Amandla kagesi angakhona - izinkinga nezixazululo

1. I-electron isheshiswa kusukela ekuphumuleni ngomehluko ongaba khona ongu-12 V. Iyini ushintsho emandleni kagesi angase abe khona e-electron?

Kwaziwa:

Ukushaja ku -electron (e) = -1.60 x 10 ^-19 Coulomb

Amandla kagesi = i-voltage (V) = ama-volt angu-12

Okufunwayo: Ushintsho emandleni kagesi angase abe khona e-electron (ΔPE)

Isixazululo:

ΔPE = q V = (-1.60 x 10 ^-19 C)(12 V) = -19.2 x 10 ^-19 Ama-Joules

Uphawu lokususa lubonisa ukuthi amandla angase abe khona ayancipha.

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2. Amapuleti amabili ahambisanayo ayashajwa. Ukuhlukaniswa phakathi kwamapuleti kungu-2 cm kanti ubukhulu bensimu kagesi phakathi kwamapuleti bungu-500 Volt/meter. Luyini ushintsho emandleni angase abe khona e-proton uma isheshiswa isuka epuletini elishajwe kahle iye epuletini elishajwe kabi.

Kwaziwa:

Ubukhulu bensimu kagesi phakathi kwamapuleti (E) = 500 Volt/meter

Ibanga phakathi kwamapuleti = 2 cm = 0,02 m

Ishaja ku-proton = +1.60 x 10 ^-19 Coulombs

Okufunwayo: Ushintsho kumandla kagesi (ΔPE)

Isixazululo:

Amandla kagesi:

V = E s

V = (500 Volt/m)(0.02 m)

V = 10 Volt

Ushintsho kumandla kagesi angase abe khona:

ΔPE = q V

I-ΔPE = (1,60 x 10 ^-19 C)(10 V)

I-ΔPE = 16 x 10 ^-19 Ama-Joule

I-ΔPE = 1.6 x 10 ^{-1 8} Joule

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3. Amashaja amabili ahlukaniswe ngebanga elingu-10 cm. Ukushaja endaweni A = +9 μC kanye nokushaja endaweni B = -4 μC. k = 9 x 10 ⁹ Nm ² C ⁻² , 1 μC = 10 ⁻⁶ C. Luyini ushintsho emandleni kagesi angase abe khona eshaja endaweni B uma lusheshiswa luye endaweni A?

Kwaziwa:

Ishaja A (q ₁ ) = +9 μC = +9 x 10 ⁻⁶ C

Ishaja B (q ₁ ) = -4 μC = -4 x 10 ⁻⁶ C

k = 9 x 10 ⁹ Nm ² C ⁻²

Ibanga eliphakathi kwezindleko A kanye no-B (r) = 10 cm = 0.1 m = 10 ^-1 m

Okufunwayo: Ushintsho kumandla kagesi (ΔEP)

Isixazululo: