Isibalo samandla adonsela phansi

Imibuzo emi-3 mayelana ne-Gravity equation

1. Izinhlayiya ezintathu ngasinye esinesisindo esingu-1 kg ziseziqongweni zonxantathu olinganayo onezinhlangothi ezi-1 m ubude. Zingakanani amandla adonsela phansi atholakala yinhlayiya ngayinye ekhombayo (ku-G)?

Isixazululo

Ubukhulu bamandla adonsela phansi atholwa yinye yezinhlayiya.

F ₁₂ = G (m ₁ )(m ₂ ) / r ² = G (1)(1) / 1 ² = G/1 = G

F ₁₃ = G (m ₁ )(m ₃ ) / r ² = G (1)(1) / 1 ² = G/1 = G

Amandla adonsela phansi aphumela endaweni 1:

F ₁ = √1 ² +1 ² = √1 +1 = √2 AmaNewton

2. Isithombe esingezansi sibonisa izinto ezintathu m ₁ = 6 kg; m ₂ = 3 kg kanye m ₃ = 4 kg zilele emgqeni oqondile. Thola ubukhulu kanye nesiqondiso samandla adonsela phansi atholakala ku-m2! (isimo ku-G)

Kwaziwa:

m₁ = 6kg

m2 = ₃ kg

m3 = ₄ kg

amandla adonsela phansi = G

r ₂₁ = 4 m

r ₂₃ = 2 m

Kufunwa: Umphumela wamandla adonsela phansi obonwe yi- _m2

Isixazululo:

Amandla adonsela phansi phakathi kuka-m2 _no - _m3 :

F = G (3)(4) / 2 ² = G 12 / 4 = 3G

Amandla adonsela phansi phakathi kuka-m2 _no - _m1 :

F = G (3)(6) / 4 ² = G 18 / 16 = 1,125G

3. Into A enesisindo esingu-1 kg kanye nento B enesisindo esingu-2 kg zihlukaniswe ngebanga elingamamitha amabili ukusuka komunye nomunye. Iphuzu P lingamamitha amabili ukusuka komunye nomunye into A kanye namamitha amabili ukusuka komunye B. Inamandla kangakanani insimu yamandla adonsela phansi endaweni P?

Kwaziwa:

m _A = 1 kg

m _B = 2 kg

r _PA = 2 m

r _PB = 2 m

Amandla adonsela phansi ahlala njalo = G

Kufunwa: U-E amandla adonsela phansi endaweni P

Isixazululo:

E _PA = G (m _A ) / r ² = G (1) / 2 ² = G/4 = 0,25G

E _PB = G (m _B ) / r ² = G (2) / 2 ² = 2G/4 = 0,5G

Amandla ensimu yamandla adonsela phansi aphumela endaweni P:

E = √0,25G ² +0,5G ² = √0,0625G ² +0,25G ² = √0,3125G ² = 0,56G N/kg