Mathata a rarollotsoeng melaong ea Newton ea motsamao – molao oa bobeli oa Newton oa motsamao
1. Ntho e boima ba 1 kg e potlakisitsoeng ka lebelo le sa fetoheng la 5 m/s 2 . Hakanya matla a letlooa a hlokahalang ho potlakisa ntho eo.
Tse tsejoang:
Boima (m) = 1 kg
Ho potlaka (a) = 5 m/s 2
Ho batloa : matla a letlooa (∑F)
Tharollo:
Re sebelisa molao oa bobeli oa Newton ho fumana matla a marang-rang.
∑ F = ma
∑ F = (1 kg)(5 m/s 2 ) = 5 kg m/s 2 = 5 Newtons
2. Boima ba ntho = 1 kg, matla a letlooa ∑F = 2 Newtons. Fumana boholo le tataiso ea ho potlaka ha ntho….
Tse tsejoang:
Boima (m) = 1 kg
Matla a letlooa (∑F) = 2 Newton
Ho batloa : Boholo le tataiso ea ho potlaka (a)
Tharollo:
a = ∑F / m
a = 2/1
a = 2 m/s 2
Tsela ea ho potlakisa = tsela ea matla a letlooa (∑F)
3. Boima ba ntho = 2 kg, F 1 = 5 Newtons, F 2 = 3 Newton. Boholo le tataiso ea ho potlaka ke…
Tse tsejoang:
Boima (m) = 2 kg
F 1 = 5 Newton
F 2 = 3 Newton
Ho batloa: Boholo le tataiso ea ho potlaka (a)
Tharollo:
matla a letlooa:
∑ F = F 1 – F 2 = 5 – 3 = 2 Newton
Boholo ba ho potlaka ha lebelo:
a = ∑F / m
a = 2/2
a = 1 m/s 2
Tsela ea ho potlakisa = tsela ea matla a letlooa = tsela ea F 1
4. Boima ba ntho = 2 kg, F 1 = 10 Newtons, F 2 = 1 Newton. Boholo le tataiso ea ho potlaka ke…
Tse tsejoang:
Boima (m) = 2 kg
F 2 = 1 Newton
F 1 = 10 Newton
F 1x = F 1 cos 60 o = (10)(0.5) = 5 Newtons
Ho batloa : Boholo le tataiso ea ho potlaka (a)
Tharollo:
Matla a marang-rang:
∑ F = F 1x – F 2 = 5 – 1 = 4 Newton
Boholo ba ho potlaka ha lebelo:
a = ∑F / m
a = 4/2
a = 2 m/s 2
Tsela ea ho potlakisa = tsela ea matla a letlooa = tsela ea F 1x
5. F 1 = 10 Newtons, F 2 = 1 Newton, m 1 = 1 kg, m 2 = 2 kg. Boholo le tataiso ya ho potlaka ke…
Tse tsejoang:
Boima ba 1 (m1 ) = 1 kg
Boima ba 2 (m2 ) = 2 kg
F 1 = 10 Newton
F 2 = 1 Newton
Ho batloa : Boholo le tataiso ea ho potlaka (a)
Tharollo:
Matla a marang-rang:
∑ F = F 1 – F 2 = 10 – 1 = 9 Newton
Boholo ba ho potlaka ha lebelo:
a = ∑F / (m 1 + m 2 )
a = 9 / (1 + 2)
a = 9/3
a = 3 m/s 2
Tsela ea ho potlakisa = tsela ea matla a letlooa = tsela ea F 1
6.
Sekotwana sa boima ba 40-kg se potlakisang ka matla a 200 N. Ho potlakisa sekotwana ke 3 m/ s 2. Fumana boholo ba matla a khohlano a fumanwang ke sekotwana.
