Boholo ba torque ea net - mathata le litharollo

1. Matla P a sebediswa pheletsong e nngwe ya lehlasedi le bolelele ba 2 m. Boholo ba lehlasedi ke bofe? torqueMothapo oa potoloho ntlheng ea A.

Boholo ba torque ea net - mathata le litharollo 1Tse tsejoang:

Matla (F) = 10 N

Bolelele ba AB (r)AB) = 2 m

Matla a F a otlolohile ho lehlaseli.

Letsoho la lever (l)) =rAB sebe 90o = (2 m)(1) = 2 m

Oa Batla: Torque e potolohileng axis ea potoloho

Tharollo:

Torque:

τ = F l = (10 N)(2 m) = 20 N m

Letšoao la ho eketsa ka lebaka la lehlaseli e potoloha ho potoloha ho ya ka lehlakoreng le leng.

2. Bolelele ba lehlaseli AB ke 2 m mme boholo ba matla F ke 10 N. Boholo ba torque ke bofe? Mothapo wa potoloho ntlheng ya A.

Boholo ba torque ea net - mathata le litharollo 2Tse tsejoang:

Matla (F) = 10 N

Bolelele ba AB (r)AB) = 2 m

Letsoho la lever (l)) =rAB sebe 60o = (2 m)(0.53) = 3 m

Oa Batla: Torque e potolohileng axis ea potoloho

Tharollo:

Torque:

τ = F l = (10 N)(3 m) = 103 N m

Letšoao la ho eketsa hobane matla F a baka mahlaseli e potoloha ho potoloha ho ya ka lehlakoreng le leng.

3. Bolelele ba lehlaseli ke 2 m. Boholo ba F1 ke 10 N le boholo ba F2 ke 15 N. Fumana torque ea letlooa bohareng ba lehlaseli.

Mothapo oa potoloho bohareng ba lehlaseli.

Boholo ba torque ea net - mathata le litharollo 3Tse tsejoang:

Matla a 1 (F)1) = 10 N

The distanta pakeng tsa F1 le bohareng ba lehlaseli (r1) = 1 m

Letsoho la lever 1 (l)1) =r1 sebe 90o = (1 m)(1) = 1 m

Matla F1 e otlolohile ho lehlaseli.

Matla a 2 (F)2) = 15 N

Sebaka se pakeng tsa F2 le bohareng ba lehlaseli (r2) = 1 m

Matla F2 e otlolohile ho lehlaseli.

Letsoho la lever 2 (l)2) =r1 sebe 90o = (1 m)(1) = 1 m

Ho batloa: Ttorque ea letlooa e potolohang mothapo oa potoloho

Tharollo:

Torque 1:

τ1 =F1 l1 = (10 N)(1 m) = 10 N m

Letšoao la ho eketsa ka lebaka la matla a F1 e baka lehlaseli e potoloha ho potoloha ho ya ka lehlakoreng le leng.

Torque 2:

τ2 =F2 l2 = (15 N)(1 m) = -15 N

Letšoao la ho tlosa hobane matla a F2 e etsa hore lehlaseli le e potoloha ka ho ya ka oache.

Torque ea letlooa:

Στ = τ1 – τ2 = 10 – 15 = – 5 N m

Letšoao la ho tlosa hobane lehlaseli ho e potoloha ka ho ya ka oache.

4. Bolelele ba lehlaseli AB ke 2 m, Boholo ba F1 ke 10 N le boholo ba F2 is 10 N. Fumana torque ea letlooa bohareng ba lehlaseli.

Boholo ba torque ea net - mathata le litharollo 4Mothapo oa potoloho bohareng ba lehlaseli.

Tse tsejoang:

Matla a 1 (F)1) = 10 Nn

Sebaka se pakeng tsa F1 le bohareng ba lehlaseli (r1) = 1 m

Letsoho la lever 1 (l)1) =r1 sebe 60o = (1 m)(0.53= 0.53 m

Matla a 2 (F)2) = 10 N

Sebaka se pakeng tsa F2 le bohareng ba lehlaseli (r2) = 1 m

Matla F2 e otlolohile ho lehlaseli.

Letsoho la lever 2 (l)2) = r2 sebe 90o = (1 m)(1) = 1 m

Ho batloa: Torque ea letlooa e mabapi le axis ea potoloho

Tharollo:

Torque 1:

τ1 =F1 l1 = (10 N)(0.53 m) = 5√3 = 8.7 Nm

Letšoao la ho eketsa hobane matla a F1 e etsa hore lehlaseli le e potoloha ka ho ya ka oache.

Torque 2:

τ2 =F2 l2 = (10 N)(1 m) = -10 N m

Letšoao la ho tlosa hobane matla a F2 e etsa hore lehlaseli le e potoloha ka ho ya ka oache.

Torque ea letlooa:

Στ = τ1 – τ2 = 8.7 – 10 = – 1.3 N m

Letšoao la ho tlosa hobane matla a letlooa a etsa hore lehlaseli le e potoloha ka ho ya ka oache.

5. Bolelele ba lehlaseli ke 10 m, boholo ba F1 ke 10 N, boholo ba F2 ke 10 N le boholo ba F3 ke 15 N. Sebaka se pakeng tsa ntlha A le ntlha C ke 7.5 m. Matla F2 e fumanehang bohareng ba lehlaseli. Fumana torque ea letlooa mabapi le ntlha ea C e fumanehang ho 2.5 m ho tloha ntlheng ea B.

Mokhahlelo oa potoloho o sebakeng sa C

Boholo ba torque ea net - mathata le litharollo 5Tse tsejoang:

Matla a 1 (F)1) = 10 N

Sebaka se pakeng tsa F1 le ntlha C (r1) = 2.5 m

Matla F1 e otlolohile ho lehlaseli.

Letsoho la lever 1 (l)1) =r1 sebe 90o = (2.5 m)(1) = 2.5 m

Matla a 2 (F)2) = 10 N

Sebaka se pakeng tsa F2 le ntlha C (r2) = 2.5 m

Matla a F2 e otlolohile ho lehlaseli.

