Kumhanya kwemutsara - matambudziko nemhinduro

1. Chinhu chinofamba ne10 m/s isingachinji. Verenga simba rakatsetseka yechinhu chacho.

Inozivikanwa :

Misa (m) = 1 kg

Velocity (v) = 10 m/s

Zvaidiwa: simba rakatsetseka (p)

Solution:

Fomura yemutsara wemutsara:

p = mv

p = kumhanya kwakatwasuka, m = uremu, v = kumhanya

Mwero wemutsara:

p = mv = (1)(10) = 10 kg m/s²

2. Chivharo che2-kg nebhuroko re4-kg zvinofamba pa20 m/s. Chii chinonzi linear momentum yemabhuroko?

Zvinozivikanwa:

Misa yebhuroko A (m)_A) = 2 kg

Misa yebhuroko B (m)_B) = 4 kg

Kumhanya kwebhuroko A (v)_A) = 20 m/s

Kumhanya kwebhuroko B (v)_B) = 20 m/s

Zvaidiwa: Mwero wemutsara webhokisi A (p)_A) uye kumhanya kwakanangana kwebhokisi B (p_B)

Solution:

Mwero wemutsara webhokisi A :

p_A = m_A v_A = (2)(20) = 40 kg m/s

Mwero wemutsara webhokisi B :

p_B = m_B v_B = (4)(20) = 80 kg m/s

3. Bhurukwa re2-kg rinofamba ne 2 m/s uye bhurukwa re2-kg rinofamba ne 4 m/s. Sarudza kuti mabhuroko acho akamira sei.

Zvinozivikanwa:

Misa yebhuroko A (m)_A) = 2 kg

Huremu hwebhuroko B (m_B) = 2 kg

Kumhanya kwebhuroko A (v)_A) = 2 m/s

Kumhanya kwebhuroko B (v_B) = 4 m/s

Zvaidiwa: simba rakatsetseka remabhuroko

Solution:

Linear momentum yebhuroko A :

p_A = m_A v_A = (2)(2) = 4 kg m/s

Mwero wemutsara webhokisi B:

p_B = m_B v_B = (2)(4) = 8 kg m/s

4. Chinhu chinorema 5 kg chiri pazororo. Chii chinonzi linear momentum ye momentum?

Zvinozivikanwa:

Huremu (m) = 5 kg

Kumhanya kwechinhu (v) = 0

Wanted : simba rakatsetseka (p)

Solution:

p = mv = (5)(0) = 0

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