1. The speed of the mafungu akachinjika Patambo ine 25 metres tambo ine 50 m/s. Simba rekumanikidzwa kwetambo i200 N. Tsvaga huremu hwetambo.
A. 0.08 kg
B. 0.5 kg
C. 0.8 kg
D. 2.0 kg
Zvinozivikanwa:
Kureba kwetambo (l) = 25 m
Kumhanya kwewave inochinjika (v) = 50 m/s
Simba rekumanikidzwa kwetambo (T) = 200 N
Kuda: Huremu hwetambo (m)
Solution:
Dambudziko iri rinogona kugadziriswa uchishandisa fomura yenzira yekuparadzira mafungu patambo.
Mhinduro chaiyo ndiD.
2. Pamusoro pedziva panoyangarara zvidimbu zviviri zvehuni, daro riri pakati pazvo i6 m. Mafungu anopararira pamusoro pedziva. Kana huni yekutanga yafamba ichikwira nekudzika katatu, huni yechipiri inongofamba ichikwira nekudzika kamwe chete. Kana masekondi maviri ega ega marudzi ese ehuni achifamba achikwira nekudzika katatu, kupararira kwemafungu kuno ...
A. 4.5 m/s
B. 3.0 m/s
C. 2.0 m/s
D. 1.5 m/s
Zvinozivikanwa:
Kureba pakati pemiti yese (l) = mamita matanhatu
Matanda ekutanga akafamba achikwira nekudzika katatu; echipiri akafamba achikwira nekudzika kamwe chete.
Kuwanda (f) = 3 / 2 = 1.5 hertz
Kuda: Kumhanya kwemafungu (v)
Solution:
Kana huni yekutanga ikafamba ichikwira nekudzika kamwe chete, wavelength 1 inofamba ichienda kuhuni rechipiri. Kana huni rekutanga richifamba richikwira nekudzika kaviri, kureba kwehurefu hwe ...
Nokudaro, the mufambo Pakati pehuni yekutanga nehuni yechipiri pane marefu maviri ewavelength (2 λ), sezvakaratidzwa mumufananidzo uri padivi.
Kureba kwehurefu hwewavelength imwe chete (λ) = 6 / 2 = mamita matatu
Kumhanya kwekupararira kwemafungu (v):
v = f λ = (1.5 hertz) (mamita matatu)
v = 4.5 m/s
Mhinduro chaiyo ndeinoti A.
3. Zvinhu zvinokurumidzisa kupararira kwemafungu patambo ndeizvi…
(1) tambanudza waya
(2) kukudza tambo
(3) kuwedzera kusimba kwewaya
(4) kuwedzera saizi yewaya. Chirevo chakarurama ndechekuti…
A. (1), (2), (3) uye (4)
B. (1), (2), uye (3)
C. (3) na (4)
D. (3) chete
Solution:
Fomura yekumhanya kwekupararira kwemafungu patambo:
Mhinduro chaiyo ndeinoti A.
v = kumhanya kwekupararira kwemafungu patambo
T = simba rekumanikidzwa kwetambo
μ = kuwanda kwetambo
m = huremu hwetambo
l = kureba kwetambo
4. Tambo inoburitsa tambo yewavelength ine frequency ye50 Hz uye wavelength ye2 m. Nguva uye kumhanya kwemafungu…
A. Masekondi 0.02 uye 50 ms-1
B. Masekondi 0.02 uye 100 ms-1
C. 0.04 masekondi uye 50 ms-1
D. Masekondi 0.5 uye 100 ms-1
Zvinozivikanwa:
Kakawanda (f) = 50 Hz
Hurefu hwemafungu (λ) = mamita maviri
Kuda: Nguva (T) uye kumhanya kwemafungu (v)
Solution:
Nguva:
T = 1/f = 1/50 Hz = 0.02 masekondi
Kumhanya kwemafungu:
v = f λ = (50 1/sekondi)(2 mamita) = 100 mamita/sekondi
Mhinduro chaiyo ndeiyi B.
5. Chivharo chiri pamusoro pemvura chinokwira nekudzika nekuda kwemafungu emvura ari pamusoro. Nguva inodiwa kubva gomo repamusoro kune gomo rinotevera inis 1.2 seconds. Kana pamusoro pemvura, daro riri pakati pemakrists maviri riri 10 cm, saka tarisa kumhanya kwekupararira kwemafungu.
A. 12 ms-1
B. 12 cm s-1
C. 8,3 ms-1
Kureba 8,3 cm s-1
Zvinozivikanwa:
Nguva inodiwa kubva pamucheto kusvika pamucheto unotevera = nguva yenguva yehurefu hwewavelength imwe = nguva (T) = 1.2 seconds.
Kureba pakati pemakrists maviri = kureba kwehurefu hwewavelength imwe (λ) = 10 cm
Zvaidiwa: Kumhanya kwekupararira kwemafungu (v)
Solution:
Kumhanya kwekupararira kwemafungu:
v = f λ = λ / T = 10 cm / 1.2 masekondi = 8.3 cm/sekondi = 8.3 cm.s-1
Mhinduro chaiyo ndiD.
