1. Vhiri re3 0 cm mu radius rinotenderera pa 5 rad/s 2 . Chii chiri kukura kwekumhanya kwemutsara kwenzvimbo iri pa (a) 10 cm kubva pakati (b) 20 cm kubva pakati (c) pamucheto wevhiri?
Zvinozivikanwa:
Nharaunda (r) = 30 cm = 0.3 m
Kukurumidza kwekona ( α ) = 5 rad/s 2
Zvinodiwa: kumhanyisa kwakatwasuka (a) r = 0.1 m (b) r = 0.2 m (c) r = 0.3 m
Solution:
Hukama huripo pakati pekumhanyisa kwemutsara (a) uye kumhanyisa kwekona:
a = r α
(a) kumhanyisa kwakatwasuka, r = 0.1 m
a = (0.1 m)(5 rad/s 2 ) = 0.5 m/s 2
(b) kumhanyisa kwakatwasuka, r = 0.2 m
a = (0.2 m)(5 rad/s 2 ) = 1 m/s 2
(c) kumhanyisa kwakatwasuka, r = 0.3 m
a = (0.3 m)(5 rad/s 2 ) = 1.5 m/s 2
2. Pulley ine 50 cm mu radius. Kana kumhanyisa kwemutsara kwenzvimbo iri pamucheto wepulley kuri 2 m/s 2 , tsvaga kumhanyisa kwekona kwepulley!
Zvinozivikanwa:
Nharaunda (r) = 50 cm = 0,5 m
kumhanya kwakatwasuka (a) = 2 m/s 2
Zvinodiwa: kukurumidza kwekona
Solution:
α = a / r = 2 / 0.5 = 4 rad/s 2
3. Mapadza ari mublender ane 20 cm mu radius, pakutanga ari pakuzorora. Mushure memasekonzi maviri, mapadza anotenderera 10 rad/s. Sarudza hukuru hwekumhanya kwakatwasuka (a) poindi iri pa10 cm kubva pakati (b) poindi iri pamucheto wemapadza.
Zvinozivikanwa:
Nharaunda (r) = 20 cm = 0.2 m
Kumhanya kwekutanga kwekona ( ωo ) = 0
Kumhanya kwekupedzisira kwekona ( ωt ) = 10 radians/ sekondi
Nguva yepakati (t) = masekondi gumi nemashanu
Zvinodiwa: kumhanyisa kwakanangana kwenzvimbo iri pa (a) r = 0.1 m (b) r = 0.2 m
Solution:
ω t = ω o + α t
10 = 0 + α (2)
10 = 2 α
α = 10 / 2
α = 5 rad/s
(a) kumhanyisa kwakanangana kwe r = 0.1 m
a = r α = (0.1 m)(5 rad/s 2 ) = 0.5 m/s 2
(b) kumhanyisa kwakanangana kwe r = 0.2 m
a = r α = (0.2 m)(5 rad/s 2 ) = 1 m/s 2
4. Vhiri re 20 cm mu radius rinokurumidziswa kwemasekonzi maviri kubva pa 20 rad/s kusvika razorora. Sarudza hukuru hwekukurumidzisa kwakanangana (a) poindi iri pa 10 cm kubva pakati (b) poindi iri pa 10 cm kubva pakati.
Zvinozivikanwa:
Nharaunda (r) = 20 cm = 0.2 m
Kumhanya kwekutanga kwekona ( ω o ) = 20 rad/s
Kumhanya kwekupedzisira kwekona ( ωt ) = 0
Nguva yepakati (t) = masekondi gumi nemashanu
Zvinodiwa: Kukurumidza kwakatwasuka (a) r = 0.1 m (b) r = 0.2 m
Solution:
ω t = ω o + α t
0 = 20 + α (2)
-20 = 2 α
α = -20 / 2
α = -10 rad/s
Chiratidzo chekusaratidza kuti kumhanya kwekona kuri kudzikira.
(a) kumhanyisa kwakanangana kwe r = 0.1 m
a = r α = (0.1 m)(-10 rad/s 2 ) = -1 m/s 2
(b) kumhanyisa kwakanangana kwe r = 0.2 m
a = r α = (0.2 m)(-10 rad/s 2 ) = -2 m/s 2
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