Likhohlano tse sa senyeheng ka tekanyo e le 'ngoe - mathata le litharollo

1. Kulo ea 30-gram e tsamaeang ka lebelo la 30 m/s e thulana le boloko ba 1-kg ha e phomotse. Fumana lebelo la boloko haeba kulo le boloko li hokahana hammoho ka lebaka la ho thulana.

Tse tsejoang:

Boima ba kulo (m ₁) = digrama tse 30 = 0.03 kg

Boima ba boloko (m2 ₎= 1 kg

Lebelo la pele la kulo ( v ₁) = 30 m/s

Lebelo la pele la boloko (v ₂) = 0 ( boloko ha e phomotse )

Ho batloa : lebelo la kulo le thibelo kamora ho thulana (v')

Tharollo:

m ₁v ₁+ m ₂v ₂= (m ₁+ m ₂) v'

(0.03)(30) + (1)(0) = (0.03 + 1) v'

0.9 + 0 = 1.03 v'

0.9 = 1,03 v'

v' = 0.9 / 1,03

v' = 0.87 m/s

[irp]

2. Bolo ea biliadi A ea boima ba 2 kg e tsamaeang ka lebelo v _A= 6 ms ⁻¹ e thulana ka hlooho le bolo ea B ea boima bo lekanang. Haeba ho thulana ho sa thekesele hantle, lebelo la libolo tse peli ke lefe ka mor'a ho thulana.

Tse tsejoang:

Boima A (m _A) = 2 kg

Boima ba B (m _B) = 2 kg

Lebelo la pele la bolo A (v _A) = -6 m/s

Lebelo la pele la bolo B (v _B) = 4 m/s

Matšoao a ho ba le kamano le ...

Ho batloa : lebelo la libolo tse peli kamora ho thulana. (v')

Tharollo:

m _Av _A+ m _Bv _B= (m _A' + m _B) v'

(2)(-6) + (2)(4) = (2 + 2) v'

-12 + 8 = 4 v'

-4 = 4 v'

v' = -4 / 4

v' = -1 m/s

[irp]

3. m₁ = 3 kg 'me m₂ = 4 kg atamelana ka lehlakoreng le fapaneng ka lebelo la v₁ = 10 m/s 'me v₂ = 12 m/s. Haeba ho thulana ho sa thekesele hantle, lebelo la libolo tse peli ka mor'a ho thulana ke lefe?

Tse tsejoang:

Ntho e boima 1 (m1 ₎= 3 kg

Ntho e boima 2 (m2 ₎= 4 kg

Lebelo la ntho 1 (v ₁) = -10 m/s

Lebelo la ntho 2 (v ₂) = 12 m/s

Ho batloa : lebelo ka mor'a ho thulana (v')

Tharollo:

m ₁v ₁+ m ₂v ₂= (m ₁' + m ₂) v'

(3)(-10) + (4)(12) = (3 + 4) v'

-30 + 48 = 7 v'

18 = 7 v'

v' = 18 / 7

v' = 2.6 m/s

[ID ea sephutheloana sa wpdm='1157′]

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