Imibuzo emi-3 mayelana ne-equation eqhubekayo yaseNtwasahlobo
1. Intwasahlobo exutshwe ngokukhululeka inobude obungu-10 cm. Engxenyeni ekhululekile, isisindo esingamagremu angu-200 siyaxhonywa ukuze ubude bentwasahlobo bube ngu-11 cm. Uma u-g = 10 m/s 2 , iyini i-spring force constant?
Kwaziwa:
Ubude bokuqala bentwasahlobo (y 1 ) = 10 cm = 0.10 m
Ubude bokugcina bentwasahlobo (y 2 ) = 11 cm = 0.11 m
Ukushintsha kobude bentwasahlobo (Δy) = 0.11 – 0.10 = 0.01 amamitha
Isisindo somthwalo (m) = 200 amagremu = 0.2 kg
Isisindo somthwalo (w) = mg = (0,2)(10) = 2 amaNewton
Okufunwayo: I-Spring constant (k)
Isixazululo:
Ifomula engaguquki yasentwasahlobo:
F = k Δy
k = F / Δy = 2 / 0,01 = 200 / 1 = 200 Newtons/meter
2. Isipilingi singalulwa ukuze sinwetshwe ngo-10 cm ngamandla angaba ngu-0.5 Joule. Iyini i-spring constant?
Kwaziwa:
Ukwengezwa kobude bentwasahlobo (Δy) = 10 cm = 0.1 imitha
Amandla angase abe khona entwasahlobo (EP) = 0.5 Joules
Okufunwayo: I-Spring constant (k)
Isixazululo:
I-spring constant ibalwa kusetshenziswa ifomula ye-Spring Potential Energy:
I-EP = ½ k Δy 2
2 EP = k Δy 2
2 (0,5) = k (0,1) 2
1 = k (0,01)
k = 1 / 0,01 = 100 / 1 = 100 amaNewton/imitha
3. Intwasahlobo edonswa ngamandla angu-100 N ikhulisa ubude bayo ngo-5 cm. Bala i-spring constant.
Kwaziwa:
Amandla (F) = 100 N
Ukwanda kobude bentwasahlobo (Δx) = 5 cm = 0.05 m
Okufunwayo: I-Spring constant (k)
Isixazululo:
F = k Δx
k = F / Δx = 100 / 0,05 = 10.000 / 5 = 2000 Newtons/meter
