hiko ki te utu 2.

Ko te utu hiko i whakaputaina e te utu -Q i te pūwāhi A :

Ngā mara hiko – ngā raruraru me ngā otinga 2

He pai te utu whakamātautau, ā, he kino te utu 2, nō reira ka tohu te ahunga o te mara hiko ki te utu 2.

Ko te hua o te mara hiko i te pūwāhi A:

Ngā mara hiko – ngā raruraru me ngā otinga 3

Hipanga 2.

Mena ka nekehia te pūwāhi A ki te taha tata o te utunga 1, koia ēnei:

Te tawhiti i waenganui i te utunga 1 me te pūwāhi A (r 1A ) = ¼ a

Ko te tawhiti i waenganui i te utunga 2 me te pūwāhi A (r 2A ) = ¾ a

Ko te papa hiko i hangaia e te utu +Q i te pūwāhi A :

Te mara hiko – he raruraru me ngā otinga 4

He pai te utu whakamātautau, ā, he pai te utu 1, kia anga ai te ahunga o te mara hiko ki te utu 2.

Ko te papa hiko i hangaia e te utu -Q i te pūwāhi A :

Ngā mara hiko – ngā raruraru me ngā otinga 5

He pai te utu whakamātautau, ā, he kino te utu 2, nō reira ka tohu te ahunga o te mara hiko ki te utu 2.

Ko te hua o te mara hiko i te pūwāhi A:

Ngā mara hiko – ngā raruraru me ngā otinga 6

2. E rua ngā utu q A = 1 μC me q B = 4 μC e wehea ana e te tawhiti o te 4 cm (k = 9 x 10 9 N m 2 C −2 ). He aha te rahi o te āpure hiko i te pokapū i waenganui i a q A me q B?

Mōhiotia:

Utu A (q A ) = 1 μC = 1 x 10 −6 C

Utu B (q B ) = 4 μC = 4 x 10 −6 C

k = 9 x 10 9 N m 2 C −2

Te tawhiti i waenganui i ngā utu A me B (r AB ) = 4 cm = 0.04 mita

Te tawhiti i waenganui i te utu A me te pūwāhi pokapū (r A ) = 0.02 mita s

Te tawhiti i waenganui i te utu B me te pūwāhi pokapū (r B ) = 0.02 mita s

E mōhiotia ana: Te rahi o te mara hiko

Rongoā:

Ko te papa hiko i hangaia e te utu A i te pūwāhi pokapū:

Ngā mara hiko – ngā raruraru me ngā otinga 7

He pai te utu whakamātautau, ā, he pai te utu A, kia anga ai te ahunga o te mara hiko ki te utu B.

Ko te papa hiko i hangaia e te utu B i te pūwāhi pokapū:

Ngā mara hiko – ngā raruraru me ngā otinga 8

He pai te utu whakamātautau, ā, he pai te utu B, kia anga ai te ahunga o te mara hiko ki te utu A.

Ko te hua o te papa hiko i te pūwāhi pokapū:

He rerekē te ahunga o E A me E B.

E = E B – E A = 9 x 10 7 – 2.25 x 10 7 = 6.75 x 10 7 NC -1

3. E ai ki te pikitia i raro nei, kei hea te pūwāhi P kia rite ai te rahi o te āpure hiko i te pūwāhi P ki te 0? ( k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)

Ngā mara hiko – ngā raruraru me ngā otinga 9

otinga

Mena kei te taha maui o Q1 te pūwāhi P ; ka tohu te mara hiko i hangaia e Q1 i te pūwāhi P ki te taha maui ( atu i Q1 ) ā, ka tohu te mara hiko i hangaia e Q2 i te pūwāhi P ki te taha matau (tohu ki Q1 ). He ritenga kē te ahunga o te mara hiko , nō reira ko te mara hiko i te pūwāhi P = 0.

Mōhiotia:

Q 1 = +9 μC = +9 x 10 −6 C

Q 2 = -4 μC = -4 x 10 −6 C

k = 9 x 10 9 Nm 2 C −2

Te tawhiti i waenganui i te utu 1 me te utu 2 = 3 cm

Te tawhiti i waenganui i a Q 1 me te pūwāhi P (r 1P ) = a

Te tawhiti i waenganui i a Q 2 me te pūwāhi P (r 2P ) = 3 + a

E hiahiatia ana: Te tūnga o te pūwāhi P

Rongoā:

Kei te taha mauī o Q 1 te Pūwāhi P.

