Te rahi o te taipana kupenga – ngā raruraru me ngā otinga

1. Ka pāngia tētahi pito o tētahi kurupae he 2 m te roa e te kaha P. He aha te rahi o te taipana ? Ko te tuaka hurihuri i te pūwāhi A.

Te rahi o te taipana kupenga – ngā raruraru me ngā otinga 1Mōhiotia:

Te kaha (F) = 10 N

Te roa o AB (r AB ) = 2 m

He poutū te kaha F ki te kurupae.

Ko te ringa rīwhi (l ) = r AB sin 90 o = (2 m)(1) = 2 m

E hiahiatia ana: Te taipana huri noa i te tuaka hurihuri

Rongoā:

Te taipana:

τ = F l = (10 N)(2 m) = 20 N m

Ko te tohu tāpiri nā te mea ka huri te hihi i te taha maui.

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2. Ko te roa o te kurupae AB ​​he 2 m, ā, ko te kaha F he 10 N. He aha te kaha o te taipana? Ko te tuaka hurihuri i te pūwāhi A.

Te rahi o te taipana kupenga – ngā raruraru me ngā otinga 2Mōhiotia:

Te kaha (F) = 10 N

Te roa o AB (r AB ) = 2 m

Ko te ringa rīwhi (l ) = r AB sin 60 o = (2 m)(0.5 √3 ) = √3 m

E hiahiatia ana: Te taipana huri noa i te tuaka hurihuri

Rongoā:

Te taipana:

τ = F l = (10 N)( √3 m) = 10 √3 N m

Ko te tohu tāpiri nā te mea ka meinga te hihi e te kaha F kia huri i te taha maui.

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3. Ko te roa o te kurupae he 2 m. Ko te rahi o F1 he 10 N, ā, ko te rahi o F2 he 15 N. Tātaihia te taipana kupenga i waenganui o te kurupae.

Te tuaka hurihuri i waenganui o te kurupae.

Te rahi o te taipana kupenga – ngā raruraru me ngā otinga 3Mōhiotia:

Kaha 1 (F 1 ) = 10 N

Ko te tawhiti i waenganui i a F 1 me te pokapū o te kurupae (r 1 ) = 1 m

Ko te ringa rīwhi 1 (l 1 ) = r 1 sin 90 o = (1 m)(1) = 1 m

He poutū te kaha F 1 ki te kurupae.

Kaha 2 (F 2 ) = 15 N

Ko te tawhiti i waenganui i a F 2 me te pokapū o te kurupae (r 2 ) = 1 m

He poutū te kaha F 2 ki te kurupae.

Ko te ringa rīwhi 2 (l 2 ) = r 1 sin 90 o = (1 m)(1) = 1 m

E hiahiatia ana: Te taipana kupenga huri noa i te tuaka hurihuri

Rongoā:

Te taipana 1:

τ 1 = F 1 l 1 = (10 N)( 1 m) = 10 N m

Ko te tohu tāpiri nā te mea ka meinga te hihi e te kaha o F 1 kia huri ki te taha maui.

Te taipana 2:

τ 2 = F 2 l 2 = (15 N)( 1 m) = -15 N

Ko te tohu tango nā te mea ka meinga te hihi e te kaha F 2 kia huri ki te taha matau.

Te taipana kupenga:

Σ τ = τ 1 – τ 2 = 10 – 15 = – 5 N m

Ko te tohu tango nā te mea ka huri te hihi ki te taha matau.

[irp]

4. Ko te roa o te kurupae AB ​​he 2 m, ko te rahi o F1 he 10 N, ā, ko te rahi o F2 he 10 N. Tātaihia te taipana kupenga i waenganui o te kurupae.

Te rahi o te taipana kupenga – ngā raruraru me ngā otinga 4Te tuaka hurihuri i waenganui o te kurupae.

Mōhiotia:

Kaha 1 (F 1 ) = 10 Nn

Ko te tawhiti i waenganui i a F 1 me te pokapū o te kurupae (r 1 ) = 1 m

Ko te ringa rīwhi 1 (l 1 ) = r 1 sin 60 o = (1 m)(0.5 √3 ) = 0.5 √3 m

Kaha 2 (F 2 ) = 10 N

Ko te tawhiti i waenganui i a F 2 me te pokapū o te kurupae (r 2 ) = 1 m

He poutū te kaha F 2 ki te kurupae.

Ko te ringa rīwhi 2 (l 2 ) = r 2 sin 90 o = (1 m)(1) = 1 m

E hiahiatia ana: Te taipana kupenga huri noa i te tuaka hurihuri

Rongoā:

Te taipana 1:

τ 1 = F 1 l 1 = (10 N)( 0.5 √3 m) = 5 √3 = 8.7 Nm

Ko te tohu tāpiri nā te mea ka meinga te hihi e te kaha F 1 kia huri ki te taha matau.

Te taipana 2:

τ 2 = F 2 l 2 = (10 N)( 1 m) = -10 N m

Ko te tohu tango nā te mea ka meinga te hihi e te kaha F 2 kia huri ki te taha matau.

