fisiks

Boholo ba torque ea net - mathata le litharollo

1. Matla P a sebediswa pheletsong e nngwe ya lehlasedi le bolelele ba 2 m. Boholo ba torque ke bofe ? Mothapo wa potoloho ntlheng ya A.

Boholo ba torque ea net - mathata le litharollo 1 Tse tsejoang:

Matla (F) = 10 N

Bolelele ba AB (r _AB) = 2 m

Matla a F a otlolohile ho lehlaseli.

Letsoho la lever (l ) = r _ABsin 90 ^o = (2 m)(1) = 2 m

Ho batloa: Torque e potolohileng axis ea potoloho

Tharollo:

Torque:

τ = F l = (10 N)(2 m) = 20 N m

Letšoao la ho eketsa hobane lehlaseli le potoloha ho potoloha ho ea ka oache.

2. Bolelele ba lehlaseli la AB ke 2 m mme boholo ba matla F ke 10 N. Boholo ba torque ke bofe? Mothapo wa potoloho ntlheng ya A.

Boholo ba torque ea net - mathata le litharollo 2 Tse tsejoang:

Matla (F) = 10 N

Bolelele ba AB (r _AB) = 2 m

Letsoho la lever (l ) = r _ABsin 60 ^o = (2 m)(0.5 √3 ) = √3 m

Ho batloa: Torque e potolohileng axis ea potoloho

Tharollo:

Torque:

τ = F l = (10 N)( √3 m) = 10 √3 N m

Letšoao la ho eketsa hobane matla a F a etsa hore lehlaseli le potolohe ho potoloha ho ea ka lehlakoreng le leng.

3. Bolelele ba lehlaseli ke 2 m. Boholo ba F ₁ ke 10 N mme boholo ba F ₂ ke 15 N. Fumana torque e nepahetseng bohareng ba lehlaseli.

Mothapo oa potoloho bohareng ba lehlaseli.

Boholo ba torque ea net - mathata le litharollo 3 Tse tsejoang:

Matla a 1 (F ₁) = 10 N

Sebaka se pakeng tsa F ₁ le setsi sa lehlaseli (r ₁ ) = 1 m

Letsoho la lever 1 (l ₁ ) = r ₁ sin 90 ^o = (1 m)(1) = 1 m

Matla a F ₁a otlolohile ho lehlaseli.

Matla a 2 (F ₂) = 15 N

Sebaka se pakeng tsa F ₂ le setsi sa lehlaseli (r ₂) = 1 m

Matla a F ₂a otlolohile ho lehlaseli.

Letsoho la lever 2 (l ₂) = r ₁ sin 90 ^o = (1 m)(1) = 1 m

Ho batloa: Torque ea net e potolohang axis ea potoloho

Tharollo:

Torque 1:

τ ₁ = F ₁ l ₁ = (10 N)( 1 m) = 10 N m

Letšoao la ho eketsa hobane matla a F ₁ a etsa hore lehlaseli le potolohe ho potoloha ho ea ka oache.

Torque 2:

τ ₂ = F ₂l ₂= (15 N)( 1 m) = -15 N

Letšoao la ho tlosa hobane matla a F ₂ a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.

Torque ea letlooa:

Σ τ = τ ₁ – τ ₂ = 10 – 15 = – 5 N m

Letšoao la ho tlosa ke hobane lehlaseli le potoloha ka lehlakoreng la oache.

4. Bolelele ba lehlaseli la AB ke 2 m, boholo ba F ₁ ke 10 N mme boholo ba F ₂ ke 10 N. Fumana torque e nepahetseng bohareng ba lehlaseli.

Mothapo oa potoloho bohareng ba lehlaseli.

Tse tsejoang:

Matla a 1 (F ₁ ) = 10 Nn

Sebaka se pakeng tsa F ₁ le setsi sa lehlaseli (r ₁ ) = 1 m

Letsoho la lever 1 (l ₁ ) = r ₁ sin 60 ^o = (1 m)(0.5 √3 ) = 0.5 √3 m

Matla a 2 (F ₂ ) = 10 N

Sebaka se pakeng tsa F ₂ le setsi sa lehlaseli (r ₂ ) = 1 m

Matla a F ₂ a otlolohile ho lehlaseli.

Letsoho la lever 2 (l ₂ ) = r ₂ sin 90 ^o = (1 m)(1) = 1 m

Ho batloa: Torque e tiileng e potolohileng axis ea potoloho

Tharollo:

Torque 1:

τ ₁ = F ₁ l ₁ = (10 N)( 0.5 √3 m) = 5 √3 = 8.7 Nm

Letšoao la ho eketsa hobane matla a F ₁ a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.

Torque 2:

τ ₂ = F ₂ l ₂ = (10 N)( 1 m) = -10 N m

Letšoao la ho tlosa hobane matla a F ₂ a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.

Torque ea letlooa:

Σ τ = τ ₁ – τ ₂ = 8.7 – 10 = – 1.3 N m

Letšoao la ho tlosa hobane matla a letlooa a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.

5. Bolelele ba lehlaseli ke 10 m, boholo ba F ₁ ke 10 N, boholo ba F ₂ ke 10 N mme boholo ba F ₃ ke 15 N. Sebaka se pakeng tsa ntlha A le ntlha C ke 7.5 m. Matla F ₂ a fumaneha bohareng ba lehlaseli. Fumana torque e nepahetseng mabapi le ntlha C e fumanehang ho 2.5 m ho tloha ntlheng B.

