1. Ma capacitor mana, C 1 = 2 μF, C 2 = 1 μF, C 3 = 3 μF, C 4 = 4 μF, akabatana mu series . Sarudza capacitance ye capacitor imwe chete ichava nemigumisiro yakafanana nekubatanidzwa.
Zvinozivikanwa:
Capacitor C 1 = 2 μ F
Capacitor C 2 = 1 μ F
Capacitor C 3 = 3 μ F
Capacitor C 3 = 4 μ F
Zvinodiwa: Capacitance yakaenzana
Solution:
Iyo capacitance yakaenzana:
1/C = 1/C 1 + 1/C 2 + 1/C 3 + 1/C 4
1/C = 1/2 + 1/1 + 1/3 + 1/4
1/C = 6/12 + 12/12 + 4/12 + 3/12
1/C = 25/12
C = 12/25
C = 0.48
Capacitance yakaenzana yemusanganiswa wese i0.48 μF.
2. Sarudza chaji iri pa capacitor C 1 kana musiyano uripo pakati peP neQ uri 12 Volts…
Zvinozivikanwa:
Capacitor C 1 = 1 0 μ F = 1 0 x 10 -6 F
Capacitor C 2 = 2 0 μ F = 2 0 x 10 -6 F
Musiyano ungangoitika (V) = 12 Volts
Zvinodiwa: kuchaja pa capacitor C 1 (Q 1 )
Solution:
Iyo capacitance yakaenzana:
1/C = 1/C 1 + 1/ C 2
1/C = 1/10 + 1/20 = 2/20 + 1/20 = 3/20
C = 20/3 μ F = (20/3) x 10 -6 F
Chaja yemagetsi pa capacitor yakaenzana:
Q = (C)(V) = (20/3)(12)(10 -6 ) = 80 x 10 -6 C
Q = 80 μC
Ma capacitor akabatanidzwa akatevedzana kuitira kuti chaji yemagetsi pama capacitor akaenzana = chaji yemagetsi pa capacitor C 1 = chaji yemagetsi pa capacitor C 2.
Chaja yemagetsi pa capacitor C 1 i80 μC.
3. Ma capacitor maviri, C 1 = 2 μF uye C 2 = 4 μF, akabatana akatevedzana. Ma capacitor anochajwa. Musiyano unogona kuitika pa capacitor C 1 i2 Volts. Chaja yemagetsi pa capacitor C 2 …
Zvinozivikanwa:
C apa c itor C 1 = 2 μ F = 2 x 10 -6 F
C apa c itor C 2 = 4 μ F = 4 x 10 -6 F
Musiyano unogona kuitika pa capacitor C 1 (V 1 ) = 2 Volts
Zvinodiwa : Chaja yemagetsi pa capacitor C2.
Solution:
Chaja yemagetsi pa capacitor C1 :
Mubvunzo 1 = C 1 V 1 = (2 x 10 -6 )(2) = 4 x 10 -6 C
Mubvunzo 1 = 4 μC
Ma capacitor akabatanidzwa akatevedzana kuitira kuti chaji yemagetsi pa capacitor C 1 = chaji yemagetsi pa capacitor C 2.
Chaji iri pa capacitor C2 i4 μC.
