Magetsi asingachinji - matambudziko nemhinduro
Simba remagetsi
1. Poindi A mumunda wemagetsi . Hukuru hwemunda wemagetsi panzvimbo A = 0.5 NC -1 . Kana 0.25-C charge yakaiswa panzvimbo A, saka simba remagetsi ripi rinoiswa pamuchina uyu?
Zvinozivikanwa:
Munda wemagetsi panzvimbo A = 0.5 NC -1
Chaja yemagetsi panzvimbo A = 0.25 C
Zvinodiwa: Simba remagetsi
Solution:
F = q E
F = (0.25 C)(0.5 NC -1 )
F = 0.125N
2. Machaji maviri 5 C uye 4 C akaparadzaniswa nedaro remamita matatu. Kana Coulomb constant iri 9 × 10 9 Nm 2 C –2 , simba remagetsi rinowanikwa nechaji mbiri ingani?
Zvinozivikanwa:
Chaja 1 (q 1 ) = 5 C
Chaja 2 (q 2 ) = 4 C
Daro riri pakati pekuchaja 1 nekuchaja 2 (r) = mamita matatu
Chimiro cheCoulomb (k) = 9 × 10 9 Nm 2 C –2
Zvinodiwa: Hukuru hwesimba remagetsi (F)
Solution:
3. Chaja yemagetsi +q 1 = 10 μC ; +q 2 = 20 μC ; uye q 3 zvakaparadzaniswa, sezvakaratidzwa mumufananidzo uri pazasi. Simba remagetsi rinoshandiswa pachaja q 2 = 0, saka chii chinonzi chaja yeq 3.
Zvinozivikanwa:
Chaja 1 (q 1 ) = 10 μC = 10 x 10 -6 C
Chaja 2 (q 2 ) = 20 μC = 20 x 10 -6 C
Zviri Kudiwa: Ndeipi muripo weQ3
Solution:
Kune masimba maviri anoitwa pa +q 2.
Simba rekutanga isimba rinodzinga riri pakati pekuchaja +q 1 nechaja +q 2 rinova F 12 , kurudyi.
Simba remagetsi rinoshanda pa q 2 = 0 saka q 3 inofanira kunge iri negative.
Simba rechipiri ndiro simba rinokwezva riri pakati pekuchaja +q 2 na -q 3 rinova F 23 , richitarisa kuruboshwe.
Masimba ese ari maviri aya anoshanda panhamba 2 , ane hukuru hwakafanana asi divi rakapesana.
Simba reNet rinoita pa +q 2 = 0.
4. Machaji matatu q 1 , q , uye q 2 ari mumutsara. Kana q = 5.0 μC uye d = 30 cm, saka chii chiri kukura uye gwara remagetsi rinoita pachaji q.
Zvinozivikanwa:
Chaja 1 (q 1 ) = 30 μC = 30 x 10 -6 C
Chaja 2 (q 2 ) = 60 μC = 60 x 10 -6 C
Chaja 3 (q) = 5 μC = 5 x 10 -6 C
Kureba pakati peq 1 neq = d
Kureba pakati peq 2 neq = 2d
d = 30 cm = 0.3 mamita
d 2 = (0.3) 2 = 0.09
Chimiro cheCoulomb (k) = 9 x 10 9 N m 2 C -2
Zvinodiwa: Hukuru uye gwara remagetsi zvinoshanda pamagetsi
Solution:
Kune masimba maviri anoshanda pa q ari F 1 kurudyi (q na q 1 zvakanaka saka F 1 kure na q na q 1 ) uye F 2 kuruboshwe (q na q 2 zvakanaka saka F 2 kure na q na q 2 ). Kutanga kuverengerwa F 1 na F 2.
Simba remambure i7.5 Newtons. Kutungamira kwesimba remambure = kutungamira kwaF1, kurudyi kunochaja q2.
Munda wemagetsi
5. Poindi yekuchaja q iri panzvimbo P mumunda wemagetsi inogadzirwa nechaja (+) zvekuti inonzwa simba re 0.05 N munzira inoenda kuchaja. Kana hukuru hwemunda wemagetsi panzvimbo P huri 2 x 10 -2 NC -1 , saka chii chiri hukuru uye rudzi rwechaja chinokonzera munda wemagetsi.
Zvinozivikanwa:
Simba remagetsi (F) = 0.05 N
Munda wemagetsi (E) = 2 x 10 –2 NC –1 = 0.02 NC –1
Zvinodiwa: Hukuru uye rudzi rwechaji yemagetsi
Solution:
Chaja yemagetsi inoverengerwa uchishandisa fomura inoratidza hukama huripo pakati pesimba remagetsi (F), munda wemagetsi (E) uye chaja yemagetsi (q):
F = q E
q = F / E = 0.05 N / 0.02 NC –1 = 2.5 Coulombs
Chaji q inosangana nesimba remagetsi munzira yekuchaja (+) iyo inoburitsa simba remagetsi, saka chaji q inenge iri negative.
