1. Isondo elingamamitha angu-1 ku-radius lishesha ngokulinganayo ku-2 rad/s 2 . Nquma ukusheshisa kwe-angular kanye nesivinini se-angular sesondo, ngemva kwemizuzwana emi-2.
Kwaziwa:
Irediyasi (r) = 1 imitha
Ukusheshisa kwe-angular (α ) = 2 rad/s 2
Okufunwayo: ukusheshisa kwe-angular kanye nesivinini se-angular ngemva kwemizuzwana emi-2.
Isixazululo:
(a) Ukusheshisa kwe-Angular ngemizuzwana emi-2
Ukusheshisa kwe-angular kuhlala njalo, ngakho-ke ngemva kwemizuzwana emi-2, ukusheshisa kwe-angular kwesondo kungama-rad angu-2/s 2.
(b) Isivinini se-Angular ngemizuzwana emi-2
Ukusheshisa kwe-angular 2 rad/s 2 kusho ukuthi ijubane le-angular landisa ama-radian angu-2/umzuzwana njalo ngomzuzwana o-1. Ngemva komzuzwana o-1, ijubane le-angular = ama-radian angu-2/umzuzwana. Ngemva kwemizuzwana emi-2, ijubane le-angular = ama-radian angu-4/umzuzwana.
2. Inhlayiya isheshisa ngokulinganayo kusukela ekuphumuleni kuya ku-60 rpm ngemizuzwana eyi-10. Thola ubukhulu bokusheshisa kwe-angular!
Kwaziwa:
Ijubane lokuqala le-angular (ω o ) = 0
Ijubane lokugcina le-angular ( ωt ) = 60 rpm = imijikelezo engu-60 / imizuzwana engu-60 = umjikelezo ongu-1 / isekhondi = ama-radians angu-6,28/ isekhondi
Isikhawu sesikhathi (t) = imizuzwana eyi-10
Okufunwayo: Ukusheshisa kwe-Angular ( α )
Isixazululo:
ω o = ijubane lokuqala le-angular, ω t = ijubane lokugcina le-angular, α = ukusheshisa kwe-angular, t = isikhawu sesikhathi, θ = i-angle.
ω t = ω o + α t
6.28 = 0 + α (10)
6.28 = 10 α
α = 6.28 / 10
α = 0.628 rad/s 2
Ubukhulu bokusheshisa kwe-angular = 0.628 rad/s 2
3. Into yehlisa ijubane kusuka kuma-rad angu-20/s kuya kuma-rad angu-10/s ngemizuzwana emi-4. Thola ubukhulu bokusheshisa kwe-angular!
Kwaziwa:
Isikhawu sesikhathi (t) = imizuzwana eyi-4
Ijubane lokuqala le-angular ( ω o ) = 20 rad/s
Ijubane lokugcina le-angular ( ω t ) = 10 rad/s
Okufunwayo : ubukhulu bokusheshisa kwe-angular (α )
Isixazululo:
ω t = ω o + α t
10 = 20 + α (4)
10 – 20 = 4 α
-10 = 4 α
α = -10 / 4
α = – 2.5 rad/s 2
Ubukhulu bokusheshisa kwe-angular bungu--2.5 rad/s 2. Uphawu olunegethivu lusho ukuthi into iyehla. Ukusheshisa = isivinini se-angular siyanda, ukusheshisa = isivinini se-angular siyancipha.
4. Into isheshiswa imizuzwana emi-2 kusukela ku-10 rad/s kuya ku-2 rad/s . 2. Thola i-engeli ezungezwe yinto!
Kwaziwa:
ijubane lokuqala le-angular ( ω o ) = 10 rad/s
ukusheshisa kwe-angular (α ) = 2 rad/s 2
isikhawu sesikhathi (t) = imizuzwana emi-2
Okufunwayo: i-engeli (θ)
Isixazululo:
θ = ω o + ½ α t 2
θ = (10)(2) + ½ (2)(2 2 )
θ = 20 + (1)(4) = 20 + 4
θ = ama-radian angu-24
5. Isondo lemoto lehla kusuka kuma-rad angu-20/s ukuze liphumule ngemva kwama-radian angu-20. Thola ubukhulu bokusheshisa kwesondo okune-angle!
Kwaziwa:
isivinini sokuqala se-angular ( ω o ) = 20 rad/s
isivinini sokugcina se-angular ( ωt ) = 0
I-engeli ( θ ) = ama-radian angu-20
Okufunwayo: ubukhulu bokusheshisa kwe-angular (α )
Isixazululo:
ω t 2 = ω o 2 + 2 α θ
0 = 20 2 + 2 α (20)
0 = 400 + 40 α
400 = – 40 α
α = – 400 / 40
α = – 10 rad/s 2
6. I-PQ yenduku enobude obungu-60 cm ijikeleza cishe iphuzu Q njenge-axis yokujikeleza kanye ne-PQ njenge-radius yendilinga. I-PQ yenduku isheshise kusukela ekuphumuleni kuya ku-0.3 rad/s 2 . Iyini ijubane eliqondile lephuzu P ku-t = imizuzwana eyi-10, uma isikhundla sokuqala se-angular singu-0.
