10 Dynamics Chinhu chakabatanidzwa netambo pamusoro pepulley Muchina weAtwood - Matambudziko neMhinduro
1. Bhuroko A rine uremu ye5 kg, yakaiswa panzvimbo yakatsetseka yakatwasuka. Bhokisi B rine huremu hwe3 kg rakarembera pamucheto wetambo yakabatana nebhokisi A pamusoro pepulley. Kuwedzera nekuda kwegiravhiti iri 10 m/s2Chii chinonzi kukurumidza yemabhuroko ese ari maviri?
Zvinozivikanwa:
Huremu hwebhuroko A (m)A) = 5 kg
Huremu hwebhuroko B (mB) = 3 kg
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s2
uremu yebhuroko B (w)B) = mB g = (3)(10) = 30 Newton
Kuda: Kukurumidzisa kwemabhuroko ese ari maviri (a)
Solution:
Nzvimbo yakatambanuka yakatsetseka saka hapana simba rekukweshana. Simba rinokurumidzisa mabhuroko ese ari maviri huremu hwebhuroko B.
ΣF = ma
wB = (mA +mB) a
30 = (5 + 3) a
30 = 8 a
a = 30 / 8
a = 3.75 m/s2
2.
Zvichibva pamufananidzo uri pamusoro apa, 
(1) kukurumidza kwechinhu = 0
(2) chinhu chinofamba nekumhanya kusingachinji
(3) chinhu chiri pazororo
(4) chinhu chinofamba kana huremu hwechinhu chacho huri hudiki pane simba rinodhonza chinhu chacho.
Solution:
(1) Kukurumidza kwechinhu = 0.
Simba reNet:
∑F = ma -> kukurumidza (a) = 0
∑F=0
F1 +F2 - F3 = 12 + 24 – 36 = 36 – 36 = 0 N
(2) Chinhu chinofamba nespeed isingachinji
Kusakurumidza zvinoreva chinhu chiri kuzorora kana kufamba nespeed isingachinji.
(3) chinhu chiri pazororo
Hapana simba remagetsi rinoreva chinhu chiri pakuzorora.
(4) chinhu chinofamba kana huremu hwechinhu chacho huri hudiki pane simba rinodhonza chinhu chacho.
Kurema kunoshanda padivi rakatwasuka, ukuwo simba rekudhonza richishanda padivi rakatwasuka.
Chinhu chinofamba nenzira yakatwasuka saka masimba akatwasuka chete ndiwo anoshanda pachinhu chacho
3. Kana chiyero che kukweshana kwekinetic pakati pebhuroko A nepamusoro petafura i0.1. Kukurumidza kunokonzerwa negiravhiti i10 m/s2, saka chii chinonzi simba rinoshanda pabhuroko A kuitira kuti sisitimu ifambe ichienda kuruboshwe mu2 m/s2.
Zvinozivikanwa:
Huremu hwebhuroko A (m)A) = 30 kg
huremu hwebhuroko A (w)A) = (30 kg)(10 m/s2) = 300 kg m/s2 or 300 Newton
Huremu hwebhuroko B (mB) = 20 kg
huremu hwebhuroko B (w)B) = (20 kg)(10 m/s2) = 200 kg m/s2 or 200 Newton
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s2
Kukweshana kwekinetic (μk= = 0.1
Kukurumidza kwesystem (a) = 2 m/s2 (kuruboshwe)
Simba rekukweshana kwekinetic (fk) = μk N= μk wA = (0.1)(300) = 30 Newton
Zvaidiwa: Hukuru hwesimba F
Solution:
Mutemo wechipiri waNewton:
ΣF = amai
Chinhu A chinoenda kuruboshwe:
F – fk - wB = (mA +mB) a
F – 30 – 200 = (30 + 20)(2)
F – 230 = (50)(2)
F – 230 = 100
F = 230 + 100
F = 330 Newton
4. Zvinhu zviviri, A = 2 kg uye B = 6 kg, zvakabatanidzwa pamucheto wetambo pamusoro pepulley, sezvakaratidzwa mumufananidzo uri pazasi. Kana kukurumidza nekuda kwegiravhiti kuri 10 ms-2 saka chii chinonzi kukurumidza kwechinhu B?