Letsoho la lever 2 (l)2) = r2 sebe 90o = (2.5 m(1) = 2.5 m

Matla a 3 (F)3) = 15 N

Sebaka se pakeng tsa F3 le ntlha C (r)3) = 7.5 m

Matla a F3 e otlolohile ho lehlaseli.

Letsoho la lever 3 (l)3) = r3 sebe 90o = (7.5 m)(1) = 7.5 m

Ho batloa: Torque ea letlooa e mabapi le axis ea potoloho

Tharollo:

Torque 1:

τ1 =F1 l1 = (10 N)(2.5 m) = 25 N m

Letšoao la ho eketsa hobane matla a F1 e etsa hore lehlaseli le e potoloha ka ho ya ka oache.

Torque 2:

τ2 =F2 l2 = (10 N)(2.5 m) = 25 N m

Tletshwao la hae le eketsehileng hobane matla a F2 e etsa hore lehlaseli le e potoloha ka ho ya ka oache.

Torque 3:

τ3 =F3 l3 = (15 N)(7.5 m) = -112..5 N m

Letšoao la ho tlosa hobane matla a F3 e etsa hore lehlaseli le e potoloha ka ho ya ka oache.

Torque ea letlooa:

Στ = τ1 + τ2 – τ3 = 25 + 25 - 112.5 = – 62.5 N m

Letšoao la ho tlosa hobane matla a letlooa a etsa hore lehlaseli le e potoloha ka ho ya ka oache.

6. Bolelele ba lehlaseli ke 10 m, boholo ba F1 ke 10 N, boholo ba F2 ke 10 N le boholo ba F3 ke 10 N. Fumana torque ea letlooa mabapi le ntlha ea A, e fumanehang 5 m ho tloha poiBoholo ba torque ea net - mathata le litharollo 6nt ea ts'ebeliso ea matla F1.

Mokhahlelo oa potoloho ntlheng ea A.

Tse tsejoang:

Matla a 1 (F)1) = 10 N

Sebaka se pakeng tsa F1 le ntlha A (r)1) = 5 m

Letsoho la lever 1 (l)1) =r1 sebe 60o = (5 m)(0.53= 2.53 m

Etsa matla 2 (F)2) = 10 N

Sebaka se pakeng tsa F2 le ntlha A (r)2= 0

Matla a F2 e otlolohile ho lehlaseli.

Letsoho la lever 2 (l)2) = r2 sebe 90o = (0)(1) = 0

Matla a 3 (F)3) = 10 N

Sebaka se pakeng tsa F3 le ntlha A (r)3) = 10 m

Letsoho la lever 3 (l)3) = r3 sebe 30o = (10 m)(0.5) = 5 m

Ho batloa: torque ea letlooa e potolohileng motsoako oa potoloho

Tharollo:

Torque 1:

τ1 =F1 l1 = (10 N)(2.5√3 limithara) = 25√3 = 43.3 N m

Letšoao la ho eketsa hobane matla a F1 e etsa hore lehlaseli le e potoloha ka ho ya ka oache.

Torque 2:

τ2 =F2 l2 = (10 N)(0) = 0

Torque 3:

τ3 =F3 l3 = (10 N)(5 m) = -50 N m

Letšoao la ho tlosa hobane matla a F3 e etsa hore lehlaseli le e potoloha ka ho ya ka oache.

Torque ea letlooa:

Στ = τ1 + τ2 – τ3 = 43.3 + 0 - 50 = – 6.7 N m

Letšoao la ho tlosa hobane matla a letlooa a etsa hore lehlaseli le e potoloha ka ho ya ka oache.

Bala haholoanyane

Ho thulana ho sa thekeseleng ka karolo e le 'ngoe - mathata le litharollo

1. A 500-grke ntho, A, ke tsamaya ho 10 limithara / s le ntho ea 200-gram, B, e tsamaeang ka lebelo la 12 m/s. Lintho lia atamelana 'me lia thulana. Haeba lebelo la ntho ea A ka mor'a Ho thulana ke 6 m/s, lebelo la ntho B ke lefe kamora ho thulana?

Tse tsejoang:

Boholo ea ntho ea 1 (m1) = digrama tse 500 = 0.5 kg

Boholo ea ntho 2 (m2) = digrama tse 200 = 0.2 kg

Qalong Velocity ea ntho ea 1 (v1) = -10 m/s

Lebelo la pele la ntho 2 (v2) = 12 m/s

Lebelo la ho qetela la ntho 1 (v1') = 6 m/s

Matšoao a ho ba le kamano le ...

o ne a batla : lebelo la ho qetela la ntho ea 2 (v2')

Tharollo:

m1 v1 +m2 v2 = m1 v1' + m2 v2'

(0.5)(-10) + (0.2)(12) = (0.5)(6) + (0.2)(v2')

-5 + 2.4 = 3 + 0.2 v2'

-2.6 = 3 + 0.2 v2'

-2.6 – 3 = 0.2 v2'

-5.6 = 0.2 v2'

v2' = -5.6 / 0.2

v2' = -28 m/s

Lebelo la ntho ea 2 kamora ho thulana ke 28 m/s.

Matšoao a ho ba le kamano le ...

2. Lintho tse peli tse lekanang ka boima lia atamelana 'me lia thulana. Lebelo la ntho ea 1 ke 6 m/s 'me lebelo la ntho ea 2 ke 8 m/s. Kamora ho thulana, ntho ea 2 e tsamaea ka letsohong le letšehali ka lebelo la 5 m/s. Boholo le tataiso ea lebelo la ntho ea 1 ke life kamora ho kopana? Ho thulana?