Mokhahlelo oa potoloho o sebakeng sa C

Boholo ba torque ea net - mathata le litharollo 5 Tse tsejoang:

Matla a 1 (F ₁) = 10 N

Sebaka se pakeng tsa F ₁ le ntlha C (r ₁ ) = 2.5 m

Matla a F ₁a otlolohile ho lehlaseli.

Letsoho la lever 1 (l ₁) = r ₁sin 90 ^o = ( 2.5 m)( 1 ) = 2.5 m

Matla a 2 (F ₂) = 10 N

Sebaka se pakeng tsa F ₂le ntlha C (r ₂) = 2.5 m

Matla a F ₂a otlolohile ho lehlaseli.

Letsoho la lever 2 (l ₂) = r ₂sin 90 ^o = ( 2.5 m)(1) = 2.5 m

Matla a 3 (F ₃) = 15 N

Sebaka se pakeng tsa F ₃ le ntlha C (r ₃) = 7.5 m

Matla a F ₃a otlolohile ho lehlaseli.

Letsoho la lever 3 (l ₃) = r ₃sin 90 ^o = (7.5 m)(1) = 7.5 m

Ho batloa: Torque e tiileng e potolohileng axis ea potoloho

Tharollo:

Torque 1:

τ ₁= F ₁l ₁= (10 N)( 2.5 m) = 25 N m

Letšoao la ho eketsa hobane matla a F ₁ a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.

Torque 2:

τ ₂= F ₂l ₂= (10 N)( 2.5 m) = 25 N m

Letšoao la ho eketsa hobane matla F ₂a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.

Torque 3:

τ ₃= F ₃l ₃= (15 N)( 7.5 m) = -112..5 N m

Letšoao la ho tlosa hobane matla a F ₃ a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.

Torque ea letlooa:

Σ τ = τ ₁+ τ ₂– τ ₃= 25 + 25 – 112.5 = – 62.5 N m

Letšoao la ho tlosa hobane matla a letlooa a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.

6. Bolelele ba lehlaseli ke 10 m, boholo ba F₁ ke 10 N, boholo ba F₂ ke 10 N le boholo ba F₃ ke 10 N. Fumana torque ea letlooa mabapi le ntlha ea A, e fumanehang 5 m ho tloha poi Boholo ba torque ea net - mathata le litharollo 6 nt ea ts'ebeliso ea matla F₁.

Mokhahlelo oa potoloho ntlheng ea A.

Tse tsejoang:

Matla a 1 (F ₁ ) = 10 N

Sebaka se pakeng tsa F ₁le ntlha A (r ₁) = 5 m

Letsoho la lever 1 (l ₁) = r ₁ sin 60 ^o = (5 m)(0.5 √3 ) = 2.5 √3 m

Matla a 2 (F ₂) = 10 N

Sebaka se pakeng tsa F ₂le ntlha A (r ₂) = 0

Matla a F2 _a otlolohile ho lehlaseli.

Letsoho la lever 2 (l ₂) = r ₂ sin 90 ^o = (0)(1) = 0

Matla a 3 (F ₃) = 10 N

Sebaka se pakeng tsa F ₃le ntlha A (r ₃) = 10 m

Letsoho la lever 3 (l ₃) = r ₃sin 30 ^o = (10 m)(0.5) = 5 m

Ho batloa: torque e tiileng e potolohileng axis ea potoloho

Tharollo:

Torque 1:

τ ₁= F ₁l ₁= (10 N)( 2.5 √3 m ) = 25√3 = 43.3 N m

Letšoao la ho eketsa hobane matla a F ₁a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.

Torque 2:

τ ₂= F ₂l ₂= (10 N)(0) = 0

Torque 3:

τ ₃= F ₃l ₃= (10 N)( 5 m) = -50 N m

Letšoao la ho tlosa hobane matla a F ₃ a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.

Torque ea letlooa:

Σ τ = τ ₁+ τ ₂– τ ₃= 43.3 + 0 – 50 = – 6.7 N m

Letšoao la ho tlosa hobane matla a letlooa a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.

Bala haholoanyane

Ho thulana ho sa thekeseleng ka karolo e le 'ngoe - mathata le litharollo

1. Ntho ea boima ba ligrama tse 500 , A, e tsamaeang ka lebelo la 10 m/s le ntho ea boima ba ligrama tse 200, B, e tsamaeang ka lebelo la 12 m/s. Lintho tsena lia atamelana 'me lia thulana. Haeba lebelo la ntho A ka mor'a ho thulana e le 6 m/s, lebelo la ntho B ka mor'a ho thulana ke lefe?

Tse tsejoang:

Boima ba ntho 1 (m ₁) = digrama tse 500 = 0.5 kg

Boima ba ntho 2 (m ₂) = digrama tse 200 = 0.2 kg

Lebelo la pele la ntho 1 (v ₁) = -10 m/s

Lebelo la pele la ntho 2 (v ₂) = 12 m/s

Lebelo la ho qetela la ntho 1 (v ₁') = 6 m/s

Matšoao a ho ba le kamano le ...

