Isivinini - izinkinga nezixazululo
1. Ibhola elingu-0.5-kg lihamba ngesivinini esingu-2 m/s. Bese ibhola lishaywa ngamandla F maqondana nesiqondiso sebhola , ngakho isivinini sebhola sishintshwa sibe ngu-6 m/s . Ibhola lithintana nomshayi isikhathi esingu -0.01 sesekhondi, kuyini ushintsho ekushukumeni kwebhola.
Kwaziwa:
Isisindo sebhola (m) = 0.5 kg
Ijubane lokuqala (v o ) = 2 m/s
Ijubane lokugcina (v t ) = -6 m/s
Isikhawu sesikhathi (t) = umzuzwana o-0.01
Okufunwayo: Ushintsho emgudwini
Isixazululo:
∆p = mv t – mv o = m (v t – v o )
∆p = (0.5 kg)(- 6 m/s – 2 m/s)
∆p = (0.5 kg)(-8)
∆p = 4 kg m/s
2. Into engamagremu ayi-100 ihamba ngesivinini esingu-5 m/s. I-Force F isebenza imizuzwana engu-0.2 ukumisa into. Thola ubukhulu bamandla F.
Kwaziwa:
Isisindo sento (m) = amagremu ayi-100 = 100/1000 = 0.1 kg
Ijubane lokuqala (v o ) = 5 m/s
Ijubane lokugcina (v t ) = 0
Isikhawu sesikhathi (Δt) = 0.2 imizuzwana
Okufunwayo: Ubukhulu bamandla F
Isixazululo:
I = ΔP
F (Δt) = m (v t – vo o )
F (0.2) = 0.1 (0 – 5)
F (0.2) = 0.1 (– 5)
F (0.2) = -0,5
F = -0,5 / 0.2
F = -2.5N
Ubukhulu bamandla F = 2.5 Newtons. Uphawu lokususa lubonisa isiqondiso samandla esiphambene nesiqondiso sento.
3. Ibhola elingamagremu ayi-100 liwa ngokukhululeka lisuka ekuphakameni okungu-20 cm ngaphandle kwejubane lokuqala bese ibhola lishaya phansi. Ngemva kokushayisana, ibhola liboniswa phezulu (ukusheshisa ngenxa yamandla adonsela phansi kungu-10 ms -2 ). Kuyini ushintsho kumfutho webhola.
Kwaziwa:
Isisindo sebhola (m) = amagremu angu-100 = 0.1 kg
Ukuphakama (h) = 20 cm = 0.2 amamitha
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
Ijubane lebhola ngemva kokushaya phansi (v t ) = 1 m/s
Okufunwayo: Ushintsho emgudwini
Isixazululo:
Ijubane lebhola ngaphambi kokushayisana (v o )
Bala ijubane lebhola ngaphambi kokushayisana usebenzisa i-equation yokunyakaza kokuwa okukhululekile. Okuyaziwayo: ukuphakama kwebhola (h) = amamitha angu-0.2, ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2 . Okufunwayo: ijubane lebhola uma lishaya phansi.
v 2 = 2 gh
v 2 = 2 (10)(0.2) = 4
v = √4 = -2 m/s
Uphawu lokususa lubonisa ukuthi indlela ibhola eliya ngayo ngaphambi kokushayisana iphambene nendlela ibhola eliya ngayo ngemva kokushayisana.
Ushintsho ku-momentum yebhola (Δp)
Δp = mv t – mv o = m (v t – v o )
Δp = (0.1)(1 – (-2)) = (0.1)(1 + 2) = (0.1)(3) = 0.3 Isekhondi likaNewton
4. Into eqale iphumule, iqhuma ibe izingxenye ezimbili ngesilinganiso esingu-3: 2. Ingxenye enkulu yobunzima iphonswa ngesivinini esingu-20 m/s. Iyini ijubane lengxenye encane.
Kwaziwa:
Isisindo sento 1 ngaphambi kokuqhuma = m
Ijubane lento 1 ngaphambi kokuqhuma = 0 (into iphumule)
Isisindo sengxenye enkulu ngemva kokuqhuma (m 1 ) = 3m
Ubunzima bengxenye encane ngemva kokuqhuma (m2 ) = 2m
Ijubane lengxenye enkulu ngemva kokuqhuma (v 1 ') = 20 m/s
Okufunwayo: Ijubane lengxenye encane ngemva kokuqhuma (v 2 ')
Isixazululo:
Isilinganiso somthetho wokulondolozwa komfutho:
m 1 v 1 = m 1 v 1 ' + m 2 v 2 '
(m)(0) = (3m)(20) + (2m) v 2 '
0 = 60m + (2m) v 2 '
60m = -2m v 2 '
60 = -2 v 2 '
v 2 ' = -60/2
v 2 ' = -30 m/s
Uphawu lokususa lubonisa ukuthi indlela eya engxenyeni encane iphambene nendlela eya engxenyeni enkulu.
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