Misalai 21 na Tambayoyin Rage Juriya
Ƙara Tsawon
1. Sanda mai kama da juna mai tsawon L, idan aka ja ta da ƙarfi F, tsayinta yana ƙaruwa da ∆L.
Don haka ƙaruwar tsayin ya zama 4 ΔL, girman ƙarfin tensile ɗin shine...
A. 1/4 F
B. 1/2 F
C. 2 F
D. 4 F
E. 16 F
Tattaunawa
An san cewa:
Ƙarfin tauri 1 (F1 ) = F
Ƙara tsawon 1 (∆L 1 ) = ∆L
Ƙara tsawon 2 (∆L 2 ) = 4 ∆L
Tambaya: Ƙarfin ja 2 (F 2 )
Amsa:
Tsarin dokar Hooke:
k = F / ΔL
Bayani: k = madaidaitan roba, F = ƙarfin tensile, ΔL = ƙaruwa a tsayi
Sandunan da aka yi amfani da su iri ɗaya ne don haka madaidaitan roba (k) iri ɗaya ne.
k 1 = k 2
F 1 / ∆L 1 = F 2 / ∆L 2
F / ΔL = F 2 / 4ΔL
F / 1 = F 2 / 4
F = F 2/4
F 2 = 4F
Amsar da ta dace ita ce D.
2. An shirya maɓuɓɓugan ruwa guda uku iri ɗaya tare da ma'aunin maɓuɓɓugar ruwa na 200 N/m kowanne kamar yadda aka nuna. Idan aka ba da nauyin gram 100 (hanzarin nauyi g = 10 m/s), ƙaruwar tsawon haɗuwar maɓuɓɓugar ruwa shine...
A. x = 0,50 cm 
B. x = 0,75 cm
C. x = 0,85 cm
D. x = 1,00 cm
E. x = 1,50 cm
Tattaunawa
An sani cewa :
Nauyin kaya (m) = gram 100 = 0,1 kg
k 1 = k 2 = k 3 = 200 N/m
w = mg = (0,1 kg)(10 m/s 2 ) = 1 kg m/s 2 = 1 Newton
An tambaya : Ƙara tsawon bazara gaba ɗaya 
?
Amsa :
Ƙayyade madaidaitan ma'aunin bazara mai maye gurbin
Bazara ta 2 (k)2) da kuma bazara ta 3 (k3) an shirya shi a layi ɗaya. Daidaitaccen ma'aunin bazara shine:
k p = k 2 + k 3 = 200 + 200 = 400 Nm −1
An shirya bazara ta 1 (k 1 ) da kuma bazarar maye gurbin layi ɗaya (k P ) a jere. Madaidaitan bazarar maye gurbin shine:
1/k s = 1/k p + 1/k 1 = 1/400 + 1/200 = 1/400 + 2/400 = 3/400
k s = 400/3 Nm −1
Daidaitaccen ma'aunin bazara don tsarin bazara mai layi ɗaya shine 400/3 Nm -1
Ƙayyade ƙaruwar tsawon bazara
Tsarin dokar Hooke:
= F / k = w / k
Karin tsawon bazara shine:
= w / k
= 1: 400/3 = 1 x 3/400 = 3/400 = mita 0,0075 = 0,75 cm
Amsar da ta dace ita ce B.
Tsarin bazara
3. A wani gwaji kan sassaucin maɓuɓɓuga, an samo bayanai kamar yadda aka nuna a teburin da ke ƙasa. Za a iya kammala da cewa ƙimar maɓuɓɓuga ita ce….
A. 1.002 N/m
B. 1.201 N/m
C. 1.225 N/m
D. 1.245 N/m
E. 1.250 N/m
Tattaunawa
Tsarin dokar Hooke:
Madawwamin bazara:
k = 0,98/0,0008 = 1,96/0,0016 = 2,94/0,0024 = 3,92/0,0032 = 1.225 N/m
Amsar da ta dace ita ce C.
4. An shirya maɓuɓɓugai uku kamar yadda aka nuna a cikin hoto mai zuwa. Idan maɓuɓɓugai masu tsayi k 1 = k 2 = 3 Nm −1 da k 3 = 6 Nm −1 , maɓuɓɓugai masu tsayi shine…..