Ko te mara hiko i hangaia e Q 1 i te pūwāhi P:

Ngā mara hiko – ngā raruraru me ngā otinga 10

He pai te utu whakamātautau, ā, he pai hoki a Q 1 , nō reira kei te taha mauī te ahunga o te āpure hiko.

Ko te mara hiko i hangaia e Q 2 i te pūwāhi P :

Ngā mara hiko – ngā raruraru me ngā otinga 11

He pai te utu whakamātautau, ā, he kino te Q 2 , nō reira kei te taha matau te ahunga o te āpure hiko.

Te hua o te papa hiko i te pūwāhi A:

Ngā mara hiko – ngā raruraru me ngā otinga 12

Whakamahia te tātai tapawhā hei kimi i tētahi:

Ngā mara hiko – ngā raruraru me ngā otinga 12

Te tawhiti i waenganui i a Q 2 me te pūwāhi P (r 2P ) = 3 + a = 3 – 1.8 = 1.2 cm , 3 + a = 3 – 9 = -6 cm rānei.

Te tawhiti i waenganui i a Q 1 me te pūwāhi P (r 1P ) = a = -9 cm, -1.8 cm rānei.

Kei te 1.2 cm te tawhiti ki te taha matau o Q 2 te Pūwāhi P.

4. Kei te 5 cm te tawhiti o te utu q 3 ki te taha matau o q 2 , e whakaaturia ana i te pikitia i raro nei. He aha te rahi o te āpure hiko i te utu q 3 (1 µC = 10 -6 C).

Ngā mara hiko – ngā raruraru me ngā otinga 14

Rongoā:

Ngā mara hiko – ngā raruraru me ngā otinga 15

He pai te utunga q 3, ā, ko te ahunga o te mara hiko i te utunga q 3 e tohu ana ki te utunga tango q 2 (E 2 ) ā, e matara atu ana i te utunga tāpiri q 1 (E 1 ). Ko te hua o te mara hiko ko te tapeke o ngā mara hiko E 1 me E 2.

Mōhiotia:

Utu q 1 = 5 µC = 5 x 10 -6 Coulomb

Utu q 2 = 5 µC = -5 x 10 -6 Coulombs

Te tawhiti i waenganui i te utu q 1 me te utu q 3 (r 1 ) = 15 cm = 0.15 m = 15 x 10 -2 mita

Te tawhiti i waenganui i te utu q 2 me te utu q 3 (r 2 ) = 5 cm = 0.05 m = 5 x 10 -2 mita

k = 9 x 10 9 N m 2 C -2

E hiahiatia ana: Te āpure hiko i te utu q 3

Rongoā:

Te mara hiko 1:

E 1 = kq 1 / r 1 2

E 1 = (9 x 10 9 )(5 x 10 -6 ) / (15 x 10 -2 ) 2

E 1 = (45 x 10 3 ) / (225 x 10 -4 )

E 1 = 0.2 x 10 7 N/C

Te mara hiko 2:

E 2 = kq 2 / r 2 2

E 2 = (9 x 10 9 )(5 x 10 -6 ) / (5 x 10 -2 ) 2

E 2 = (45 x 10 3 ) / (25 x 10 -4 )

E 2 = 1.8 x 10 7 N/C

Ngā hua o te mara hiko:

Ko te hua o te āpure hiko i te utu q 3 :

E = E2 – E1 = (1.8 x 107 ) – (0.2 x 107 ) = 1.6 x 107N /C

Ka anga te ahunga o te papa hiko ki te taha maui (he rite tonu ki te ahunga E 2 ).

5. E rua ngā utu e wehea ana e whakaaturia ana i te pikitia i raro nei. He aha te āpure hiko i te pūwāhi P (k = 9 x 10 9 N m 2 C -2 )

otinga

Ngā mara hiko – ngā raruraru me ngā otinga 16

Mōhiotia:

Utu q A = +2.5 C

Utu q B = -2 C

Te tawhiti i waenganui i te utu q A me te pūwāhi P (r A ) = 5 m

Te tawhiti i waenganui i te utu q B me te pūwāhi P (r B ) = 2 m

k = 9 x 10 9 N m 2 C -2

E hiahiatia ana: te rahi o te āpure hiko i te pūwāhi P.