Tseba :

Boholo ea ntho 1 (m1) = m

Boholo ea ntho ea 2 (m2) = m

Lebelo la pele la ntho 1 (v1) = -6 m/s

lebelo la pele la ntho ea 2 (v2) = 8 m/s

Lebelo la ho qetela la ntho ea 2 (v2') = -5 m/s

o ne a batla : boholo le tataiso ea ntho ea 1 kamora ho thulana

Tharollo:

Foromo ea paballo ea lebelo le otlolohileng :

m1 v1 +m2 v2 = m1 v1' + m2 v2'

mv1 +m v2 = m v1' + m v2'

m (v1 + v2) = m (v1' + v2')

v1 + v2 = v1' + v2'

-6 + 8 = v1' – 5

2 = v1' – 5

2 + 5 = v1'

v1' = 7 m/s

Lebelo la ntho ea 1 kamora ho thulana (v1') is 3m/s.

Matšoao a ho ba le kamano le ...

3. Bolo ea 1-kg ea 1 le 2-kg ea 2 li na le tsela e tšoanang 'me li thulana ka mokhoa o sa tsitsang. Pele ho thulana, bolo ea 1 e tsamaea ka lebelo la 10 m/s 'me bolo ea 2 e tsamaea ka lebelo la 5 m/s. Lebelo la bolo ea 2 kamora ho thulana ke 4 m/s. Fumana lebelo la bolo ea 1 kamora ho thulana.

Tse tsejoang:

Boholo Bolo 1 (m1) = 1 kg

Boholo Bolo 2 (m2) = 2 kg

Lebelo la bolo 1 (ka hare ho1) = 10 m/s

Lebelo la bolo 2 (v2) = 5 m/s

Lebelo la ho qetela la bolo 2 (v2') = 4 m/s

Letšoao la ho eketsa lebelo le bontša hore libolo li shebile ka lehlakoreng le le leng.

o ne a batla : lebelo la ho qetela la bolo 1 (v1')

Tharollo:

m1 v1 +m2 v2 = m1 v1' + m2 v2'

(1)(10) + (2)(5) = (1)(v1') + (2)(4)

10 + 10 = v1' + 8

20 – 8 = v1'

v1' = 12 m/s

Lebelo la bolo 1 kamora ho thulana ke 12m/s.

[ID ea sephutheloana sa wpdm='1190′]

  1. Mathata le litharollo tsa lebelo la mola
  2. Mathata le litharollo tsa ho potlaka le ho susumetsoa ke maikutlo
  3. Ho thulana ho tenyetsehang ka ho phethahetseng mathateng le litharollong tsa tekanyo e le 'ngoe
  4. Likhohlano tse phethahetseng tsa inelastic mathateng le litharollo tsa tekanyo e le 'ngoe
  5. Mathata le litharollo tsa ho thulana ha inelastic ka tekanyo e le 'ngoe

Bala haholoanyane

Likhohlano tse sa senyeheng ka tekanyo e le 'ngoe - mathata le litharollo

1. Kulo ea 30 gram e tsamaeang ka lebelo la 30 m/s e thulana le boloko ea 1-kg ha e phomotse. Fumana lebelo la boloko haeba kulo le boloko li hokahana hammoho ka lebaka la Ho thulana.

Tse tsejoang:

Boholo ea kulo (m1) = digrama tse 30 = 0.03 kg

Boholo ea boloko (m2) = 1 kg

Lebelo la pele la kulo (v1) = 30 m/s

lebelo la pele la boloko (v2) = 0 (thipa e phomotseng)

o ne a batla : lebelo la kulo le thibelo kamora ho thulana (v')

Tharollo:

m1 v1 +m2 v2 = (m1 +m2) v'

(0.03)(30) + (1)(0) = (0.03 + 1) v'

0.9 + 0 = 1.03 v'

0.9 = 1,03 v'

v' = 0.9 / 1,03

v' = 0.87 m/s

2. Bolo ea biliadi A ea boima ba 2 kg e tsamaeang ka lebelo vA = 6 ms-1 e thulana ka hlooho le bolo ea B e boima bo lekanang. Haeba ho thulana ho sa thekesele hantle, lebelo la libolo tse peli ka mor'a ho thulana ke lefe.

Tse tsejoang:

Boima A (mA) = 2 kg

Boima ba B (mB) = 2 kg

Lebelo la pele la bolo A (vA) = -6 m/s

Lebelo la pele la bolo B (vB) = 4 m/s

Matšoao a ho ba le kamano le ...

o ne a batla: lebelo la libolo tse peli ka mor'a ho thulana. (v')

Tharollo:

mA vA +mB vB = (mA' + mB) v'

(2)(-6) + (2)(4) = (2 + 2) v'

-12 + 8 = 4 v'

-4 = 4 v'

v' = -4 / 4

v' = -1 m/s

3. m1 = 3 kg 'me m2 = 4 kg atamelana ka lehlakoreng le fapaneng ka lebelo la v1 = 10 m/s 'me v2 = 12 m/s. Haeba ho thulana ho sa thekesele hantle, lebelo la libolo tse peli ka mor'a ho thulana ke lefe?

Tse tsejoang:

Boholo be ntho 1 (m1) = 3 kg

Boholo be ntho 2 (m2) = 4 kg

Lebelo la ntho 1 (v1) = -10 m/s

Lebelo la ntho 2 (v2) = 12 m/s

o ne a batla : lebelo ka mor'a ho thulana (v')

Tharollo:

m1 v1 +m2 v2 = (m1' + m2) v'

(3)(-10) + (4)(12) = (3 + 4) v'

-30 + 48 = 7 v'

18 = 7 v'

v' = 18 / 7

v' = 2.6 m/s

[ID ea sephutheloana sa wpdm='1157′]

  1. Mathata le litharollo tsa lebelo la mola
  2. Mathata le litharollo tsa ho potlaka le ho susumetsoa ke maikutlo
  3. Ho thulana ho tenyetsehang ka ho phethahetseng mathateng le litharollong tsa tekanyo e le 'ngoe
  4. Likhohlano tse phethahetseng tsa inelastic mathateng le litharollo tsa tekanyo e le 'ngoe
  5. Mathata le litharollo tsa ho thulana ha inelastic ka tekanyo e le 'ngoe

Bala haholoanyane

Ho thulana ho tenyetsehang ka ho phethahetseng ka tekanyo e le 'ngoe - mathata le litharollo

1. Bolo ea ligrama tse 200, A, e tsamaeang ka lebelo la 10 m/s e otla bolo ea ligrama tse 200, B, ha e phomotse. Lebelo la bolo ea A le la B ke lefe ka mor'a moo? Ho thulana?

