Mathata a rarollotsoeng melaong ea Newton ea motsamao – Matla a tloaelehileng
1. Ntho e phomotseng tafoleng, e bontšitsoeng setšoantšong se ka tlase. Boima ba ntho ke 1 kg. Ho potlaka ha matla a khoheli ke 9.8 m/s 2 . Fumana matla a tloaelehileng a sebelisoang nthong eo tafoleng.

Tse tsejoang:
Boima (m) = 1 kg
Ho potlaka ha matla a khoheli (g) = 9.8 m/s 2
Boima (w) = mg = (1 kg)(9.8 m/s 2 ) = 9.8 kg m/s 2 = 9.8 Newtons
Ho batloa: matla a tloaelehileng (N)
Tharollo:

Ntho e phomotse tafoleng, kahoo matla a letlooa holim'a ntho ke lefela (molao oa pele kapa oa bobeli oa Newton). Boima ba ntho bo sebetsa ka ho otloloha ho ea tlase, ho ea bohareng ba Lefatše. Ho tlameha ho be le matla a mang holim'a ntho ho leka-lekanya matla a khoheli . Ntho e phomotseng tafoleng, e le hore tafole e sebelise matla ana a holimo. Matla a sebelisoang ke tafole hangata a bitsoa matla a tloaelehileng (N). Tloaelehileng e bolela ho ema ka ho sa feleng.
Khetha tataiso e yang hodimo e le tataiso e ntle ya y. Matla a sebele nthong ke:
∑ Fy = 0
N – w = 0
N = w
N = mg
N = 9.8 Newton
Matla a tloaelehileng nthong, a sebelisoang ke tafole ke 9.8 N ho ea holimo.
[irp]
2. Lintho tse peli tse lutseng tafoleng. Boima ba ntho 1 (m 1 ) = 1 kg, boima ba ntho 2 (m 2 ) = 2 kg, ho potlaka ka lebaka la matla a khoheli (g) = 9.8 m/s 2. Fumana boholo le tataiso ea matla a tloaelehileng a sebelisoang ke m 2 ho m 1 le matla a tloaelehileng a sebelisoang ke tafole ho m 2.

tharollo

Tse tsejoang:
Boima ba ntho 1 (m1 ) = 1 kg
Boima ba ntho 2 (m2 ) = 2 kg
Ho potlaka ha matla a khoheli (g) = 9.8 m/s 2
Boima ba ntho 1 (w 1 ) = m 1 g = (1)(9.8 m/s 2 ) = 9.8 kg m/s 2 = 9.8 Newtons
Boima ba ntho 2 (w 2 ) = m 2 g = (2)(9.8 m/s 2 ) = 19.6 kg m/s 2 = 19.6 Newtons
Ho batloa: N 1 le N 2
Tharollo:
(a) Matla a tloaelehileng a sebelisoang ke m 2 ho m 1 (N 1 )
N 1 = w 1 = 9.8 Newton
Tsela ea N1 e ea holimo.
(b) Matla a tloaelehileng a sebelisoang ke tafole ho m 2 (N 2 )
N 2 = w 1 + w 2 = 9.8 Newton + 19.6 Newton = 29.4 Newton
Tsela ea N2 e ea holimo.
[irp]
3. Ntho e phomotseng tafoleng. Boima ba ntho ke 2 kg, ho potlaka ka lebaka la matla a khoheli ke 9.8 m/s 2 . Boholo ba matla F ke 10 Newtons. Fumana boholo le tataiso ea matla a tloaelehileng a sebelisoang ke tafole holim'a ntho eo.

tharollo

Tse tsejoang:
Boima ba ntho (m) = 2 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 9.8 m/s 2
Boima (w) = mg = (2 kg)(9.8 m/s 2 ) = 19.6 kg m/s 2 = 19.6 Newtons
Matla F (F) = 10 Newton
Ho batloa : boholo le tataiso ea matla a tloaelehileng (N)
Tharollo:
tataiso ea matla a tloaelehileng e ea holimo.
Boholo ba matla a tloaelehileng:
∑ F = 0
N – F – w = 0
N = F + w
N = 10 Newtons + 20 Newtons
N = 30 Newton
[irp]
4. Ntho e phomotseng tafoleng. Boima ba ntho ke 1 kg, ho potlaka ka lebaka la matla a khoheli ke 9,8 m/s 2 , matla F 1 ke 10 N mme matla F 2 ke 20 N. Fumana boholo le tataiso ea matla a tloaelehileng a sebelisoang ke tafole nthong eo. g = 9.8 m/s 2

tharollo

Tse tsejoang:
Boima (m) = 1 kg
Ho potlaka ha matla a khoheli (g) = 9.8 m/s 2
Boima (w) = mg = (1 kg)(9.8 m/s 2 ) = 9.8 kg m/s 2 = 9.8 Newtons
F 1 = 10 Newton
F 2 = 20 Newton
Ho batloa: boholo le tataiso ea matla a tloaelehileng (N)
Tharollo:
Tsela eo matla a tloaelehileng a lebang ho yona e ya hodimo.
Boholo ba matla a tloaelehileng:
∑ F = 0
N – F 2 – w + F 1 = 0
N = F 2 + w – F 1
N = 20 Newtons + 9.8 Newtons – 10 Newtons
N = 19.8 Newton
[irp]
5. Boima ba ntho (m) = 2 kg, ho potlaka ha matla a khoheli (g) = 9.8 m/s 2 , sekhutlo = 30 o . Fumana boholo le tataiso ea matla a tloaelehileng a sebelisoang nthong eo.

Tharollo:

w ke boima, w x ke karolo e rapameng ea boima, w y ke karolo e otlolohileng ea boima, N ke matla a tloaelehileng.
Tse tsejoang:
boima (m) = 2 kg
ho potlaka ha matla a khoheli (g) = 9.8 m/s 2
boima (w) = mg = (2 kg)(9.8 m/s 2 ) = 19.6 kg m/s 2 = 19.6 Li-Newton
w x = w sin 60 o = (19.6 N)(0.5) √ 3 = 9.8 √ 3 Li-Newton
w y = w cos 60 = (19.6 N)(0.5) = 9.8 Newton
Ho batloa: matla a tloaelehileng (N)
Tharollo:
∑ F = 0
N – w y = 0
N = w y
N = 9.8 Newton
[irp]
[ID ea sephutheloana sa wpdm='467′]
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