A. 15 N
B. 40 N
C. 43 N
D. 80 N
Tse tsejoang:
Boima (m) = 40 kg
Matla (F) = 200 N
Ho potlaka (a) = 3 m/s 2
Ho batloa: Matla a khohlano (F g )
Tharollo:
Tekanyo ea molao oa bobeli oa Newton oa motsamao
∑ F = ma
∑ F = matla a letlooa, m = boima, a = ho potlaka
Tsela ea matla F e lebile ka ho le letona, tsela ea matla a khohlano e lebile ka ho le letšehali (tsela ea matla a khohlano e fapane le tsela ea motsamao oa ntho).
Khetha ho le letona e le ntle le ho le letšehali e le mpe.
∑ F = ma
F – F g = ma
200 – F g = (40)(3)
200 – F g = 120
F g = 200 – 120
F g = 80 Newton
Karabo e nepahetseng ke D.
7. Boloko A e nang le boima ba digrama tse 100 e behe ka hodima boloko B e nang le boima ba digrama tse 300, ebe boloko B e sutumelletswa ka matla a 5 N hodimo ka ho otloloha. Fumana matla a tlwaelehileng a sebediswang ke boloko B ho boloko A.
A. 1 N
B. 1.25 N
C. 2 N
D. 3 N
Tse tsejoang:
Matla (F) = 5 Newton
Boima ba boloko A (m A ) = digrama tse 100 = 0.1 kg
Boima ba boloko B (m B ) = digrama tse 300 = 0.3 kg
Ho potlaka ha matla a khoheli (g) = 10 m/s 2
Boima ba boloko A (w A ) = (0.1 kg)(10 m/s 2 ) = 1 kg m/s 2 = 1 Newton
Boima ba boloko B (w B ) = (0.3 kg)(10 m/s 2 ) = 3 kg m/s 2 = 3 Newtons
Ho batloa: Matla a tloaelehileng a sebelisoang ke boloko B ho thibela A
Tharollo:
Ho na le matla a 'maloa a sebetsang holim'a li-block ka bobeli, joalo ka ha ho bontšitsoe setšoantšong.
F = matla a sutumelletsang (ketso hodima boloko B)
w A = boima ba boloko A (ketso holim'a boloko A)
w B = boima ba boloko B (sebetsa hodima boloko B)
N A = matla a tloaelehileng a sebelisoang ke boloko B holim'a boloko A (Etsa joalo ka boloko A)
N A ' = matla a tloaelehileng a sebelisoang ke boloko A holim'a boloko B (Etsa ketso holim'a boloko B)
Sebelisa molao oa bobeli oa Newton oa motsamao holim'a li-block ka bobeli:
∑ F = ma
F – w A – w B + N A – N A ' = (m A + m B ) a
N A le N A ke matla a karabelo ya ketso a nang le boholo bo tshwanang empa a fapane ka lehlakoreng kahoo a tloswa ho equation.
F – w A – w B = (m A + m B ) a
5 – 1 – 3 = (0.1 + 0.3) a
5 – 4 = (0.4) a
1 = (0.4) a
a = 1/0.4
a = 2.5 m/s 2
Sebelisa molao oa bobeli oa Newton oa ho sisinyeha holim'a boloko A:
∑ F = ma
N A – w A = m A a
N A – 1 = (0.1)(2.5)
NA – 1 = 0.25
NA = 1 + 0.25
NA = 1.25 Newtons
Karabo e nepahetseng ke B.
8. Ntho e boima ba 4 N e tshehetswang ke thapo le pulley. Matla a 2 N a sebetsa hodima boloko le pheletsong e nngwe ya thapo e hulwang ke matla a 9 N. Fumana hore na matla a letlowa a sebetsa jwang nthong ya X.
A. 3 N ho ea holimo
B. 4 N ho ea tlase
C. 9 N ho ea holimo
D. 9 N ho ea tlase
Tse tsejoang:
Boima ba X (w X ) = 4 Newton
Matla a ho hula (F x ) = 2 Newton
Matla a kgatello (F T ) = 9 Newtons
Ho batloa: Matla a marang-rang a sebetsa nthong
Tharollo:
Matla a holimo a otlolohileng a sebetsang nthong
Matla a kgatello a na le boholo bo lekanang dikarolong tsohle tsa thapo. Kahoo matla a kgatello ke 9 N.
