Imibuzo emi-3 mayelana nezibalo zensimu kagesi
1. Ibhola eliqhubayo elinobubanzi obuyi-10 cm linomshini kagesi ongama-500 μC. Amaphuzu A, B, no-C ahambisana nendawo ephakathi yebhola ebangeni elingama-12 cm, 10 cm kanye no-8 cm ngokulandelana ukusuka enkabeni yebhola. Bala amandla ensimu kagesi kumaphuzu A, B, kanye no-C!
Kuyaziwa:
Irediyasi yebhola eliqhubayo (R) = 10 cm = 0.1 m
Ishaja kagesi (q) = 500 μC = 500 x 10 -6 C
r A = 12 cm = 0,12 m
r B = 10 cm = 0,1 m
r C = 8 cm = 0,08 m
I-Coulomb constant (k) = 9 x 10 9
Okufunwayo: Amandla ensimu kagesi endaweni A (EA ) , endaweni B (EB ) kanye nendawo C ( EC )
Isixazululo:
a) Amandla ensimu kagesi endaweni A
E A = kq / r A 2 = (9 x 10 9 )(500 x 10 -6 ) / (0,12) 2 = (4500 x 10 3 ) / 0,0144 = 312500 x 10 3 = 3,125 x 10 8 N/C
b) Amandla ensimu kagesi endaweni B
E B = kq / r B 2 = (9 x 10 9 )(500 x 10 -6 ) / (0,1) 2 = (4500 x 10 3 ) / 0,01 = 450.000 x 10 3 = 4,5 x 10 8 N/C
c) Amandla ensimu kagesi endaweni C
E C = 0 ngokuba sebholeni.
2. Uma ishaja yokuhlola engu-4 nC ibekwa endaweni ethile, ishaja ithola amandla angu-5 × 10 - 4 N. Ubukhulu bensimu kagesi u-E bungakanani ngaleso sikhathi?
Kwaziwa:
Ishaja kagesi yokuhlola (q) = 4 nC = 4 x 10 -9 Coulomb
Amandla kagesi (F) = 5 × 10 -4 N
Okufunwayo: Ubukhulu bensimu kagesi (E)
Isixazululo:
E = F / q = (5 × 10 -4 ) / (4 x 10 -9 ) = 1,25 x 10 5 N/C
3. Amashaja amabili q B = 12 μC kanye q C = 9 μC abekwa emaphethelweni kanxantathu ongakwesokudla njengoba ku-Fig. Thola amandla ensimu kagesi azwakele endaweni A!
Kwaziwa:
Ukushaja endaweni B (qB) = 12 μC = 12 x 10 -6 C
Ukushaja endaweni C (qC) = 9 μC = 9 x 10 -6 C
I-Coulomb constant (k) = 9 x 10 9
r AC = 4 cm = 0,04 m
r AB = 3 cm = 0,03 m
Okufunayo: amandla ensimu kagesi endaweni A
Isixazululo:
I-E AC = kq / r 2 = (9 x 10 9 )(9 x 10 -6 ) / (0,04) 2 = 81 x 10 3 / 0,0016 = 5,0 x 10 7 N/C
E AB = kq / r 2 = (9 x 10 9 )(9 x 10 -6 ) / (0,03) 2 = 81 x 10 3 / 0,0009 = 9,0 x 10 7 N/C
