Gurumuda Networks
1. Based on the figure below, if the radius of the curvature of the wire is 50 cm, determine the magnitude of the magnetic field at the center of curvature (at point 0, see figure below). (µo = 4π.10-7 Wb.A-1 m-1)
Known :
Radius (r) = 50 cm = 0.5 m
Electric current (I) = 1.5 Ampere
The vacuum permeability (µo) = 4π.10-7 Wb.A-1 m-1
Wanted: The magnitude of the magnetic field
3 Electromagnetic induction Induced EMF – Problems and Solutions
1. A coil replaced with another coil that has loops 2 times the initial loops and the rate of change of magnetic flux is constant. Determine the ratio of initial and final induced emf.
Known :
Initial loops (N) = 1
Final loops (N) = 2
The rate of change of initial magnetic flux (ΔØB / Δt) = the rate of change of final magnetic flux (ΔØB / Δt)
1. If R1 = 2 Ω, R2 = 4 Ω, R3 = 6 Ω, determine the electric current flows in the circuit below.
Known :
Resistor 1 (R1) = 2 Ω 
Resistor 2 (R2) = 4 Ω
Resistor 3 (R3) = 6 Ω
Source of emf 1 (E1) = 9 V
Source of emf 2 (E2) = 3 V
1. Based on the following equation of the fusion reaction, determine the energy produced in the fusion reaction!
Solution
1. Based on the figure below, determine the electric current through R1.
Known :
Resistor 1 (R1) = 4 Ω
Resistor 2 (R2) = 4 Ω
Resistor 3 (R3) = 8 Ω
Electric voltage (V) = 40 Volt
3 Mechanical waves (Frequency Period Wavelength The wave speed) – Problems and Solutions
1. Two corks are on the crests of the waves. Both move up and down over the surface of the sea 20 times in 4 seconds. If the distance of both corks is 100 cm and between them, there are two troughs and one crest, determine the wave frequency and the wave speed.
Known :
Both corks are at the tops of the waves and between the two corks, there are 2 troughs and 1 crest (see figure). So, there are two wavelengths between the two corks.
Diffraction by a single slit – problems and solutions
1. Light with wavelength of 500 nm passes through a slit 0.2 mm wide. The diffraction pattern on a screen 60 cm away. Determine the distance between the central maximum and the second minimum.
Known :
Youngs double-slit experiment – problems and solutions
1. d is the distance between 2 slits, L is the distance between the slit and the viewing screen, P2 is the distance between the second-order fringe and the center of the screen. Determine the wavelength of light (1 Å = 10-10 m).
Known :
Distance between two slits (d) = 1 mm = 1 x 10-3 m
Distance between slit and the viewing screen (L) = 1 m
Distance between the second-order fringe and the central fringe (P2) = 1 mm = 1 x 10-3 m
Order (n) = 2
1. A hollow cylindrical object (I = m R2) moves to roll without slipping up a rough inclined plane with an initial velocity of 10 m/s. The inclined plane has an elevation angle θ with tan θ = 0.75. If the gravitational acceleration g = 10 m.s-2, the velocity of the object is reduced to 5 m.s-1 then the distance on the inclined plane of the object is…
Known :
Moment of inertia of the hollow cylinder (I) = m R2
Elevation angle = θ, where tan θ = 0.75 = 75/100 = opp / adj
Sin θ = opp / hyp = 75/125 = 3/5 = 0.6
Acceleration due to gravity (g) = 10 m/s2
Initial velocity (vo) = 10 m/s
Final velocity (vt) = 5 m/s
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