Matla a theohelang a otlolohileng a sebetsang hodima ntho
Ho na le matla a mabeli a sebetsang nthong ea X 'me matla ka bobeli a theohela tlase ka ho otloloha, karolo e bataletseng ea boima ba w x le karolo e bataletseng ea matla F x.
Ketso ea matla a netweke nthong eo
F T – w X – F x = 9 – 4 – 2 = 9 – 6 = 3
Matla a letlooa a sebetsang nthong X ke li-Newton tse 3, a phahame ka holimo.
Karabo e nepahetseng ke A.
9. Ntho e phomotseng qalong hodima bokahodimo bo boreleli bo bataletseng. Matla a 16 N a sebetsa hodima ntho eo kahoo ntho e potlaka ka lebelo la 2 m/s 2 . Haeba ntho e le nngwe e phomotseng hodima bokahodimo bo bataletseng bo bataletseng kahoo matla a kgohlano a sebetsa hodima ntho eo ke 2 N, jwale fumana hore na matla a tshwanang a 16 N a sebetsa hodima ntho eo.
A. 1.75 m/s 2
B. 1.50 m/s 2
C. 1.00 m/s 2
D. 0.88 m/s 2
Tse tsejoang:
Matla (F) = 16 Newtons = 16 kg m/s 2
Ho potlaka (a) = 2 m/s 2
Matla a khohlano (F fric ) = 2 Li-Newton = 2 kg m/s 2
Ho Batloa: Ho potlaka ha ntho?
Tharollo:
Boreleli bo bataletseng bo otlolohileng (ha ho na matla a khohlano):
∑F = ma
F = ma
16 = (m) 2
m = 16 / 2
m = 8 kg
Boima ba ntho eo ke lik'hilograma tse 8.
Bokaholimo bo bataletseng bo sa tsitsang (ho na le matla a khohlano):
∑F = ma
F – F fric = ma
16 – 2 = 8 a
14 = 8 a
a = 14/8
a = 1.75 m/s 2
Ho potlaka ha ntho ke 1.75 m/s 2.
Karabo e nepahetseng ke A.
10. Tom le Andrew ba sutumelletsa ntho fatše le boreleli. Tom o sutumelletsa ntho ka matla a 5.70 N. Haeba boima ba ntho e le 2.00 kg mme lebelo le bonoang ke ntho e le 2.00 ms -2 , joale fumana boholo le tataiso ea ketso ea matla ke Tom.
A. 1.70 N mme tataiso ya yona e fapane le kgatello e entsweng ke Andre.w
B. 1.70 N le tataiso ea eona li tšoana le matla a entsoeng ke Andrew
C. 2.30 N mme tataiso ya yona e fapane le kgatello e entsweng ke Andrew.
D. 2.30 N le tataiso ea eona li tšoana le matla a entsoeng ke Andrew.
Tse tsejoang:
Matla a sutumelletsang a sebetsoang ke Andrew (F 1 ) = 5.70 Newton
Boima ba ntho (m) = 2.00 kg
Ho potlaka (a) = 2.00 m/s 2
Ho batloa: Boholo le tataiso ea matla a sebelisoang ke Tom (F 2 )?
Tharollo:
Sebelisa molao oa bobeli oa Newton oa motsamao:
∑ F = ma
F 1 + F 2 = ma
5.70 + F 2 = (2)(2)
5.70 + F 2 = 4
F 2 = 4 – 5.70
F 2 = – 1.7 Newton
Letšoao la ho tlosa le bontšitse hore (F 2 ) le fapane le ketso ea Andrew ea ho sutumelletsa matla (F 1 ).
