Ho sisinyeha ha sefofane se sekametseng ntle le matla a khohlano – ts'ebeliso ea mathata le litharollo tsa molao oa Newton oa ho sisinyeha

1. Boima ba lebokose = 2 kg, ho potlaka ka lebaka la matla a khoheli = 9.8 m/s 2 . Fumana (a) matla a letlooa a potlakisang lebokose ho ya tlase (b) boholo ba potlakalo ya lebokose.

Ho sisinyeha ha sefofane se sekametseng ntle le matla a khohlano - ts'ebeliso ea mathata le litharollo tsa molao oa Newton oa ho sisinyeha 1

tharollo

Ho sisinyeha ha sefofane se sekametseng ntle le matla a khohlano - ts'ebeliso ea mathata le litharollo tsa molao oa Newton oa ho sisinyeha 2

Tse tsejoang:

Boima (m) = 2 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 9.8 m/s 2

Boima (w) = mg = (2)(9.8) = 19.6 Newtons

w x = w sin 30 = (19.6)(0.5) = 9.8 Newton

w y = w cos 30 = (19.6)(0.5√3) = 9.8√3 Li-Newton

Tharollo:

(a) Letlooa bakeng sa ce le potlakisang lebokose

Sepakapaka se sekametseng se boreleli, kahoo ha ho na matla a khohlano. Matla feela a sebetsang nthong ke w x.

F = w x

F = 9.8 Newton

(b) boholo ba ho potlaka

F = ma

9.8 = (2) a

a = 9.8/2

a = 4.9 m/s 2

Boholo ba ho potlaka ke 4.9 m/s 2 , tataiso ea ho potlaka e theohela tlase.

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2. Sepakapaka se sekametseng se boreleli kahoo ha ho na matla a khohlano . Boima ba ntho ke 3 kg, ho potlaka ka lebaka la matla a khoheli ke 9.8 m/s 2 . Fumana boholo ba matla F haeba (a) ntho e phomotse (b) ntho e theohela tlase ka ho potlaka ho sa feleng ha 2 m/s 2 (c) ntho e nyolohela holimo ka ho potlaka ho sa feleng ha 2 m/s 2.

Ho sisinyeha ha sefofane se sekametseng ntle le matla a khohlano - ts'ebeliso ea mathata le litharollo tsa molao oa Newton oa ho sisinyeha 3

tharollo

Ho sisinyeha ha sefofane se sekametseng ntle le matla a khohlano - ts'ebeliso ea mathata le litharollo tsa molao oa Newton oa ho sisinyeha 4

Tse tsejoang:

Boima (m) = 3 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 9.8 m/s 2

Boima (w) = mg = (3)(9.8) = 29.4 Li-Newton

w x = w sin 30 = (29.4)(0.5) = 14.7 Newton

w y = w cos 30 = (29.4)(0.5√3) = 14.7√3 Li-Newton

Tharollo:

(a) Boholo ba matla F haeba ntho e phomotse

Molao oa pele oa Newton oa motsamao o re haeba ntho e phomotse, matla a letlooa a sebetsa nthong eo ke lefela.

F = 0

F – w x = 0

F = w x

F = 14.7 Newton

(b) Boholo ba matla F haeba ntho e theohela tlase ka lebelo le sa fetoheng la 2 m/s 2

F = ma

w x – F = ma

14.7 – F = (3)(2)

14.7 – F = 6

F = 14.7–6

F = 8.7 Newton

(c) Boholo ba matla F haeba ntho e ntse e nyolohela hodimo ka lebelo le sa fetoheng la 2 m/s 2

F = ma

F – w x = ma

F – 14.7 = (3)(2)

F – 14.7 = 6

F = 14.7 + 6

F = 20.7 Newton

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[ID ea sephutheloana sa wpdm='479′]

  1. Boima le boima
  2. Matla a tloaelehileng
  3. Molao oa bobeli oa Newton oa ho sisinyeha
  4. Matla a khohlano
  5. Ho sisinyeha holim'a bokaholimo bo otlolohileng ntle le matla a khohlano
  6. Motsamao oa 'mele e 'meli e nang le lebelo le tšoanang holim'a bokaholimo bo bataletseng bo bataletseng ka matla a khohlano
  7. Ho sisinyeha ha sefofane se sekametseng ntle le matla a khohlano
  8. Motsamao sefofaneng se sekametseng ka thata ka matla a khohlano
  9. Motsamao ka lifting
  10. Motsamao oa 'mele o hokahantsoe ka lithapo le li-pulleys
  11. 'Mele e 'meli e nang le boholo bo tšoanang ba ho potlaka
  12. Ho potoloha mothapo o bataletseng - matla a motsamao o chitja
  13. Ho potoloha mothapo o kobehileng - matla a motsamao o chitja
  14. Motsamao o tšoanang ka selikalikoe se otlolohileng
  15. Matla a bohareng a motsamao o chitja o tšoanang

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