Izinto eziyi-10 ezixhunywe ngentambo phezu kwe-pulley Umshini we-Atwood – Izinkinga Nezixazululo
1. Ibhulokhi A enesisindo esingu -5 kg, ibekwe endaweni ebushelelezi evundlile. Ibhulokhi B enesisindo esingu-3 kg ilenga kolunye uhlangothi lwentambo exhunywe nebhulokhi A phezu kwe-pulley. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s 2. Kuyini ukusheshisa kwamabhulokhi womabili?
Kwaziwa:
Isisindo sebhulokhi A (mA) = 5 kg
Isisindo sebhulokhi B (m B ) = 3 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
Isisindo sebhulokhi B (w B ) = m B g = (3)(10) = 30 AmaNewton
Okufunwayo: Ukusheshisa kwamabhulokhi womabili (a)
Isixazululo:
Indiza evundlile ibushelelezi ngakho-ke akukho mandla okungqubuzana. Amandla asheshisa womabili amabhlogo isisindo sebhlogo B.
ΣF = ma
w B = (m A + m B ) a
30 = (5 + 3) a
30 = 8 a
a = 30/8
a = 3.75 m/s 2
2.
Ngokusekelwe esithombeni esingenhla, 
(1) ukusheshisa kwento = 0
(2) into ihamba ngesivinini esingaguquki
(3) into ephumule
(4) into iyanyakaza uma isisindo sento sincane kunamandla adonsa into.
Isixazululo:
(1) Ukusheshisa kwento = 0.
Amandla aphelele:
∑ F = ma –> ukusheshisa (a) = 0
∑ F = 0
F 1 + F 2 – F 3 = 12 + 24 – 36 = 36 – 36 = 0 N
(2) Into ihamba ngesivinini esingaguquki
Ukungasheshi kusho into ephumule noma ehamba ngesivinini esingaguquki.
(3) into ephumule
Ukungabikho kwamandla aphelele kusho into ephumule.
(4) into iyanyakaza uma isisindo sento sincane kunamandla adonsa into.
Isisindo sisebenza ngendlela eqondile, kuyilapho amandla okudonsa esebenza ngendlela eqondile.
Into ihamba ngendlela evundlile ngakho-ke amandla avundlile kuphela asebenza entweni
3. Uma i-coefficient of kinetic friction phakathi kwebhulokhi A kanye nobuso betafula ingu-0.1. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s2, khona-ke yiliphi amandla asebenza kubhulokhi A ukuze uhlelo luhambe luye ngakwesobunxele ku-2 m/s 2.
Kwaziwa:
Isisindo sebhulokhi A (mA) = 30 kg
isisindo sebhulokhi A (w A ) = (30 kg)(10 m/s 2 ) = 300 kg m/s 2 noma 300 AmaNewton
Isisindo sebhulokhi B (m B ) = 20 kg
isisindo sebhulokhi B (w B ) = (20 kg)(10 m/s 2 ) = 200 kg m/s 2 noma 200 AmaNewton
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
I-coefficient yokungqubuzana kwe- kinetic ( μk ) = 0.1
Ukusheshisa kwesistimu (a) = 2 m/s 2 (ukuya kwesobunxele)
Amandla okungqubuzana kwe-kinetic (f k ) = μ k N = μ k w A = (0.1)(300) = 30 AmaNewton
Okufunwayo: Ubukhulu bamandla F
Isixazululo:
Umthetho wesibili kaNewton:
ΣF = ma
Into u-A iya ngakwesobunxele:
F – f k – w B = (m A + m B ) a
F – 30 – 200 = (30 + 20)(2)
F – 230 = (50)(2)
F – 230 = 100
F = 230 + 100
F = 330 Newton
4. Izinto ezimbili, u-A = 2 kg kanye no-B = 6 kg, ezinamathiselwe kolunye uhlangothi lwentambo phezu kwe-pulley, njengoba kuboniswe esithombeni esingezansi. Uma ukusheshisa ngenxa yamandla adonsela phansi kungu-10 ms -2 khona-ke kuyini ukusheshisa kwento u-B.
