1. Boima ba lebokose la 1 ke 2 kg, boima ba lebokose la 2 ke 4 kg, ho potlaka ha matla a khoheli ke 10 m/s 2 , boholo ba matla F ke 40 Newtons. Coefficient ea khohlano ea kinetic pakeng tsa lebokose la 1 le fatše ke 0.2 'me coefficient ea khohlano ea kinetic pakeng tsa lebokose la 2 le fatše ke 0.3. Fumana (a) Boholo le tataiso ea ho potlaka ha lebokose (b) Boholo ba matla a sebelisoang ke lebokose la 1 lebokoseng la 2 (F 12 ) le boholo ba matla a sebelisoang ke lebokose la 2 lebokoseng la 1 (F 21 ).

tharollo

Tse tsejoang:
Boima ba lebokose 1 (m1 ) = 2 kg
Boima ba lebokose 2 (m2 ) = 4 kg
Ho potlaka ha matla a khoheli (g) = 10 m/s 2 ,
Matla F = 40 Newton,
Koefficient ea khohlano ea kinetic pakeng tsa lebokose la 1 le fatše ( μ k1 ) = 0.2
Koefficient ea khohlano ea kinetic pakeng tsa lebokose la 2 le fatše ( μ k2 ) = 0.3
Boima ba lebokose 1 (w 1 ) = m 1 g = (2)(10) = 20 Newtons
Boima ba lebokose 2 (w 2 ) = m 2 g = (4)(10) = 40 Newtons
Matla a tloaelehileng a sebelisoang lebokoseng la 1 (N 1 ) = w 1 = 20 Newtons
Matla a tloaelehileng a sebelisoang lebokoseng la 2 (N 2 ) = w 2 = 40 Newtons
Matla a khohlano ea kinetic e sebelisitsoeng lebokoseng la 1 (f k1 ) = ( μ k1 )(N 1 ) = (0.2)(20) = 4 Newtons
Matla a khohlano ea kinetic e sebelisitsoeng lebokoseng la 2 (f k2 ) = ( μ k1 )(N 2 ) = (0.3)(40) = 12 Newtons
Tharollo:
(a) Boholo le tataiso ea lebelo la lebokose
ΣF = ma
F – f k1 – f k2 = (m 1 + m 2 ) a
40 – 4 – 12 = (2 + 4) a
24 = 6 a
a = 24/6
a = 4 m/s 2
Tsela ea ho potlakisa = tsela ea matla a letlooa = tsela e eang ka ho le letona.
(b) Boholo ba matla a sebelisoang ke lebokose la 1 lebokoseng la 2 (F 12 ) le boholo ba matla a sebelisoang ke lebokose la 2 lebokoseng la 1 (F 21 ).
Bala boholo ba F 12 :
ΣF = ma
F 12 – f k2 = (m 2 ) a
F 12 – 12 = (4)(4)
F 12 – 12 = 16
F 12 = 16 + 12
F 12 = 28 Newton
F 12 le F 21 ke matla a ketso le karabelo a sebetsang linthong tse fapaneng. F 12 le F 21 li na le boholo bo tšoanang le tataiso e fapaneng.
F 12 = 28 Li-Newton = F 21 = 28 Li-Newton.
[irp]
2. Boima ba lebokose la 1 ke 2 kg, boima ba lebokose la 2 ke 4 kg, ho potlaka ha matla a khoheli ke 10 m/s 2 , matla a F ke 40 N. Koefficient ya kgohlano ya kinetic pakeng tsa lebokose la 1 le mokatong ke 0.2 mme koefficient ya kgohlano ya kinetic pakeng tsa lebokose la 2 le mokatong ke 0.3. Fumana (a) Boholo le tataiso ya ho potlaka (b) Kgatelelo thapong e hokahanyang mabokose. Hlokomoloha boima ba thapo.

