1. Bolo e nyane e lahlelwa ka ho otloloha ka lebelo le sa fetoheng la 10 m/s. Bolo e otla lebota mme e bonahatsa ka lebelo le tshwanang. Phetoho ke efe ho lebelo le otlolohileng ea bolo?
Tse tsejoang:
Boholo (m) = 0.2 kg
Lebelo la pele (v)o) = -10 m/s
Lebelo la ho qetela (v)t) = 10 m/s
Matšoao a ho ba le kamano le ...
o ne a batla : phetoho motsamaong o otlolohileng (Δp)
Tharollo:
Foromo ea phetoho motsamaong o otlolohileng :
Δp = mvt – mvo = m (vt - vo)
Phetoho motsamaong o otlolohileng:
Δp = 0.2 (10 – (-10)) = 0.2 (10 + 10)
Δp = 0.2 (20)
Δp = 4 kg m/s
2. Bolo ea ligrama tse 10 o oa ka bolokolohi ho tloha bophahamong, e otla fatshe ka lebelo la 15 m/s, ebe e kgutlela hodimo ka lebelo la 10 m/s. Fumana hore na modumo o fella kae!
Tse tsejoang:
Boima (m) = digrama tse 10 = 0.01 kg
Lebelo la pele (v)o) = -15 m/s
Lebelo la ho qetela (v)t) = 10 m/s
Ho batloa: tšusumetso e tsoang ho (Ke)
Tharollo:
Tšusumetso (I) e lekana le phetoho ea momentum (Δp)
Ke = mvt – mvo = m (vt - vo)
Tšusumetso:
Ke = 0.01 (10 – (-15)) = 0.01 (10 + 15)
Ke = 0.01 (25)
I = 0.25 kg m/s
3. Bolo ea ligrama tse 200 e ile ea lahleloa ka ho rapama ka lebelo la 4 m/s, eaba bolo e otloa ka lehlakoreng le le leng. Bolo e kopana le kota ke 2 milmetsotsoana e 'meli 'me lebelo la bolo ka mor'a ho tloha beteng ke 12 m/s. boholo ba lebotho la exerted ka motsu o bolong ke …
Tse tsejoang:
Boima (m) = digrama tse 200 = 0.2 kg
Lebelo la pele (v)o) = 4 m/s
Lebelo la ho qetela (v)t) = 12 m/s
Nako e sa fellang (t) = 2 milliseconds = (2/1000) metsotsoana = 0.002 metsotsoana
o ne a batla : Boholo ba matla (F)
Tharollo:
Foromo ea tšusumetso:
Ke = F t
Foromo ea phetoho ea lebelo:
mvt – mvo = m (vt - vo)
Tšusumetso (I) e lekana le phetoho ea momentum (Δp)
I = Δp
F t = m (vt - vo)
F (0.002) = (0.2)(12 - 4)
F (0.002) = (0.2)(8)
F (0.002) = 1.6
F = 1.6 / 0.002
F = 800 Newton
[ID ea sephutheloana sa wpdm='1155′]
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