Kwaziwa:
Isisindo sento A (mA) = 2 kg, mB = 6 kg, g = 10 m/s2
isisindo sento A (w A ) = (m A )(g) = (2)(10) = 20 N
isisindo sento B (w B ) = (m B )(g) = (6)(10) = 60 N
Okufunwayo: Ukusheshisa kwento b (ukusheshisa kwesistimu).
Isixazululo:
w B > w A ukuze into B iye phansi, into A iye phezulu
ΣF = ma
w B – w A = (m A + m B ) a
60 – 20 = (2 + 6) a
40 = (8) a
a = 5 m/s 2
5. Izinto ezimbili ezixhunywe ngentambo phezu kwe-pulley ebushelelezi, njengoba kuboniswe esithombeni esingezansi. Uma u-m 1 = 1 kg, u-m 2 = 2 kg, futhi ukusheshisa ngenxa yamandla adonsela phansi kungu-10 ms -2 , khona-ke iyini amandla okucindezela u-T.
Kwaziwa:
Isisindo sento 1 (m1) = 1 kg
Isisindo sento 2 (m 2 ) = 2 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
isisindo sento 1 (w 1 ) = m 1 g = (1 kg)(10 m/s 2 ) = 10 kg m/s 2 noma 10 AmaNewton
isisindo sento 2 (w 2 ) = m 2 g = (2 kg)(10 m/s 2 ) = 20 kg m/s 2 noma 20 AmaNewton
Okufunwayo: Amandla okucindezela (T)?
Isixazululo:
w 2 > w 1 ngakho-ke m 2 wehla , m 1 wehla.
Umthetho wesibili kaNewton wokunyakaza :
ΣF = ma
w 2 – w 1 = (m 1 + m 2 ) a
20 – 10 = (1 + 2) a
10 = (3) a
a = 3.3 m/s 2
Ukusheshisa kwesistimu = 3.3 m/s 2.
m2 iqhubekela phansi :
w 2 – T 2 = m 2 a
20 – T 2 = (2)(3.33)
20 – T 2 = 6.66
Isigaba 2 = 20 – 6.66
I-T 2 = 13.3 Newton
m1 iqhubekela phezulu:
I-T 1 – w 1 = m 1 a
I-T 1 – 10 = (1)(3.3)
Isigaba 1 – 10 = 3.33
I-T 1 = 10 + 3.33
I-T 1 = 13.3 Newton
Amandla okucindezela (T) = 13.3 amaNewton.
6. Isisindo esingu-m 1 = 6 kg kanye nesisindo esingu-m 2 = 4 kg. Ubuso obuvundlile bubushelelezi. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s 2 . Kuyini ukusheshisa kwesistimu.
Kwaziwa:
Isisindo sika-m1 = 6kg
isisindo se-m2 = 4 kg
ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
isisindo se-w 1 = m 1 g = (6 kg)(10 m/s 2 ) = 60 kg m/s 2 noma 60 AmaNewton
isisindo se-w 2 = m 2 g = (4 kg)(10 m/s 2 ) = 40 kg m/s 2 noma 40 AmaNewton
Okufunwayo: Ukusheshisa kwesistimu (a)
Isixazululo:
m 1 endizeni ebushelelezi evundlile ngaphandle kokungqubuzana ukuze uhlelo lusheshiswe yisisindo sebhulokhi 2.
Sebenzisa umthetho wesibili kaNewton:
∑ F = ma
w 2 = (m 1 + m 2 ) a
40 N = (6 kg + 4 kg) a
40 N = (10 kg) a
a = 40 N / 10 kg
a = 4 m/s 2
7. Amabhulokhi amabili, ibhulokhi ngalinye linobunzima obungu-2 kg, obuxhunywe ngentambo phezu kwe-pulley, njengoba kuboniswe esithombeni esingezansi. Indiza evundlile kanye ne-pulley kubushelelezi. Uma ibhulokhi B lidonswa ngamandla avundlile angama-Newton angu-40, khona-ke kuyini ukusheshisa kwebhulokhi. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s 2.
