1. Matla P a sebediswa pheletsong e nngwe ya lehlasedi le bolelele ba 2 m. Boholo ba torque ke bofe ? Mothapo wa potoloho ntlheng ya A.
Tse tsejoang:
Matla (F) = 10 N
Bolelele ba AB (r AB ) = 2 m
Matla a F a otlolohile ho lehlaseli.
Letsoho la lever (l ) = r AB sin 90 o = (2 m)(1) = 2 m
Ho batloa: Torque e potolohileng axis ea potoloho
Tharollo:
Torque:
τ = F l = (10 N)(2 m) = 20 N m
Letšoao la ho eketsa hobane lehlaseli le potoloha ho potoloha ho ea ka oache.
[irp]
2. Bolelele ba lehlaseli la AB ke 2 m mme boholo ba matla F ke 10 N. Boholo ba torque ke bofe? Mothapo wa potoloho ntlheng ya A.
Tse tsejoang:
Matla (F) = 10 N
Bolelele ba AB (r AB ) = 2 m
Letsoho la lever (l ) = r AB sin 60 o = (2 m)(0.5 √3 ) = √3 m
Ho batloa: Torque e potolohileng axis ea potoloho
Tharollo:
Torque:
τ = F l = (10 N)( √3 m) = 10 √3 N m
Letšoao la ho eketsa hobane matla a F a etsa hore lehlaseli le potolohe ho potoloha ho ea ka lehlakoreng le leng.
[irp]
3. Bolelele ba lehlaseli ke 2 m. Boholo ba F 1 ke 10 N mme boholo ba F 2 ke 15 N. Fumana torque e nepahetseng bohareng ba lehlaseli.
Mothapo oa potoloho bohareng ba lehlaseli.
Tse tsejoang:
Matla a 1 (F 1 ) = 10 N
Sebaka se pakeng tsa F 1 le setsi sa lehlaseli (r 1 ) = 1 m
Letsoho la lever 1 (l 1 ) = r 1 sin 90 o = (1 m)(1) = 1 m
Matla a F 1 a otlolohile ho lehlaseli.
Matla a 2 (F 2 ) = 15 N
Sebaka se pakeng tsa F 2 le setsi sa lehlaseli (r 2 ) = 1 m
Matla a F 2 a otlolohile ho lehlaseli.
Letsoho la lever 2 (l 2 ) = r 1 sin 90 o = (1 m)(1) = 1 m
Ho batloa: Torque ea net e potolohang axis ea potoloho
Tharollo:
Torque 1:
τ 1 = F 1 l 1 = (10 N)( 1 m) = 10 N m
Letšoao la ho eketsa hobane matla a F 1 a etsa hore lehlaseli le potolohe ho potoloha ho ea ka oache.
Torque 2:
τ 2 = F 2 l 2 = (15 N)( 1 m) = -15 N
Letšoao la ho tlosa hobane matla a F 2 a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.
Torque ea letlooa:
Σ τ = τ 1 – τ 2 = 10 – 15 = – 5 N m
Letšoao la ho tlosa ke hobane lehlaseli le potoloha ka lehlakoreng la oache.
[irp]
4. Bolelele ba lehlaseli la AB ke 2 m, boholo ba F 1 ke 10 N mme boholo ba F 2 ke 10 N. Fumana torque e nepahetseng bohareng ba lehlaseli.
Mothapo oa potoloho bohareng ba lehlaseli.
Tse tsejoang:
Matla a 1 (F 1 ) = 10 Nn
Sebaka se pakeng tsa F 1 le setsi sa lehlaseli (r 1 ) = 1 m
Letsoho la lever 1 (l 1 ) = r 1 sin 60 o = (1 m)(0.5 √3 ) = 0.5 √3 m
Matla a 2 (F 2 ) = 10 N
Sebaka se pakeng tsa F 2 le setsi sa lehlaseli (r 2 ) = 1 m
Matla a F 2 a otlolohile ho lehlaseli.
Letsoho la lever 2 (l 2 ) = r 2 sin 90 o = (1 m)(1) = 1 m
Ho batloa: Torque e tiileng e potolohileng axis ea potoloho
Tharollo:
Torque 1:
τ 1 = F 1 l 1 = (10 N)( 0.5 √3 m) = 5 √3 = 8.7 Nm
Letšoao la ho eketsa hobane matla a F 1 a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.
Torque 2:
τ 2 = F 2 l 2 = (10 N)( 1 m) = -10 N m
Letšoao la ho tlosa hobane matla a F 2 a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.