Tse tsejoang:
Boima ba lebokose 1 (m1 ) = 2 kg
Boima ba lebokose 2 (m2 ) = 4 kg
Ho potlaka ha matla a khoheli (g) = 10 m/s 2 ,
Matla F = 40 Newton,
Koefficient ea khohlano ea kinetic pakeng tsa lebokose la 1 le fatše ke 0.2 ( μ k1 ) = 0.2
Koefficient ea khohlano ea kinetic pakeng tsa lebokose la 2 le fatše ke 0.2 ( μ k2 ) = 0.3
Boima ba lebokose 1 (w 1 ) = m 1 g = (2)(10) = 20 Newtons
Boima ba lebokose 2 (w 2 ) = m 2 g = (4)(10) = 40 Newtons
Matla a tloaelehileng a sebelisoang lebokoseng la 1 (N 1 ) = w 1 = 20 Newtons
Matla a tloaelehileng a sebelisoang lebokoseng la 2 (N 2 ) = w 2 = 40 Newtons
Matla a khohlano ea kinetic e sebelisitsoeng lebokoseng la 1 (f k1 ) = ( μ k1 )(N 1 ) = (0.2)(20) = 4 Newtons
Matla a khohlano ea kinetic e sebelisitsoeng lebokoseng la 2 (f k2 ) = ( μ k1 )(N 2 ) = (0.3)(40) = 12 Newtons
Tharollo:
(a) boholo le tataiso ea ho potlaka
ΣF = ma
F – f k1 – f k2 = (m 1 + m 2 ) a
40 – 4 – 12 = (2 + 4) a
24 = 6 a
a = 24/6
a = 4 m/s 2
Boholo ba ho potlaka ke 4 m/s 2 , tataiso ea ho potlaka = tataiso ea matla a letlooa = ka ho le letona.
(b) Kgatelelo ka hara thapo
Matla a sebetsang lebokoseng la 1 ka lehlakoreng le otlolohileng ke kgatello ya 1 (T 1 ) e lebileng ka ho le letona le matla a kgatello ya kinetic ya 1 (f k1 ) e lebileng ka ho le letshehadi. Sebedisa molao wa bobedi wa Newton:
ΣF = ma
T 1 – f k1 = m 1 a
T 1 – 4 = (2)(4)
T 1 – 4 = 8
T 1 = 8 + 4 = 12 Newton
Matla a sebetsang lebokoseng la 2 ka lehlakoreng le otlolohileng ke kgatello ya 2 (T 2 ) ho ya ka letsohong le letshehadi le matla a kgatello ya kinetic ya 2 (f k2 ) ho ya ka letsohong le letona. Sebedisa molao wa bobedi wa Newton :
ΣF = ma
F – T 2 – f k2 = m 2 a
40 – T 2 – 12 = (4)(4)
28 – T 2 = 16
T 2 = 28 – 16 = 12 Newton
Kgatelelo e thapong e hokahanyang mabokose = T 1 = T 2 = T = 12 Newtons.
[irp]
[ID ea sephutheloana sa wpdm='493′]
- Boima le boima
- Matla a tloaelehileng
- Molao oa bobeli oa Newton oa ho sisinyeha
- Matla a khohlano
- Motsamao holim'a bokaholimo bo otlolohileng ntle le matla a khohlano
- Motsamao oa 'mele e 'meli ka lebelo le tšoanang holim'a sebaka se bataletseng se bataletseng ka matla a khohlano
- Motsamao sefofaneng se sekametseng ntle le matla a khohlano
- Motsamao sefofaneng se sekametseng ka thata ka matla a khohlano
- Motsamao ka lifting
- Motsamao oa 'mele o hokahaneng ka lithapo le li-pulley
- 'Mele e 'meli e nang le boholo bo tšoanang ba ho potlaka
- Ho potoloha mothapo o bataletseng - matla a motsamao o chitja
- Ho potoloha mothapo o kobehileng - matla a motsamao o chitja
- Motsamao o tšoanang ka selikalikoe se otlolohileng
- Matla a bohareng a motsamao o chitja o tšoanang