Zvinozivikanwa:
Huremu hwechinhu A (m)A) = 2 kg, mB = 6 kg, g = 10 m/s2
huremu hwechinhu A (w)A) = (mA)(g) = (2)(10) = 20 N
huremu hwechinhu B (w)B) = (mB)(g) = (6)(10) = 60 N
Zvaidiwa: Kukurumidzisa kwechinhu b (kukurumidzisa kwesystem).
Solution:
wB > wA saka chinhu B chinodzika pasi, chinhu A chinokwira kumusoro
ΣF = amai
wB - wA = (mA +mB) a
60 – 20 = (2 + 6) a
40 = (8) a
a = 5 m/s2
5. Zvinhu zviviri zvakabatana netambo pamusoro pechipuri chakatsetseka, sezvakaratidzwa mumufananidzo uri pazasi. Kana m1 = 1 kg, m2 = 2 kg, uye kukurumidza nekuda kwegiravhiti ndeye 10 ms-2, saka chii chinonzi simba rekumanikidza T.
Zvinozivikanwa:
Huremu hwechinhu 1 (m1) = 1 kg
Huremu hwechinhu 2 (m2) = 2 kg
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s2
huremu hwechinhu 1 (w)1) = m1 g = (1 kg)(10 m/s2) = 10 kg m/s2 kana 10 Newton
huremu hwechinhu 2 (w)2) = m2 g = (2 kg)(10 m/s2) = 20 kg m/s2 kana 20 Newton
Zvaidiwa: Simba rekumanikidza (T) ?
Solution:
w2 > w1 so m2 inofamba ichidzika, m1 inofamba ichikwira kumusoro.
The Mutemo wechipiri wekufamba waNewton :
ΣF = amai
w2 - w1 = (m1 +m2) a
20 – 10 = (1 + 2) a
10 = (3) a
a = 3.3 m/s2
Kukurumidza kwesystem = 3.3 m / s2.
m2 inofamba ichidzika pasi:
w2 - T2 = m2 a
20 - T2 = (2)(3.33)
20 - T2 = 6.66
T2 = 20 - 6.66
T2 = 13.3 Newton
m1 inofamba ichikwira:
T1 - w1 = m1 a
T1 – 10 = (1)(3.3)
T1 - 10 = 3.33
T1 = 10 + 3.33
T1 = 13.3 Newton
Simba rekumanikidza (T) = 13.3 maNewton.
6. Huremu hwe m1 = 6 kg uye huremu hwe m2 = 4 kg. Nzvimbo yakatambanuka yakatsetseka. Kumhanya kunokonzerwa negiravhiti i10 m/s2Chii chiri kukonzera kukurumidza kwesystem iyi?
Zvinozivikanwa:
Huremu hwe m1 = 6 kg
huremu hwe m2 = 4 kg
kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s2
huremu hwe w1 = m1 g = (6 kg)(10 m/s2) = 60 kg m/s2 kana 60 Newton
huremu hwe w2 = m2 g = (4 kg)(10 m/s2) = 40 kg m/s2 kana 40 Newton
Zvaidiwa: Kukurumidza kwesystem (a)
Solution:
m1 panzvimbo yakatsetseka yakatwasuka isina kukweshana kuitira kuti sisitimu ikurumidziswe nehuremu hwebhuroko 2.
Shandisa mutemo wechipiri waNewton:
∑F = ma
w2 = (m1 +m2) a
40 N = (6 kg + 4 kg) a
40 N = (10 kg) a
a = 40 N / 10 kg
a = 4 m/s2
7. Mabhuroko maviri, bhuroko rimwe nerimwe rine huremu hwe2 kg, rakabatanidzwa netambo pamusoro pepulley, sezvakaratidzwa mumufananidzo uri pazasi. Nzvimbo yakatambanudzwa nepulley zvakatsetseka. Kana bhuroko B rikadhonzwa nesimba rakatambanudzwa re40 Newtons, saka chii chinonzi kukurumidza kwebhuroko? Kukurumidza kunokonzerwa negiravhiti i10 m/s2.
