Matla a tloaelehileng - mathata le litharollo

Mathata a rarollotsoeng melaong ea Newton ea motsamao – Matla a tloaelehileng 

1. Ntho e phomotseng tafoleng, e bontšitsoeng setšoantšong se ka tlase. Boima ba ntho ke 1 kg. Ho potlaka ha matla a khoheli ke 9.8 m/s 2 . Fumana matla a tloaelehileng a sebelisoang nthong eo tafoleng.

Matla-a tloaelehileng-–-mathata-le-tharollo-1-1

Tse tsejoang:

Boima (m) = 1 kg

Ho potlaka ha matla a khoheli (g) = 9.8 m/s 2

Boima (w) = mg = (1 kg)(9.8 m/s 2 ) = 9.8 kg m/s 2 = 9.8 Newtons

Ho batloa: matla a tloaelehileng (N)

Tharollo:

Matla a tloaelehileng - mathata le litharollo 2

Ntho e phomotse tafoleng, kahoo matla a letlooa holim'a ntho ke lefela (molao oa pele kapa oa bobeli oa Newton). Boima ba ntho bo sebetsa ka ho otloloha ho ea tlase, ho ea bohareng ba Lefatše. Ho tlameha ho be le matla a mang holim'a ntho ho leka-lekanya matla a khoheli . Ntho e phomotseng tafoleng, e le hore tafole e sebelise matla ana a holimo. Matla a sebelisoang ke tafole hangata a bitsoa matla a tloaelehileng (N). Tloaelehileng e bolela ho ema ka ho sa feleng.

Khetha tataiso e yang hodimo e le tataiso e ntle ya y. Matla a sebele nthong ke:

∑ Fy = 0

N – w = 0

N = w

N = mg

N = 9.8 Newton

Matla a tloaelehileng nthong, a sebelisoang ke tafole ke 9.8 N ho ea holimo.

[irp]

2. Lintho tse peli tse lutseng tafoleng. Boima ba ntho 1 (m 1 ) = 1 kg, boima ba ntho 2 (m 2 ) = 2 kg, ho potlaka ka lebaka la matla a khoheli (g) = 9.8 m/s 2. Fumana boholo le tataiso ea matla a tloaelehileng a sebelisoang ke m 2 ho m 1 le matla a tloaelehileng a sebelisoang ke tafole ho m 2.

Matla a tloaelehileng - mathata le litharollo 3

tharollo

Matla a tloaelehileng - mathata le litharollo 4

Tse tsejoang:

Boima ba ntho 1 (m1 ) = 1 kg

Boima ba ntho 2 (m2 ) = 2 kg

Ho potlaka ha matla a khoheli (g) = 9.8 m/s 2

Boima ba ntho 1 (w 1 ) = m 1 g = (1)(9.8 m/s 2 ) = 9.8 kg m/s 2 = 9.8 Newtons

Boima ba ntho 2 (w 2 ) = m 2 g = (2)(9.8 m/s 2 ) = 19.6 kg m/s 2 = 19.6 Newtons

Ho batloa: N 1 le N 2

Tharollo:

(a) Matla a tloaelehileng a sebelisoang ke m 2 ho m 1 (N 1 )

N 1 = w 1 = 9.8 Newton

Tsela ea N1 e ea holimo.

(b) Matla a tloaelehileng a sebelisoang ke tafole ho m 2 (N 2 )

N 2 = w 1 + w 2 = 9.8 Newton + 19.6 Newton = 29.4 Newton

Tsela ea N2 e ea holimo.

[irp]

3. Ntho e phomotseng tafoleng. Boima ba ntho ke 2 kg, ho potlaka ka lebaka la matla a khoheli ke 9.8 m/s 2 . Boholo ba matla F ke 10 Newtons. Fumana boholo le tataiso ea matla a tloaelehileng a sebelisoang ke tafole holim'a ntho eo.