Ho batloa : lebelo la ho qetela la ntho ea 2 (v ₂')

Tharollo:

m₁ v₁ +m₂ v₂ = m₁ v₁' + m₂ v₂'

(0.5) (-10) + (0.2) (12) = (0.5) (6) + (0.2) (v ₂')

-5 + 2.4 = 3 + 0.2 v ₂'

-2.6 = 3 + 0.2 v ₂'

-2.6 – 3 = 0.2 v ₂'

-5.6 = 0.2 v ₂'

v ₂' = -5.6 / 0.2

v ₂' = -28 m/s

Lebelo la ntho ea 2 kamora ho thulana ke 28 m/s.

Matšoao a ho ba le kamano le ...

2. Lintho tse peli tse lekanang ka boima lia atamelana 'me lia thulana. Lebelo la ntho ea 1 ke 6 m/s 'me lebelo la ntho ea 2 ke 8 m/s. Kamora ho thulana, ntho ea 2 e tsamaea ka letsohong le letšehali ka lebelo la 5 m/s. Boholo le tataiso ea lebelo la ntho ea 1 ke life kamora ho thulana?

Tseba :

Boima ba ntho 1 (m ₁) = m

Boima ba ntho 2 (m ₂) = m

Lebelo la pele la ntho 1 (v ₁) = -6 m/s

lebelo la pele la ntho 2 (v ₂) = 8 m/s

Lebelo la ho qetela la ntho 2 (v ₂') = -5 m/s

Ho batloa : boholo le tataiso ea ntho ea 1 kamora ho thulana

Tharollo:

Foromo ea paballo ea lebelo le otlolohileng :

m₁ v₁ +m₂ v₂ = m₁ v₁' + m₂ v₂'

mv ₁+ m v ₂= m v ₁' + m v ₂'

m (v ₁+ v ₂) = m (v ₁' + v ₂')

v ₁+ v ₂= v ₁' + v ₂'

-6 + 8 = v ₁' – 5

2 = v ₁' – 5

2 + 5 = v ₁'

v ₁' = 7 m/s

Lebelo la ntho 1 kamora ho thulana (v ₁') ke 3 m/s.

Matšoao a ho ba le kamano le ...

3. Bolo ea 1-kg ea 1 le 2-kg ea 2 li na le tsela e tšoanang 'me li thulana ka mokhoa o sa tsitsang. Pele ho thulana, bolo ea 1 e tsamaea ka lebelo la 10 m/s 'me bolo ea 2 e tsamaea ka lebelo la 5 m/s. Lebelo la bolo ea 2 kamora ho thulana ke 4 m/s. Fumana lebelo la bolo ea 1 kamora ho thulana.

Tse tsejoang:

Bolo e boima 1 (m1 ₎= 1 kg

Bolo e boima 2 (m2 ₎= 2 kg

Lebelo la bolo 1 (v ₁) = 10 m/s

Lebelo la bolo 2 (v ₂) = 5 m/s

Lebelo la ho qetela la bolo 2 (v ₂') = 4 m/s

Letšoao la ho eketsa lebelo le bontša hore libolo li shebile ka lehlakoreng le le leng.

Ho batloa : lebelo la ho qetela la bolo 1 (v ₁')

Tharollo:

m₁ v₁ +m₂ v₂ = m₁ v₁' + m₂ v₂'

(1) (10) + (2) (5) = (1) (v ₁') + (2) (4)

10 + 10 = v ₁' + 8

20 – 8 = v ₁'

v ₁' = 12 m/s

Lebelo la bolo 1 kamora ho thulana ke 12 m/s.

[ID ea sephutheloana sa wpdm='1190′]

Bala haholoanyane

Likhohlano tse sa senyeheng ka tekanyo e le 'ngoe - mathata le litharollo

1. Kulo ea 30-gram e tsamaeang ka lebelo la 30 m/s e thulana le boloko ba 1-kg ha e phomotse. Fumana lebelo la boloko haeba kulo le boloko li hokahana hammoho ka lebaka la ho thulana.

Tse tsejoang:

Boima ba kulo (m ₁) = digrama tse 30 = 0.03 kg

Boima ba boloko (m2 ₎= 1 kg

Lebelo la pele la kulo ( v ₁) = 30 m/s

Lebelo la pele la boloko (v ₂) = 0 ( boloko ha e phomotse )

Ho batloa : lebelo la kulo le thibelo kamora ho thulana (v')

Tharollo:

m ₁v ₁+ m ₂v ₂= (m ₁+ m ₂) v'

(0.03)(30) + (1)(0) = (0.03 + 1) v'

0.9 + 0 = 1.03 v'

0.9 = 1,03 v'

v' = 0.9 / 1,03

v' = 0.87 m/s

2. Bolo ea biliadi A ea boima ba 2 kg e tsamaeang ka lebelo v _A= 6 ms ⁻¹ e thulana ka hlooho le bolo ea B ea boima bo lekanang. Haeba ho thulana ho sa thekesele hantle, lebelo la libolo tse peli ke lefe ka mor'a ho thulana.

Tse tsejoang:

Boima A (m _A) = 2 kg

Boima ba B (m _B) = 2 kg

Lebelo la pele la bolo A (v _A) = -6 m/s

Lebelo la pele la bolo B (v _B) = 4 m/s

Matšoao a ho ba le kamano le ...

