Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro

1. Verenga hukuru negwara remagetsi panzvimbo A iri pa5 cm kubva papoindi yekuchaja Q = +10 μC. k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)

Zvinozivikanwa:

Chaja yemagetsi (Q) = +10 μC = +10 x 10 -6 C

Daro riri pakati penzvimbo A nechaji yepoindi Q (r A ) = 5 cm = 0.05 m = 5 x 10 -2 m

k = 9 x 10 9 Nm 2 C −2

Zvinodiwa: Hukuru uye kwakanangana nemagetsi panzvimbo A

Solution:

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 1

Kutungamira kwemunda wemagetsi panzvimbo A:

Chaji yemagetsi yakanaka saka divi remagetsi riri kure nechaji yemagetsi uye mapoinzi A.

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2. Verenga hukuru negwara remagetsi panzvimbo P iri pa10 cm kubva papoindi yekuchaja Q = -2 0 μC. k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C.

Zvinozivikanwa:

Chaja yemagetsi (q) = -20 μC = -20 x 10 -6 C

Nhambwe iri pakati penzvimbo P nechaji yemagetsi (r P ) = 10 cm = 0.1 m = 1 x 10 -1 m

k = 9 x 10 9 Nm 2 C −2

Zvinodiwa: Hukuru uye kwakanangana nemagetsi panzvimbo P

Solution:

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 2

Kutungamira kwemunda wemagetsi panzvimbo A:

Chaji yemagetsi haina kunaka saka divi remagetsi rinoenda kune chaji yemagetsi.

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3. Mapoinzi maviri anopatsanurwa nedaro remasendimita makumi mana. Ndeipi nzvimbo yemagetsi iri pakati pemapoinzi maviri aya uye divi rayo riri papi P pakati pemapoinzi maviri aya, kureva kuti 20 cm kubva papoinzi A?

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 3

Zvinozivikanwa:

Chaja A (q A ) = -2 μC = -2 x 10 -6 C

Chaja B (q B ) = + 4 μC = +4 x 10 -6 C

Daro riri pakati pekuchaja A nepoindi P (r AP ) = 20 cm = 0.2 m = 2 x 10 -1 m

Daro riri pakati pekuchaja B nepoindi P (r BP ) = 20 cm = 0.2 m = 2 x 10 -1 m

Zvinodiwa: Hukuru uye divi remagetsi panzvimbo P.

Solution:

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 4

Chaji A haina kunaka zvekuti divi remagetsi riri paQ A (kuruboshwe).

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 5

Chaji B yakanaka zvekuti divi renzvimbo dzemagetsi riri kure neQ B (kuruboshwe).

Huwandu hwemagetsi ari panzvimbo A:

E = E A + E B

E = (4.5 x 10 5 ) + (9 x 10 5 )

E = 13.5 x 10 5 N/C

Kutungamira kwesimba remagetsi kunongedzera kuQ A (kuruboshwe).

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4. Hukuru hwesimba remagetsi harisi zero pa…

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 6

Chaja A iri positive uye chaja B iri positive zvekuti hukuru hwesimba remagetsi huri zero riri panzvimbo P, pakati pechaja dzese dziri mbiri.

Zvinozivikanwa:

Chaja A (q A ) = + 20 μC = +20 x 10 −6 C

Chaja B (q B ) = +40 μC = +40 x 10 −6 C

k = 9 x 10 9 Nm 2 C −2

Daro riri pakati pechaji A nechaji B = 20 cm

Mutengo uri pakati pechaji A nepoindi P (r AP ) = a

Daro riri pakati pekuchaja B nepoindi P (r BP ) = 20 – a

Zvinodiwa: Hukuru hwesimba remagetsi harisi zero riri pa….

Solution:

Hukuru hwesimba remagetsi rinogadzirwa nechaji A panzvimbo P

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 7

Chaji A yakanaka zvekuti divi renzvimbo dzemagetsi riri kure nechaji A (kurudyi).

Hukuru hwesimba remagetsi rinogadzirwa nechaji B panzvimbo P:

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 8

Chaji B yakanaka zvekuti divi renzvimbo dzemagetsi riri kure nechaji B (kuruboshwe).

Munda wemagetsi wese panzvimbo P = 0:

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 9

Tinoshandisa fomura yequadratic kuti tizive a.

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 10

Hukuru hwesimba remagetsi harisi zero riri pa 8 cm kubva pachaji A kana 12 cm kubva pachaji B.

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5. Zvichibva pamufananidzo uri pazasi, w pano pane poindi P kuitira kuti munda wemagetsi papoindi P uve zero? (k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 11

mhinduro

To verenga simba remagetsi panzvimbo P, zvichifungidzirwa kuti panzvimbo P pane muripo wekuyedza wakanaka. Q1 zvakanaka uye Q2 iri negative, saka poindi P inofanira kunge iri kurudyi rweQ2 kana kuruboshwe rweQ1Kana poindi P iri kuruboshwe rweQ1; munda wemagetsi unogadzirwa naQ1 panzvimbo P iri kuruboshwe (kure neQ)1) uye simba remagetsi rinogadzirwa neQ2 panzvimbo P kurudyi (kuna Q1). Kwakanangana nemunda wemagetsi kwakatarisana kuitira kuti minda miviri yemagetsi iparadzane kuitira kuti simba remunda wemagetsi panzvimbo P rive zero.

Zvinozivikanwa:

Mubvunzo 1 = +9 μC = +9 x 10 −6 C

Mubvunzo 2 = -4 μC = -4 x 10 −6 C

k = 9 x 10 9 Nm 2 C −2

Daro riri pakati pekuchaja 1 nekuchaja 2 = 3 cm

Daro riri pakati peQ 1 nepoindi P (r 1P ) = a

Daro riri pakati peQ 2 nepoindi P (r 2P ) = 3 + a

Zvinodiwa: nzvimbo yepoindi P kuitira kuti munda wemagetsi papoindi P uve zero

Solution:

Poindi P iri kuruboshwe rweQ1.

Munda wemagetsi wakagadzirwa neQ 1 panzvimbo P:

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 12

Chaji yekuyedza iri positive uye Q 1 iri positive zvekuti divi remagetsi riri kuruboshwe.

Munda wemagetsi wakagadzirwa neQ 2 panzvimbo P:

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 13

Chaji yekuyedza iri positive uye Q2 iri negative zvekuti divi remagetsi riri kurudyi.

Munda wemagetsi weNet panzvimbo A:

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 14

Shandisa fomura yequadratic kuti uone a :

a = -1.25, b = -13.5, c = -20.25

Hukuru uye divi reminda yemagetsi - matambudziko nemhinduro 15

Daro riri pakati peQ 2 nepoindi P (r 2P ) = 3 + a = 3 – 1.8 = 1.2 cm.

Poindi P iri kurudyi rwe1.2 cm kubva paQ 1.

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