A. 1 Nm-1
B. 3 Nm −1
C. 7,5 Nm −1
D. 12 Nm −1
E. 15 Nm −1
Tattaunawa
An san cewa:
Madaidaici na bazara 1 (k1 ) = madaidaici na bazara 2 (k2 ) = 3 Nm −1
Madaidaitan bazara 3 (k3 ) = 6 Nm −1
An tambaya: madaidaitan bazara (k)
Amsa:
An shirya bazara ta 1 (k 1 ) da bazara ta 2 (k 2 ) a layi ɗaya. Daidaitaccen ma'aunin bazara shine:
k p = k 1 + k 2 = 3 + 3 = 6 Nm −1
An shirya maɓuɓɓugar maye gurbin layi ɗaya (k P ) da bazara 3 (k 3 ) a jere. Maɓallin maɓuɓɓugar maye gurbin shine:
1/k s = 1/k p + 1/k 3 = 1/6 + 1/3 = 1/6 + 2/6 = 3/6
k s = 6/2 = 3 Nm −1
Daidaitaccen ma'aunin bazara na tsarin bazara mai kama da juna a sama shine 3 Nm −1
Amsar da ta dace ita ce B.
5. Ana jan maɓuɓɓugar ruwa mai tsawon L da kaya a jere kuma bayanan da aka samu suna kamar haka a cikin tebur mai zuwa. Dangane da bayanan tebur, za a iya kammala da cewa girman maɓuɓɓugar ruwa shine….
A. 300 Nm-1
B. 500 Nm -1
C. 600 Nm -1
D. 800 Nm -1
E. 1000 Nm -1
Tattaunawa
Tsarin dokar Hooke:
k = F /
Madawwamin bazara:
k = 10/0,02 = 20/0,04 = 30/0,06 = 40/0,08 = 500 Nm -1
Amsar da ta dace ita ce B.
6. Bayanan da ke cikin teburin gwaji mai zuwa sakamakon gwaji ne da ya shafi sassauƙan abubuwa. A cikin gwajin, kayan roba da aka yi amfani da su bututun ciki ne na babur. (g = 10 m/s 2 ). Dangane da teburin da ke sama, za a iya kammala da cewa kayan roba suna da madaidaicin roba na….
A. 122 N/m
B. 96 N/m
C. 69 N/m
D. 56 N/m
E. 40 N/m
Tattaunawa
Tsarin dokar Hooke :
k = F / = w / = mg /
Bayani: k = daidaitaccen sassauci, w = nauyi, m = nauyi, g = hanzartawa saboda nauyi, = ƙaruwa a tsawon roba
Madawwamin bazara:
k = 2/0,05 = 4/0,1 = 6/0,15 = 8/0,20 = 10/0,25 = 40 N/m
Amsar da ta dace ita ce E.
7. An shirya maɓuɓɓugai uku kamar yadda aka nuna a cikin hoton da ke ƙasa. Idan maɓuɓɓugai na bazara K1 = 4K, to ƙimar maɓuɓɓugai na bazara shine ....
A. 3/4K
B. 3K/4
C. 4K/3
D. 3K
E. 4K
Tattaunawa
Maɓuɓɓugan ruwa guda biyu da aka shirya a layi ɗaya. Daidaitaccen maɓuɓɓugan ruwa guda biyu da aka shirya a layi ɗaya shine:
k p = K + K = 2K
An shirya maɓuɓɓugai guda biyu a jere. Daidaiton maɓuɓɓugai na maɓuɓɓugai guda biyu da aka shirya a jere shine:
1/k s = 1/k p + 1/K 1 = 1/2K + 1/4K = 2/4K + 1/4K = 3/4K
k s = 4K/3
Daidaitaccen ma'aunin bazara na tsarin bazara da ke sama shine 4K/3
Amsar da ta dace ita ce C.
8. An rataye roba mai tsawon L da kaya ta yadda bayanan da aka samu za su kasance kamar yadda yake a cikin teburin. Dangane da teburin, za a iya kammala da cewa girman madaurin bazara shine….
A. 250 Nm-1
B. 360 Nm —1
C. 400 Nm —1
D. 450 Nm —1
E. 480 Nm —1
Tattaunawa
Tsarin dokar Hooke:
k = F / 
Madawwamin bazara:
k = 2/0,0050 = 3/0,0075 = 4/0,01 = 400 Nm -1
Amsar da ta dace ita ce C.