Torque ea letlooa:
Σ τ = τ 1 – τ 2 = 8.7 – 10 = – 1.3 N m
Letšoao la ho tlosa hobane matla a letlooa a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.
[irp]
5. Bolelele ba lehlaseli ke 10 m, boholo ba F 1 ke 10 N, boholo ba F 2 ke 10 N mme boholo ba F 3 ke 15 N. Sebaka se pakeng tsa ntlha A le ntlha C ke 7.5 m. Matla F 2 a fumaneha bohareng ba lehlaseli. Fumana torque e nepahetseng mabapi le ntlha C e fumanehang ho 2.5 m ho tloha ntlheng B.
Mokhahlelo oa potoloho o sebakeng sa C
Tse tsejoang:
Matla a 1 (F 1 ) = 10 N
Sebaka se pakeng tsa F 1 le ntlha C (r 1 ) = 2.5 m
Matla a F 1 a otlolohile ho lehlaseli.
Letsoho la lever 1 (l 1 ) = r 1 sin 90 o = ( 2.5 m)( 1 ) = 2.5 m
Matla a 2 (F 2 ) = 10 N
Sebaka se pakeng tsa F 2 le ntlha C (r 2 ) = 2.5 m
Matla a F 2 a otlolohile ho lehlaseli.
Letsoho la lever 2 (l 2 ) = r 2 sin 90 o = ( 2.5 m)(1) = 2.5 m
Matla a 3 (F 3 ) = 15 N
Sebaka se pakeng tsa F 3 le ntlha C (r 3 ) = 7.5 m
Matla a F 3 a otlolohile ho lehlaseli.
Letsoho la lever 3 (l 3 ) = r 3 sin 90 o = (7.5 m)(1) = 7.5 m
Ho batloa: Torque e tiileng e potolohileng axis ea potoloho
Tharollo:
Torque 1:
τ 1 = F 1 l 1 = (10 N)( 2.5 m) = 25 N m
Letšoao la ho eketsa hobane matla a F 1 a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.
Torque 2:
τ 2 = F 2 l 2 = (10 N)( 2.5 m) = 25 N m
Letšoao la ho eketsa hobane matla F 2 a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.
Torque 3:
τ 3 = F 3 l 3 = (15 N)( 7.5 m) = -112..5 N m
Letšoao la ho tlosa hobane matla a F 3 a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.
Torque ea letlooa:
Σ τ = τ 1 + τ 2 – τ 3 = 25 + 25 – 112.5 = – 62.5 N m
Letšoao la ho tlosa hobane matla a letlooa a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.
[irp]
6. Bolelele ba lehlaseli ke 10 m, boholo ba F1 ke 10 N, boholo ba F2 ke 10 N le boholo ba F3 ke 10 N. Fumana torque ea letlooa mabapi le ntlha ea A, e fumanehang 5 m ho tloha poi
nt ea ts'ebeliso ea matla F1.
Mokhahlelo oa potoloho ntlheng ea A.
Tse tsejoang:
Matla a 1 (F 1 ) = 10 N
Sebaka se pakeng tsa F 1 le ntlha A (r 1 ) = 5 m
Letsoho la lever 1 (l 1 ) = r 1 sin 60 o = (5 m)(0.5 √3 ) = 2.5 √3 m
Matla a 2 (F 2 ) = 10 N
Sebaka se pakeng tsa F 2 le ntlha A (r 2 ) = 0
Matla a F2 a otlolohile ho lehlaseli.
Letsoho la lever 2 (l 2 ) = r 2 sin 90 o = (0)(1) = 0
Matla a 3 (F 3 ) = 10 N
Sebaka se pakeng tsa F 3 le ntlha A (r 3 ) = 10 m
Letsoho la lever 3 (l 3 ) = r 3 sin 30 o = (10 m)(0.5) = 5 m
Ho batloa: torque e tiileng e potolohileng axis ea potoloho
Tharollo:
Torque 1:
τ 1 = F 1 l 1 = (10 N)( 2.5 √3 m ) = 25√3 = 43.3 N m
Letšoao la ho eketsa hobane matla a F 1 a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.
Torque 2:
τ 2 = F 2 l 2 = (10 N)(0) = 0
Torque 3:
τ 3 = F 3 l 3 = (10 N)( 5 m) = -50 N m
Letšoao la ho tlosa hobane matla a F 3 a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.
Torque ea letlooa:
Σ τ = τ 1 + τ 2 – τ 3 = 43.3 + 0 – 50 = – 6.7 N m
Letšoao la ho tlosa hobane matla a letlooa a etsa hore lehlaseli le potolohe ka lehlakoreng la oache.
