Nguva yesimba - matambudziko nemhinduro
1. Kana FR isimba guru reF1, F2,uye f3, simba F rakakura sei?2 uye x?
Zvinozivikanwa:
Simba reNet (F)R) = 40 N
Simba 1 (F)1) = 10 N
Simba (F)3) = 20 N
Kuda: Hukuru hwesimba F2 uye daro ra x
Solution:
Tsvaga hukuru hwesimba F2 :
Kumanikidza kunongedzera kumusoro, chiratidzo chekuramba uye chiratidzo chekuramba pasi, chiratidzo chekuramba.
ΣF = 0
- FR +F1 +F2 - F3 = 0
– 40 + 10 + F2 - 20 = 0
– 30 + F2 - 20 = 0
– 50 + F2 = 0
F2 = MaNewton makumi mashanu.
Chiratidzo chekuwedzera chinoratidza kuti divi resimba riri kumusoro.
Tsvaga x.
Sarudza A sechikamu chekutenderera.
τ1 =F1 l1 = (10 N)(1 m) = 10 Nm
Torque 1 inotenderera danda remwenje richipesana newachi saka tinoisa chiratidzo chakanaka kutorque 3.
τ2 =F2 x = (50)(x) = 50x Nm
Torque 1 inotenderera danda remwenje richipesana newachi saka tinoisa chiratidzo chakanaka kutorque 3.
τ3 =F3 x = (20 N)(1.75 m) = -35 Nm
Torque 2 inotenderera mwenje uchitenderera wachi saka tinoisa chiratidzo chekusashanda zvakanaka kutorque 2.
Mambure e nguva yesimba :
Στ = 0
10 + 50x – 35 = 0
50x - 25 = 0
50x = 25
x = 25/50
x = 0.5 m
2. Masimba eF1, F2, F3,uye f4 inoshanda patsvimbo yeABCD sezvakaratidzwa pamufananidzo. Kana huremu hwetsvimbo hukasatariswa, chii chiri kukura kwesimba panguva iyoyo, pamusoro pepoindi A.
Chikamu chekutenderera = poindi A.
Zvinozivikanwa:
Simba F1 = 10 N, ruoko rwechirever l1 = 0 
Simba F2 = 4 N, ruoko rwechirever l2 = 2 mamita
Simba F3 = 5 N, ruoko rwechirever l3 = 3 mamita
Simba F4 = 10 N, ruoko rwechirever l4 = 6 mamita
Zvaidiwa: nguva yesimba pamusoro pepfungwa A
Solution:
Nguva yesimba 1 (τ1) = F1 l1 = (10)(0) = 0
Nguva yesimba 2 (τ2) = F2 l2 = (4)(2) = -8 Nm
Nguva yesimba 3 (τ3) = F3 l3 = (5)(3) = 15 Nm
Nguva yesimba 4 (τ4) = F4 l4 = (10)(6) = -60 Nm
Kana torque ikatenderera tsvimbo inopesana newachi, tinopa chiratidzo chakanaka.
Kana torque ikatenderera tsvimbo newachi, tinoisa chiratidzo chekusaratidza.
Mhedzisiro yenguva yesimba:
τ = 0 – 8 Nm + 15 Nm – 60 Nm
τ = -68 Nm + 15 Nm
τ = -53 Nm
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
3. Masimba matatu anoshanda patsvimbo, FA =FC = 10 N uye FB = 20 N, sezvakaratidzwa mumufananidzo uri pazasi. Kana daro reAB = BC = 20 cm, chii chinonzi nguva yesimba pamusoro pepoindi C?
Zvinozivikanwa:
Kutenderera kwechikamu chepakati C.
Kureba pakati peFA uye axis yekutenderera (r)AC) = 40 cm = 0,4 metres
Kureba pakati peFB uye axis yekutenderera (r)BC) = 20 cm = 0.2 metres
Kureba pakati peFC uye axis yekutenderera (r)CC) = 0 cm
FA = 10 Newton
FB = 20 Newton
FC = 10 Newton
Zvaidiwa: Mhedzisiro yenguva yesimba pamusoro pepfungwa C.
Solution:
Nguva yesimba A:
ΣτA = (F)A)(rAC pasina 90o) = (10 N)(0,4 m)(1) = -4 Nm
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
Nguva yesimba B:
ΣτB = (F)B)(rBC pasina 90o) = (20 N)(0,2 m)(1) = 4 Nm
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
Nguva yesimba C:
ΣτC = (F)C)(rCC pasina 90o) = (10 N)(0)(1) = 0
Mhedzisiro yenguva yesimba:
Στ = Στ1 + Στ2 + Στ3
Στ = -4 + 4 + 0
Στ = 0 Nm
4. Kureba kwetsvimbo ndeye 50 cm. Masimba matatu anoshanda patsvimbo, sezvakaratidzwa mumufananidzo uri pazasi. Kana axis yekutenderera iri poindi C, chii chinonzi net yemoment yesimba.