Tse tsejoang:

Boholo ea bolo A (mA) = digrama tse 200 = 0.2 kg

Boima ba bolo B (mB) = digrama tse 200 = 0.2 kg

Lebelo la bolo A pele ho thulana (v)A) = 10 m/s

Lebelo la bolo B pele ho thulana (v)B= 0

Oa Batla: lebelo la bolo A (v)A') le lebelo la bolo B (vB') kamora ho thulana

Tharollo:

vA' = vB = 0

vB' = vA = 10 m/s

2. Lintho tse peli tse lekanang ka boima lia atamelana, lia thulana ebe lia tlola. Lebelo la boima ba A pele ho thulano ke 8 m/s 'me lebelo la boima ba B pele ho thulano ke 12 m/s. Boholo le tataiso ea eona ke efe? Velocity ea boima ba A le boima ba B kamora ho thulana!

Tse tsejoang:

Boima A (mA) = m

Boima ba B (mB) = m

Lebelo la boima A pele ho thulana (v)A) = -8 m/s

Lebelo la boima B pele ho thulana (v)B) = 12 m/s

Matšoao a ho ba le kamano le ...

Oa Batla: boholo le tataiso ea lebelo la boima A (v)A') le boima B (vB') kamora ho thulana

Tharollo:

Ka ho thulana ho tenyetsehang ka ho phethahetseng, haeba lintho tse boima bo lekanang joale lebelo la A kamora ho thulana (vA') = lebelo la B pele ho thulana (vB) le lebelo la B kamora ho thulana (vB') = lebelo la A pele ho thulano (vA).

Haeba pele ho thulana, A e ya ka letsohong le letona mme B e ya ka letsohong le letshehadi, ebe, kamora ho thulana, A e ya ka letsohong le letshehadi mme B e ya ka letsohong le letona.

Lintho li na le boima bo lekanang 'me Ho thulana ho tenyetseha ka ho phethahetseng kahoo lintho ka bobeli li fapanyetsana lebelo.

vA' = -vB = -12 m/s

vB' = vA = 8 m/s

Matšoao a ho ba le kamano le ...

3. Ntho ea boima ba 2-kg, A, e tsamaeang ka lebelo la 10 m/s e otla bolo ea 4-kg, B, e tsamaea ka lebelo la 20 m/s. Haeba ho thulana ho tenyetseha ka ho feletseng, lebelo la ntho A le ntho B ke lefe ka mor'a ho thulana?

Tse tsejoang:

Boima A (mA) = 2 kg

Boima ba B (mB) = 4 kg

Lebelo la ntho A pele ho thulana (v)A) = 10 m/s

Lebelo la ntho B pele ho thulana (vB) = 20 m/s

o ne a batla : lebelo la ntho A (vA') le lebelo la ntho B (vB') kamora ho thulana

tharollo :

In ho thulana ka botlalo, haeba lintho li na le boima bo lekanang 'me li atamelana, lebelo la ntho ka mor'a ho thulana le baloa ho sebelisoa mokhoa ona:

Ho thulana ho tenyetsehang ka ho phethahetseng ka tekanyo e le 'ngoe - mathata le litharollo 1

Lebelo la ntho A kamora ho thulana:

Ho thulana ho tenyetsehang ka ho phethahetseng ka tekanyo e le 'ngoe - mathata le litharollo 2

4. Ho tsamaea ha 100-gram ka lebelo la 20 m/s ho otla lebota ka ho feletseng. Boholo le tataiso ea lebelo la ntho ka mor'a ho thulana ke life?

Tse tsejoang:

Boima (mA) = digrama tse 100 = 0.1 kg

Boima ba lebota (mB) = ho se fele

Lebelo la boima pele ho thulana (vA) = 20 m/s

Lebelo la boima ka mor'a ho thulana (vB= 0

o ne a batla : boholo le tataiso ea lebelo ka mor'a ho thulana

Tharollo:

Haeba vB = 0, mA e nyane haholo le m2 e kholo haholo ho feta vA' = -vA le v2' = 0.

Matšoao a ho ba le kamano le ...

5. Libolo tse peli, A ka bongata ba 2 kg le bolo B e nang le boima ba 5-kg, pele le ka mora ho thulana di bontshitswe setshwantshong se ka tlase. Haeba ho thulana ho tenyetseha ka ho phethahetseng, lebelo la bolo A ke lefe pele ho thulana?

Tse tsejoang:

Boima ba bolo A (mA) = 2 kgHo thulana ho tenyetsehang ka ho phethahetseng - mathata le litharollo 1

Boima ba bolo B (m)B) = 5 kg

Lebelo la bolo B pele ho thulana (vB) = 2 m/s

Lebelo la bolo A kamora ho thulana (vA') = 5 m/s

Lebelo la bolo B kamora ho thulana (vB') = 4 m/s

Libolo ka bobeli li ntse li tsamaea ka letsohong le letona kahoo lebelo la tsona le saennoe hantle.

Ho batloa: Lebelo la bolo A pele ho thulana (vA)

Tharollo:

mA vA +mB vB = mA vA' + mB vB'

2(vA) + (5)(2) = (2)(5) + (5)(4)

2(vA) + 10 = 10 + 20

2(vA) + 10 = 30

2(vA) = 30 – 10

2(vA= 20

vA = 20 / 2

vA = 10 m/s

6. Lintho A le B li tsamaea ka sefofane se bataletseng, joalo ka ha ho bontšitsoe setšoantšong se ka tlase. Haeba ho thulana ho tenyetseha ka ho phethahetseng 'me lebelo la ntho B kamora ho thulana le 15 limithara / s1, Lebelo la ntho A ke lefe ka mora ho thulana.

