Ngā Raru Whakaoti i roto i te Ahupūngao Taketake

Ngā whanaketanga o ngā matūriki – ngā raruraru me ngā otinga

1. Ko te Taonga A he 6-kg te taumaha, ā, ko te Taonga B he papatipu o te 4-kg i honoa e te taura, ā, i tōia e te kaha o F = 60 N, e whakaaturia ana i te pikitia i raro nei. Ko te tauwehenga o te waku nekeneke Ko te tawhiti i waenganui i te papa me ngā mea e rua he 0.5 (tan θ = ¾). Whakaterenga na te kaha o te kaha he 10 m/s²He aha te rahi o te kaha kume?

Mōhiotia:

Papatipu o te mea A (m_A) = 6 kirokaramu

Papatipu o te mea B (m_B) = 4 kirokaramu

Te Kaha (F) = 60 Newton

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Te mātotoru me te rere i te taurite – ngā raruraru me ngā otinga

1. He poraka kua whakanohoia ki roto i ngā wai e rua me ngā momo rerekē. I roto i ngā wai A, 0.6 te wāhanga o tētahi mea kei roto i te wai. I roto i ngā wai B, 0.5 te wāhanga o tētahi mea kei roto i te wai. Whakatauhia te ōwehenga o kiato mai i te wai A ki te wai B.

Mōhiotia:

Te mātotoru o te poraka = x

Wāhanga o te mea i roto i te wai A = 0.6

Te mātotoru o te wai A = y

Wāhanga o te mea i roto i te wai B = 0.5

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Te tiaki i te pūngao miihini i runga i ngā mata piko – ngā raruraru me ngā otinga

1. Mena ko te tere o te pōro i te pūwāhi A he 6 m/s, ko te tere o te pōro i te pūwāhi B he √92 m/s, ā, te whakaterenga nā te kaha ā-papa ko g = 10 m/s²He aha te teitei o te pūwāhi B (h)?

Mōhiotia:

Tere o te pōro i te pūwāhi A (v)_A) = 6 m/s

Tere o te pōro i te pūwāhi B (v_B) = √92 m/s

Te whakaterenga nā te kaha ā-papa (g) = 10 m/s²

Te teitei o A (h_A) = 5.6 mita

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Te Pokapū o te kaha taumaha – ngā raruraru me ngā otinga

1. Whakatauhia ngā taunga o te Tuhinga o mua o te mea e whakaaturia ana i te pikitia i raro nei.

Rongoā:

Wehea te mea kia toru ngā wāhanga.

Te horahanga o te wāhanga 1 (A₁) = (2)(6) = 12 henemita²

Kei te tuaka-x te pūwāhi pokapū (x₁) = 1/2 (2) = 1 henemita

Kei te tuaka-y te pūwāhi pokapū (y₁) = 1/2 (6) = 3 henemita

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Te ariā a Torricelli – ngā raruraru me ngā otinga

1. He ngongo he 100 cm te teitei kua whakakīia ki te wai. Kei te 10 cm te teitei o te kōhao Q i runga ake i te whenua. He aha te tawhiti whakapae (x)?

Mōhiotia:

Te tawhiti i waenganui i te poka me te mata o te wai (h) = 100 cm – 10 cm = 90 cm = 0.9 m

Whakaterenga na te kaha o te kaha (g) = 10 m/s²

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Wetereo – ngā raruraru me ngā otinga

Te Wetereo me te Tauine

1. I roto i ngā kōwhiringa e whai ake nei, arā, ko ngā takirua tauine-tauine…

A. Te kaha – te whakaterenga

B. Pressure – kaha

C. displacement – tere

D. Iahiko – ​​pēhanga

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Karuārai Matū – ngā raruraru me ngā otinga

1.

E ai ki te pikitia i runga ake nei, he aha te whakanui whānui? Ki te kī he kanohi noa, ko te pūwāhi tata (N) = 25 cm.

Mōhiotia:

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Ngā rahinga ā-tinana Ngā waeine Ngā rahinga – Ngā raruraru me ngā otinga

1.

I runga anō i te ripanga i runga ake nei, ko ēhea ngā rahinga he waeine me he ine tūturu.

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Te whakaterenga pūtoro – ngā raruraru me ngā otinga

1. Ko tēhea kauwhata i raro nei e whakaatu ana i te whanaungatanga i waenga i te whakaterenga porotītaha me te whakaterenga porowhita (a_R) me te tere rārangi (v) i roto i nekehanga porowhita ōrite.

Rongoā:

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Pūngao pūmanawa – ngā raruraru me ngā otinga

Te pūngao pūngao tōkaha

1. Pūngao 4900 Joule e whakamahia ana hei whakaara i tētahi mea he 50 kg te taumaha ki te teitei o h. He aha te teitei o h? Whakaterenga na te kaha o te kaha (g) = 9.8 ms^-2.

Mōhiotia:

Tuhinga o mua te kaha haere (ΔPE) = 4900 Joule

Mass o te mea (m) = 50 kg

Te whakaterenga nā te kaha ā-papa (g) = 9.8 m/s²

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