5 Ukunyakaza kwe-parabolic Umsebenzi kanye namandla e-kinetic Ukunyakaza okuqondile Ukunyakaza okuqondile nokuqondile Izinkinga nezixazululo
1. Ibhola liphonswa lisuka phezulu kwesakhiwo ngesivinini sokuqala esingu -8 m/s nge-engeli engu-20 o ngaphansi kwe-horizontal. Ibhola lishaya phansi ngemva kwemizuzwana emi-3.
a) Ibanga elingakanani ukusuka phansi kwesakhiwo ibhola elithinta umhlabathi
b) Liphakeme kangakanani ibhola eliphonswe endaweni
c) Ubude bebhola bufinyelela kumamitha ayi-10 ukusuka endaweni yokuphonsa ibhola
vox =vo ibe 20o = 8 (0.939) = 7.512 m/s
v oy = v o isono 20 o = 8 (0.342) = 2.736 m/s
a) x
Ukunyakaza okuvundlile kuhlaziywa njengokunyakaza okuqondile okufanayo, ngakho-ke kusetshenziswa ifomula yokunyakaza okuqondile okufanayo.
x = v ox t
x = (7.512 m/s)(3 s)
x = 22.536 m
b) y
Ukunyakaza kwesiqondiso esiqondile kuhlaziywa njengokunyakaza kokuwa kwamahhala kusetshenziswa ifomula yokunyakaza kokuwa kwamahhala.
Sebenzisa le fomula u-y = vot + ½ gt 2
Ekunyakazeni kokuwa okukhululekile, i-v o = 0 ngakho ifomula iba: y = ½ gt 2
y = ½ (9.8)(3 2 )
y = (4.9)(9)
y = 44 m
c) y = 10 m
Sebenzisa ifomula u-y = ½ gt 2
10 = ½ (9,8) t 2
10 = 4.9 t 2
t 2 = 10 / 4.9
t 2 = 2
t = 1.4 imizuzwana
2. Ithimba lesitimela sezinja lidonsa isisindo somthwalo ongamakhilogremu ayi-100 kuze kufike kumakhilomitha amabili ngaphezu kwendawo evundlile ngesivinini esingaguquki. Uma i-coefficient of friction phakathi kwesitimela neqhwa ingu-0.15, thola:
a) umsebenzi owenziwe yinja
Bala i- ukungqubuzana kwe-kinetic:
F k = µ k N = µ k w = µ k mg = (0.15) (100 kg) (9.8 m/s 2 ) =147 N
Ijubane lesisindo aliguquguquki ngakho-ke, ngokomthetho kaNewton, amandla aphumelayo = 0. Ngakho-ke F k = F = 147 N
Umsebenzi owenziwe yinja :
W = F d = (147 N)(2000 m) = 294,000 J
b) Amandla alahleka ngenxa yokungqubuzana
Amandla alahleka ngenxa yokungqubuzana:
Umsebenzi = amandla, ngakho-ke:
W = F k d = (147 N)(2000 m) = 294,000 J
3. Amandla avundlile angu-150 N asetshenziselwa ukusunduza ibhokisi ngamamitha angu-6 ngaphezu kwendawo evundlile. Uma ibhokisi lihamba ngesivinini esingaguquki:
a) Umsebenzi owenziwe ngamandla ka-150 N
W = F d = (150 N) (6 m) = 900 J
b) Amandla alahlekile ngenxa yokungqubuzana
Ibhokisi lihamba ngesivinini esingaguquki ukuze amandla aphumayo asebenze ebhokisini = 0.
Ngakho-ke, amandla avundlile = 150 N = ukungqubuzana kwe-kinetic.
Amandla alahlekile ngenxa yokungqubuzana:
W = F ks = (150 N)(6 m) = 900 J
c) I-coefficient yokungqubuzana kwe-kinetic
Ifomula yamandla okungqubuzana:
F k = µ k N = µ k w = µ k mg
150 = µ km m (10)
15 = µ km m
µk = 15 / m
m = isisindo sebhokisi
µ k = i-coefficient yokungqubuzana kwe-kinetic
Ukungqubuzana kwe-kinetic kusebenza lapho izinto zihamba, ukungqubuzana okungaguquki kusebenza lapho izinto zisamile.
4. Inhlayiya inesivinini (3i-4h) m/s. Thola ingxenye ye-momentum ku-x kanye ne-y-axis kanye nobukhulu be-momentum.
Isivinini ku-x-axis: 3 m/s
Isivinini ku-y-axis: 4 m/s
Umfutho ku-x-axis: mv = 3 m
umfutho ku-y-axis: mv = 4 m
Ubukhulu bomfutho:
p 2 = (3 m) 2 + (4 m) 2
p 2 = 9 m 2 + 16 m 2
ikhasi 2 = 25 m 2
p = 5 m
u-p uwuphawu lomfutho oqondile.
5. Imoto isheshiswa ngendlela efanayo kusukela endaweni emile kuya ku-22 m/s imizuzwana engu-9. Uma ububanzi bethayi bungu-58 cm, chaza:
a) inani lamasondo ngesikhathi sokunyakaza (cabanga ukuthi akukho ukushelela)
Bala ukusheshisa imoto:
v t = vo o + at
22 = 0 + a 9
22 = 9a
a = 22/9 = 2.44
Bala ibanga:
d = vot + ½ ku- 2 = 0 + ½ ku- 2
d = ½ ku- 2 = ½ (2.44)(9 2 ) = (1.22)(81) = 98.82 m
Ibanga lemoto = 98.82 amamitha = 9882 cm
Ububanzi bethayi = 58 cm
Inani lokujikeleza = 9882 cm / 58 cm = 170.38 rev
b) Isivinini sokugcina sokujikeleza kwethayi ngesivinini/ngomzuzu
Isivinini sokugcina = amamitha angu-22/umzuzwana = 2200 cm/ umzuzwana
1 rev = 1 ububanzi bethayi = 58 cm
Inani lezinguquko:
2200 cm / 58 cm = ama-revolution angu-40
Ngakho-ke, isivinini sokugcina ekuguqukeni/umzuzu
40 rev/second = 40 rev / 60 seconds = 0.67 rev/minute noma 0.67 rev/minute