Tse tsejoang:

Boima ba ntho A (mA) = 5 kgHo thulana ho tenyetsehang ka ho phethahetseng - mathata le litharollo 2

Boima ba ntho B (m)B) = 2 kg

Lebelo la ntho A pele ho thulana (vA) = 12 m/s

Lebelo la ntho B pele ho thulana (vB) = 10 m/s

Lebelo la ntho B kamora ho thulana (vB') = 15 m/s

Lintho ka bobeli, pele le ka mor'a ho thulana, li ea ka ho le letona e le hore lebelo la tsona le saennoe hantle.

Ho batloa: Lebelo la ntho A kamora ho thulana (vA')

Tharollo:

mA vA +mB vB = mA vA' + mB vB'

(5)(12) + (2)(10) = (5)vA' + (2)(15)

60 + 20 = (5)vA'+ 30

80 = (5)vA'+ 30

80 – 30 = (5)vA'

50 = (5)vA'

vA' = 50/5

vA' = 10 m/s

[ID ea sephutheloana sa wpdm='1156′]

  1. Mathata le litharollo tsa lebelo la mola
  2. Mathata le litharollo tsa ho potlaka le ho susumetsoa ke maikutlo
  3. Ho thulana ho tenyetsehang ka ho phethahetseng mathateng le litharollong tsa tekanyo e le 'ngoe
  4. Likhohlano tse phethahetseng tsa inelastic mathateng le litharollo tsa tekanyo e le 'ngoe
  5. Mathata le litharollo tsa ho thulana ha inelastic ka tekanyo e le 'ngoe

Bala haholoanyane

Matla le takatso - mathata le litharollo

1. Bolo e nyane e lahlelwa ka ho otloloha ka lebelo le sa fetoheng la 10 m/s. Bolo e otla lebota mme e bonahatsa ka lebelo le tshwanang. Phetoho ke efe ho lebelo le otlolohileng ea bolo?

Tse tsejoang:

Boholo (m) = 0.2 kg

Lebelo la pele (v)o) = -10 m/s

Lebelo la ho qetela (v)t) = 10 m/s

Matšoao a ho ba le kamano le ...

o ne a batla : phetoho motsamaong o otlolohileng (Δp)

Tharollo:

Foromo ea phetoho motsamaong o otlolohileng :

Δp = mvt – mvo = m (vt - vo)

Phetoho motsamaong o otlolohileng:

Δp = 0.2 (10 – (-10)) = 0.2 (10 + 10)

Δp = 0.2 (20)

Δp = 4 kg m/s

2. Bolo ea ligrama tse 10 o oa ka bolokolohi ho tloha bophahamong, e otla fatshe ka lebelo la 15 m/s, ebe e kgutlela hodimo ka lebelo la 10 m/s. Fumana hore na modumo o fella kae!

Tse tsejoang:

Boima (m) = digrama tse 10 = 0.01 kg

Lebelo la pele (v)o) = -15 m/s

Lebelo la ho qetela (v)t) = 10 m/s

Ho batloa: tšusumetso e tsoang ho (Ke)

Tharollo:

Tšusumetso (I) e lekana le phetoho ea momentum (Δp)

Ke = mvt – mvo = m (vt - vo)

Tšusumetso:

Ke = 0.01 (10 – (-15)) = 0.01 (10 + 15)

Ke = 0.01 (25)

I = 0.25 kg m/s

3. Bolo ea ligrama tse 200 e ile ea lahleloa ka ho rapama ka lebelo la 4 m/s, eaba bolo e otloa ka lehlakoreng le le leng. Bolo e kopana le kota ke 2 milmetsotsoana e 'meli 'me lebelo la bolo ka mor'a ho tloha beteng ke 12 m/s. boholo ba lebotho la exerted ka motsu o bolong ke …

Tse tsejoang:

Boima (m) = digrama tse 200 = 0.2 kg

Lebelo la pele (v)o) = 4 m/s

Lebelo la ho qetela (v)t) = 12 m/s

Nako e sa fellang (t) = 2 milliseconds = (2/1000) metsotsoana = 0.002 metsotsoana

o ne a batla : Boholo ba matla (F)

Tharollo:

Foromo ea tšusumetso:

Ke = F t

Foromo ea phetoho ea lebelo:

mvt – mvo = m (vt - vo)

Tšusumetso (I) e lekana le phetoho ea momentum (Δp)

I = Δp

F t = m (vt - vo)

F (0.002) = (0.2)(12 - 4)

F (0.002) = (0.2)(8)

F (0.002) = 1.6

F = 1.6 / 0.002

F = 800 Newton

[ID ea sephutheloana sa wpdm='1155′]

  1. Mathata le litharollo tsa lebelo la mola
  2. Mathata le litharollo tsa ho potlaka le ho susumetsoa ke maikutlo
  3. Ho thulana ho tenyetsehang ka ho phethahetseng mathateng le litharollong tsa tekanyo e le 'ngoe
  4. Likhohlano tse phethahetseng tsa inelastic mathateng le litharollo tsa tekanyo e le 'ngoe
  5. Mathata le litharollo tsa ho thulana ha inelastic ka tekanyo e le 'ngoe

Bala haholoanyane

Motsamao o otlolohileng - mathata le litharollo

1. Ntho e tsamaya ka lebelo le sa fetoheng la 10 m/s. Bala lebelo le otlolohileng ea ntho eo.

Tsejoa :

Boholo (m) = 1 kg

Velocity (v) = 10 m/s

Ho batloa: lebelo le otlolohileng (p)

Tharollo:

Foromo ea momentum e otlolohileng:

p = mv

p = lebelo le otlolohileng, m = boima, v = lebelo

Motsamao o otlolohileng:

p = mv = (1)(10) = 10 kg m/s2

2. Seboloko sa 2-kg le seboloko sa 4-kg se tsamaya ka lebelo le sa fetoheng la 20 m/s. Motsamao o otlolohileng wa diboloko ke ofe?

