Nguva yesimba - matambudziko nemhinduro
1. Kana F R iri simba guru reF 1 , F 2 , uye F 3 , simba guru reF 2 na x nderei?
Zvinozivikanwa:
Simba reNet (F)R) = 40 N
Simba 1 (F 1 ) = 10 N
Simba (F 3 ) = 20 N
Zvinodiwa: Hukuru hwesimba F 2 uye daro ra x
Solution:
Tsvaga hukuru hwesimba F 2 :
Kumanikidza kunongedzera kumusoro, chiratidzo chekuramba uye chiratidzo chekuramba pasi, chiratidzo chekuramba.
ΣF = 0
– F R + F 1 + F 2 – F 3 = 0
– 40 + 10 + F 2 – 20 = 0
– 30 + F 2 – 20 = 0
– 50 + F 2 = 0
F 2 = 50 Newtons.
Chiratidzo chekuwedzera chinoratidza kuti divi resimba riri kumusoro.
Tsvaga x.
Sarudza A sechikamu chekutenderera.
τ 1 = F 1 l 1 = (10 N)(1 m) = 10 Nm
Torque 1 inotenderera danda remwenje richipesana newachi saka tinoisa chiratidzo chakanaka kutorque 3.
τ 2 = F 2 x = (50)(x) = 50x Nm
Torque 1 inotenderera danda remwenje richipesana newachi saka tinoisa chiratidzo chakanaka kutorque 3.
τ 3 = F 3 x = (20 N)(1.75 m) = -35 Nm
Torque 2 inotenderera mwenje uchitenderera wachi saka tinoisa chiratidzo chekusashanda zvakanaka kutorque 2.
Nguva chaiyo yesimba :
Στ = 0
10 + 50x – 35 = 0
50x - 25 = 0
50x = 25
x = 25/50
x = 0.5 m
2. Masimba eF 1 , F 2 , F 3 , uye F 4 anoshanda patsvimbo yeABCD sezvakaratidzwa pamufananidzo. Kana huremu hwetsvimbo hukasatariswa, chii chiri kukura kwesimba, pamusoro pepoindi A.
Chikamu chekutenderera = poindi A.
Zvinozivikanwa:
Simba F1 = 10 N, ruoko rwechirever l1 = 0 
Simba F 2 = 4 N, ruoko rwechitsigiro l 2 = 2 mamita
Simba F 3 = 5 N, ruoko rwechitsigiro l 3 = 3 mamita
Simba F 4 = 10 N, ruoko rwechitsigiro l 4 = 6 mamita
Zvinodiwa: nguva yesimba pamusoro penzvimbo A
Solution:
Nguva yesimba 1 (τ 1 ) = F 1 l 1 = (10)(0) = 0
Nguva yesimba 2 (τ 2 ) = F 2 l 2 = (4) (2) = -8 Nm
Nguva yesimba 3 (τ 3 ) = F 3 l 3 = (5)(3) = 15 Nm
Nguva yesimba 4 (τ 4 ) = F 4 l 4 = (10) (6) = -60 Nm
Kana torque ikatenderera tsvimbo inopesana newachi, tinopa chiratidzo chakanaka.
Kana torque ikatenderera tsvimbo newachi, tinoisa chiratidzo chekusaratidza.
Mhedzisiro yenguva yesimba:
τ = 0 – 8 Nm + 15 Nm – 60 Nm
τ = -68 Nm + 15 Nm
τ = -53 Nm
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
3. Masimba matatu anoshanda patsvimbo, F A = F C = 10 N uye F B = 20 N, sezvakaratidzwa mumufananidzo uri pazasi. Kana daro reAB = BC = 20 cm, chii chiri nguva yesimba pamusoro pepoindi C.
Zvinozivikanwa:
Kutenderera kwechikamu chepakati C.
Daro riri pakati peF A ne axis yekutenderera (r AC ) = 40 cm = 0,4 metres
Daro riri pakati peF B ne axis yekutenderera (r BC ) = 20 cm = 0.2 metres
Daro riri pakati peF C ne axis yekutenderera (r CC ) = 0 cm
F A = 10 Newton
F B = 20 Newton
FC = 10 Newtons
Zvinodiwa: Mugumisiro wenguva yesimba pamusoro pepfungwa C.
Solution:
Nguva yesimba A:
Στ A = (F A )(r AC chivi 90 o ) = (10 N)(0,4 m)(1) = -4 Nm
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
Nguva yesimba B:
Στ B = (F B )(r BC chivi 90 o ) = (20 N)(0,2 m)(1) = 4 Nm
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
Nguva yesimba C:
Στ C = (F C )(r CC chivi 90 o ) = (10 N)(0)(1) = 0
Mhedzisiro yenguva yesimba:
Στ = Στ 1 + Στ 2 + Στ 3
Στ = -4 + 4 + 0
Στ = 0 Nm
4. Kureba kwetsvimbo ndeye 50 cm. Masimba matatu anoshanda patsvimbo, sezvakaratidzwa mumufananidzo uri pazasi. Kana axis yekutenderera iri poindi C, chii chinonzi net yemoment yesimba.
