1. The mufambo Pakati pemigero miviri yemafungu emvura pane 20 m. Chinhu chinoyangarara pamusoro pemvura zvekuti chinonzwa kufamba kwekudengenyeka. Kana nguva yekufamba kwekudengenyeka kumwe chete iri masekondi mana, saka kumhanya kwemafungu ndeku …. m/s
A. 20
B. 15
C. 10
D. 5
Zvinozivikanwa:
Wavelength (λ) = mamita makumi maviri
Nguva (T) = masekondi maviri
Kuda: Kumhanya kwemafungu (v)
Solution:
Kuenzanisa kwekumhanya kwemafungu:
v = λ / T = mamita makumi maviri / masekonzi mana = mamita mashanu / sekondi
Mhinduro chaiyo ndiD.
2. Mapoinzi maviri A naB ari patambo uye ari kure nemasendimita 90 kubva kune mumwe nemumwe. Patambo inopararira mafungu akachinjika, saka poindi A iri pamusoro pemafungu, poindi B iri pasi pemafungu, uye pakati pawo, pane maburi maviri nematafura maviri. Kana nguva yemafungu iri 0.3 seconds, saka kupararira kwemafungu…
A. 10.8 cm/s
B. 18.0 cm/s
C. 120.0 cm/s
D. 200.0 cm/s
Zvinozivikanwa:
Kureba AB (l) = 90 cm
Nguva yemafungu (T) = masekondi 0.3
Kuwanda kwemafungu (f) = 1/0.3 masekondi
Poindi A iri pamusoro pemafungu uye poindi B iri pakati pemafungu.
Pakati penzvimbo A neB, pane macrests maviri nematafura maviri.
Zvaidiwa: Kumhanya kwemafungu (v = f λ)
Solution:
Zvichibva pamufananidzo, tinogona kugumisa kuti pane mawavelengths maviri nehafu. Kureba kwewavelength (λ) = 90 cm / 2.5 = 36 cm
Kumhanya kwemafungu:
v = f λ = (1 / 0.3) (36) = 36 / 0.3 = 120 cm/s.
Mhinduro chaiyo ndeinoti C.
3. Girafu rinotevera rinoratidza kuchinjika kwenzvimbo mune imwe nzira senzira yenguva apo mafungu anopfuura nepakati penzira.

Kana kureba kwemafungu kuri mamita matanhatu, saka kumhanya kwekupararira kwemafungu ndiko…
A. 3 m/s
B. 6 m/s
C. 8 m/s
D. 12 m/s
Zvinozivikanwa:
Kune mawavelength maviri zvichibva pagirafu iri pamusoro.
Kureba kwehurefu hwewavelength imwe (λ) = mamita matanhatu / 2 = mamita matatu
Nguva (T) = masekondi maviri
Zvaidiwa: Kumhanya kwemafungu (v)
Solution:
v = f λ = λ / T = mamita matatu / masekonzi 0.5 = mamita matanhatu / sekondi
Mhinduro chaiyo ndeiyi B.
4. Zvichibva pamufananidzo uri pazasi, tpoindi ine musiyano wechikamu ¾ nepoindi A iri ….
A. Poindi B
B. Poindi C
C. Poindi D
D. Poindi E
mhinduro
Poindi B ine musiyano wechikamu che ¼ λ nepoindi A
Poindi C ine musiyano wechikamu che 2/4 λ kana 1/2 λ nepoindi A
Poindi D ine musiyano wechikamu che3/4 λ nepoindi A
Poindi F ine musiyano wechikamu we5/4 λ nepoindi A.
Mhinduro chaiyo ndeinoti C.
5. Pamusoro pedziva, pane mashizha maviri akaoma ari kure nemasendimita makumi matanhatu kubva kune rimwe nerimwe. Ose anofamba achikwira nekudzika sepamusoro pemvura ine frequency ye2 Hz. Kana shizha rimwe riri pamusoro, mamwe mashizha ari pagomba, uye pakati pawo, pane goko rimwe nerimwe. Sarudza kumhanya kwekupararira kwemafungu.
A. 20 cm/s
B. 30 cm/s
C. 80 cm/s
D. 120 cm/s
Zvinozivikanwa:
Kureba pakati pemashizha ese = 60 cm
Kakawanda (f) = 2 Hz = 2
Zvaidiwa: Kumhanya kwemafungu
Solution:
Pakati pemashizha ese ari maviri, pane marefu ewavelength 1.5. Daro rewavelength 1 i (λ) = 60 cm / 1.5 = 40 cm
Kumhanya kwemafungu (v):
v = f λ = (2 Hz)(40 cm) = 80 cm/sekondi
Mhinduro chaiyo ndeinoti C.
6. Zvichibva pamufananidzo uri pazasi, sarudza amplitude, period, frequency, uye speed yemafungu.

Solution:
Kukura kwenzvimbo (A) = mamita mana
Nguva (T) = masekondi matanhatu / 3 = masekondi maviri
Kuwanda (f) = 1 / T = 1 / 2 = 0.5 hertz
Hurefu hwemafungu (λ) = mamita makumi maviri nemana / 3 = mamita masere
Kumhanya kwemafungu (v) = f λ = (0.5 hertz)(mamita 8) = mamita 4/sekondi kana
Kumhanya kwemafungu (v) = λ / T = mamita 8 / masekondi maviri = mamita 4/sekondi
Mhinduro chaiyo ndiD.
7. Patambo ine urefu hwe 1.2 m nehuremu hwe 200 g yakaumbwa mafungu e sinusoidal 1.5 ane frequency ye 50 Hz. Zvichibva padata iri, sarudza nguva yemafungu uye simba rekumanikidzwa kwetambo.
A. Nguva = masekondi 0.02 uye simba rekumanikidzwa = 6.67 N
B. Nguva = masekondi 0.01 uye simba rekumanikidzwa = 6.67 N
C. Nguva = masekondi 0.02 uye simba rekumanikidzwa = 266.67 N
D. Nguva = masekondi 0.01 uye simba rekumanikidzwa = 266.67 N
Zvinozivikanwa:
Kureba kwetambo (l) = 1.2 metres uye kune 1.5 sinusoidal waves saka daro re1 wavelength (λ) = 1.2 metres / 1.5 = 0.8 metres
Huremu hwetambo (m) = 200 magiramu = 0.2 kg
Kakawanda (f) = 50 Hz
Kuwanda kwetambo (µ) = m/l = 0.2 kg / 1.2 metres = (1/6) kg/mita
Zvaidiwa: Nguva yemafungu (T) uye simba rekumanikidzwa kwetambo (T)
Solution:
Nguva yemafungu:
T = 1 / f = 1 / 50 Hz = 0.02 masekondi
Kumhanya kwemafungu patambo:
v = f λ = (50 Hz)(0.8 mamita) = 40 mamita/sekondi
Simba rekumanikidza (T):

Mhinduro chaiyo ndeinoti C.