9. Ka lura da bayanan gwaji na nau'ikan tayoyin roba guda biyar A, B, C, D, da E waɗanda aka ja da ƙarfi F don tsawonsu ya ƙaru. Tayar roba mai ƙaramin madaidaitan maɓuɓɓuga ita ce…
Tattaunawa
Tsarin dokar Hooke:
k = F / Δx
Bayani: k = madaidaitan roba, F = ƙarfi, Δx = ƙaruwa a tsawon roba
Daidaiton sassaucin roba:
k A = F / Δx = 1 / 0,05 = 20 N/m
k B = F / Δx = 2 / 0,025 = 80 N/m
k C = F / Δx = 1 / 0,025 = 40 N/m
k D = F / Δx = 2 / 0,05 = 40 N/m
k E = F / Δx = 2 / 0,25 = 8 N/m
Amsar da ta dace ita ce E.
10. Daga gwajin da aka yi don tantance sassaucin roba ta amfani da robar taya, bayanan da aka samu suna kamar haka a cikin tebur mai zuwa. Za a iya kammala da cewa mafi girman ƙimar da ba ta canzawa ita ce gwajin….
Tattaunawa
Tsarin dokar Hooke:
k = F / Δx
Madawwamin bazara:
k A = 7/0,035 = 200 Nm -1
k B = 8/0,025 = 320 Nm -1
k C = 6/0,020 = Nm 300 -1
k D = 9/0,045 = 200 Nm -1
k E = 10/0,033 = 303 Nm -1
Mafi girman madaidaitan roba shine 320 Nm -1.
Amsar da ta dace ita ce B.
11. Jadawalin da ke ƙasa yana nuna alaƙar da ke tsakanin canjin kaya (ΔF) da ƙaruwar tsayi (ΔX), jadawalin da ke nuna ƙaramin ƙimar madaidaitan roba...
Tattaunawa
Tsarin dokar Hooke
k = F / Δx
Bayani:
Δx = ƙaruwa a tsayi, F = ƙarfi, k = madaidaitan roba
Daidaitaccen sassauci
k A = F / Δx = 1/8 = 0,125
k B = F / Δx = 8 / 3 = 2,7
k C = F / Δx = 6 / 6 = 1
k D = F / Δx = 3 / 5 = 0,6
k E = F / Δx = 2 / 4 = 0,5
Amsar da ta dace ita ce A.
12. Duba jadawalin dangantakar da ke tsakanin ƙarfi (F) da ƙaruwar tsayi (ΔX) a ƙasa! Wanne ne ke da mafi girman madaidaitan roba?
Tattaunawa
Daidaitaccen sassauci
k A = F / Δx = 50 / 10 = 5
k B = F / Δx = 50 / 0,1 = 500
k C = F / Δx = 5 / 0,1 = 50
k D = F / Δx = 500 / 0,1 = 5000
k E = F / Δx = 500 / 10 = 50
Amsar da ta dace ita ce D.
Makamashin Da Zai Iya Rage Makogwaro
13. Jadawalin (Fx) yana nuna alaƙar da ke tsakanin ƙarfi da ƙaruwar tsawon bazara. Girman ƙarfin da bazara ke da shi bisa ga jadawalin da ke sama shine...
A. 20 joules
B. 16 joules
C. 3,2 joules
D. 1,6 joules
E. 1,2 joules
Tattaunawa
An san cewa:
F = 40N
x = mita 0,08
Tambaya: Ƙarfin kuzarin bazara
Amsa:
Madawwamin bazara:
k = F / Δx = 40/0,08 = 500 N/m
Ƙarfin kuzarin bazara:
EP = 1/2 kx 2 = 1/2 (500)(0,08) = (250)(0,08) = Joules 20
Amsar da ta dace ita ce A.
14. Ana ba wa maɓuɓɓuga nauyi na kilogiram 2 kamar yadda aka nuna a cikin hoton da ke ƙasa. Idan maɓuɓɓugar ta sami ƙaruwa a tsawon 5 cm kuma saurin da aka samu saboda nauyi ya kai 10 ms -2 , to kuzarin da ke da ƙarfin maɓuɓɓugar ya...
A. 4,0 J
B. 3,0 J
C. 2,5 J
D. 1,0 J
E. 0,5 J
An sani cewa :
Ƙara tsayi (Δx) = 5 cm = mita 0,05
Saurin gudu saboda nauyi (g) = 10 m/s 2
Nauyin kaya (m) = 2 kg
Nauyin kaya (w) = mg = (2)(10) = 20 Newton
Tambaya : Ƙarfin roba mai yuwuwa?
An sani cewa :
Ƙara tsayi (Δx) = 5 cm = mita 0,05
Saurin gudu saboda nauyi (g) = 10 m/s 2
Nauyin kaya (m) = 2 kg
Nauyin kaya (w) = mg = (2)(10) = 20 Newton
Tambaya : Ƙarfin roba mai yuwuwa?