Zvinozivikanwa:
Kutenderera kwechikamu chepakati C.
Daro riri pakati peF 1 ne axis yekutenderera (r 1 ) = 30 cm = 0,3 metres
Daro riri pakati peF2 ne axis yekutenderera (r2 ) = 10 cm = 0,1 metres
Daro riri pakati peF3 ne axis yekutenderera (r3 ) = 20 cm = 0,2 metres
F 1 = 10 Newton
F 2 = 10 Newton
F 3 = 10 Newton
Zvinodiwa: Zvinobva pakumanikidzwa kwechinhu pamusoro pepfungwa C.
Solution:
Nguva yesimba 1:
Στ 1 = (F 1 )(r 1 chivi 90 o ) = (10 N)(0,3 m)(1) = -3 Nm
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
Nguva yesimba 2:
Στ 2 = (F 2 )(r 2 chivi 90 o ) = (10 N)(0,1 m)(1) = 1 Nm
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
Nguva yesimba 3:
Στ 3 = (F 3 )(r 3 chivi 30 o ) = (10 N)(0,2 m)(0,5) = -1 Nm
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
Mhedzisiro yenguva yesimba:
Στ = Στ 1 + Στ 2 + Στ 3
Στ = -3 + 1 – 1
Στ = -3 Nm
Chiratidzo chekudzima chinoratidza kuti mhedzisiro yesimba inotenderera tsvimbo newachi.
5. Masimba matatu F 1 , F 2 , uye F 3 anoshanda patsvimbo sezvakaratidzwa mumufananidzo uri pazasi. Kureba kwetsvimbo mamita mana. Ndeipi nguva yesimba pamusoro penzvimbo C?
(chivi 53 o = 0.8, cos 53 o = 0.6, AB = BC = CD = DE = mita imwe)
Zvinozivikanwa:
Kutenderera kwechikamu chepakati C. 
Simba 1 (F 1 ) = 5 Newton
Daro riri pakati pemutsetse wekuita weF1 ne axis of rotation (r 1 ) = 2 metres
Simba 2 (F 2 ) = 0.4 Newton
Daro riri pakati pemutsetse wekuita weF2 ne axis of rotation (r2 ) = 1 mita
Simba 3 (F 3 ) = 4.8 Newton
Daro riri pakati pemutsetse wekuita weF3 ne axis of rotation (r 3 ) = 2 metres
Zvinodiwa: Nguva yesimba pamusoro pepfungwa C.
Solution:
Nguva yesimba 1:
τ 1 = F 1 r chivi 53 o = (5 N) (2 m) (0,8) = (10) (0,8) N = 8 N
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
Nguva yesimba 2:
τ 2 = F 2 r chivi 90 o = (0,4 N)(1 m)(1) = -0,4 N
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
Nguva yesimba 3:
τ 3 = F 3 r chivi 90 o = (4,8 N)(2 m)(1) = -9,6 N
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
Mhedzisiro yenguva yesimba:
Στ = τ 1 – τ 2 – τ 3 = 8 – 0,4 – 9,6 = 8 – 10 = 2 Nm
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
6. Chii chinoitika panguva yekusimba pamusoro pedenderedzwa rekutenderera panzvimbo yeO nemasimba ari patsvimbo, sezvakaratidzwa mumufananidzo uri pazasi?
Zvinozivikanwa:
Mutsetse wekutenderera panzvimbo yeO. 
Simba 1 (F 1 ) = 6 Newton
Daro riri pakati pemutsetse wekuita weF1 ne axis of rotation (r1 ) = 1 mita
Simba 2 (F 2 ) = 6 Newton
Daro riri pakati pemutsetse wekuita weF2 ne axis of rotation (r 2 ) = 2 metres
Simba 3 (F 3 ) = 4 Newton
Daro riri pakati pemutsetse wekuita weF3 ne axis of rotation (r 3 ) = 2 metres
Zvinodiwa: Mugumisiro wenguva yesimba pamusoro pepoindi C
Solution:
Nguva yesimba 1:
τ 1 = F 1 l 1 = (6 N) (1 m) = 6 Nm
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
Nguva yesimba 2:
τ 2 = F 2 r 2 chivi 30 o = (6 N)(2 m)(0,5)= 6 Nm
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
Nguva yesimba 3:
τ 3 = F 3 l 3 = (4 N)(2 m) = -8 Nm
Chiratidzo chekudzima chinoratidza kuti nguva yesimba inotenderera tsvimbo newachi.
Mhedzisiro yenguva yesimba:
Στ = τ 1 + τ 2 – τ 3 = 6 + 6 – 8 = 4 Nm
Chiratidzo chekuwedzera chinoratidza kuti nguva yesimba inotenderera tsvimbo inopesana newachi.
