Ukunyakaza kwe-Momentum Impulse kanye ne-Projectile – Izinkinga Nezixazululo
1. Ibhola elingu-0.2 kg lizofakwa emgodini C, njengoba kuboniswe esithombeni esingezansi. Umshayi ushaya ibhola ngomzuzwana ongu-0.01 bese indlela ye-BC ihambe ngomzuzwana o-1. Thola ubukhulu bamandla ukuze ibhola lifakwe emgodini C. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s 2.
Kwaziwa:
I-engeli (θ) = 60 o
Isisindo sebhola (m) = 0.2 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
Isikhawu sesikhathi (Δt) = 0.01 imizuzwana
Isikhathi sokuphumula endleleni yokuhamba BC (t) = 1 isekhondi
Kufunwa: Amandla (F)
Isixazululo:
Isibalo se-impulse : I = F Δt
Isibalo soshintsho ku- momentum : Δp = m (v t – vo o ).
Isifiso silingana noshintsho kumfutho :
I = Δp
F Δt = m (v t – vo o )
F = m (v t – vo o ) / Δt
Kwaziwa:
Δt = 0.01 isekhondi
m = 0.2 kg
v t = isivinini sokugcina esilinganisweni se-impulse-momentum = isivinini sokuqala sebhola (v o ) ekunyakazeni kwe-projectile
v o = isivinini sokuqala esilinganisweni se-impulse-momentum = 0 m/s (ekuqaleni ibhola lapho liphumule)
F = m (v t – vo o ) / Δt
F = 0.2 (v t – 0) / 0.01
F = 0.2 v t / 0,01
iyaqhubeka ……
Nquma isivinini sokuqala sebhola (v o ) ekunyakazeni okubonakalayo
Njengoba ibhola lishaywa kuze kube yilapho ibhola lifika ephuzwini B = ingxenye 1 yokunyakaza kwe-projectile.
Ibhola lihamba lisuka endaweni B liye ku-C = ingxenye 2 yokunyakaza kwe-projectile.
Ingxenye 2 yokunyakaza okuqoshwe phansi:
Ukunyakaza okubonakalayo kungaqondwa ngokuhlaziya izingxenye ezivundlile neziqondile zokunyakaza ngokwehlukana. Ukunyakaza kuka-x kwenzeka ngesivinini esingaguquki kanti ukunyakaza kuka-y kwenzeka ngokusheshisa okungaguquki kwamandla adonsela phansi.
Kwaziwa:
Ibanga elivundlile (x) = amamitha angu-5
Isikhathi emoyeni (t) = umzuzwana o-1
u-x no-t bayaziwa ukuze u-v ox angabalwe kusetshenziswa i-equation yokunyakaza okuqondile okufanayo . u-v ox uyingxenye evundlile yesivinini sokuqala sebhola.
v ox = x / t = amamitha ama-5 / umzuzwana o-1 = 5 m/s.
Ingxenye 1 yokunyakaza okuqoshwe phansi:
Ingxenye evundlile yejubane, i-v ox ihlale ifana ngakho-ke i-v ox engxenyeni 1 yokunyakaza kwe-projectile = v ox engxenyeni 2 yokunyakaza kwe-projectile = 5 m/s.
Kuyaziwa
i-v ox = 5 m/s
θ = 60 o
u-v ox no-θ bayaziwa ngakho isivinini sokuqala (vo o ) singabalwa.
cos θ = isichasiselo / i-hyp
cos θ = v ox / v o
v o = v ox / cos θ = 5 / cos 60 o = 5 / 0.5 = 10 m/s
Ijubane lokuqala (v o ) lingu-10 m/s.
Isivinini sokuqala sebhola (v o ) ekunyakazeni okubonakalayo = isivinini sokugcina sebhola (v t ) esilinganisweni se-impulse-momentum.
Nquma ubukhulu bamandla (F)
F = 0.2 v t / 0.01
F = 0.2 (10) / 0.01
F = 2 / 0.01
F = 200 Newton
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