Zvinozivikanwa:
huremu hwebhuroko A (mA) = huremu hwebhuroko B (mB) = 2 kg
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s2
Simba reF = 40 N
huremu hwechinhu A (w)A) = mg = (2)(10) = 20 N
Zvaidiwa: Kukurumidza kwesystem (a)?
Solution:
Shandisa mutemo wechipiri waNewton:
∑F = ma
F – wA = (mA +mB) a
40 – 20 = (2 + 2) a
20 = (4) a
a = 20 / 4
a = 5 m/s2
8. Huremu hwebhuroko A = 2 kg uye huremu hwebhuroko B = 1 kg. Bhuroko B pakutanga rakazorora, rozokurumidza kudzika kusvika rasvika pasi. Kumhanya kunokonzerwa negiravhiti i10 m/s2Simba rekumanikidzwa rakakura sei?
Zvinozivikanwa:
Huremu hwebhuroko A (m)A) = 2 kg
Huremu hwebhuroko B (mB) = 1 kg
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s2
Kurema kwebhuroko B (w)B) = mB g = (1)(10) = 10 Newton
Zvaidiwa: Hukuru hwesimba rekumanikidzwa (T)
Solution:
Usafuratira simba rekukweshana.
Kukurumidza kwesystem (a)
∑F = ma
wB = (mA +mB) a
10 = (2 + 1) a
10 = 3 a
a = 10/3
Simba rekushushikana (T)
Simba rekumanikidzwa pabhuroko A:
∑F = ma
T = mA a = (2)(10/3) = 20/3 = 6.7 Newtons
Simba rekumanikidzana pabhuroko B:
∑F = ma
wB – T = mB a
10 – T = (1)(10/3)
10 – T = 3.3
T = 10 – 3.3 = 6.7 Newton
Simba rekumanikidza (T) = 6.7 Newtons
9. Huremu hwebhuroko A = 2 kg uye huremu hwebhuroko B = 1 kg. Simba rekukweshana riri pakati pechinhu A nenzvimbo yakatwasuka = 2.5 Newtons. Usafuratire kukweshana papulley netambo. Chii chinonzi kukurumidza kwemabhuroko ese ari maviri?
Zvinozivikanwa:
Huremu hwebhuroko A (m)A) = 2 kg
Huremu hwebhuroko B (mB) = 1 kg
Simba rekukweshana pakati pekiyi a nendege yakatwasuka (f)kA) = 2.5 Newton
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s2
Kurema kwebhuroko (w)B) = mB g = (1)(10) = 10 Newton
Zvaidiwa: Kukurumidzisa kwemabhuroko ese ari maviri (a)
Solution:
Shandisa mutemo wechipiri waNewton:
∑F = ma
wB - fk = (mA +mB) a
10 – 2.5 = (2 + 1) a
7.5 = 3 a
a = 7.5 / 3
a = 2.5 m/s2
10. Huremu hwebhuroko a = 30 kg, mira panzvimbo yakatwasuka yakabatana nebhuroko B nehuremu hwe10 kg pamusoro pepulley. Chii chinonzi kukurumidza kwesystem? Kukurumidza kunokonzerwa negiravhiti i10 ms-2.
Zvinozivikanwa:
Huremu hwebhuroko A (m)A) = 30 kg
Huremu hwebhuroko B (mB) = 10 kg
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s2
huremu hwebhuroko B (w)B) = mB g = (10)(10) = 100 Newton
Zvaidiwa: Kukurumidza kwesystem (a)
Solution:
∑F = ma
wB = (mA +mB) a
100 = (30 + 10) a
100 = 40 a
a = 100 / 40
a = 2.5 m/s2
