1. Kei te whakaatuhia te kauwhata o te kaha (F) me te roa (x ) i te pikitia i raro nei. Kimihia te pūmau puna!
otinga
k = F / x
F = te kaha (Newton)
k = pūmau puna (Newton/mita)
x = te huringa o te roa (mita)
Pūmau puna:
k = 10 / 0.02 = 20 / 0.04
k = 500 N/m
[irp]
2. Tāutuhia te pūmau puna.
otinga
Pūmau puna:
k = F / x
k = 5 / 0.01 = 10 / 0.02 = 15 / 0.03 = 20 / 0.04
k = 500 N/m
[irp]
3. Ko te roa taketake o te puna A he 60 cm, ā, ko te roa taketake o te puna B he 90 cm. Ko te pumau o te puna A he 100 N/m, ko te pumau o te puna B he 200 N/m. Ko te ōwehenga o te huringa o te roa o te puna A ki te huringa o te roa o te puna B ko…
Mōhiotia:
Pūmau o te puna A (k A ) = 100 N/m
Pūmau o te puna B (kB ) = 200 N/m
Te kaha i runga i te puna A (F A ) = F
Te kaha i runga i te puna B (F B ) = F
E hiahiatia ana: Δl A : Δl B
Rongoā:
Te tauira ture a Hooke:
Δl = F / k
Δl = te huringa o te roa, F = te kaha, k = te pumau
Te huringa o te roa o te puna A:
Δl A = F A / k A = F / 100
Te huringa o te roa o te puna B:
Δl B = F B / k B = F / 200
Ko te ōwehenga o te huringa o te roa o te puna A ki te huringa o te roa o te puna B:
Δl A : Δl B
F/100 : F/200
1 / 100 : 1 / 200
1 / 1 : 1 / 2
2: 1
[irp]
4. Ka tōia he aho nairona, he 20 cm te roa taketake, e te kaha o te 10 N. Ko te huringa o te roa o te aho he 2 cm. Tātaihia te rahi o te kaha mēnā he 6 cm te huringa o te roa.
Mōhiotia:
Te kaha (F) = 10 N
Ko te panonitanga o te roa ( Δl ) = 2 cm = 0.02 m
E hiahiatia ana: te rahi o te kaha (F) mēnā ko Δl = 0.06 m.
Rongoā:
Pūmau:
k = F / Δl
k = 10 / 0.02 = 500 N/m
Te rahi o te kaha (F) mēnā ko Δl = 0.06 m:
F = kx
F = (500)(0.06)
F = 30N
[irp]
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