Te taipana kupenga:

Σ τ = τ 1 – τ 2 = 8.7 – 10 = – 1.3 N m

Ko te tohu tango nā te mea ka meinga te hihi kia huri ki te taha matau e te kaha kupenga.

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5. Ko te roa o te kurupae he 10 m, ko te rahi o F1 he 10 N, ko te rahi o F2 he 10 N, ā, ko te rahi o F3 he 15 N. Ko te tawhiti i waenganui i te pūwāhi A me te pūwāhi C he 7.5 m. Kei waenganui o te kurupae te Kaha F2. Tātaihia te taipana kupenga e pā ana ki te pūwāhi C kei te 2.5 m mai i te pūwāhi B.

Kei te pūwāhi C te tuaka hurihuri

Te rahi o te taipana kupenga – ngā raruraru me ngā otinga 5Mōhiotia:

Kaha 1 (F 1 ) = 10 N

Ko te tawhiti i waenganui i a F 1 me te pūwāhi C (r 1 ) = 2.5 m

He poutū te kaha F 1 ki te kurupae.

Ko te ringa rīwhi 1 (l 1 ) = r 1 sin 90 o = ( 2.5 m)( 1 ) = 2.5 m

Kaha 2 (F 2 ) = 10 N

Ko te tawhiti i waenganui i a F 2 me te pūwāhi C (r 2 ) = 2.5 m

He poutū te kaha F 2 ki te kurupae.

Ko te ringa rīwhi 2 (l 2 ) = r 2 sin 90 o = ( 2.5 m)(1) = 2.5 m

Kaha 3 (F 3 ) = 15 N

Ko te tawhiti i waenganui i a F 3 me te pūwāhi C (r 3 ) = 7.5 m

He poutū te kaha F 3 ki te kurupae.

Ko te ringa rīwhi 3 (l 3 ) = r 3 sin 90 o = (7.5 m)(1) = 7.5 m

E hiahiatia ana: Te taipana kupenga huri noa i te tuaka hurihuri

Rongoā:

Te taipana 1:

τ 1 = F 1 l 1 = (10 N)( 2.5 m) = 25 N m

Ko te tohu tāpiri nā te mea ka meinga te hihi e te kaha F 1 kia huri ki te taha matau.

Te taipana 2:

τ 2 = F 2 l 2 = (10 N)( 2.5 m) = 25 N m

Ko te tohu tāpiri nā te mea ka meinga te hihi e te kaha F 2 kia huri ki te taha matau.

Te taipana 3:

τ 3 = F 3 l 3 = (15 N)( 7.5 m) = -112..5 N m

Ko te tohu tango nā te mea ka meinga te hihi e te kaha F 3 kia huri ki te taha matau.

Te taipana kupenga:

Σ τ = τ 1 + τ 2 – τ 3 = 25 + 25 – 112.5 = – 62.5 N m

Ko te tohu tango nā te mea ka meinga te hihi kia huri ki te taha matau e te kaha kupenga.

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6. Ko te roa o te kurupae he 10 m, ko te rahi o F1 ko te 10 N, ko te rahi o F2 he 10 N, ā, ko te rahi o F3 ko te 10 N. Tātaihia te taipana kupenga mō te pūwāhi A, kei te 5 m mai i te pouTe rahi o te taipana kupenga – ngā raruraru me ngā otinga 6te whakamahinga o te kaha F1.

Te tuaka hurihuri i te pūwāhi A.

Mōhiotia:

Kaha 1 (F 1 ) = 10 N

Ko te tawhiti i waenganui i a F 1 me te pūwāhi A (r 1 ) = 5 m

Ko te ringa rīwhi 1 (l 1 ) = r 1 sin 60 o = (5 m)(0.5 √3 ) = 2.5 √3 m

Kaha 2 (F 2 ) = 10 N

Ko te tawhiti i waenganui i a F 2 me te pūwāhi A (r 2 ) = 0

He poutū te kaha F 2 ki te kurupae.

Ko te ringa rīwhi 2 (l 2 ) = r 2 sin 90 o = (0)(1) = 0

Ko te kaha 3 (F 3 ) = 10 N

Ko te tawhiti i waenganui i a F 3 me te pūwāhi A (r 3 ) = 10 m

Ko te ringa rīwhi 3 (l 3 ) = r 3 sin 30 o = (10 m)(0.5) = 5 m

E hiahiatia ana: te taipana kupenga huri noa i te tuaka hurihuri

Rongoā:

Te taipana 1:

τ 1 = F 1 l 1 = (10 N)( 2.5 √3 m ) = 25√3 = 43.3 N m

Ko te tohu tāpiri nā te mea ka meinga te hihi e te kaha F 1 kia huri ki te taha matau.

Te taipana 2:

τ 2 = F 2 l 2 = (10 N)(0) = 0

Te taipana 3:

τ 3 = F 3 l 3 = (10 N)( 5 m) = -50 N m

Ko te tohu tango nā te mea ka meinga te hihi e te kaha F 3 kia huri ki te taha matau.

Te taipana kupenga:

Σ τ = τ 1 + τ 2 – τ 3 = 43.3 + 0 – 50 = – 6.7 N m

Ko te tohu tango nā te mea ka meinga te hihi kia huri ki te taha matau e te kaha kupenga.

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