Ho batloa : lebelo la libolo tse peli kamora ho thulana. (v')

Tharollo:

m _Av _A+ m _Bv _B= (m _A' + m _B) v'

(2)(-6) + (2)(4) = (2 + 2) v'

-12 + 8 = 4 v'

-4 = 4 v'

v' = -4 / 4

v' = -1 m/s

3. m₁ = 3 kg 'me m₂ = 4 kg atamelana ka lehlakoreng le fapaneng ka lebelo la v₁ = 10 m/s 'me v₂ = 12 m/s. Haeba ho thulana ho sa thekesele hantle, lebelo la libolo tse peli ka mor'a ho thulana ke lefe?

Tse tsejoang:

Ntho e boima 1 (m1 ₎= 3 kg

Ntho e boima 2 (m2 ₎= 4 kg

Lebelo la ntho 1 (v ₁) = -10 m/s

Lebelo la ntho 2 (v ₂) = 12 m/s

Ho batloa : lebelo ka mor'a ho thulana (v')

Tharollo:

m ₁v ₁+ m ₂v ₂= (m ₁' + m ₂) v'

(3)(-10) + (4)(12) = (3 + 4) v'

-30 + 48 = 7 v'

18 = 7 v'

v' = 18 / 7

v' = 2.6 m/s

[ID ea sephutheloana sa wpdm='1157′]

Bala haholoanyane

Ho thulana ho tenyetsehang ka ho phethahetseng ka tekanyo e le 'ngoe - mathata le litharollo

1. Bolo ea ligrama tse 200, A, e tsamaeang ka lebelo la 10 m/s e otla bolo ea ligrama tse 200, B, ha e phomotse. Lebelo la bolo A le bolo B ke lefe ka mor'a ho thulana?

Tse tsejoang:

Boima ba bolo A (m _A) = 200 grams = 0.2 kg

Boima ba bolo B (m _B) = 200 grams = 0.2 kg

Lebelo la bolo A pele ho thulana (v _A) = 10 m/s

Lebelo la bolo B pele ho thulana (v _B) = 0

Ho batloa: lebelo la bolo A (v _A') le lebelo la bolo B (v _B') kamora ho thulana

Tharollo:

v _A' = v _B= 0

v _B' = v _A= 10 m/s

2. Lintho tse peli tse lekanang ka boima lia atamelana, lia thulana ebe lia tlola. Lebelo la boima ba A pele ho thulano ke 8 m/s 'me lebelo la boima ba B pele ho thulano ke 12 m/s. Boholo le tataiso ea lebelo la boima ba A le boima ba B kamora thulano ke life!

Tse tsejoang:

Boima A (m _A) = m

Boima B (m _B) = m

Lebelo la boima A pele ho thulana (v _A) = -8 m/s

Lebelo la boima ba B pele ho thulana (v _B) = 12 m/s

Matšoao a ho ba le kamano le ...

Ho batlwa: boholo le tataiso ea lebelo la boima A (v _A') le boima B (v _B') kamora ho thulana

Tharollo:

Khohlanong e tenyetsehang ka ho phethahetseng, haeba lintho tse nang le boima bo lekanang joale lebelo la A kamora khohlano (v _A') = lebelo la B pele ho khohlano (v _B) le lebelo la B kamora khohlano (v _B') = lebelo la A pele ho khohlano (v _A).

Haeba pele ho thulana, A e ya ka letsohong le letona mme B e ya ka letsohong le letshehadi, ebe, kamora ho thulana, A e ya ka letsohong le letshehadi mme B e ya ka letsohong le letona.

Lintho tsena li na le boima bo lekanang 'me ho thulana ho tenyetseha ka ho phethahetseng kahoo lintho tsena ka bobeli li fapanyetsana lebelo.

v _A' = -v _B= -12 m/s

v _B' = v _A= 8 m/s

Matšoao a ho ba le kamano le ...

3. Ntho ea boima ba 2-kg, A, e tsamaeang ka lebelo la 10 m/s e otla bolo ea 4-kg, B, e tsamaea ka lebelo la 20 m/s. Haeba ho thulana ho tenyetseha ka ho feletseng, lebelo la ntho A le ntho B ke lefe ka mor'a ho thulana?

Tse tsejoang:

Boima A (m _A) = 2 kg

Boima ba B (m _B) = 4 kg

Lebelo la ntho A pele ho thulana (v _A) = 10 m/s

Lebelo la ntho B pele ho thulana (v _B) = 20 m/s

Ho batlwa : lebelo la ntho A (v _A') le lebelo la ntho B (v _B') kamora ho thulana

Tharollo :

Khohlanong e tenyetsehang ka ho phethahetseng , haeba lintho li na le boima bo lekanang 'me li atamelana, lebelo la ntho ka mor'a khohlano le baloa ho sebelisoa mokhoa ona:

Ho thulana ho tenyetsehang ka ho phethahetseng ka tekanyo e le 'ngoe - mathata le litharollo 1

Lebelo la ntho A kamora ho thulana:

Ho thulana ho tenyetsehang ka ho phethahetseng ka tekanyo e le 'ngoe - mathata le litharollo 2

4. Ho tsamaea ha 100-gram ka lebelo la 20 m/s ho otla lebota ka ho feletseng. Boholo le tataiso ea lebelo la ntho ka mor'a ho thulana ke life?

Tse tsejoang:

Boima (m _A) = digrama tse 100 = 0.1 kg

Boima ba lebota (m _B) = ho se fele

Lebelo la boima pele ho thulana (v _A) = 20 m/s

Lebelo la boima kamora ho thulana (v _B) = 0

Ho batloa : boholo le tataiso ea lebelo ka mor'a ho thulana

Tharollo:

Haeba v _B= 0, m _Ae nyane haholo mme m ₂e kgolo haholo, joale v _A' = -v _Ale v ₂' = 0.