Tse tsejoang:

Boholo ea boloko A (mA) = 2 kg

Boholo ea boloko B (m)B) = 4 kg

Lebelo la boloko A (v)A) = 20 m/s

Lebelo la boloko B (v)B) = 20 m/s

Ho batloa: Motsamao o otlolohileng oa boloko A (p)A) le lebelo le otlolohileng la boloko B (pB)

Tharollo:

Motsamao o otlolohileng oa boloko A :

pA = mA vA = (2)(20) = 40 kg m/s

Motsamao o otlolohileng oa boloko B :

pB = mB vB = (4)(20) = 80 kg m/s

3. Boloko ba 2-kg bo tsamaya ka lebelo le sa fetoheng la 2 m/s mme boloko ba 2-kg bo tsamaya ka lebelo le sa fetoheng la 4 m/s. Fumana lebelo le otlolohileng la diboloko.

Tse tsejoang:

Boholo ea boloko A (mA) = 2 kg

Boima ba boloko B (mB) = 2 kg

Lebelo la boloko A (vA) = 2 m/s

Lebelo la boloko B (vB) = 4 m/s

Ho batloa: lebelo le otlolohileng la li-block

Tharollo:

Mothati oa momentum ea boloko A :

pA = mA vA = (2)(2) = 4 kg m/s

Motsamao o otlolohileng oa boloko B:

pB = mB vB = (2)(4) = 8 kg m/s

4. Ntho e boima ba lik'hilograma tse 5 e phomotseng. Motsamao o otlolohileng oa motsamao ke ofe?

Tse tsejoang:

Boima (m) = 5 kg

Lebelo la ntho (v) = 0

o ne a batla : lebelo le otlolohileng (leq)

Tharollo:

p = mv = (5)(0) = 0

[ID ea sephutheloana sa wpdm='1155′]

  1. Mathata le litharollo tsa lebelo la mola
  2. Mathata le litharollo tsa ho potlaka le ho susumetsoa ke maikutlo
  3. Ho thulana ho tenyetsehang ka ho phethahetseng mathateng le litharollong tsa tekanyo e le 'ngoe
  4. Likhohlano tse phethahetseng tsa inelastic mathateng le litharollo tsa tekanyo e le 'ngoe
  5. Mathata le litharollo tsa ho thulana ha inelastic ka tekanyo e le 'ngoe

Bala haholoanyane

Matla - mathata le litharollo

Matla ke sekhahla seo mosebetsi o etsoang ka sona nakong e itseng. Ho ya ka dipalo, matla ke karolelano ya mosebetsi/nako.

P = Bophara/Bophara

Tlhaloso: P = matla (Joule/motsotswana = Watt), W = mosebetsi (Joule), t = nako e sa fellang (motsotswana)

Ho latela equation ena, ho ka fihlelwa qeto ya hore ha sekgahla sa mosebetsi se le seholo, matla a ba maholo. Ka lehlakoreng le leng, ha sekgahla sa mosebetsi se le senyenyane, matla a ba manyane. Sekgahla sa mosebetsi se bolela sekgahla seo mosebetsi o etswang ka sona.

Matla ke sekalase. Yuniti ya matla ya SI ke Joule/bobedi. Joule/bobedi = Watt (e kgutsufaditsweng e le W), e rehelletsweng jwalo ho hlompha James Watt. Yuniti ya mmuso wa Brithani ya matla ke boima ba maoto ka motsotsoana.

Yuniti ena e nyane haholo bakeng sa merero e sebetsang, kahoo yuniti e kholoanyane ea matla a lipere (e khutsufalitsoeng e le hp) e sebelisoa. Matla a lipere a le mong = liponto tse 550 tsa maoto ka motsotsoana = Watts tse 764 = ¾ kilowatt.

Palo ea mosebetsi e ka boela ea hlalosoa ka matla x nako ea diyuniti, mohlala, kilowatt-hours kapa kWh. KWh e le 'ngoe e bolela mosebetsi o etsoang ka sekhahla se sa fetoheng sa 1 kiloWatt ka hora e le 'ngoe.

1. Boima ba 50-kg motho o matha ho nyoloha litepisi tse bophahamo ba limithara tse 10 in 2 metsotso. Aho potlaka kahobane matla a khoheli (g) ke 10 m/s2. Etsa qeto ea matla.

Tse tsejoang:

Boholo (m) = 50 kg

Height (h) = 10 mli-eter

Ho potlakisa ka baka la matla a khoheli (g) = 10 m/s2

Nako ea nako (t) = 2 motsotso = 2 (60) = 120 ea bobelis

o ne a batla : matla (P)

Tharollo:

Foromo ea matla:

P = W / t

P= matla, W = mosebetsi, t = nako

Foromo ea Mosebetsi:

W = F s = wh = mgh

W= mosebetsi, F = lebotho la, w = boima ba 'mele, d = ho baleha, h = bophahamo, m = boima, g = ho potlaka ka lebaka la matla a khoheli

W = mgh = (50)(10)(10) = 5000 Joule.

P = W / t = 5000 / 120 = 41.7 Joules/second.

2. Bala matla a hlokahalang bakeng sa motho ea boima ba lik'hilograma tse 60 ea hloang sefate se bolelele ba limithara tse 5 ka metsotsoana e 10. Ho potlaka ka lebaka la matla a khoheli ke 10 m/s2.

Tse tsejoang:

Boima (m) = 60 kg

Height (h) = limithara tse 5s

Ho potlakisa ka baka la matla a khoheli (g) = 10 m/s2

Nako ea nako (t) = 10 metsotsoana

o ne a batla : matla

Tharollo:

Mosebetsi:

W = mgh = (60)(10)(5) = 3000 Joule

Matla:

P = W / t = 3000 / 10 = 300 Joules/semaemo.