Kwaziwa:
isisindo sebhulokhi A (mA) = isisindo sebhulokhi B (mB) = 2 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
Amandla ka-F = 40 N
isisindo sento A (w A ) = mg = (2)(10) = 20 N
Okufunwayo: Ukusheshisa kwesistimu (a)?
Isixazululo:
Sebenzisa umthetho wesibili kaNewton:
∑ F = ma
F – w A = (m A + m B ) a
40 – 20 = (2 + 2) a
20 = (4) a
a = 20/4
a = 5 m/s 2
8. Isisindo sebhulokhi A = 2 kg kanye nesisindo sebhulokhi B = 1 kg. Ibhulokhi B ekuqaleni lapho iphumule, bese isheshiswa yehla ize ifike phansi. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s 2 . Ubukhulu bamandla okucindezela buyini.
Kwaziwa:
Isisindo sebhulokhi A (mA) = 2 kg
Isisindo sebhulokhi B (m B ) = 1 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
Isisindo sebhulokhi B (w B ) = m B g = (1)(10) = 10 AmaNewton
Okufunwayo: Ubukhulu bamandla okucindezela (T)
Isixazululo:
Ungawanaki amandla okungqubuzana.
Ukusheshisa kwesistimu (a)
∑ F = ma
w B = (m A + m B ) a
10 = (2 + 1) a
10 = 3 a
a = 10/3
Amandla okucindezela (T)
Amandla okucindezela ebhulokini A:
∑ F = ma
T = m A a = (2)(10/3) = 20/3 = 6.7 AmaNewton
Amandla okucindezela ebhulokini B:
∑ F = ma
w B – T = m B a
10 – T = (1)(10/3)
10 – T = 3.3
T = 10 – 3.3 = 6.7 Newton
Amandla okucindezela (T) = 6.7 amaNewton
9. Isisindo sebhulokhi A = 2 kg kanye nesisindo sebhulokhi B = 1 kg. Amandla okungqubuzana phakathi kwento A kanye nendiza evundlile = 2.5 Newtons. Unganaki ukungqubuzana ku-pulley kanye nentambo. Kuyini ukusheshisa kwamabhulokhi womabili.
Kwaziwa:
Isisindo sebhulokhi A (mA) = 2 kg
Isisindo sebhulokhi B (m B ) = 1 kg
Amandla okungqubuzana phakathi kokukhiya u-a kanye nendiza evundlile (f kA ) = 2.5 amaNewton
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
Isisindo sebhulokhi (w B ) = m B g = (1)(10) = 10 AmaNewton
Okufunwayo: Ukusheshisa kwamabhulokhi womabili (a)
Isixazululo:
Sebenzisa umthetho wesibili kaNewton:
∑ F = ma
w B – f k = (m A + m B ) a
10 – 2.5 = (2 + 1) a
7.5 = 3 a
a = 7.5/3
a = 2.5 m/s 2
10. Isisindo sebhulokhi a = 30 kg, phumula endaweni evundlile exhunywe nebhulokhi B enesisindo esingu-10 kg phezu kwe-pulley. Kuyini ukusheshisa kwesistimu. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 ms -2.
Kwaziwa:
Isisindo sebhulokhi A (mA) = 30 kg
Isisindo sebhulokhi B (m B ) = 10 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
isisindo sebhulokhi B (w B ) = m B g = (10)(10) = 100 amaNewton
Okufunwayo: Ukusheshisa kwesistimu (a)
Isixazululo:
∑ F = ma
w B = (m A + m B ) a
100 = (30 + 10) a
100 = 40 a
a = 100/40
a = 2.5 m/s 2