Rongoā:

Te mara hiko A:

EA = kqA / rA 2​

E A = (9 x 10 9 )(2.5) / (5) 2

EA = ( 22.5 x 10 9 ) / 25

EA = 0.9 x 109 N / C

Te mara hiko B:

E B = kq B / r B 2

E B = (9 x 10 9 )(2) / (2) 2

E B = (18 x 10 9 ) / 4

EB = 4.5 x 109 N / C

Ngā hua o te mara hiko:

Te hua o te papa hiko i te pūwāhi P:

E = E B – EA = (4.5 – 0.9) x 10 9 = 3.6 x 10 9 N/C

Ko te ahunga ki maui (ko te ahunga kotahi ki a E B ).

6. E rua ngā utu Q 1 = -40 µC me Q 2 = +5 µC e whakaaturia ana i te pikitia i raro nei (k = 9 x 10 9 Nm 2 .C -2 me 1 µC = 10 -6 C),. He aha te rahi o te āpure hiko i te pūwāhi P.

Ngā mara hiko – ngā raruraru me ngā otinga 17

Mōhiotia:

Utu q 1 = -40 µC = -40 x 10 -6 C

Utu q 2 = +5 µC = +5 x 10 -6 C

Te tawhiti i waenganui i a q 1 me te pūwāhi P (r 1 ) = 40 cm = 0.4 m = 4 x 10 -1 m

Te tawhiti i waenganui i a q 2 me te pūwāhi P (r 2 ) = 10 cm = 0.1 = 1 x 10 -1 m

k = 9 x 10 9 N m 2 C -2

E hiahiatia ana: te rahi o te āpure hiko i te pūwāhi P.

Rongoā:

Te mara hiko 1:

E 1 = kq 1 / r 1 2

E 1 = (9 x 10 9 )(40 x 10 -6 ) / (4 x 10 -1 ) 2

E 1 = (360 x 10 3 ) / (16 x 10 -2 )

E 1 = 22.5 x 10 5 N/C

Te mara hiko 2:

E 2 = kq 2 / r 2 2

E 2 = (9 x 10 9 )(5 x 10 -6 ) / (1 x 10 -1 ) 2

E 2 = (45 x 10 3 ) / 1 x 10 -2

E 2 = 45 x 10 5 N/C

Ngā hua o te mara hiko:

Ko te hua o te mara hiko i te pūwāhi P:

E = E 2 – E1 = (45 – 22.5) x 10 5 = 22.5 x 10 5 N/C

E = 2.25 x 106 N/C

Ko te ahunga o te mara hiko e anga ana ki te taha matau (he rite te ahunga ki te E 2 ).

7. E rua ngā utu pūwāhi e whakaaturia ana i te pikitia i raro nei.

Ngā mara hiko – ngā raruraru me ngā otinga 18

Kei hea te pūwāhi P e tū ai kia rite te rahi o te āpure hiko i te pūwāhi P ki te 0. k = 9.10 9 Nm 2 .C -2 , 1 µC = 10 -6 C.

Mōhiotia:

Utu 1 (q 1 ) = -9 µC = -9.10 -6 Coulombs

Utu 2 (q 2 ) = 1 µC = 1.10 -6 Coulomb

Te tawhiti i waenganui i a q1 me q2 ( r12 ) = 1 cm

k = 9.10 9 Nm 2 .C -2

E hiahiatia ana: Te tūnga o te pūwāhi P

Rongoā:

E 1 = te rahi o te papa hiko i hangaia e q 1 i te pūwāhi P

Ko te ahunga o E 1 ki q 1 nā te mea he kino a q 1 .

E 2 = te rahi o te āpure hiko i hangaia e q 2 i te pūwāhi P

Kei tawhiti atu te ahunga o E 2 i q 2 nā te mea he pai a q 2 .

Ngā mara hiko – ngā raruraru me ngā otinga 19

Ngā mara hiko – ngā raruraru me ngā otinga 20

Ko te papa hiko i te pūwāhi = 0.

Whakamahia te tātai tapawhā:

Ngā mara hiko – ngā raruraru me ngā otinga 22

Te tawhiti i waenganui i a P me q 2 = x = 0.5 cm.

Kei te 0.5 cm te taha matau q₂ , kei te 0.25 cm te taha maui q₂ rānei te pūwāhi P.