Matla a tloaelehileng - mathata le litharollo 5

tharollo

Matla a tloaelehileng - mathata le litharollo 6

Tse tsejoang:

Boima ba ntho (m) = 2 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 9.8 m/s 2

Boima (w) = mg = (2 kg)(9.8 m/s 2 ) = 19.6 kg m/s 2 = 19.6 Newtons

Matla F (F) = 10 Newton

Ho batloa : boholo le tataiso ea matla a tloaelehileng (N)

Tharollo:

tataiso ea matla a tloaelehileng e ea holimo.

Boholo ba matla a tloaelehileng:

∑ F = 0

N – F – w = 0

N = F + w

N = 10 Newtons + 20 Newtons

N = 30 Newton

[irp]

4. Ntho e phomotseng tafoleng. Boima ba ntho ke 1 kg, ho potlaka ka lebaka la matla a khoheli ke 9,8 m/s 2 , matla F 1 ke 10 N mme matla F 2 ke 20 N. Fumana boholo le tataiso ea matla a tloaelehileng a sebelisoang ke tafole nthong eo. g = 9.8 m/s 2

Matla a tloaelehileng - mathata le litharollo 7

tharollo

Matla a tloaelehileng - mathata le litharollo 8

Tse tsejoang:

Boima (m) = 1 kg

Ho potlaka ha matla a khoheli (g) = 9.8 m/s 2

Boima (w) = mg = (1 kg)(9.8 m/s 2 ) = 9.8 kg m/s 2 = 9.8 Newtons

F 1 = 10 Newton

F 2 = 20 Newton

Ho batloa: boholo le tataiso ea matla a tloaelehileng (N)

Tharollo:

Tsela eo matla a tloaelehileng a lebang ho yona e ya hodimo.

Boholo ba matla a tloaelehileng:

∑ F = 0

N – F 2 – w + F 1 = 0

N = F 2 + w – F 1

N = 20 Newtons + 9.8 Newtons – 10 Newtons

N = 19.8 Newton

[irp]

5. Boima ba ntho (m) = 2 kg, ho potlaka ha matla a khoheli (g) = 9.8 m/s 2 , sekhutlo = 30 o . Fumana boholo le tataiso ea matla a tloaelehileng a sebelisoang nthong eo.

Matla a tloaelehileng - mathata le litharollo 9

Tharollo:

Matla a tloaelehileng - mathata le litharollo 10

w ke boima, w x ke karolo e rapameng ea boima, w y ke karolo e otlolohileng ea boima, N ke matla a tloaelehileng.

Tse tsejoang:

boima (m) = 2 kg

ho potlaka ha matla a khoheli (g) = 9.8 m/s 2

boima (w) = mg = (2 kg)(9.8 m/s 2 ) = 19.6 kg m/s 2 = 19.6 Li-Newton

w x = w sin 60 o = (19.6 N)(0.5) √ 3 = 9.8 √ 3 Li-Newton

w y = w cos 60 = (19.6 N)(0.5) = 9.8 Newton

Ho batloa: matla a tloaelehileng (N)

Tharollo:

∑ F = 0

N – w y = 0

N = w y

N = 9.8 Newton

[irp]

[ID ea sephutheloana sa wpdm='467′]

  1. Boima le boima
  2. Matla a tloaelehileng
  3. Molao oa bobeli oa Newton oa ho sisinyeha
  4. Matla a khohlano
  5. Ho sisinyeha holim'a bokaholimo bo otlolohileng ntle le matla a khohlano
  6. Motsamao oa 'mele e 'meli e nang le lebelo le tšoanang holim'a bokaholimo bo bataletseng bo bataletseng ka matla a khohlano
  7. Ho sisinyeha ha sefofane se sekametseng ntle le matla a khohlano
  8. Motsamao sefofaneng se sekametseng ka thata ka matla a khohlano
  9. Motsamao ka lifting
  10. Motsamao oa 'mele o hokahantsoe ka lithapo le li-pulleys
  11. 'Mele e 'meli e nang le boholo bo tšoanang ba ho potlaka
  12. Ho potoloha mothapo o bataletseng - matla a motsamao o chitja
  13. Ho potoloha mothapo o kobehileng - matla a motsamao o chitja
  14. Motsamao o tšoanang ka selikalikoe se otlolohileng
  15. Matla a bohareng a motsamao o chitja o tšoanang

Leave a Comment