Kwaziwa:
Ubude benduku ye-PQ = irediyasi yendilinga (r) = 60 cm = 60/100 m = 0.60 m
Isivinini sokuqala se-angular (ω o ) = 0 rad/s
Ukusheshisa kwe-angular (α) = 0.3 rad s -2
Isikhundla sokuqala se-angular (θ o ) = 0
Okufunwayo: Isivinini esiqondile (v) sephuzu P ku-t = imizuzwana eyi-10
Isixazululo:
Isivinini sokugcina se-angular ngemuva kwemizuzwana eyi-10:
ω t = ω o + α t = 0 rad/s + (0.3 rad s -2 )(10 s) = 3 rad/s
Isivinini sokugcina esiqondile ngemva kwemizuzwana eyi-10:
v = r ω = (0.6 m)(3 rad/s) = 1.8 m/s
7. Into ijikeleza ngesivinini sokuqala esingu-4 rad/s kanti ukusheshisa kwe-angular kungu-0.5 rad/s 2. Iyini ijubane lento ngemva kwemizuzwana emi-4.
Kwaziwa:
Isivinini sokuqala se-angular (ω o ) = 4 rad/s
Ukusheshisa kwe-angular (α) = 0.5 rad/s 2
Isikhawu sesikhathi (t) = imizuzwana eyi-4
Okufunwayo: Isivinini sento ngemva kwemizuzwana emi-4 (ω t )
Isixazululo:
ω t = ω o + α t
ω t = 4 + (0.5)(4)
ω t = 4 + 2
ω t = 6 rad/s
8. Iwashi lodonga elinobubanzi obuyi-10 cm linezinaliti ezintathu, ngayinye ukukhombisa amahora, imizuzu namasekhondi. Ukuqhathanisa inani lezindilinga zenaliti yehora: inaliti yemizuzu: inaliti yesibili.
A. 1: 3: 180
B. 1 : 12 : 720
C. 4 : 12 : 180
D. 4 : 12 : 720
Kwaziwa:
Ihora eli-1 = imizuzu engama-60
Amahora ayi-12 = (12)(imizuzu engama-60) = imizuzu engama-720
Ijubane le-angular lenaliti yehora = ukujikeleza oku-1 / amahora ayi-12 = ukujikeleza oku-1 / imizuzu engama-720
Ijubane le-angular lenaliti yemizuzu = ukujikeleza oku-1 / ihora eli-1 = ukujikeleza oku-1 / imizuzu engama-60
Isivinini se-angular senalithi yesibili = ukujikeleza okungu-1 / umzuzu ongu-1
Okufunwayo: Ukuqhathanisa inani lemijikelezo yenaliti yehora: inaliti yemizuzu: inaliti yesibili
Isixazululo:
Isibalo sokunyakaza okujikelezayo:
Isivinini se-angular = inani lokujikeleza / isikhawu sesikhathi
Inani lokujikeleza = isivinini se-angular x isikhawu sesikhathi
Ngesikhathi esifanayo, isibonelo, umzuzu owodwa, ukuthi zingaki izinguquko zenaliti yehora, inaliti yemizuzu, kanye nenaliti yesibili.
Inani lokuzungeza kwenaliti yehora = isivinini se-angular x isikhawu sesikhathi = (ukujikeleza okungu-1 / imizuzu engu-720) (umzuzu ongu-1) = ukuzungeza okungu-1/720
Inani lokuzungeza kwenaliti yemizuzu = isivinini se-angular x isikhawu sesikhathi = (ukujikeleza okungu-1 / imizuzu engama-60) (umzuzu ongu-1) = ukuzungeza okungu-1/60
Inani lokuzungeza kwenaliti yesibili = isivinini se-angular x isikhawu sesikhathi = (ukujikeleza okungu-1 / umzuzu ongu-1) (umzuzu ongu-1) = ukujikeleza okungu-1/1
Ukuqhathanisa inani lezinguquko:
Inani lokuzungeza kwenaliti yehora: inani lokuzungeza kwenaliti yemizuzu: inani lokuzungeza kwenaliti yesibili.
1/720 : 1/60 : 1/1
1/720 : 12/720 : 720/720
1:12:720
Impendulo efanele ngu-B.
9. Ibhola eliboshwe ngentambo. Ibhola liyajikeleziswa ukuze lihambe ngendlela eyindilinga ehambisana nobuso bomhlaba. Kulokhu kunyakaza, ibhola liyashesha ngoba…..
A. Ukungqubuzana komoya
B. Isisindo sebhola
C. Amandla okucindezela
Isixazululo:
Umthetho wesibili wokunyakaza kukaNewton uthi into iyasheshiswa uma kukhona amandla avelayo. Ibhola lixhunywe entanjeni futhi lapho intambo ijikeleza, nebhola liyajikeleza. Uma ibhola lijikeleza (ibhola lihamba ngendilinga), ibhola lidlula ekusheshisweni kwe-centripetal. Zonke izinto ezihambayo ziyindilinga ekusheshisweni kwe-centripetal. Ukusheshiswa kwe-centripetal kubangelwa amandla e-centripetal . Amandla e-centripetal kuleli cala amandla okucindezela.
Impendulo efanele ithi C.
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- Ukuguqula izinkinga zesampula zamayunithi e-engeli ngezixazululo
- Izinkinga zesampula zokufuduka kwe-angular kanye nokufuduka okuqondile kanye nezixazululo
- Izinkinga zesampula yejubane eliyindilinga kanye nesivinini esiqondile ngezixazululo
- Izinkinga zesampula zokusheshisa eziqondile kanye nokusheshisa okuqondile ngezixazululo
- Isampula yezinkinga zesampula yokunyakaza okujikelezayo okufanayo ngezixazululo
- Izinkinga zesampula yokusheshisa ye-Centripetal ngezixazululo
- Isampula yezinkinga zesampula zokunyakaza okujikelezayo okungalingani ngezixazululo