8. E ai ki te ahua i raro nei, mēnā ko te rahi o te āpure hiko i te pūwāhi P = k Q/x 2 , ko x = ….

Ngā mara hiko – ngā raruraru me ngā otinga 23

Mōhiotia:

EP = k Q / x 2

E hiahiatia ana: x

Rongoā:

Ngā mara hiko – ngā raruraru me ngā otinga 24

E 2 = Te rahi o te papa hiko i te pūwāhi P e te utu +32Q

r 2 = Te tawhiti i waenganui i te utu +32Q me te pūwāhi P = a + x

Ngā mara hiko – ngā raruraru me ngā otinga 25

Whakamahia te tātai tapawhā:

Ngā mara hiko – ngā raruraru me ngā otinga 26

  1. He aha te mara hiko?
    • WhakautuKo te papa hiko he rohe e karapoti ana i tētahi mea kua whakakīia, ka taea e ētahi atu mea kua whakakīia te pā ki ngā kaha hiko. He papa whārite tēnei, arā, he nui, he ahunga hoki tōna i ia pūwāhi.
  2. Me pēhea te whakatau i te kaha o te papa hiko?
    • WhakautuTe kaha, te rahi rānei o te papa hiko i tētahi pūwāhi ka tautuhia ko te kaha i pāngia e te utu whakamātautau pai i whakanohoia ki taua wāhi, ka wehea e te rahi o te utu whakamātautau tonu: .
  3. He pēhea te rerekētanga o te āpure hiko e hua mai ana i tētahi utu pūwāhi i runga i te tawhiti?
    • WhakautuTe mara hiko nā te utu tohu he rite whakamuri ki te tapawhā o te tawhiti mai i te utu. Nā te , i reira ko te pūmau a Coulomb.
  4. He aha te ahunga o te papa hiko nā te utu pai?
    • WhakautuKo te mara hiko o te utu pai e anga atu ana ki waho mai i te utu. Mō te utu kino, ka anga atu te mara ki roto, ki te utu.
  5. Me pēhea e taea ai e koe te whakaatu i ngā āpure hiko mā te kauwhata?
    • WhakautuKa taea te whakaatu i ngā mara hiko mā te whakamahi i ngā rārangi mara (ngā rārangi kaha rānei). Ko te ahunga o te mara i tētahi pūwāhi he pātata ki te rārangi mara i taua pūwāhi, ā, ko te kiato o ngā rārangi e tohu ana i te rahi o te mara.
  6. He aha te mea ka pā ki te papa hiko i roto i te ara iahiko i roto i te taurite hiko?
    • WhakautuI roto i te ara iahiko i te taurite hiko, he kore te papa hiko. Nā te mea ka tukuna anōtia ngā irahiko kore utu i roto i te ara iahiko e tētahi ara iahiko o waho, ka whakakorea te papa o waho o roto.
  7. He pēhea te whanonga o ngā rārangi papa hiko e tata ana ki te taha koi o tētahi ara iahiko?
    • WhakautuI te taha koi, i te pito koi rānei o te ara hiko, ka kukū ake ngā rārangi o te papa hiko, ā, ka kaha ake te papa hiko i taua rohe. Koinei te pūtake o te whakahaere o ngā taputapu pēnei i te tokotoko uira.
  8. Me pēhea te pānga o ngā mātāpono taupatupatu ki ngā mara hiko?
    • WhakautuKo te papa hiko e puta mai ana i ngā utu maha i tētahi pūwāhi he tapeke noa iho o ngā papa hiko e puta mai ana i ia utu takitahi. E mōhiotia ana tēnei ko te mātāpono taupatupatu.
  9. He aha te hononga o te mahi a te ākena o waho ki te papa hiko ina nekehia ana te utu i roto i te papa?
    • WhakautuTe mahi i mahia e tētahi āpiha o waho i te neke i tētahi utu mai i tētahi pūwāhi ki tētahi atu i roto i tētahi mara hiko he ōrite ki te kino o te huringa o te pūngao pūmanawa hiko, arā , i reira ko te huringa o te pūmanawa hiko.
  10. Ka taea e ngā rārangi papa hiko te whiti tetahi ki tetahi?

    • WhakautuKāore, kāore e taea e ngā rārangi o te mara hiko te whiti tetahi ki tetahi. Mēnā ka whiti, ko te tikanga kei te pūwāhi e tūtaki ai, e rua ngā ahunga rerekē o te mara hiko, he mea kāore e taea.