3 ngā pātai mō te whārite taumaha
1. E toru ngā matūriki, he 1 kg te taumaha, kei ngā pito o tētahi tapatoru ōrite, ā, 1 m te roa o ōna taha. E hia te rahi o te kaha ā-papa e pāngia ana e ia matūriki pūwāhi (i roto i te G)?
otinga
Te rahi o te kaha ā-papa e pāngia ana e tētahi o ngā matūriki.
F 12 = G (m 1 )(m 2 ) / r 2 = G (1)(1) / 1 2 = G/1 = G
F 13 = G (m 1 )(m 3 ) / r 2 = G (1)(1) / 1 2 = G/1 = G
Te hua o te kaha ā-papa i te pūwāhi 1:
F 1 = √1 2 +1 2 = √1+1 = √2 Ngā Newton
2. E whakaatu ana te ahua i raro nei i ētahi mea e toru , ko m1 = 6 kg; ko m2 = 3 kg me m3 = 4 kg e takoto ana i runga i tētahi rārangi tika. Tātaihia te rahi me te ahunga o te kaha ā-papatipu e pāngia ana e m2! (whakahuatia ki te G)
Mōhiotia:
m1 = 6 kirokaramu
m2 = 3 kirokaramu
m3 = 4 kirokaramu
pūmau ā-papatipu = G
r 21 = 4 mita
r 23 = 2 mita
E hiahiatia ana: Te hua o te kaha ā-papatipu F i pāngia e te m 2
Rongoā:
Ko te kaha ā-papa i waenganui i te m2 me te m3 :
F = G (3)(4) / 2 2 = G 12 / 4 = 3G
Ko te kaha ā-papa i waenganui i te m2 me te m1 :
F = G (3)(6) / 4 2 = G 18 / 16 = 1,125G
3. Kei te wehea te taonga A he 1 kg te taumaha me te taonga B he 2 kg te taumaha mā te tawhiti o te 2 m i a rātou anō. Ko te pūwāhi P he 2 m mai i te taonga A, ā, ko te pūwāhi B he 2 m. He pēhea te kaha o te papa tōpana i te pūwāhi P?
Mōhiotia:
m A = 1 kg
m B = 2 kg
r PA = 2 mita
r PB = 2 mita
Pūmau taumaha = G
E hiahiatia ana: Te kaha ā-papatipu E i te pūwāhi P
Rongoā:
E PA = G (m A ) / r 2 = G (1) / 2 2 = G/4 = 0,25G
E PB = G (m B ) / r 2 = G (2) / 2 2 = 2G/4 = 0,5G
Te kaha o te papa tōpana i te pūwāhi P:
E = √0,25G 2 +0,5G 2 = √0,0625G 2 +0,25G 2 = √0,3125G 2 = 0,56G N/kg