Matšoao a ho ba le kamano le ...

5. Libolo tse peli, A e nang le boima ba 2-kg le bolo B e nang le boima ba 5-kg, pele le ka mora ho thulana li bontšitsoe setšoantšong se ka tlase. Haeba ho thulana ho tenyetseha ka ho feletseng, lebelo la bolo A ke lefe pele ho thulana?

Tse tsejoang:

Boima ba bolo A (m_A) = 2 kg Ho thulana ho tenyetsehang ka ho phethahetseng - mathata le litharollo 1

Boima ba bolo B (m _B) = 5 kg

Lebelo la bolo B pele ho thulana (v _B) = 2 m/s

Lebelo la bolo A kamora ho thulana (v _A') = 5 m/s

Lebelo la bolo B kamora ho thulana (v _B') = 4 m/s

Libolo ka bobeli li ntse li tsamaea ka letsohong le letona kahoo lebelo la tsona le saennoe hantle.

Ho batloa: Lebelo la bolo A pele ho thulana (v _A)

Tharollo:

m_A v_A +m_B v_B = m_A v_A' + m_B v_B'

2(v _A) + (5)(2) = (2)(5) + (5)(4)

2(v _A) + 10 = 10 + 20

2(v _A) + 10 = 30

2(v _A) = 30 – 10

2(v _A) = 20

v _A= 20/2

v _A = 10 m/s

6. Lintho A le B li tsamaea ka sefofane se otlolohileng, joalo ka ha ho bontšitsoe setšoantšong se ka tlase. Haeba ho thulana ho tenyetseha ka ho phethahetseng 'me lebelo la ntho B kamora ho thulana e le 15 m/s ¹ , lebelo la ntho A kamora ho thulana ke lefe.

Tse tsejoang:

Boima ba ntho A (m_A) = 5 kg Ho thulana ho tenyetsehang ka ho phethahetseng - mathata le litharollo 2

Boima ba ntho B (m _B) = 2 kg

Lebelo la ntho A pele ho thulana (v _A) = 12 m/s

Lebelo la ntho B pele ho thulana (v _B) = 10 m/s

Lebelo la ntho B kamora ho thulana (v _B') = 15 m/s

Lintho ka bobeli, pele le ka mor'a ho thulana, li ea ka ho le letona e le hore lebelo la tsona le saennoe hantle.

Ho batloa: Lebelo la ntho A kamora ho thulana (v _A')

Tharollo:

m_A v_A +m_B v_B = m_A v_A' + m_B v_B'

(5)(12) + (2)(10) = (5)v _A' + (2) (15)

60 + 20 = (5)v _A' + 30

80 = (5)v _A' + 30

80 – 30 = (5)v _A'

50 = (5)v _A'

v _A' = 50/5

v _A' = 10 m/s

[ID ea sephutheloana sa wpdm='1156′]

Bala haholoanyane

Matla le takatso - mathata le litharollo

1. Bolo e nyane e lahlelwa ka ho otloloha ka lebelo le sa fetoheng la 10 m/s. Bolo e otla lebota mme e bonahatsa ka lebelo le tshwanang. Phetoho ya motsamao o otlolohileng wa bolo ke efe?

Tse tsejoang:

Boima (m) = 0.2 kg

Lebelo la pele (vo _o ) = -10 m/s

Lebelo la ho qetela (v _t ) = 10 m/s

Matšoao a ho ba le kamano le ...

Ho batloa : phetoho motsamaong o otlolohileng (Δp)

Tharollo:

Foromo ea phetoho motsamaong o otlolohileng :

Δp = mv _t – mv _o = m (v _t – v _o )

Phetoho motsamaong o otlolohileng:

Δp = 0.2 (10 – (-10)) = 0.2 (10 + 10)

Δp = 0.2 (20)

Δp = 4 kg m/s

2. Bolo ea ligrama tse 10 e oela ka bolokolohi ho tloha bophahamong, e otla fatše ka lebelo la 15 m/s, ebe e hlaha holimo ka lebelo la 10 m/s. Fumana hore na tšusumetso e kae!

Tse tsejoang:

Boima (m) = digrama tse 10 = 0.01 kg

Lebelo la pele (vo _o ) = -15 m/s

Lebelo la ho qetela (v _t ) = 10 m/s

Ho Batloa: Tšusumetso (I)

Tharollo:

Tšusumetso (I) e lekana le phetoho ea momentum (Δp)

Ke = mv _t – mv _o = m (v _t – v _o )

Tšusumetso:

Ke = 0.01 (10 – (-15)) = 0.01 (10 + 15)

Ke = 0.01 (25)

I = 0.25 kg m/s

3. Bolo ea ligrama tse 200 e ile ea lahleloa ka ho otloloha ka lebelo la 4 m/s, eaba bolo e otloa ka lehlakoreng le le leng. Nako ea bolo ha e kopana le koto ke metsotsoana e 2 mil l 'me lebelo la bolo ka mor'a ho tloha kotong ke 12 m/s. Boholo ba matla a sebelisoang ke koto bolong ke …

Tse tsejoang:

