I-flux kagesi - izinkinga nezixazululo

1. Insimu kagesi efanayo E = 8000 N/C idlula endaweni eyisikwele eyisicaba A = 10 m2 . Thola ukugeleza kukagesi.

Ugesi uhamba ezindaweni nasezindaweni ezivaliwe - izinkinga nezixazululo 1Kwaziwa:

Ubukhulu bensimu kagesi (E) = 8000 N/C

Indawo (A) = 10 m 2

θ = 0 o (i-engeli ephakathi kwesiqondiso sensimu kagesi kanye nomugqa odwetshwe uqonde endaweni)

Okufunwayo: Ugesi ogelezayo ( Φ)

Isixazululo:

Ifomula ye-flux kagesi:

Φ = EA cos q

Φ = ukugeleza kukagesi ( Nm 2 /C) , E = insimu kagesi (N/C), A = indawo (m 2 ), q = i-engeli phakathi komugqa wensimu kagesi nomugqa ojwayelekile.

Ukushintshashintsha kukagesi:

Φ = EA cos q = (8000)(10)( cos 0) = (8000)(10)(1 ) = 80,000 = 8 x 10 4 Nm 2 /C

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2. Insimu kagesi efanayo E = 5000 N/C idlula endaweni yesikwele esiyisicaba A = 2 m 2. Thola ukugeleza kukagesi.

Ugesi uhamba ezindaweni nasezindaweni ezivaliwe - izinkinga nezixazululo 2Kwaziwa:

Insimu kagesi (E) = 5000 N/C

Indawo (A) = 2 m 2

θ = 60 o (i-engeli ephakathi kwesiqondiso sensimu kagesi kanye nomugqa odwetshwe uqonde endaweni)

Okufunwayo: Ugesi ogelezayo ( Φ)

Isixazululo:

Ukushintshashintsha kukagesi:

Φ = EA cos q = (5000)(2)( cos 60) = (5000)(2)(0.5 ) = 5000 = 5 x 10 3 Nm 2 /C

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3. Ibhola eliqinile elinobubanzi obungamamitha angu-0.5 lineshaja kagesi engu-10 μC phakathi nendawo. Thola ukugeleza kukagesi okudlula ebholeni eliqinile.

Ugesi uhamba ezindaweni nasezindaweni ezivaliwe - izinkinga nezixazululo 3Kwaziwa:

Irediyasi yebhola (r) = 0.5 m

Ishaja kagesi (Q) = 10 μC = 10 x 10 -6 C

Okufunwayo: Ugesi ogelezayo ( Φ)

Isixazululo:

Insimu kagesi:

E = kq/r 2

E = (9 x 10 9 Nm 2 /C 2 ) ( 10 x 10 -6 C) / 0.5 2

E = (90 x 10 3 ) / 0,25

E = 360 x 10 3

E = 3.60 x 10 5 N/C

Indawo engaphezulu:

A = 4 π r 2 = 4 (3.14) (0.5) 2 = (12.56) (0.25) = 3.14 m 2

Ukushintshashintsha kukagesi:

Imigqa yensimu kagesi iqonde ngqo endaweni, ukuze i-engeli ephakathi kwesiqondiso sensimu kagesi kanye nomugqa odwetshwe uqonde ngqo endaweni, ibe ngu -0 o.

Φ = EA cos q

Φ = ( 3.60 x 10 5 )( 3.14 )( cos 0)

Φ = (11.304 x 10 5 )(1)

Φ = 11.304 x 10 5

Φ = 1.13 x 10 6 Nm 2 /C

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