6. Machaji A neB akaparadzaniswa nedaro remamita mana. Poindi C iri pakati pemachaji ese ari maviri, mita imwe kubva poindi A. Kana Q A = –300 μC, Q B = 600 μC. 1/4 π ε 0 = 9 × 10 9 N m 2 C– 2, saka chii chiri kukura kwesimba remagetsi panzvimbo C rinogadzirwa nemachaji ese ari maviri.
Zvinozivikanwa:
Kureba pakati pemari A neB (r AB ) = mamita mana
Daro riri pakati pepoindi C nechaji A (r AC ) = mita imwe
Daro riri pakati penzvimbo C nechaji B (r BC ) = mamita matatu
Chaja A (q A ) = –300 μC = -300 x 10 -6 C = -3 x 10 -4 Coulomb
Chaja B (q B ) = 600 μC = 600 x 10 -6 C = 6 x 10 -4 Coulombs
Nguva dzose (k) = 9 × 10 9 N m 2 C –2
Zviri kudiwa: Munda wemagetsi panzvimbo C
Solution:
Munda wemagetsi unogadzirwa nechaji A panzvimbo C:
Chaji A haina kunaka zvekuti divi remagetsi rinonongedzera kuchaji A uye kure nechaji B (kuruboshwe).
Munda wemagetsi unogadzirwa nechaji B panzvimbo C:
Chaji B yakanaka zvekuti divi remagetsi riri kure nechaji B uye nzvimbo dziri kure nechaji A (kuruboshwe).
Mhedzisiro yemunda wemagetsi panzvimbo A:
E = E A + E B
E = (27 x 10 5 ) + (6 x 10 5 )
E = 33 x 10 5 N/C
Kwakananga simba remagetsi kunongedzera kuchaja A uye kure nechaja B (kuruboshwe).
7. Guruva re 1-mg richiyangarara mumhepo. Kana guruva richichaja 0.5 μC uye kumhanyisa nekuda kwegiravhiti kuri 10 m/s2, sarudza kukura kwesimba remagetsi rinotsigira guruva.
Zvinozivikanwa:
Huremu hweguruva (m) = 1 mg = 1 x 10 -6 kg
Kuchaja kweguruva (q) = 0.5 μC = 0.5 x 10 -6 C
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2
Zviri kudiwa: Nzvimbo yemagetsi
Solution:
w = mg
w = huremu hweguruva, m = huremu hweguruva, g = kukurumidza nekuda kwegiravhiti
Simba regiravhiti rinoshanda paguruva:
w = mg = (1 x 10 -6 kg)(10 m/s 2 ) = 10 x 10 -6 kg m/s 2 = 10 x 10 -6 Newtons
Kuenzanisa kwemunda wemagetsi:
E = F/q
E = munda wemagetsi, F = simba remagetsi, q = kuchaja kwemagetsi
Isa F mu equation ye electric field na w mu equation ye weight :
E = F/q = w/q
E = (10 x 10 -6 N) / (0.5 x 10 -6 C)
E = 10 N / 0,5 C
E = 20 N/C
8. Machaji maviri q 1 = 32 μC uye q 2 = -214 μC akaparadzaniswa nedaro re x, sezvakaratidzwa mumufananidzo uri pazasi. Hapana nzvimbo yemagetsi panzvimbo P iri pa10 cm kubva paq 2. Tsvaga x.
Zvinozivikanwa:
Chaja 1 (Q 1 ) = 32 μC
Chaja 2 (Q 2 ) = -214 μC
Kureba kwenzvimbo P kubva pa q 1 = x + 10 cm
Kureba kwenzvimbo P kubva pa q 2 = 10 cm
Anodiwa: x
Solution:
E 1 = munda wemagetsi unogadzirwa nechaji Mubvunzo 1. Kutungamira kwemunda wemagetsi kuri kure neMubvunzo 1 nekuti Mubvunzo 1 wakanaka. E 2 = munda wemagetsi unogadzirwa neMubvunzo 2. Kutungamira kwemunda wemagetsi kunongedzera kuMubvunzo 2 nekuti Mubvunzo 2 hauna kunaka.
Hapana simba remagetsi panzvimbo p iri pa10 cm kubva Q 2
Shandisa fomura yequadratic:
9. Poindi yekuchaja q iri panzvimbo P mumunda wemagetsi inogadzirwa nechaja (+), nokudaro iine simba re 0.05 N. Kana chaja iri +5 × l0 –6 Coulomb, saka hukuru hwemunda wemagetsi panzvimbo C chii.
Zvinozivikanwa:
Simba remagetsi (F) = 0.05 Newtons
Chaja yemagetsi (Q) = +5 × l0 –6 Coulomb = 0.000005
Zviri kudiwa: Munda wemagetsi panzvimbo P
Solution:
E = F / Q
E = 0.05 Newtons / 0.000005 Coulombs
E = 5 Newtons / 0.0005 Coulombs
E = 10,000 Newton/Coulomb
E = 10 4 N/C
E = 10 4 NC -1
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