1. Chinhu chine nguva yekusashanda zvakanaka ye 2 kg m 2 chinotenderera pa 1 rad/s. Chii chinonzi angular momentum yechinhu chacho?
Zvinozivikanwa:
Nguva yekusaita basa (I) = 2 kg m 2
Kumhanya kwekona ( ω ) = 1 rad/s
Zvinodiwa: Angular momentum (L)
Solution:
Fomura ye angular momentum:
L = I ω
L = angular momentum (kg m 2 /s), I = nguva yekusaita basa (kg m 2 ), ω = angular speed (rad/s)
Mwenje wekona:
L = I ω = (2)(1) = 2 kg m 2 /s
2. Pureyi yesimbi inorema 2 kg ine radius ye 0.1 m inotenderera nekumhanya kwakafanana kwe 2 rad/s. Chii chinonzi angular momentum yepureyi?
Zvinozivikanwa:
Huremu hwepulley (m) = 2 kg g
Nharaunda yepulley (r) = 0.1 m
Kumhanya kwekona (ω) = 2 r ad/s
Zvinodiwa: Angular momentum
Solution:
Fomura yenguva yekusagadzikana kwesimbi yakasimba:
Ini = 1/2 mr 2
I = nguva yekusaita basa (kg m 2 ), m = huremu (kg), r = radius (m)
Nguva yekusaita basa:
I = 1/2 (2)(0.1) 2 = (1)(0.01) = 0.01 kg m 2
Kumhanya kwekona:
L = I ω = ( 0.01 )( 2 ) = 0.02 kg m 2 /s
3. Bhora rinorema 2 kg rine dhayamita ye 0.2 m rinotenderera pa 4 rad/s. Chii chinonzi angular momentum yebhora?
Zvinozivikanwa:
Huremu hwebhora (m) = 2 kg
Nharaunda yebhora (r) = 0.2 m
Kumhanya kwekona (ω) = 4 ra d/s
Zvinodiwa: Angular momentum
Solution:
Fomura yenguva yekusagadzikana kwechikamu chimwe chete:
Ini = (2/5) mr 2
I = nguva t yekusashanda (kg m 2 ), m = uremu (kg), r = dhayasi (m)
Nguva yekusagadzikana kwenzvimbo imwechete:
I = (2/5)(2)(0.2) 2 = (4/5)(0.04) = 0.032 kg m 2
Mwenje wekona webhora:
L = I ω = ( 0.032 )( 4 ) = 0.128 kg m 2 /s
4. Chidimbu che1-kg chinotenderera nekumhanya kwakafanana kwe2 rad/s. Chii chinonzi kumhanya kwekona kana radius yedenderedzwa iri 10 cm?
Zvinozivikanwa:
Huremu hwechinhu (m) = 1 kg g
Radiyo yedenderedzwa (r) = 10 cm = 10/100 = 0.1 m
Kumhanya kwekona (ω) = 2 rad/ s
Zvinodiwa: Angular momentum
Solution:
Fomura yenguva yekusagadzikana kwezvikamu:
Ini = mr 2 = (1)(0.1) 2 = (1)(0.01) = 0.01 kg m 2
Mwenje wekona:
L = I ω = (0.01)(2) = 0.02 kg m 2 /s
