Matla le takatso - mathata le litharollo

1. Bolo e nyane e lahlelwa ka ho otloloha ka lebelo le sa fetoheng la 10 m/s. Bolo e otla lebota mme e bonahatsa ka lebelo le tshwanang. Phetoho ke efe ho lebelo le otlolohileng ea bolo?

Tse tsejoang:

Boholo (m) = 0.2 kg

Lebelo la pele (v)o) = -10 m/s

Lebelo la ho qetela (v)t) = 10 m/s

Matšoao a ho ba le kamano le ...

o ne a batla : phetoho motsamaong o otlolohileng (Δp)

Tharollo:

Foromo ea phetoho motsamaong o otlolohileng :

Δp = mvt – mvo = m (vt - vo)

Phetoho motsamaong o otlolohileng:

Δp = 0.2 (10 – (-10)) = 0.2 (10 + 10)

Δp = 0.2 (20)

Δp = 4 kg m/s

bona le  Ho fapoha ha lekhalo le le leng - mathata le litharollo

2. Bolo ea ligrama tse 10 o oa ka bolokolohi ho tloha bophahamong, e otla fatshe ka lebelo la 15 m/s, ebe e kgutlela hodimo ka lebelo la 10 m/s. Fumana hore na modumo o fella kae!

Tse tsejoang:

Boima (m) = digrama tse 10 = 0.01 kg

Lebelo la pele (v)o) = -15 m/s

Lebelo la ho qetela (v)t) = 10 m/s

Ho batloa: tšusumetso e tsoang ho (Ke)

Tharollo:

Tšusumetso (I) e lekana le phetoho ea momentum (Δp)

Ke = mvt – mvo = m (vt - vo)

Tšusumetso:

Ke = 0.01 (10 – (-15)) = 0.01 (10 + 15)

Ke = 0.01 (25)

I = 0.25 kg m/s

bona le  Matla a makenete a hlahisoang ke lithapo tse peli tse tsamaisang motlakase tse bapileng - mathata le litharollo

3. Bolo ea ligrama tse 200 e ile ea lahleloa ka ho rapama ka lebelo la 4 m/s, eaba bolo e otloa ka lehlakoreng le le leng. Bolo e kopana le kota ke 2 milmetsotsoana e 'meli 'me lebelo la bolo ka mor'a ho tloha beteng ke 12 m/s. boholo ba lebotho la exerted ka motsu o bolong ke …

Tse tsejoang:

Boima (m) = digrama tse 200 = 0.2 kg

Lebelo la pele (v)o) = 4 m/s

Lebelo la ho qetela (v)t) = 12 m/s

Nako e sa fellang (t) = 2 milliseconds = (2/1000) metsotsoana = 0.002 metsotsoana

o ne a batla : Boholo ba matla (F)

Tharollo:

Foromo ea tšusumetso:

Ke = F t

Foromo ea phetoho ea lebelo:

mvt – mvo = m (vt - vo)

Tšusumetso (I) e lekana le phetoho ea momentum (Δp)

I = Δp

F t = m (vt - vo)

F (0.002) = (0.2)(12 - 4)

F (0.002) = (0.2)(8)

F (0.002) = 1.6

F = 1.6 / 0.002

F = 800 Newton

[ID ea sephutheloana sa wpdm='1155′]

  1. Mathata le litharollo tsa lebelo la mola
  2. Mathata le litharollo tsa ho potlaka le ho susumetsoa ke maikutlo
  3. Ho thulana ho tenyetsehang ka ho phethahetseng mathateng le litharollong tsa tekanyo e le 'ngoe
  4. Likhohlano tse phethahetseng tsa inelastic mathateng le litharollo tsa tekanyo e le 'ngoe
  5. Mathata le litharollo tsa ho thulana ha inelastic ka tekanyo e le 'ngoe

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