Boima (m) = digrama tse 200 = 0.2 kg

Lebelo la pele (vo _o ) = 4 m/s

Lebelo la ho qetela (v _t ) = 12 m/s

Nako e sa fellang (t) = 2 milliseconds = (2/1000) metsotsoana = 0.002 metsotsoana

Ho batloa : Boholo ba matla (F)

Tharollo:

Foromo ea tšusumetso:

Ke = F t

Foromo ea phetoho ea lebelo:

mv _t – mv _o = m (v _t – v _o )

Tšusumetso (I) e lekana le phetoho ea momentum (Δp)

I = Δp

F t = m (v _t – vo _o )

F (0.002) = (0.2)(12 - 4)

F (0.002) = (0.2)(8)

F (0.002) = 1.6

F = 1.6 / 0.002

F = 800 Newton

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Bala haholoanyane

Motsamao o otlolohileng - mathata le litharollo

1. Ntho e tsamaya ka lebelo le sa fetoheng la 10 m/s. Bala lebelo le otlolohileng la ntho.

Tse tsejoang :

Boima (m) = 1 kg

Lebelo (v) = 10 m/s

Ho batloa: momentum o otlolohileng (p)

Tharollo:

Foromo ea momentum e otlolohileng:

p = mv

p = lebelo le otlolohileng, m = boima, v = lebelo

Motsamao o otlolohileng:

p = mv = (1)(10) = 10 kg m/s ²

2. Seboloko sa 2-kg le seboloko sa 4-kg se tsamaya ka lebelo le sa fetoheng la 20 m/s. Motsamao o otlolohileng wa diboloko ke ofe?

Tse tsejoang:

Boima ba boloko A (m _A) = 2 kg

Boima ba boloko B (m _B) = 4 kg

Lebelo la boloko A (v _A) = 20 m/s

Lebelo la boloko B (v _B) = 20 m/s

Ho batloa: Motsamao o otlolohileng oa boloko A (p _A) le motsamao o otlolohileng oa boloko B (p _B)

Tharollo:

Motsamao o otlolohileng oa boloko A :

p _A= m _Av _A= (2) (20) = 40 kg m/s

Motsamao o otlolohileng oa boloko B :

p _B= m _Bv _B= (4)(20) = 80 kg m/s

3. Boloko ba 2-kg bo tsamaya ka lebelo le sa fetoheng la 2 m/s mme boloko ba 2-kg bo tsamaya ka lebelo le sa fetoheng la 4 m/s. Fumana lebelo le otlolohileng la diboloko.

Tse tsejoang:

Boima ba boloko A (m _A) = 2 kg

Boima ba boloko B (m _B) = 2 kg

Lebelo la boloko A (v _A) = 2 m/s

Lebelo la boloko B (v _B) = 4 m/s

Ho batloa: lebelo le otlolohileng la li-block

Tharollo:

Motsamao o otlolohileng oa boloko A :

p _A= m _Av _A= (2) (2) = 4 kg m/s

Motsamao o otlolohileng oa boloko B:

p _B= m _Bv _B= (2)(4) = 8 kg m/s

4. Ntho e boima ba 5-kg e phomotseng. Motsamao o otlolohileng wa motsamao ke ofe?

Tse tsejoang:

Boima (m) = 5 kg

Lebelo la ntho (v) = 0

Ho batloa : motsamao o otlolohileng (p)

Tharollo:

p = mv = (5)(0) = 0

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Bala haholoanyane

Matla - mathata le litharollo

Matla ke sekhahla seo mosebetsi o etsoang ka sona nakong e itseng. Ho ya ka dipalo, matla ke karolelano ya mosebetsi/nako.

P = Bophara/Bophara

Tlhaloso: P = matla (Joule/motsotswana = Watt), W = mosebetsi (Joule), t = nako e sa fellang (motsotswana)

Ho latela equation ena, ho ka fihlelwa qeto ya hore ha sekgahla sa mosebetsi se le seholo, matla a ba maholo. Ka lehlakoreng le leng, ha sekgahla sa mosebetsi se le senyenyane, matla a ba manyane. Sekgahla sa mosebetsi se bolela sekgahla seo mosebetsi o etswang ka sona.

Matla ke sekalase. Yuniti ya matla ya SI ke Joule/bobedi. Joule/bobedi = Watt (e kgutsufaditsweng e le W), e rehelletsweng jwalo ho hlompha James Watt. Yuniti ya mmuso wa Brithani ya matla ke boima ba maoto ka motsotsoana.

Yuniti ena e nyane haholo bakeng sa merero e sebetsang, kahoo yuniti e kholoanyane ea matla a lipere (e khutsufalitsoeng e le hp) e sebelisoa. Matla a lipere a le mong = liponto tse 550 tsa maoto ka motsotsoana = Watts tse 764 = ¾ kilowatt.

Palo ea mosebetsi e ka boela ea hlalosoa ka matla x nako ea diyuniti, mohlala, kilowatt-hours kapa kWh. KWh e le 'ngoe e bolela mosebetsi o etsoang ka sekhahla se sa fetoheng sa 1 kiloWatt ka hora e le 'ngoe.

1. Motho ea boima ba lik'hilograma tse 50 o matha litepising tse bophahamo ba limithara tse 10 ka metsotso e 2. Ho potlaka ka lebaka la matla a khoheli (g) ke 10 m/ s ^2. Fumana matla.

