Imibuzo emi-3 mayelana ne-Gravity equation
1. Izinhlayiya ezintathu ngasinye esinesisindo esingu-1 kg ziseziqongweni zonxantathu olinganayo onezinhlangothi ezi-1 m ubude. Zingakanani amandla adonsela phansi atholakala yinhlayiya ngayinye ekhombayo (ku-G)?
Isixazululo
Ubukhulu bamandla adonsela phansi atholwa yinye yezinhlayiya.
F12 = G (m1)(m2) /r2 = G (1)(1) / 12 = G/1 = G
F13 = G (m1)(m3) /r2 = G (1)(1) / 12 = G/1 = G
Amandla adonsela phansi aphumela endaweni 1:
