1. Erekitironi inokurumidziswa kubva pakuzorora kuburikidza nemusiyano we potential we 12 V. Chii chinonzi shanduko mu electric potential energy ye erekitironi?
Zvinozivikanwa:
Mutengo we erekitironi (e) = -1.60 x 10 -19 Coulomb
Simba remagetsi = voltage (V) = 12 Volts
Zvinodiwa: Kuchinja kwesimba remagetsi remaerekitironi (ΔPE)
Solution:
ΔPE = q V = (-1.60 x 10 -19 C)(12 V) = -19.2 x 10 -19 Joules
Chiratidzo chekusiya chinoratidza kuti simba rinogona kuderera.
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2. Maplate maviri akafanana anochajwa. Kupatsanurwa kwemaplate i2 cm uye hukuru hwesimba remagetsi pakati peplate i500 Volt/meter. Chii chinochinja simba ringangoitika reproton kana rakurumidza kubva paplate ine chaji yakanaka kuenda paplate ine chaji yakaipa.
Zvinozivikanwa:
Hukuru hwesimba remagetsi pakati pemaplate (E) = 500 Volt/mita
Kureba pakati pemaplate (s) = 2 cm = 0,02 m
Kuchaja paproton = +1.60 x 10 -19 Coulombs
Zvinodiwa: Kuchinja kwesimba remagetsi (ΔPE)
Solution:
Kugona kwemagetsi:
V = E s
V = (500 Volt/m)(0.02 m)
V = 10 Volt
Kuchinja kwesimba remagetsi:
ΔPE = q V
ΔPE = (1,60 x 10 -19 C)(10 V)
ΔPE = 16 x 10 -19 Joule
ΔPE = 1.6 x 10 -1 8 Joule
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3. Mapoinzi maviri anopatsanurwa nedaro re 10 cm. Chaja papoinzi A = +9 μC uye chaja papoinzi B = -4 μC. k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C. Chii chinochinja musimba remagetsi rinogoneka pakuchaja papoinzi B kana rikakurumidza kusvika papoinzi A?
Zvinozivikanwa:
Chaja A (q 1 ) = +9 μC = +9 x 10 −6 C
Chaja B (q 1 ) = -4 μC = -4 x 10 −6 C
k = 9 x 10 9 Nm 2 C −2
Nhambwe iri pakati pemari A neB (r) = 10 cm = 0.1 m = 10 -1 m
Zvinodiwa: Kuchinja kwesimba remagetsi (ΔEP)
Solution:
