Motsamao o nang le ho potlaka ho sa khaotseng - mathata le litharollo

Mathata a Rarollotsoeng Motsamaong o Mola - Ho potlaka ho sa khaotseng

1. Koloi e potlakisa ho tloha phomolong ho ea ho 20 m/s ka metsotsoana e 10. Fumana lebelo la koloi!

tharollo

Tse tsejoang:

Lebelo la pele (v)_o) = 0 (phomolo)

Nako ea ho arohana (t) = metsotsoana e 10

Lebelo la ho qetela (v)_t) = 20 m/s

o ne a batla Ho potlaka (a)

Tharollo:

v_t = v_o + ho

20 = 0 + (a)(10)

20 = 10 a

a = 20/10

a = 2 m/s²

2. Koloi e theoha lebelo ho tloha ho 30 m/s ho ea phomola ka metsotsoana e 10. Fumana lebelo la koloi.

tharollo

Tse tsejoang:

Lebelo la pele (v)_o) = 30 m/s

Lebelo la ho qetela (v)_t= 0

Nako ea ho arohana (t) = metsotsoana e 10

Ho batloa: ho potlakisa (a)

Tharollo:

v_t = v_o + ho

0 = 30 + (a)(10)

– 30 = 10 a

a = – 30 / 10

a = -3 m/s²

Letšoao le fosahetseng le hlaha hobane la ho qetela Velocity lebelo le ka tlase ho lebelo la pele.

3. Koloi e qala le ho potlakisa ka lebelo le sa fetoheng la 4 m/s² in Motsotsoana o le 1. Fumana lebelo le sebaka kamora metsotsoana e 10.

tharollo

(a) Lebelo

Ho potlaka 4 m/s² ho bolela keketseho ea lebelo ka 4 m/s motsotsoana o mong le o mong o le mong. Kamora metsotsoana e 2, lebelo la koloi ke 8 m/s. Kamora metsotsoana e 10, lebelo la koloi ke 40 m/s.

(b) Sebaka

Tse tsejoang:

Lebelo la pele (v)_o= 0

Lebelo la ho qetela (v)_t) = 40 m/s

Ho potlaka (a) = 4 m/s²

Ho batloa: distanta

Tharollo:

s = v_o t + ½ ho² = 0 + ½ (4)(10²) = (2)(100) = limithara tse 200

4. Koloi e tsamaea ka lebelo le sa fetoheng la 10 m/s, ebe e theoha ka lebelo le sa fetoheng la 2 m/s² ho fihlela phomolo. Fumana nako e fetileng le ea koloi distanta pele ho phomolo.

Tse tsejoang:

Lebelo la pele (v)_o) = 10 m/s

Ho potlaka (a) = -2 m/s² (Letšoao le fosahetseng le hlaha hobane lebelo la ho qetela le ka tlase ho lebelo la pele)

Lebelo la ho qetela (v)_t) = 0 (phomolo)

Ho batloa: Nako le sebaka

Tharollo:

(a) Nako e sa fellang (t)

v_t = v_o + ho

0 = 10 + (-2)(t)

0 = 10 – 2 t

10 = 2 t

t = 10 / 2 = metsotsoana e 5

(b) Sebaka

v_t² = v_o² + Li-axle tse 2

0 = 10² + 2(-2) s

0 = 100 – 4 metsotsoana

100 = metsotsoana e 4

s = 100 / 4 = limithara tse 25

5. Koloi e tsamaea ka lebelo la 40 m/s, e theoha butle ka lebelo le sa fetoheng la 4 m/s² ho fihlela o phomola. Fumana lebelo le sebaka ka mora ho fokotsa lebelo ka metsotsoana e 10!

tharollo

Tse tsejoang:

Lebelo la pele (v)_o) = 40 m/s

Ho potlaka (a) = -4 m/s²

Nako ea ho arohana (t) = metsotsoana e 10

Ho batloa: lebelo la ho qetela (v_t) le sebaka (libaka)

Tharollo:

(a) Lebelo la ho qetela

v_t = v_o + ho = 40 + (-4)(10) = 40 – 40 = 0 m/s

0 m/s e bolela phomolo ea koloi.

(b) Sebaka

s = v_o t + ½ ho² = (40)(10) + ½ (-4)(10²) = 400 + (-2)(100) = 400 – 200 = limithara tse 200

6. Fumana sebaka ka mora metsotsoana e 10!

tharollo

Sebaka: s = vt = (10-0)(5-0) = (10)(5) = limithara tse 50

7. Fumana sebaka ka mora metsotsoana e 4!

tharollo

Sebaka = sebaka se sekwere + sebaka se kgutlotharo

Sebaka = (8-0)(8-0) + ½ (16-8)(8-0) = (8)(8) + ½ (8)(8) = 64 + 32 = 96 metres

8. Fumana sebaka sa koloi ka mor'a metsotsoana e 4!

tharollo

Sebaka = sebaka sa khutlotharo = ½ (4-0)(8-0) = ½ (4)(8) = limithara tse 16

9. Koloi e tsamaea ka lebelo la 90 km/h ho feta koloi ea mapolesa e emang ka thoko ho tsela. Motsotso o le mong hamorao, koloi ea mapolesa ea lelekisa at 0.8 limithara / s². Koloi ea mapolesa e fihla bohōleng bofees koloi?

Tse tsejoang:

Lebelo la koloi (v) = 90 km/hora = 90,000 metres / metsotsoana e 3600 = 25 metres/motsotsoana

Nako e sa fellang (t) = motsotso o le 1 = metsotsoana e 60

Ho potlaka ha koloi ea mapolesa (a) = 0.8 m/s²

Lebelo la pele la koloi ea mapolesa (v_o) = 0 m/s

Ho batloa: Sebaka se tsamauoang ka koloi ea mapolesa

Tharollo:

Koloi e tsamaea ka lebelo le sa fetoheng. Sebaka se tsamauoang ka koloi:

Sebaka sa pele:

s = vt = (25)(60) = limithara tse 1500

Sebaka sa ho qetela:

s = vt = (25)(t)

Kakaretso ea sebaka = 1500 + 25 t

Koloi ea mapolesa e tsamaea ka lebelo le sa khaotseng. Sebaka se tsamauoang ke koloi ea mapolesa:

s = v_o t + ½ ho² = (0)(t) + ½ (0.8)(t²) = 0 + 0.4 t² = 0.4 t²

Ha koloi ea mapolesa e fihla koloing, sebaka se tsamauoang ke koloi ea mapolesa se tšoana le sebaka se tsamauoang ke koloi.

Sebaka se tsamauoang ka koloi = sebaka se tsamauoang ke koloi ea mapolesa

1500 + 25 t = 0.4 t²

0.4 t² – 25 t – 1500 = 0

Sebelisa foromo ea quadratic:

Sebaka se tsamauoang ka koloi ea mapolesa:

s = 0.4 t² = (0.4)(100²) = (0.4)(10,000) = limithara tse 4000s = 4 km

10. A koloi e tsamaea ka lebelo le sa fetoheng la 24 m/s li-brake e le hore e be le ho fokotseha ho sa khaotseng ha lebelo ea 0.952 m/s². Fumana lebelo la koloi akamora sebaka sa 250 mli-eter.

Tse tsejoang:

Lebelo la pele (v)_o) = 24 m/s

matsapa (a) = – 0.952 m/s² (ho saennoe hampe hobane ho fokotseha ha lebelo)

distanta (d) = limithara tse 250s

Ho batloa: Lebelo la koloi ka mor'a moo Monyetla oa 250s

Tharollo:

Tse tsejoang: lebelo la pele (v_o), ho potlaka (a), distanta (d), e batloang: lebelo la ho qetela (v_t) kahoo sebelisa equation ea v_t² = v_o² + 2 a d

v_t = lebelo la ho qetela,v_o = lebelo la pele, a = ho potlaka, d = distanta

v_t² = (24)² + (2)(-0.952)(250)

v_t² = 576 - 476

v_t² = 100

v_t = √100

v_t = 10 m/s

[ID ea sephutheloana sa wpdm='507′]

[ID ea sephutheloana sa wpdm='517′]

1. Sebaka le ho falla
2. Lebelo le tloaelehileng le lebelo le tloaelehileng
3. Lebelo le sa fetoheng
4. Ho potlaka kamehla
5. Motsamao oa hoetla o lokolohileng
6. Motsamao oa ho theoha ha ho oa ka bolokolohi
7. Motsamao o yang hodimo le tlase nakong ya ho wa ha mahala