Karabo e nepahetseng ke A.
11. Haeba boima ba boloko bo tshwana, ke setshwantsho sefe se bontshang lebelo le lenyenyane ka ho fetisisa?
tharollo
Matla a nete A:
ΣF = 4 N + 2 N – 3 N = 6 N – 3 N = 3 Newtons, ka ho le letshehadi
Matla a letlooa B:
ΣF = 2 N + 3 N – 4 N = 5 N – 4 N = 1 Newtons, ka ho le letona
Matla a nete C:
ΣF = 4 N + 3 N – 2 N = 7 N – 2 N = 5 Newtons, ka ho le letona
Matla a nete D:
ΣF = 3 N + 4 N + 2 N = 9 Newtons, ka ho le letona
Tekanyo ea molao oa bobeli oa Newton:
ΣF = ma
a = ΣF / m
a = ho potlaka, ΣF = matla a letlooa, m = boima
Ho latela foromo e ka hodimo, ho potlakisa (a) ho lekana ka ho toba le matla a letlowa (ΣF) mme ho lekana ka tsela e fapaneng le boima (m). Haeba boima ba ntho bo tshwana, ha matla a hlahang a le maholo, ho potlakisa ho le hoholo kapa ha matla a hlahang a le manyane, ho potlakisa ho le honyenyane.
Ho latela palo e ka holimo, matla a manyane ka ho fetisisa a letlooa ke 1 Newton kahoo ho potlakisa le hona ke ho honyenyane ka ho fetisisa.
Karabo e nepahetseng ke B.
12. Matla a mang a sebetsa nthong e boima ba 20 kg, joalo ka ha ho bontšitsoe setšoantšong se ka tlase.
Fumana lebelo la ntho.
Tse tsejoang:
Boima ba ntho (m) = 20 kg
Matla a marang-rang (ΣF) = 25 N + 30 N – 15 N = 40 N
Ho batloa: Ho potlakisa ntho
Tharollo:
Ho potlakisa ha ntho ho balwa ho sebediswa equation ya molao wa bobedi wa Newton:
ΣF = ma
a = ΣF / m = 40 N / 20 kg = 2 N/kg = 2 m/s 2
13. Ke polelo efe e ka tlase e hlalosang molao oa boraro oa Newton?
(1) Bapalami ba ile ba sutumelletsa pele ha bese e roba brake ka tshohanyetso
(2) Libuka tse pampiring ha li oe ha pampiri e huloa kapele
(3) Ha o bapala skateboard ha leoto le sutumelletsa fatshe morao, skateboard e tla thellela pele
(4) Li- ars li sutumelletsoa morao, likepe li ea pele
Tharollo:
(2) Molao oa pele oa Newton
(3) Molao oa boraro oa Newton
(4) Molao oa boraro oa Newton
[ID ea sephutheloana sa wpdm='470′]
- Boima le boima
- Matla a tloaelehileng
- Molao oa bobeli oa Newton oa ho sisinyeha
- Matla a khohlano
- Ho sisinyeha holim'a bokaholimo bo otlolohileng ntle le matla a khohlano
- Motsamao oa 'mele e 'meli e nang le lebelo le tšoanang holim'a bokaholimo bo bataletseng bo bataletseng ka matla a khohlano
- Ho sisinyeha ha sefofane se sekametseng ntle le matla a khohlano
- Motsamao sefofaneng se sekametseng ka thata ka matla a khohlano
- Motsamao ka lifting
- Motsamao oa 'mele o hokahantsoe ka lithapo le li-pulleys
- 'Mele e 'meli e nang le boholo bo tšoanang ba ho potlaka
- Ho potoloha mothapo o bataletseng - matla a motsamao o chitja
- Ho potoloha mothapo o kobehileng - matla a motsamao o chitja
- Motsamao o tšoanang ka selikalikoe se otlolohileng
- Matla a bohareng a motsamao o chitja o tšoanang
