1. Bala ubukhulu kanye nesiqondiso sensimu kagesi endaweni ethi A etholakala ku-5 cm ukusuka endaweni yokushaja Q = +10 μC. k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)
Kwaziwa:
Ishaja kagesi (Q) = +10 μC = +10 x 10 -6 C
Ibanga eliphakathi kwephuzu A kanye neshaja yephuzu Q (r A ) = 5 cm = 0.05 m = 5 x 10 -2 m
k = 9 x 10 9 Nm 2 C −2
Okufunwayo: Ubukhulu kanye nesiqondiso sensimu kagesi endaweni A
Isixazululo:
Isiqondiso sensimu kagesi endaweni A:
Ishaja kagesi ilungile ngakho-ke isiqondiso sensimu kagesi sikude neshaja kagesi kanye namaphuzu A.
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2. Bala ubukhulu kanye nesiqondiso sensimu kagesi endaweni ethi P etholakala ku-10 cm ukusuka ekushajweni kwephuzu Q = -2 0 μC. k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C.
Kwaziwa:
Ishaja kagesi (q) = -20 μC = -20 x 10 -6 C
Ibanga eliphakathi kwephuzu P kanye nokushaja kagesi (r P ) = 10 cm = 0.1 m = 1 x 10 -1 m
k = 9 x 10 9 Nm 2 C −2
Okufunwayo: Ubukhulu kanye nesiqondiso sensimu kagesi endaweni P
Isixazululo:
Isiqondiso sensimu kagesi endaweni A:
Ishaja kagesi ayilungile yingakho insimu kagesi iqondiswa yishaja kagesi.
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3. Amashaja amabili ahlukaniswe ngebanga elingama-40 cm. Ubukhulu kanye nesiqondiso sensimu kagesi endaweni ethi P phakathi kwamashaja amabili, okungukuthi ama-20 cm ukusuka endaweni ethi A?
Kwaziwa:
Ishaja A (q A ) = -2 μC = -2 x 10 -6 C
Ishaja B (q B ) = + 4 μC = +4 x 10 -6 C
Ibanga phakathi kokushaja u-A kanye nephuzu u-P (r AP ) = 20 cm = 0.2 m = 2 x 10 -1 m
Ibanga phakathi kweshaja B kanye nephuzu P (r BP ) = 20 cm = 0.2 m = 2 x 10 -1 m
Okufunwayo: Ubukhulu kanye nesiqondiso sensimu kagesi endaweni P.
Isixazululo:
Ishaja A ayilungile ukuze isiqondiso samaphuzu ensimu kagesi sibheke ku-Q A (ngakwesobunxele).
Ishaja B ilungile kangangokuthi isiqondiso samaphuzu ensimu kagesi siqhelelene ne-Q B (ngakwesobunxele).
Insimu kagesi iyonke endaweni A:
E = E A + E B
E = (4.5 x 10 5 ) + (9 x 10 5 )
E = 13.5 x 10 5 N/C
Isiqondiso sensimu kagesi sikhomba ku-Q A (ngakwesobunxele).
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4. Ubukhulu bensimu kagesi buyi-zero ku-…
Ishaja u-A ilungile kanti ishaja u-B ilungile kangangokuthi ubukhulu bensimu kagesi bungu-zero etholakala endaweni engu-P, phakathi kwamabili amashaja.
Kwaziwa:
Ishaja A (q A ) = + 20 μC = +20 x 10 −6 C
Ishaja B (q B ) = +40 μC = +40 x 10 −6 C
k = 9 x 10 9 Nm 2 C −2
Ibanga phakathi kweshaja A kanye neshaja B = 20 cm
Inkokhelo phakathi kwenkokhelo A nephuzu P (r AP ) = a
Ibanga phakathi kokushaja u-B kanye nephuzu u-P (r BP ) = 20 – a
Okufunwayo: Ubukhulu bensimu kagesi bungu-zero etholakala ku-….
Isixazululo:
Ubukhulu bensimu kagesi ekhiqizwa yishaja u-A endaweni P
Ishaja A ilungile ukuze isiqondiso samaphuzu ensimu kagesi sibe kude neshaja A (ngakwesokudla).
Ubukhulu bensimu kagesi ekhiqizwa yishaja B endaweni P:
Ishaja B ilungile kangangokuthi isiqondiso samaphuzu ensimu kagesi sikude neshaja B (ngakwesobunxele).
Insimu kagesi iyonke endaweni P = 0:
Sisebenzisa ifomula ye-quadratic ukuthola u-a.
Ubukhulu bensimu kagesi bungu-zero obutholakala ku-8 cm ukusuka ekushajeni u-A noma ku-12 cm ukusuka ekushajeni u-B.
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5. Ngokusekelwe esithombeni esingezansi, u-w nansi iphuzu u-P ukuze insimu kagesi ephuzwini u-P ibe yi-zero? (k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)
Isixazululo
To bala amandla ensimu kagesi endaweni P, kucatshangwa ukuthi endaweni P kukhona inkokhelo yokuhlola enhle. Q1 unethemba futhi u-Q2 ayilungile, ngakho-ke iphuzu P kumele libe ngakwesokudla kwe-Q2 noma ngakwesobunxele se-Q1Uma iphuzu P lingakwesobunxele se-Q1insimu kagesi ekhiqizwa yi-Q1 endaweni ethi P ingakwesobunxele (kude no-Q1) kanye nensimu kagesi ekhiqizwa yi-Q2 endaweni ethi P ngakwesokudla (ebheke ku-Q1). Isiqondiso sensimu kagesi siphambene ukuze amasimu amabili kagesi ahlukane ukuze amandla ensimu kagesi endaweni P abe yi-zero.
Kwaziwa:
Q 1 = +9 μC = +9 x 10 −6 C
Q 2 = -4 μC = -4 x 10 −6 C
k = 9 x 10 9 Nm 2 C −2
Ibanga phakathi kokushaja 1 nokushaja 2 = 3 cm
Ibanga phakathi kuka-Q 1 nephuzu P (r 1P ) = a
Ibanga phakathi kuka-Q 2 nephuzu P (r 2P ) = 3 + a
Okufunwayo: indawo yephuzu P ukuze insimu kagesi ephuzu P ibe yi-zero
Isixazululo:
Iphuzu P lingakwesobunxele se-Q 1.
Insimu kagesi ekhiqizwe yi-Q 1 endaweni P:
Ishaja yokuhlola ilungile kanti i-Q 1 ilungile ukuze isiqondiso sensimu kagesi siye ngakwesobunxele.
Insimu kagesi ekhiqizwe yi-Q 2 endaweni P:
Ishaja yokuhlola ilungile kanti u-Q 2 ulungile ukuze isiqondiso sensimu kagesi sibe ngakwesokudla.
Insimu kagesi ehlanzekile endaweni A:
Sebenzisa ifomula ye-quadratic ukuthola i-:
a = -1.25, b = -13.5, c = -20.25
Ibanga phakathi kwe-Q 2 nephuzu P (r 2P ) = 3 + a = 3 – 1.8 = 1.2 cm.
Iphuzu P lingakwesokudla esingu-1.2 cm kwe-Q 1.
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