15. Don shimfiɗa maɓuɓɓugar ruwa mai tsawon santimita 5, ana buƙatar ƙarfin N20. Ƙarfin da za a iya samu daga maɓuɓɓugar ruwa idan ta miƙe santimita 10 shine…
A. Joule 2
B. 4 Joule
C. 20 Joule
D. 50 Joule
E. 100 Joule
Tattaunawa
An sani cewa :
Ƙara tsayi (Δx) = 5 cm = mita 0,05
Ƙarfi (F) = Newtons 20
Tambaya : Menene EP na bazara lokacin da bazara ta miƙe 10 cm?
Amsa :
Madawwamin bazara:
k = F / Δx = 20 / 0,05 = 400 N/m
Ƙarfin da za a iya samu daga bazara idan Δx = 10 cm = mita 0,1:
EP = ½ k Δx 2 = ½ (400)(0,1) 2 = (200)(0,01)
EP = Joule 2
Amsar da ta dace ita ce A.
Nauyin Load
16.
A. 6 N
B. 12 N
C. 30 N
D. 45 N
E. 60 N
Maɓuɓɓugan ruwa guda huɗu iri ɗaya, kowannensu yana da madaidaitan roba na 800 Nm −1 , an shirya su a jere da layi ɗaya (duba hoto). Nauyin da aka dakatar yana sa tsarin bazara ya sami ƙaruwa gabaɗaya na tsawon 5 cm. Nauyin nauyin w shine…
Tattaunawa
An sani cewa :
k 1 = k 2 = k 3 = k 4 = 800 N m −1
= 5 cm = 0,05 m
An tambaya : nauyin kaya (w)?
Amsa :
Ƙayyade madaidaitan ma'aunin bazara mai maye gurbin
Bazara ta 1 (k)1), bazara ta 2 (k2) da kuma bazara ta 3 (k3) an shirya shi a layi ɗaya. Daidaitaccen ma'aunin bazara shine:
k p = k 1 + k 2 + k 3 = 800 + 800 + 800 = 2400 Nm −1
An shirya maɓuɓɓugar maye gurbin layi ɗaya (k P ) da maɓuɓɓugar 4 (k 4 ) a jere. Maɓallin maɓuɓɓugar maye gurbin shine:
1/k s = 1/k p + 1/k 4 = 1/2400 + 1/800 = 1/2400 + 3/2400 = 4/2400
k s = 2400/4 = 600 Nm −1
Daidaitaccen ma'aunin bazara na tsarin bazara mai kama da juna a sama shine 600 Nm -1
Ƙayyade nauyin nauyin
Tsarin dokar Hooke:
F = ku ko w = k
Nauyin nauyin shine:
w = (600 Nm -1 )(0,05 m) = Newtons 30
Nauyin nauyin shine Newtons 30.
Amsar da ta dace ita ce C.
17. Maɓuɓɓugan ruwa guda huɗu iri ɗaya, kowannensu yana da madaidaitan roba na 1600 N/m, an shirya su a jere da layi ɗaya (duba hoto). Nauyin da aka dakatar yana sa tsarin bazara ya fuskanci ƙaruwa gaba ɗaya na tsawon 5 cm. Nauyin nauyin w shine….
A. 60 N
B. 120 N
C. 300 N
D. 450 N
E. 600 N
Tattaunawa
An sani cewa :
k 1 = k 2 = k 3 = k 4 = 1600 N m −1
= 5 cm = 0,05 m
An tambaya : nauyin kaya (w)?
Amsa :
Ƙayyade madaidaitan ma'aunin bazara mai maye gurbin
An shirya bazara ta 1 (k 1 ), bazara ta 2 (k 2 ) da bazara ta 3 (k 3 ) a layi ɗaya. Daidaitaccen ma'aunin bazara shine:
k P = k 1 + k 2 + k 3 = 1600 + 1600 + 1600 = 4800 Nm −1
An shirya maɓuɓɓugar maye gurbin layi ɗaya (k P ) da maɓuɓɓugar 4 (k 4 ) a jere. Maɓallin maɓuɓɓugar maye gurbin shine:
1/k s = 1/k p + 1/k 4 = 1/4800 + 1/1600 = 1/4800 + 3/4800 = 4/4800
k s = 4800/4 = 1200 Nm −1
Daidaitaccen ma'aunin bazara don tsarin bazara mai layi ɗaya shine 1200 Nm -1
Ƙayyade nauyin nauyin
Tsarin dokar Hooke:
F = ku ko w = k
Nauyin nauyin shine:
w = (1200 Nm -1 )(0,05 m) = Newtons 60
Nauyin nauyin shine Newtons 60.
