Kumhanya kwemutsara - matambudziko nemhinduro

1. Chinhu chinofamba ne10 m/s. Verengai mutsetse wekufamba kwechinhu chacho.

Zvinozivikanwa :

Huremu (m) = 1 kg

Kumhanya (v) = 10 m/s

Zvinodiwa: linear momentum (p)

Solution:

Fomura yemutsara wemutsara:

p = mv

p = kumhanya kwakatwasuka, m = uremu, v = kumhanya

Mwero wemutsara:

p = mv = (1)(10) = 10 kg m/s 2

[irp]

2. Chivharo che2-kg nebhuroko re4-kg zvinofamba pa20 m/s. Chii chinonzi linear momentum yemabhuroko?

Zvinozivikanwa:

Huremu hwebhuroko A (m A ) = 2 kg

Huremu hwebhuroko B (m B ) = 4 kg

Kumhanya kwebhuroko A (v A ) = 20 m/s

Kumhanya kwebhuroko B (v B ) = 20 m/s

Zvinodiwa: Linear momentum yeblock A (p A ) uye linear momentum yeblock B (p B )

Solution:

Mwero wemutsara webhokisi A :

p A = m A v A = (2) (20) = 40 kg m/s

Mwero wemutsara webhokisi B :

p B = m B v B = (4)(20) = 80 kg m/s

[irp]

3. Bhokisi re2-kg rinofamba ne 2 m/s uye bhokisi re2-kg rinofamba ne 4 m/s. Sarudza kuti mabhokisi acho akamira sei.

Zvinozivikanwa:

Huremu hwebhuroko A (m A ) = 2 kg

Huremu hwebhuroko B (m B ) = 2 kg

Kumhanya kwebhuroko A (v A ) = 2 m/s

Kumhanya kwebhuroko B (v B ) = 4 m/s

Zvinodiwa: mwero wezvidhinha

Solution:

Mwero wemutsara webhokisi A :

p A = m A v A = (2) (2) = 4 kg m/s

Mwero wemutsara webhokisi B:

p B = m B v B = (2)(4) = 8 kg m/s

[irp]

4. Chinhu chinorema 5 kg chakazorora. Chii chinonzi linear momentum ye momentum?

Zvinozivikanwa:

Huremu (m) = 5 kg

Kumhanya kwechinhu (v) = 0

Zvinodiwa : musimboti wakatarwa (p)

Solution:

p = mv = (5)(0) = 0

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  1. Matambudziko emutsara uye mhinduro
  2. Matambudziko ekukurumidza uye ekukurumidza uye mhinduro
  3. Kuroverana kwakakwana mumatambudziko echikamu chimwe chete uye mhinduro
  4. Kuroverana kwakakwana kwekusagadzikana mumatambudziko echikamu chimwe chete uye mhinduro
  5. Kusangana kweinelastic mumatambudziko echikamu chimwe chete uye mhinduro

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