Tse tsejoang:

Boima (m) = 50 kg

Bophahamo (h) = limithara tse 10

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s ²

Nako e sa fellang (t) = metsotso e 2 = 2 (60) = metsotsoana e 120

Ho Batloa : Matla (P)

Tharollo:

Foromo ea matla:

P = W / t

P = matla , W = mosebetsi , t = nako

Foromo ea Mosebetsi:

W = F s = wh = mgh

W = mosebetsi , F = matla , w = boima , d = ho falla , h = bophahamo , m = boima, g = ho potlaka ka lebaka la matla a khoheli

W = mgh = (50)(10)(10) = 5000 Joule.

P = W / t = 5000 / 120 = 41.7 Lijoule/se c ho d.

2. Bala matla a hlokahalang bakeng sa motho ea boima ba lik'hilograma tse 60 ea hloang sefate se bolelele ba limithara tse 5 ka metsotsoana e 10. Ho potlaka ka lebaka la matla a khoheli ke 10 m/s ².

Tse tsejoang:

Boima (m) = 60 kg

Bophahamo (h) = limithara tse 5 s

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s ²

Nako ea ho arohana (t) = metsotsoana e 10

Ho batloa : Matla

Tharollo:

Mosebetsi:

W = mgh = (60)(10)(5) = 3000 Joule

Matla:

P = W / t = 3000 / 10 = 300 Joules/se cond.

3. Metlae e potolohang e nang le matla a li-watts tse 300 le nako ea metsotso e 5 e potolohang lipotoloho tse 5. Matla ao e a sebelisang ke….

A. 15 kJ

B. 75 kJ

C. 90 kJ

D. 450 kJ

Tse tsejoang:

Matla (P) = 300 Watts = 300 Joules/motsotsoana

Nako (T) = metsotso e 5 = 5 (metsotsoana e 60) = metsotsoana e 300

Palo ea lipotoloho = 5

Ho batloa: Matla a sebelisoang ke metlae e potolohang

Tharollo:

Matla - mathata le litharollo

Karabo e nepahetseng ke D.

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Bala haholoanyane

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng - mathata le litharollo

1. Boloko bo thella fatshe hodima sekgahla se sekametseng hantle ntle le kgohlano . Lebelo la boloko ke eng ha le fihla fatshe? Ho potlaka ka lebaka la matla a khoheli ke 10 m/s ²

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng 1 Tse tsejoang:

Bolelele (h) = 8 m

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s ²

Ho batloa : lebelo (v)

Tharollo :

Matla a pele a mechini (ME _o) = matla a khoheli a ka bang teng (PE)

ME _o= PE = mgh = m (10)(8) = 80 m

Matla a ho qetela a mechini (ME _t ) = matla a kinetic (KE)

ME _t= KE = ½ mv ²

Molao-motheo oa paballo ea matla a mechini o bolela hore matla a pele a mechini = matla a ho qetela a mechini:

ME _o= ME _t

80 m = ½ mv ²

80 = ½ v ²

160 = v ²

v = √160 = √(16)(10) = 4√10 m/s

2. Ntho e boima ba 1-kg e thella tlase ka dimithara tse 8. Fumana matla a kinetic kamora hore ntho e tsamaye ka dimithara tse 5… Ho potlaka ka lebaka la matla a khoheli g = 10 m/s ²

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng 2 Tse tsejoang:

Boima (m) = 0.2 kg

d = limithara tse 5

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s ²

Ho batloa : matla a kinetic (KE)

Tharollo:

sebe 30 ^o = h / d

0.5 = lihora / 5

h = (0.5)(5) = limithara tse 2.5

Phetoho ea bophahamo ba ntho ke limithara tse 2.5.

Matla a pele a mechini (ME _o ) = matla a khoheli a ka bang teng (PE)

ME _o= PE = mgh = (1)(10)(2.5) = 25 Joule

Matla a ho qetela a mechini (ME _t ) = matla a kinetic (KE)

ME _t = KE

Molao-motheo oa paballo ea matla a mechini o bolela hore matla a pele a mechini = matla a ho qetela a mechini:

ME _o= ME _t

25 = KE

Matla a kinetic = 25 Joule.

[ID ea sephutheloana sa wpdm='1170′]

Bala haholoanyane

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a libaka tse kobehileng - mathata le litharollo

1. Sekotwana sa 1-kg se thella fatshe hodima bokahodimo bo boreledi bo kobehileng. Fumana matla a kinetic le lebelo la sekotwana sebakeng se tlase ka ho fetisisa. Ho potlaka ka lebaka la matla a khoheli ke 10 m/s ².

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a libaka tse kobehileng 1 Tse tsejoang:

Boima (m) = 1 kg

Phetoho ea bophahamo (h) = 5 m

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s ²

Ho batloa: Matla a kinetic (KE) le lebelo la block.

Tharollo:

(a) Matla a kinetic

Matla a pele a mechini = matla a khoheli a ka bang teng

ME _o= PE = mgh = (1)(10)(5) = 50 Joule

Matla a ho qetela a mechini = matla a kinetic

ME _t= KE = ½ mv _t²

Molao-motheo oa paballo ea matla a mechini o bolela hore matla a pele a mechini = matla a ho qetela a mechini:

ME _o= ME _t

PE = KE

50 = KE

Matla a Kinetic (KE) = 50 Joules.