3. Metlae e potolohang e nang le matla a li-watts tse 300 le nako ea metsotso e 5 e potolohang lipotoloho tse 5. Matla ao e a sebelisang ke….

A. 15 kJ

B. 75 kJ

C. 90 kJ

D. 450 kJ

Tse tsejoang:

Matla (P) = 300 Watts = 300 Joules/motsotsoana

Nako (T) = metsotso e 5 = 5 (metsotsoana e 60) = metsotsoana e 300

Palo ea lipotoloho = 5

Oa Batla: Matla a sebelisoang ke metlae e potolohang

Tharollo:

Matla - mathata le litharollo

Karabo e nepahetseng ke D.

[ID ea sephutheloana sa wpdm='1190′]

  1. Mosebetsi o entsoe ka mathata a matla le litharollo
  2. Mathata le litharollo tsa matla a kinetic a mosebetsi
  3. Mathata le litharollo tsa motheo oa matla a sebetsang le a mechini
  4. Mathata a matla a khoheli le litharollo
  5. Matla a ka bang teng a mathata le ditharollo tsa selemo se tenyetsehang
  6. Mathata a motlakase le litharollo
  7. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa ho oa ka bolokolohi
  8. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa holimo le tlase motsamaong oa ho oa ka bolokolohi
  9. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a bokaholimo bo kobehileng
  10. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng
  11. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane

Bala haholoanyane

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng - mathata le litharollo

1. Boloko bo thella bo boreleli sefofane se sekametseng ntle khohlano. . Block's ke eng Velocity ha e fihla fatshe. Ho potlaka ka lebaka la matla a khoheli ke 10 m/s2

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng 1Tse tsejoang:

Bolelele (h) = 8 m

Ho potlakisa ka baka la matla a khoheli (g) = 10 m/s2

o ne a batla : lebelo (v)

tharollo :

Matla a pele a mechini (ME)o) = matla a khoheli a ka bang teng (LEOTO)

MEo = PE = mgh = m (10) (8) = 80 m

Matla a ho qetela a mechini (ME)t) = matla a kinetic (HO)

MEt = KE = ½ mv2

Molao-motheo oa paballo ea matla a mechini o bolela hore matla a maiketsetso = matla a ho qetela a mechini:

MEo = 'NAt

80 m = ½ mv2

80 = ½ v2

160 = v2

v = √160 = √(16)(10) = 4√10 m/s

2. Ntho e boima ba 1-kg e thella tlase ka dimithara tse 8. Fumana matla a kinetic kamora hore ntho e tsamaye ka dimithara tse 5… Ho potlaka ka lebaka la matla a khoheli g = 10 m/s2

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng 2Tse tsejoang:

Boima (m) = 0.2 kg

d = limithara tse 5

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s2

o ne a batla : matla a kinetic (KE)

Tharollo:

sebe 30o = h / d

0.5 = lihora / 5

h = (0.5)(5) = limithara tse 2.5

Phetoho ea bophahamo ba ntho ke limithara tse 2.5.

Matla a pele a mechini (ME)o) = matla a khoheli a khoheli (PE)

MEo = PE = mgh = (1)(10)(2.5) = 25 Joule

Matla a ho qetela a mechini (ME)t) = matla a kinetic (KE)

MEt = HO

Molao-motheo oa paballo ea matla a mechini e bolela hore matla a pele a mechini = matla a ho qetela a mechini:

MEo = 'NAt

25 = KE

Matla a kinetic = Lijoule tse 25.

[ID ea sephutheloana sa wpdm='1170′]

  1. Mosebetsi o etsoang ka mathata a matla le litharollo
  2. Mathata le litharollo tsa matla a kinetic a mosebetsi
  3. Mathata le litharollo tsa motheo oa matla a sebetsang le a mechini
  4. Mathata a matla a khoheli le litharollo
  5. Matla a ka bang teng a mathata le ditharollo tsa selemo se tenyetsehang
  6. Mathata a motlakase le litharollo
  7. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa ho oa ka bolokolohi
  8. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa holimo le tlase motsamaong oa ho oa ka bolokolohi
  9. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a bokaholimo bo kobehileng
  10. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng
  11. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane

Bala haholoanyane

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a libaka tse kobehileng - mathata le litharollo

1. Sekotwana sa 1-kg se thella hodima bokaholimo bo boreledi bo kobehileng. Fumana matla a kinetic le lebelo la boloko sebakeng se tlase ka ho fetisisa. Ho potlakisa ka baka la matla a khoheli ke 10 m/s2.

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a libaka tse kobehileng 1Tse tsejoang:

Boholo (m) = 1 kg

Phetoho ea bophahamo (h) = 5 m

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s2

Oa Batla: Kinetic energy (KE) le Velocity ea boloko.

Tharollo:

(a) Matla a kinetic

qalong matla a maiketsetso = matla a khoheli a ka bang teng

MEo = PE = mgh = (1)(10)(5) = 50 Joule

Matla a ho qetela a mechini = matla a kinetic

MEt = KE = ½ mvt2

Molao-motheo oa paballo ea matla a mechini e bolela hore matla a pele a mechini = matla a ho qetela a mechini:

MEo = 'NAt

PE = KE

50 = KE

Matla a kinetic (KE) = 50 Joule.

(b) Lebelo la Block

Molao-motheo oa paballo ea matla a mechini:

Matla a pele a mechini (ME)o) = matla a ho qetela a mechini (MEt)

Matla a khoheli a ka bang teng (PE) = matla a kinetic (KE)

50 = ½ mv2

2(50) / m = v2

100 / 1 = v2

100 = v2

v = √100

v = 10 m/s

2. Ntho e boima ba 2-kg e thella fatshe ntle le kgohlano. Matla a kinetic le lebelo la ntho eo dimithareng tse 2 ka hodima lefatshe ke eng. Ho potlaka ka lebaka la matla a khoheli ke 10 m/s2

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a libaka tse kobehileng 2Tse tsejoang:

Boima (m) = 2 kg

Phetoho ea bophahamo (h) = 10 – 2 = 8 m

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s2

o ne a batla : matla a kinetic (KE) le lebelo (v) ho limithara tse 2 ka holim'a lefatše.

