1. Kuchaja mapoinzi maviri, QA = +8 μC uye QB = -5 μC, dzakaparadzaniswa nechinhambwe r = 10 cm. Ukuru hwe simba remagetsi. Iyo k isingachinji = 8.988 x 109 Nm2C-2 = 9 x gumi9 Nm2C-2.
Zvinozivikanwa:
Chaja A (q A ) = +8 μC = +8 x 10 -6 C
Chaja B (q B ) = -5 μC = -5 x 10 -6 C
k = 9 x 10 9 Nm 2 C −2
Nhambwe iri pakati pechaja A neB (r AB ) = 10 cm = 0.1 m
Zvinodiwa : Hukuru hwesimba remagetsi
Solution:
Fomura yemutemo waCoulomb :
Hukuru hwesimba remagetsi:
2. Zvidimbu zviviri zvine chaji sezvakaratidzwa pamufananidzo uri pazasi. Q P = +10 μC uye Q q = +20 μC zvakaparadzaniswa nedaro r = 10 cm. Chii chinonzi hukuru hwesimba remagetsi.
Zvinozivikanwa:
Chaja P (Q P ) = +10 μC = +10 x 10 -6 C
Chaja Q (Q Q ) = +20 μC = +20 x 10 -6 C
k = 9 x 10 9 Nm 2 C −2
Nhambwe iri pakati pechaji P neQ (r PQ ) = 12 cm = 0.12 m = 12 x 10 -2 m
Zvinodiwa: Hukuru hwesimba remagetsi
Solution:
3. Zvidimbu zvitatu zvakachajwa zvakarongwa mumutsara sezvakaratidzwa mumufananidzo uri pazasi. Chaji A = -5 μC, chaji B = +10 μC uye chaji C = -12 μC. Verenga simba remagetsi rinogara riripo pachikamu B nekuda kwezvimwe zviviri zvinochajwa.
Zvinozivikanwa:
Chaja A (q A ) = -5 μC = -5 x 10 -6 C
Chaja B (q B ) = +10 μC = +10 x 10 -6 C
Chaja C (q C ) = -12 μC = -12 x 10 -6 C
k = 9 x 10 9 Nm 2 C −2
Nhambwe iri pakati pezvikamu A naB (r AB ) = 6 cm = 0.06 m = 6 x 10 -2 m
Nhambwe iri pakati pezvikamu B naC (r BC ) = 4 cm = 0.04 m = 4 x 10 -2 m
Zvinodiwa: Hukuru uye gwara resimba remagetsi pachikamu B
Solution:
Simba guru riri pachikamu B ndiro huwandu hwesimba reF BA rinoiswa pachikamu B nechikamu A uye simba reF BC rinoiswa pachikamu B nechikamu C.
Simba raF BA rinoshandiswa pachikamu B nechikamu A:
Kutungamira kwesimba remagetsi kunongedzera kuchinhu A (nongedzo kuruboshwe).
Simba raF BC rinoshandiswa pachikamu B nechikamu A:
Kutungamira kwesimba remagetsi kunongedzera kuchikamu C (nongedzo kurudyi).
Simba remagetsi rinogara riri pachikamu B :
F B = F AB – F BC = 675 N – 125 N = 550 maNewton.
Kutungamira kwesimba remagetsi pachikamu B kunongedzera kuchikamu C (kunongedzera kurudyi).
4. +Q 1 = 10 μC, +Q 2 = 50 μC uye Q 3 zvakaparadzaniswa sezvakaratidzwa mumufananidzo uri pazasi. Chii chinonzi electrostatic charge pachikamu 3 kana simba re electrostatic pachikamu 2 riri zero.
Zvinozivikanwa:
Chaja 1 (q 1 ) = +10 μC = +10 x 10 -6 C
Chaja 2 (q 2 ) = +50 μC = +50 x 10 -6 C
Nhambwe iri pakati pemachaji 1 ne2 (r 12 ) = 2 cm = 0.02 m = 2 x 10 -2 m
Nhambwe iri pakati pechaji 2 nechaji 3 (r 23 ) = 6 cm = 0.06 m = 6 x 10 -2 m
Simba remagetsi rinogara riri pachikamu chechipiri (F2 ) = 0
Zvinodiwa : muripo 3 (q 3 )
Solution:
Simba remagetsi pachikamu chechipiri ihuwandu hwesimba F 21 rakashandiswa pachikamu chechipiri nechikamu chekutanga uye simba F 23 rakashandiswa pachikamu chechipiri nechikamu chechipiri.
Simba F 21 rakashandiswa pachikamu chechipiri nechikamu 1:
Kutungamira kwesimba remagetsi kunongedzera kuchikamu 3 (nongedza kurudyi).
Simba F23 inoshandiswa pachikamu chechipiri nechikamu 3: 
Kutungamira kwesimba remagetsi kunongedzera kuchikamu 1 (nongedzo kuruboshwe).
Simba remagetsi rinogara riri pachikamu 2 = 0:
