Te huri i ngā tauine pāmahana (tauine Celsius Tauine Fahrenheit Tauine Kelvin)

9 Te huri i ngā tauine pāmahana (tauine Celsius Tauine Fahrenheit Tauine Kelvin)

1. 50 ° C = ….. ° F ?

otinga

I te pēhanga hauhautanga paerewa , ko te pūwāhi tio o te wai he 0 ° C i te tauine Celsius me te 32 ° F i te tauine Fahrenheit. I te pēhanga hauhautanga paerewa, ko te pūwāhi kohua o te wai he 100 ° C i te tauine Celsius me te 212 ° F i te tauine Fahrenheit.

0 o C = 32 o F me 1 00 o C = 212 o F. Ko te panonitanga o te 5 C o = te panonitanga o te 9 F o.

Mō te tauine Celsius, ka wehea te tawhiti i waenga i te 0 ° C me te 100 ° C kia 100 ngā āputa ōrite. Mō te tauine Fahrenheit, ka wehea te tawhiti i waenga i te 0 ° C me te 100 ° C kia 180 ngā āputa ōrite.

Ki te F = (180/100) Ki te C + 32

Ki te F = (9/5) Ki te C + 32

Ki te F = (9/5) 50 + 32

Ki te F = (9) 10 + 32

Ki te F = 90 + 32

Ki te F = 122

50 ° C = 122 ° F

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2. 86 o F = ….. o C ?

otinga

Ki te C = (100/180)(Ki te F – 32)

Ki te C = (5/9)(Ki te F – 32)

Ki a C = (5/9)(86 – 32)

Ki a C = (5/9)(54)

Ki a C = (5)(6)

Ki te C = 30

86 ° F = 30 ° C

3. 50 ° C = ….. K ?

otinga

T = Ki C + 273

T = 50 + 273

T = 323

50 ° C = 323 K

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4. 212 o F = ….. K ?

otinga

Ki te C = (100/180)(Ki te F – 32)

Ki te C = (5/9)(Ki te F – 32)

Ki a C = (5/9)(212 – 32)

Ki a C = (5/9)(180)

Ki a C = (5)(20)

Ki te C = 100

212 o F = 100 o C + 273

212 o F = 373 K

 

5. x o C = x o F

x = ….. ?

otinga

1: Te huri i te tauine Celsius ki te tauine Fahrenheit

Te huri i ngā tauine pāmahana (tauine Celsius, tauine Fahrenheit, tauine Kelvin) – ngā raruraru me ngā otinga 1

2: Te huri i te tauine Fahrenheit ki te tauine Celsius

Te huri i ngā tauine pāmahana (tauine Celsius, tauine Fahrenheit, tauine Kelvin) – ngā raruraru me ngā otinga 2

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6. 122°F = ….. Celsius

otinga

Ka taea te tuhi i te huringa i waenga i ngā tauine pāmahana e rua:

T C = 5/9 (T F – 32)

T C = Te pāmahana i roto i te Celsius, T F = te pāmahana i roto i te Fahrenheit

Te pāmahana i roto i te Celsius:

T C = 5/9 (122 – 32) = T C = 5/9 (90) = 5 (10)

T C = 50 o C

7. E whakaatu ana te pikitia i raro nei i te ine pāmahana o tētahi wai mā te whakamahi i te inemahana tauine Fahrenheit! Mena ka inehia te pāmahana o te wai mā te whakamahi i te inemahana tauine Celsius, he aha te pāmahana o te wai?

Mōhiotia:Te huri i ngā tauine pāmahana (tauine Celsius, tauine Fahrenheit, tauine Kelvin) – ngā raruraru me ngā otinga 5

Tauine Fahrenheit (T F ) = 95 o F

E hiahiatia ana: Tauine Celsius

Rongoā:

I te pēhanga o te 1 atm, ko te pūwāhi tio o te wai he 0 °C, ko te tauine Fahrenheit he 32 ° F. I tetahi atu taha, ko te pūwāhi kohua o te wai mō te tauine Celsius he 100 ° C, ko te tauine Fahrenheit he 212 ° F.

I te tauine Celsius, i waenga i te 0 °C me te 100 °C he 100 °, i te tauine Fahrenheit ia i waenga i te 32 °F ki te 212 °F he 180 °.

T C = 100/180 (T F – 32)

T C = 5/9 (T F – 32)

T C = 5/9 ( 95 – 32)

T C = 5/9 ( 63 )

T C = 315/9

T C = 35 o C

8. E ai ki te pikitia i raro nei, tātaihia te pāmahana P i runga i te inemahana Celsius.

otinga

TC = 100/180 (TF - 32) Te huri i ngā tauine pāmahana (tauine Celsius, tauine Fahrenheit, tauine Kelvin) – ngā raruraru me ngā otinga 6

T C = 5/9 (T F – 32)

T C = 5/9 (104 – 32)

T C = 5/9 (72)

T C = 360/9

T C = 40 o C

9. Mēnā ko te pāmahana o te tauine Celsius e whakaaturia ana i te pikitia i raro nei, tātaihia te pāmahana o te tauine Fahrenheit e whakaaturia ana i te pikitia i raro nei.

Rongoā:

ToF = (180/100) ToC + 32Te huri i ngā tauine pāmahana (tauine Celsius, tauine Fahrenheit, tauine Kelvin) – ngā raruraru me ngā otinga 7

Ki te F = (9/5) Ki te C + 32

Ki te F = (9/5) 60 + 32

Ki te F = (9) 12 + 32

Ki te F = 108 + 32

Ki te F = 140

  1. Te huri i ngā tauine pāmahana
  2. Whānuitanga rārangi
  3. Te whakawhānui ake i te rohe
  4. Whakawhanuitanga rōrahi
  5. Heat
  6. Te ōrite ā-pūkaha o te wera
  7. Te wera motuhake me te kaha wera
  8. Te wera huna, te wera o te hanumi, te wera o te mimiti
  9. Te tiaki pūngao mō te whakawhiti wera

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