Tharollo:

(a) Matla a kinetic a limithara tse 2 ka holim'a lefatše

Matla a pele a mechini = matla a khoheli a ka bang teng

MEo = PE = mgh = (2)(10)(8) = 160 Joule

Matla a ho qetela a mechini = matla a kinetic

MEt = KE = ½ mvt2

Molao-motheo oa paballo ea matla a mechini o bolela hore matla a pele a mechini = matla a ho qetela a mechini:

MEo = 'NAt

PE = KE

160 = KE

Matla a kinetic (KE) a limithara tse 2 ka holim'a lefatše ke 160 Joules.

(b) Lebelo la ntho sebakeng se tlase ka ho fetisisa

Molao-motheo oa paballo ea matla a mechini:

Matla a pele a mechini (ME)o) = matla a ho qetela a mechini (EM)t)

Matla a khoheli a ka bang teng (PE) = matla a kinetic (KE)

160 = ½ mv2

160 = ½ (2) v2

160 = v2

v = √160 = √(16)(10) = 4√10 m/s

[ID ea sephutheloana sa wpdm='1167′]

  1. Mosebetsi o etsoang ka mathata a matla le litharollo
  2. Mathata le litharollo tsa matla a kinetic a mosebetsi
  3. Mathata le litharollo tsa motheo oa matla a sebetsang le a mechini
  4. Mathata a matla a khoheli le litharollo
  5. Matla a ka bang teng a mathata le litharollo tsa selemo se tenyetsehang
  6. Mathata a motlakase le litharollo
  7. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa ho oa ka bolokolohi
  8. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa holimo le tlase motsamaong oa ho oa ka bolokolohi
  9. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a bokaholimo bo kobehileng
  10. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng
  11. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane

Bala haholoanyane

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane - mathata le litharollo

1. Bolo ea maoto e rahiloeng e tloha fatše ka sekhutlo θ = 30o ka lebelo la pele la 10 m/s. boima = 0.1 lik'hilograma. Ho potlakisa ka baka la matla a khoheli ke 10 limithara / s2. Etsa qeto (a) The matla a khoheli a ka bang teng ntlheng e phahameng ka ho fetisisa (b) Ntlha e phahameng ka ho fetisisa kapa bophahamo bo phahameng ka ho fetisisa

Tse tsejoang:

Boima (m) = 0.1 kg

Lebelo la pele (v)o) = 10 m/s

Sekhutlo = 30o

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s2

Tharollo:

(a) Matla a khoheli a ka bang teng

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane - mathata le litharollo 1

Bala karolo e rapameng (v)ox) le karolo e otlolohileng (voy) ea lebelo la pele.

Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane - mathata le litharollo 2Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane - mathata le litharollo 2vox = vo cos θ = (10)(cos 30o) = (10)(0.5√3) = 5√3 m/s

voy = vo ntle θ = (10)(sebe sa 30o) = (10)(0.5) = 5 m/s

Matla a pele a mechini

qalong matla a maiketsetso (Nnao) = matla a kinetic (HO)

MEo = KE = ½ mvo2 = ½ (0.1)(10)2 = ½ (0.1)(100) = ½ (10) = 5 Joule

Matla a ho qetela a mechini

Matla a kinetic ntlheng e phahameng ka ho fetisisa:

KE = ½ mvox2 = ½ (0.1)(5√3)2 = ½ (0.1)((25)(3)) = ½ (0.1)(75) = 3.75 Dijoule

Molao-motheo oa paballo ea matla a mechini

Matla a pele a mechini (ME)o) = matla a ho qetela a mechini (MEt)

KE = PE + KE

5 = EP + 3.75

PE = 5 – 3.75 = 1.25 Joule

Matla a khoheli a ka bang teng ntlheng e phahameng ka ho fetisisa ke 1.25 Joules.

(b) Ntlha e phahameng ka ho fetisisa kapa bophahamo bo phahameng ka ho fetisisa

PE = mgh

1.25 = (0.1)(10) h

1.25 = h

Bophahamo bo phahameng ka ho fetisisa ke limithara tse 1.25.

2. Bolo ea 0.1-kg e phaphametse ka ho otloloha ka lebelo la pele vo = 10 m/s ho tloha mohahong o bophahamo ba limithara tse 10. Ho potlaka ka lebaka la matla a khoheli ke 10 m/s2Fumana matla a kinetic a bolo ha e otla fatše.

Tse tsejoang:

Boima (m) = 0.1 kg

Lebelo la pele (v)o) = 10 m/s

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s2

Phetoho ea bophahamo (h) = 10 – 2 = 8 m

Oa Batla: matla a kinetic a limithara tse 2 ka holim'a lefatše

Tharollo:

Matla a khoheli a ka bang teng (PE) = mgh = (0.1)(10)(10) = 10 Joules

Matla a kinetic a pele (KE) = ½ mvo2 = ½ (0.1)(10)2 = ½ (0.1)(100) = ½ (10) = 5 Joule

Matla a ho qetela a kinetic = matla a pele a khoheli + matla a pele a kinetic = 10 + 5 = 15 Joules

[ID ea sephutheloana sa wpdm='1173′]

  1. Mosebetsi o etsoang ka mathata a matla le litharollo
  2. Mathata le litharollo tsa matla a kinetic a mosebetsi
  3. Mathata le litharollo tsa motheo oa matla a sebetsang le a mechini
  4. Mathata a matla a khoheli le litharollo
  5. Matla a ka bang teng a mathata le ditharollo tsa selemo se tenyetsehang
  6. Mathata a motlakase le litharollo
  7. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa ho oa ka bolokolohi
  8. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa holimo le tlase motsamaong oa ho oa ka bolokolohi
  9. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a bokaholimo bo kobehileng
  10. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng
  11. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane

Bala haholoanyane