He tuhinga mō ngā Ātete i te whakarara
Mena ka honoa ngā ātete pēnei i te pikitia, ka honoa ngā ātete ki te taha whakarara.
Ko te iahiko (iahiko = te utu hiko e rere ana i roto i tētahi wā) e tomo ana ki te pūwāhi hononga he rite tonu ki te iahiko e puta ana mai i te pūwāhi hononga. He maha ngā hononga, nō reira ko te iahiko katoa = te nui o te iahiko e rere ana i ia hononga. Mā te pāngarau, I = I 1 + I 2 + I 3. Ahakoa he rite te rerekētanga pūmanawa hiko, te ngaohiko hiko rānei i ia hononga.
I = V/R, nō reira ka huri te whārite i runga ake nei ki I = V/R1 + V/R2 + V/R3 . He ōrite te ngaohiko hiko, nō reira ka huri tēnei whārite ki I = V (1/R1 + 1/R2 + 1/ R3 ). Mena ko te ātete ōrite ko 1/R, ko I = V (1/R). Nō reira, 1/R = 1/R1 + 1/R2 + 1/ R3.
He painga tō ngā ara iahiko whakarara, ki te motu te iahiko ki tētahi o ngā ātete, ka rere tonu te iahiko ki ngā ātete kē atu. Engari i roto i te ara iahiko raupapa, ki te motu te iahiko i roto i tētahi ātete, kāore ngā ātete katoa e hiko.
Tauira raruraru 1:
E mōhiotia ana ko R 1 = 2 Ω, R 2 = 3 Ω. He whakarara ngā ātete e rua. He aha te uara o te ātete ōrite? (Ω = Ohm).
Rongoā:
1/R = 1/R 1 + 1/R 2 = 1/2 + 1/3 = 3/6 + 2/6 = 5/6
R = 6/5 = 1.2 Ω.
E whakaatu ana tēnei hua he iti iho te uara ātete ōrite i te uara o ia ātete whakarara.
Tauira raruraru 2:
E rua ngā ātete R 1 = 50 Ω me te 50 e honoa ana i roto i te raupapa me te whakarara, e honoa ana ki te pākahiko 12 Volt. Whakatauhia:
(a) Te ātete ōrite
(b) Te au hiko e puta ana i ia ātete
Rongoā:
(a) Ngā ātete raupapa:
R = R 1 + R 2 = 50 Ω + 50 Ω = 100 Ω.
Ngā ātete whakarara:
1/R = 1/R 1 + 1/R 2 = 1/50 + 1/50 Ω = 2/50
R = 50/2 = 25 Ω
(b) Ngā ātete raupapa:
I = V / R = 12 Ngā Waohiko / 100 Ω = 0.12 A
Ngā ātete whakarara:
I = V / R = 12 Ngā Waohiko / 25 Ω = 0.48 A
E whakaatu ana tēnei hua he nui ake te iahiko katoa e rere ana i roto i te ara iahiko whakarara, engari he iti ake te iahiko katoa e rere ana i roto i te ara iahiko raupapa.