(b) Lebelo la Block

Molao-motheo oa paballo ea matla a mechini:

Matla a pele a mechini (ME _o) = matla a ho qetela a mechini (ME _t)

Matla a khoheli a ka bang teng (PE) = matla a kinetic (KE)

50 = ½ mv ²

2(50) / m = v ²

100 / 1 = v ²

100 = v ²

v = √100

v = 10 m/s

2. Ntho e boima ba 2-kg e thella fatshe ntle le kgohlano. Matla a kinetic le lebelo la ntho eo ke eng ho dimithara tse 2 ka hodima lefatshe. Ho potlaka ka lebaka la matla a khoheli ke 10 m/s ²

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a libaka tse kobehileng 2 Tse tsejoang:

Boima (m) = 2 kg

Phetoho ea bophahamo (h) = 10 – 2 = 8 m

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s ²

Ho batlwa : matla a kinetic (KE) le lebelo (v) ho limithara tse 2 ka holim'a lefatše.

Tharollo:

(a) Matla a kinetic a limithara tse 2 ka holim'a lefatše

Matla a pele a mechini = matla a khoheli a ka bang teng

ME _o= PE = mgh = (2)(10)(8) = 160 Joule

Matla a ho qetela a mechini = matla a kinetic

ME _t= KE = ½ mv _t²

Molao-motheo oa paballo ea matla a mechini o bolela hore matla a pele a mechini = matla a ho qetela a mechini:

ME _o= ME _t

PE = KE

160 = KE

Matla a kinetic (KE) a limithara tse 2 ka holim'a lefatše ke 160 Joules.

(b) Lebelo la ntho sebakeng se tlase ka ho fetisisa

Molao-motheo oa paballo ea matla a mechini:

Matla a pele a mechini (ME _o) = matla a ho qetela a mechini (EM _t)

Matla a khoheli a ka bang teng (PE) = matla a kinetic (KE)

160 = ½ mv ²

160 = ½ (2) v ²

160 = v ²

v = √160 = √(16)(10) = 4√10 m/s

[ID ea sephutheloana sa wpdm='1167′]

Bala haholoanyane

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane - mathata le litharollo

1. Bolo ea maoto e rahiloeng e tloha fatše ka sekhutlo θ = 30 ^o ka lebelo la pele la 10 m/s. Boima ba bolo = 0.1 kg. Ho potlaka ka lebaka la matla a khoheli ke 1 0 m/s ² . Fumana (a) Matla a khoheli a ka bang teng ntlheng e phahameng ka ho fetisisa (b) Ntlha e phahameng ka ho fetisisa kapa bophahamo bo phahameng ka ho fetisisa

Tse tsejoang:

Boima (m) = 0.1 kg

Lebelo la pele (vo _o) = 10 m/s

Sekhutlo = 30 ^o

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s ²

Tharollo:

(a) Matla a khoheli a ka bang teng

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane - mathata le litharollo 1

Bala karolo e rapameng (v _ox) le karolo e otlolohileng (v _oy) ea lebelo la pele.

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane - mathata le litharollo 2 v_ox= v_o cos θ = (10)(cos 30^o) = (10)(0.5√3) = 5√3 m/s

v _oy= v _o sebe θ = (10)(sebe 30 ^o ) = (10)( 0.5) = 5 m/s

Matla a pele a mechini

Matla a pele a mechini (ME _o) = matla a kinetic (KE)

ME _o= KE = ½ mv _o² = ½ (0.1) (10) ² = ½ (0.1) (100) = ½ (10) = 5 Joules

Matla a ho qetela a mechini

Matla a kinetic ntlheng e phahameng ka ho fetisisa:

KE = ½ mv _ox² = ½ (0.1) (5√3) ² = ½ (0.1) ((25) (3)) = ½ (0.1) (75) = 3.75 Joules

Molao-motheo oa paballo ea matla a mechini

Matla a pele a mechini (ME _o) = matla a ho qetela a mechini (ME _t)

KE = PE + KE

5 = EP + 3.75

PE = 5 – 3.75 = 1.25 Joule

Matla a khoheli a ka bang teng ntlheng e phahameng ka ho fetisisa ke 1.25 Joules.

(b) Ntlha e phahameng ka ho fetisisa kapa bophahamo bo phahameng ka ho fetisisa

PE = mgh

1.25 = (0.1)(10) h

1.25 = h

Bophahamo bo phahameng ka ho fetisisa ke limithara tse 1.25.

2. Bolo ea 0.1-kg e shebiloe ka ho otloloha ka lebelo la pele v _o= 10 m/s ho tloha mohahong o bophahamo ba limithara tse 10. Ho potlaka ka lebaka la matla a khoheli ke 10 m/s ^2. Fumana matla a kinetic a bolo ha e otla fatše.

Tse tsejoang:

Boima (m) = 0.1 kg

Lebelo la pele (vo _o) = 10 m/s

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s ²

Phetoho ea bophahamo (h) = 10 – 2 = 8 m

Ho batloa: matla a kinetic a limithara tse 2 ka holim'a lefatše

Tharollo:

Matla a khoheli a ka bang teng (PE) = mgh = (0.1)(10)(10) = 10 Joules

Matla a kinetic a pele (KE)= ½ mv _o² = ½ (0.1)(10) ² = ½ (0.1)(100) = ½ (10) = 5 Joules

Matla a ho qetela a kinetic = matla a pele a khoheli + matla a pele a kinetic = 10 + 5 = 15 Joules

[ID ea sephutheloana sa wpdm='1173′]

Bala haholoanyane