1. Chinhu chinodedera nefrequency ye5 Hz kuenda kurudyi nekuruboshwe. Chinhu chinofamba kubva pa equilibrium point kuenda pa maximum kudzingiswa Kurudyi. Sarudza nguva inodiwa kuti usvike pakudzikama kukuru kurudyi kagumi nerimwe.
A. 2.05
B. 2.20
C. 2.25
D. 2.50
Zvinozivikanwa:
Kuwanda (f) = huwandu hwekudengenyeka kwesekondi imwe chete = 5 Hz
Nguva (T) = iyo nguva yekudedera kamwe chete = 1/f = 1/5 = 0.2 masekonzi
Kuda: Nguva inodiwa kuti usvike pakufambiswa kwepamusoro-soro kurudyi kagumi nerimwe
Solution:
Maitiro ekudedera kwechinhu:
(1 kudedera) : B → C → B → A → B
Pakuzununguka kumwe chete, chinhu chinoita kuzununguka kunana kunoti B kusvika C, C kusvika B, B kusvika A, A kusvika B. Nguva inodiwa kuti kuzununguka kumwe chete ive 0.2 seconds / 4 = 0.05 seconds.
Nguva inodiwa kuti usvike pakufambiswa kwepamusoro-soro kurudyi kagumi nerimwe = (10 x 0.2 masekondi) + 0.05 masekondi = 2 masekondi + 0.05 masekondi = 2.05 masekondi.
Mhinduro chaiyo ndeinoti A.
2. Chitubu chinoturikwa nechinhu chobva chazunguzika. Kuti frequency yekuzunguzika iwedzere kaviri frequency yekuzunguzika yekutanga, ipapo huremu hwechinhu hunochinjwa kuita…
A. huremu hwakapetwa kaviri hwemutoro wekutanga
B. huremu hwakapetwa kana kupfuura hwemutoro wekutanga
C. hafu yenguva yehuremu hwemutoro
D. chikamu chimwe muzvina chehuremu hwemutoro wekutanga
Solution:
Kuenzanisa kwehuwandu hwekudengenyeka kwechitubu:
f = frequency, k = constant, m = huremu hwechinhu
Kuwanda (f) kwekuzunguzika kwechitubu kana k = 1 nguva, m = 1 nguva :
Kuti frequency ye (f) spring vibration ive kaviri, huremu (m) hunochinjwa kuita 0.25 times kana 1/4 times:
Mhinduro chaiyo ndiD.
3. Chitubu chine k = 1000 N/m chinoturikwa nechinhu chine huremu hwemagiramu 400. Chinhu chacho chinodhonzwa kurudyi kusvika pa5 cm, chobva chaburitswa, saka chinhu chacho chinobviswa. maharmoniki ari nyore anotendereraSarudza amplitude uye frequency yekufamba-famba kwechinhu.
Zvinozivikanwa:
Chimiro chemuchirimo (k) = 1000 N/m
Misa yechinhu (m) = magiramu 400 = 0.4 kg
Kukura kwehukuru (Δx) = 5 cm = 0.05 m
Zvaidiwa: Kukura uye kuwanda kwekufamba-famba
Solution:
Hukuru hwekutenderera kwechitubu = Δx = 5 cm.
Kuwanda kwekufamba-famba:
Mhinduro chaiyo ndeiyi B.