Zvinozivikanwa:
Kutenderera kwechikamu chepakati C.
Kureba pakati peF1 uye axis yekutenderera ndeye (r1) = 30 cm = 0,3 metres
Kureba pakati peF2 uye axis yekutenderera (r)2) = 10 cm = 0,1 metres
Kureba pakati peF3 uye axis yekutenderera (r)3) = 20 cm = 0,2 metres
F1 = 10 Newton
F2 = 10 Newton
F3 = 10 Newton
Zvaidiwa: Mhedzisiro yesimba pamusoro pepfungwa C.
Solution:
Nguva yesimba 1:
Στ1 = (F)1)(r1 pasina 90o) = (10 N)(0,3 m)(1) = -3 Nm
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
Nguva yesimba 2:
Στ2 = (F)2)(r2 pasina 90o) = (10 N)(0,1 m)(1) = 1 Nm
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
Nguva yesimba 3:
Στ3 = (F)3)(r3 pasina 30o) = (10 N)(0,2 m)(0,5) = -1 Nm
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
Mhedzisiro yenguva yesimba:
Στ = Στ1 + Στ2 + Στ3
Στ = -3 + 1 – 1
Στ = -3 Nm
Chiratidzo chekudzima chinoratidza kuti mhedzisiro yesimba inotenderera tsvimbo newachi.
5. Mauto matatu F1, F2,uye f3 chiito patsvimbo sezvakaratidzwa pamufananidzo uri pazasi. Kureba kwetsvimbo mamita mana. Ndeipi nguva yesimba pamusoro penzvimbo C?
(chivi 53o = 0.8, cos 53o = 0.6, AB = BC = CD = DE = mita imwe)
Zvinozivikanwa:
Kutenderera kwechikamu chepakati C. 
Simba 1 (F)1) = 5 Newton
Daro riri pakati pemutsetse wekuita waF1 ne axis yekutenderera (r)1) = mamita makumi matanhatu
Simba 2 (F)2) = 0.4 Newton
Daro riri pakati pemutsetse wekuita waF2 ne axis yekutenderera (r)2) = 1 mamita
Simba 3 (F)3) = 4.8 Newton
Daro riri pakati pemitsara yezviito zve F3 nechikamu chekutenderera (r3) = 2 mita
Kuda: Nguva yesimba pamusoro pepfungwa C.
Solution:
Nguva yesimba 1:
τ1 =F1 r chivi 53o = (5 N)(2 m)(0,8) = (10)(0,8) N = 8 N
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
Nguva yesimba 2:
τ2 =F2 r chivi 90o = (0,4 N)(1 m)(1) = -0,4 N
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
Nguva yesimba 3:
τ3 =F3 r chivi 90o = (4,8 N)(2 m)(1) = -9,6 N
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
Mhedzisiro yenguva yesimba:
Στ = τ1 – τ2 – τ3 = 8 – 0,4 – 9,6 = 8 – 10 = 2 Nm
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
6. Chii chinoitika panguva yekusimba pamusoro pedenderedzwa rekutenderera panzvimbo yeO nemasimba ari patsvimbo, sezvakaratidzwa mumufananidzo uri pazasi?
Zvinozivikanwa:
Mutsetse wekutenderera panzvimbo yeO. 
Simba 1 (F)1) = 6 Newton
Daro riri pakati pemutsetse wekuita waF1 ne axis yekutenderera (r)1) = 1 mamita
Simba 2 (F)2) = 6 Newton
Daro riri pakati pemutsetse wekuita waF2 ne axis yekutenderera (r)2) = mamita makumi matanhatu
Simba 3 (F)3) = 4 Newton
Daro riri pakati pemutsetse wekuita waF3 ne axis yekutenderera (r)3) = mamita makumi matanhatu
Kuda: Mhedzisiro yenguva yesimba pamusoro pepfungwa C
Solution:
Nguva yesimba 1:
τ1 =F1 l1 = (6 N)(1 m) = 6 Nm
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
Nguva yesimba 2:
τ2 =F2 r2 pasina 30o = (6 N)(2 m)(0,5)= 6 Nm
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
Nguva yesimba 3:
τ3 =F3 l3 = (4 N)(2 m) = -8 Nm
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
Mhedzisiro yenguva yesimba:
Στ = τ1 + τ2 – τ3 = 6 + 6 – 8 = 4 Nm
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
