Whakatauhia te hua o ngā whārite e rua mā te whakamahi i ngā wāhanga o te whārite

Ngā raruraru kua whakatauhia i roto i ngā whārite – te whakatau i te hua o ngā whārite e rua mā te whakamahi i ngā wāhanga o te whārite

1. F ₁ = 6 N, F ₂ = 10 N. Tātaihia te hua o te whārite.

otinga

F _1x = F ₁ cos 60 ^o = (6)(0.5) = 3 N ( he pai nā te mea he rite te ahunga ki te tuaka x )

F _2x = F ₂ cos 30 ^o = (10)(0.5 √ 3) = 5 √ 3 = (5)(1.372) = -8.66 N (kino nā te mea he rite te ahunga ki te tuaka -x)

F _1y = F ₁ sin 60 ^o = (6)(0.5 √ 3) = 3 √ 3 ​​​​= (3)(1.372) = 4.116 N ( he pai nā te mea he rite te ahunga ki te tuaka y )

F _2y = F ₂ sin 30 ^o = (10)(0.5 ) = -5 N (kino nā te mea he rite te ahunga ki te tuaka -y)

F _x = F _1x – F _2x = 3 – 8.66 = -5.66 N

F _y = F _1y – F _2y = 4.116 – 5 = -0.884 N

Ko te hua o ēnei kaha e rua ko 5.7 N.

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2. F ₁ = 4 N, F ₂ = 4 N, F ₃ = 8 N. Tātaihia te hua o te whārite.

otinga

F_1x =F₁ whaimana 60^o = (4)(0.5) = 2 N (he pai nā te mea he rite te ahunga ki te tuaka x)

F _2x = -4 N (kino nā te mea he rite te ahunga ki te tuaka -x)

F _3x = F ₃ cos 60 ^o = (8)(0.5) = 4 N ( he pai nā te mea he rite te ahunga ki te tuaka x )

F_1y =F₁ hara 60^o = (4)(0.5√3) = 2√3 N (he pai nā te mea he rite te ahunga ki te tuaka-y)

F _2y = 0

F_3y =F₃ hara 60^o = (8)(0.5√3) = -4√3 N (kino nā te mea he rite te ahunga ki te tuaka -y)

F _x = F _1x – F _2x + F _3x = 2 – 4 + 4 = 2 N

F_y =F_1y +F_2y - F_3y = 2√3 + 0 – 4√3 = -2√3 N

Ko te hua o ēnei kaha e toru ko 5.7 N.

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1. Whakatauhia te hua o te i roto i te rārangi whārite
2. Whakatauhia ngā wāhanga whārite
3. Whakatauhia te hua o ngā whārite e rua mā te whakamahi i te ariā Pythagorean
4. Whakatauhia te hua o ngā whārite e rua mā te whakamahi i te whārite cosine
5. Whakatauhia te hua o ngā whārite e rua mā te whakamahi i ngā wāhanga o ngā whārite