Amsar da ta dace ita ce A.
Na roba da filastik
18. 
Duba jadawalin dangantakar da ke tsakanin ƙarfi ΔF da ƙaruwar tsayi Δx a kan wani marmaro da ke ƙasa!
Dangane da jadawalin, maɓuɓɓugar ruwa za ta ci gaba da kasancewa mai laushi a ƙarfin tauri na….
A. 0 zuwa 4 N
B. 0 zuwa 8 N
C. 0 zuwa 12 N
D. 8 N zuwa 12 N
E. 8 N zuwa 16 N
Tattaunawa
Maɓuɓɓugar ruwa za ta ci gaba da zama mai laushi idan dokar Hooke ta ci gaba da aiki a kanta. A fannin lissafi, dokar Hooke tana bayyana ta hanyar dabarar:
k = ΔF / Δx
Bayanin dabara:
k = madaidaitan roba, ΔF = ƙarfi, Δx = tsawon bazara
Dokar Hooke ta bayyana cewa rabon canjin ƙarfi (ΔF) zuwa canjin tsayi (Δx) na bazara koyaushe yana nan daram. Idan ƙimar k ta canza, dokar Hooke ba ta aiki ga bazara kuma wannan yana nuna cewa bazara ba ta sake yin laushi ba.
Ka lura da jadawalin da ke sama kuma ka fahimci lissafin da ke ƙasa.
k 1 = ΔF / Δx = 4/2 = 2
k 2 = ΔF / Δx = 8/4 = 2
k 3 = ΔF / Δx = 12/7 = 1,7
Madaidaitan bazara (k) yana nan har zuwa ƙarfin tensile na Newtons 8. Saboda haka, madaidaitan bazara zai ci gaba da kasancewa mai laushi a ƙarfin tensile na 0 zuwa 8 Newtons.
Amsar da ta dace ita ce B.
19. Jadawalin da ke ƙasa yana nuna alaƙar da ke tsakanin ƙaruwar tsayin Δx da ƙarfin ΔF na robar da aka ja da ƙarfi. Dangane da jadawalin, robar za ta canza halayenta na filastik lokacin da ƙarfi ya yi aiki akan robar...
A. 0 zuwa 2 N
B. 0 zuwa 4 N
C. 2 N zuwa 6 N
D. 4 N zuwa 8 N
E. 6 N zuwa 8 N
Tattaunawa
Roba zai ci gaba da zama mai laushi matuƙar dai mai laushi ya kasance mai tsabta. Idan mai laushi ya fara canzawa, robar za ta fara canzawa daga mai laushi zuwa roba. Mai laushi yana nufin cewa bayan an cire ƙarfin tauri, robar za ta koma siffarta ta asali. Akasin haka, filastik yana nufin cewa bayan an cire ƙarfin tauri, robar ba ta komawa siffarta ta asali ba.
Ka lura da jadawalin da ke sama kuma ka fahimci waɗannan lissafin:
k 1 = ΔF / Δx = 2/2 = 1
k 2 = ΔF / Δx = 4/4 = 1
k 3 = ΔF / Δx = 6/6 = 1
k 4 = ΔF / Δx = 7/8 = 0,87
k 4 = ΔF / Δx = 8/12 = 0,6
Roba zai canza ƙarfinsa idan aka yi amfani da ƙarfin Newtons 6 zuwa 8 a kansa. Idan ƙarfin ya fi Newtons 8, robar za ta karye.
20.
Duba jadawalin dangantakar da ke tsakanin ƙarfi ΔF da ƙaruwar tsayi Δx a kan wani marmaro da ke ƙasa!
Dangane da jadawalin, maɓuɓɓugar ruwa za ta ci gaba da kasancewa mai laushi a ƙarfin tauri na….
A. 0 zuwa 4 N
B. 0 zuwa 8 N
C. 0 zuwa 12 N
D. 8 N zuwa 12 N
E. 8 N zuwa 16 N
Tattaunawa
Maɓuɓɓugar ruwa za ta ci gaba da zama mai laushi idan dokar Hooke ta ci gaba da aiki a kanta. A fannin lissafi, dokar Hooke tana bayyana ta hanyar dabarar:
k = ΔF / Δx
Bayanin dabara:
k = madaidaitan roba, ΔF = ƙarfi, Δx = tsawon bazara
Dokar Hooke ta bayyana cewa rabon canjin ƙarfi (ΔF) zuwa canjin tsayi (Δx) na bazara koyaushe yana nan daram. Idan ƙimar k ta canza, dokar Hooke ba ta aiki ga bazara kuma wannan yana nuna cewa bazara ba ta sake yin laushi ba.
Ka lura da jadawalin da ke sama kuma ka fahimci lissafin da ke ƙasa.
k1 = ΔF / Δx = 4/2 = 2
k2 = ΔF / Δx = 8/4 = 2
k3 = ΔF / Δx = 12/7 = 1,7
Madaidaitan bazara (k) yana nan har zuwa ƙarfin tensile na Newtons 8. Saboda haka, madaidaitan bazara zai ci gaba da kasancewa mai laushi a ƙarfin tensile na 0 zuwa 8 Newtons.
Amsar da ta dace ita ce B.
21.
Jadawalin da ke ƙasa yana nuna alaƙar da ke tsakanin ƙaruwar tsayin Δx da ƙarfin ΔF na robar da aka ja da ƙarfi. Dangane da jadawalin, robar za ta canza halayenta na filastik lokacin da ƙarfi ya yi aiki a kanta...
A. 0 zuwa 2 N
B. 0 zuwa 4 N
C. 2 N zuwa 6 N
D. 4 N zuwa 8 N
E. 6 N zuwa 8 N
Tattaunawa
Roba zai ci gaba da zama mai laushi matuƙar dai mai laushi ya kasance mai tsabta. Idan mai laushi ya fara canzawa, robar za ta fara canzawa daga mai laushi zuwa roba. Mai laushi yana nufin cewa bayan an cire ƙarfin tauri, robar za ta koma siffarta ta asali. Akasin haka, filastik yana nufin cewa bayan an cire ƙarfin tauri, robar ba ta komawa siffarta ta asali ba.
Ka lura da jadawalin da ke sama kuma ka fahimci waɗannan lissafin:
k1 = ΔF / Δx = 2/2 = 1
k2 = ΔF / Δx = 4/4 = 1
k3 = ΔF / Δx = 6/6 = 1
k4 = ΔF / Δx = 7/8 = 0,87
k5 = ΔF / Δx = 8/12 = 0,6
Roba zai canza ƙarfinsa idan aka yi amfani da ƙarfin Newtons 6 zuwa 8 a kansa. Idan ƙarfin ya fi Newtons 8, robar za ta karye.
Amsar da ta dace ita ce E.
Daidaitaccen sassauci
22. Ka lura da bayanan gwaji na nau'ikan tayoyin roba guda biyar A, B, C, D da E waɗanda aka ja da ƙarfi F don tsawonsu ya ƙaru. Tayar roba mai ƙaramin madaidaitan ma'aunin bazara ita ce…
Tattaunawa
Tsarin dokar Hooke :
k = F / Δx
Bayani: k = madaidaitan elasticity, F = gaya, Δx = ƙaruwa a tsawon roba
Daidaiton sassaucin roba:
kA = F / Δx = 1 / 0,05 = 20 N/m
kB = F / Δx = 2 / 0,025 = 80 N/m
kC = F / Δx = 1 / 0,025 = 40 N/m
kD = F / Δx = 2 / 0,05 = 40 N/m
kE = F / Δx = 2 / 0,25 = 8 N/m
Amsar da ta dace ita ce E.
23. Daga gwajin da aka yi don tantance sassaucin roba ta amfani da robar taya, bayanan da aka samu kamar haka ne a cikin tebur mai zuwa. Za a iya kammala da cewa mafi girman ƙimar da ba ta canzawa ita ce gwajin….
Tattaunawa
Tsarin dokar Hooke:
k = F / Δx
Madawwamin bazara:
kA = 7/0,035 = 200 Nm-1
kB = 8/0,025 = 320 Nm-1
kC = 6/0,020 = 300 Nm-1
kD = 9/0,045 = 200 Nm-1
kE = 10/0,033 = 303 Nm-1
Mafi girman madaidaitan roba shine 320 Nm-1.
Amsar da ta dace ita ce B.
Tushen tambaya:
Tambayoyin Nazarin Fizik na Ƙasa ga Makarantar Sakandare ta Babbar Sakandare/Makarantar Sakandare ta Sana'a
