Kubonderana kwakanyatsosimba muchikamu chimwe chete - matambudziko nemhinduro

1. Bhora remagiramu 200, A, richifamba nekumhanya kwe10 m/s rinorova bhora remagiramu 200, B, parakambomira. Chii chinonzi kumhanya kwebhora A nebhora B mushure me kudhumhana?

Zvinozivikanwa:

Misa yebhora A (m_A) = magiramu mazana mashanu = 0.2 kg

Huremu hwebhora B (m)_B) = magiramu mazana mashanu = 0.2 kg

Kumhanya kwebhora A usati warovera (v)_A) = 10 m/s

Kumhanya kwebhora B usati warovera (v)_B= = 0

Kuda: kumhanya kwebhora A (v)_A') uye kumhanya kwebhora B (v)_B') mushure mekuroverana

Solution:

v_A' = v_B = 0

v_B' = v_A = 10 m/s

2. Zvinhu zviviri zvakaenzana zvine huremu zvinosangana, zvobonderana zvobva zvasvetuka. Kumhanya kwehuremu A isati yaroverana i8 m/s uye kumhanya kwehuremu B isati yaroverana i12 m/s. Ndeipi hukuru uye gwara reiyo velocity yehukuru A uye huremu B mushure mekuroverana!

Zvinozivikanwa:

Huremu A (m)_A) = m

Huremu B (m)_B) = m

Kumhanya kwehukuru A usati warovera (v)_A) = -8 m/s

Kumhanya kwehukuru B usati wasangana (v)_B) = 12 m/s

Zviratidzo zve "plus" ne "minus" zvinoratidza kuti zvinhu zviri kufamba nenzira yakasiyana.

Kuda: hukuru uye gwara rekumhanya kwehukuru A (v)_A') uye huremu B (v_B') mushure mekuroverana

Solution:

Mukusangana kwakanyatsosimba, kana zvinhu zvine huremu hwakaenzana, ipapo kumhanya kwaA mushure mekusangana (v)_A') = kumhanya kwaB usati warovera (v_B) uye kumhanya kwaB mushure mekuroverana (v_B') = kumhanya kwaA pamberi pekurovera (v)_A).

Kana A ichienda kurudyi uye B ichienda kuruboshwe, ipapo, mushure mekurovera, A inoenda kuruboshwe uye B inoenda kurudyi.

Zvinhu izvi zvine huremu hwakaenzana uye Kuroverana kwakanyatsosimba saka zvinhu zvese zviri zviviri zvinochinjana kumhanya.

v_A' = -v_B = -12 m/s

v_B' = v_A = 8 m/s

Zviratidzo zve "plus" ne "minus" zvinoratidza kuti zvinhu zviri kufamba nenzira yakasiyana.

3. Chinhu chinorema 2 kg, A, chichifamba nekumhanya kwe10 m/s chinorova bhora re4 kg, B, chichifamba nekumhanya kwe20 m/s. Kana kuroverana kwacho kwakanyatsopfava, chii chinomhanya chinhu A nechinhu B mushure mekuroverana?

Zvinozivikanwa:

Huremu A (m)_A) = 2 kg

Huremu B (m)_B) = 4 kg

Kumhanya kwechinhu A usati wasangana (v)_A) = 10 m/s

Kumhanya kwechinhu B chisati chasangana (v)_B) = 20 m/s

Wanted : kumhanya kwechinhu A (v)_A') uye kumhanya kwechinhu B (v_B') mushure mekubonderana

mhinduro :

In zvakakwana elastic kudhumhana, kana zvinhu zvacho zvine huremu hwakaenzana uye zvichiswedera pedyo, kumhanya kwechinhu mushure mekubonderana kunoverengerwa uchishandisa fomura iyi:

Kumhanya kwechinhu A mushure mekubonderana:

4. 100-gram ichifamba ne20 m/s inorova madziro akapfava zvakakwana. Chii chiri kukura uye divi rekumhanya kwechinhu mushure mekurovera.

Zvinozivikanwa:

Huremu (m)_A) = magiramu mazana mashanu = 0.1 kg

Huremu hwemadziro (m)_B) = kusingaperi

Kumhanya kwehukuru usati wasangana (v)_A) = 20 m/s

Kumhanya kwehukuru mushure mekurovera (v)_B= = 0

Wanted : hukuru uye gwara rekumhanya mushure mekurovera

Solution:

Kana v_B = 0, m_A kadiki kwazvo uye m₂ hombe kwazvo kupfuura v_A' = -v_A uye v₂' = 0.

Zviratidzo zve "plus" ne "minus" zvinoratidza kuti zvinhu zviri kufamba nenzira yakasiyana.

5. Mabhora maviri, A nehukuru hwe 2 kg uye bhora B rine huremu hwe 5-kg, mufananidzo uri pazasi unoratidza kuti bhora A risati rasangana uye rapera. Kana bhora iri rakanyatsosimba, chii chinoita kuti bhora A risati rasangana?

Zvinozivikanwa:

Huremu hwebhora A (m)_A) = 2 kg

Huremu hwebhora B (m)_B) = 5 kg

Kumhanya kwebhora B vasati vasangana (v_B) = 2 m/s

Kumhanya kwebhora A mushure mekubonderana (v_A') = 5 m/s

Kumhanya kwebhora B mushure mekubonderana (v_B') = 4 m/s

Mabhora ese ari maviri ari kufamba kurudyi saka kumhanya kwavo kwakaratidza kuti vane hunyanzvi.

Zvaidiwa: Kumhanya kwebhora A usati warovera (v_A)

Solution:

m_A v_A +m_B v_B = m_A v_A' + m_B v_B'

2(v)_A) + (5)(2) = (2)(5) + (5)(4)

2(v)_A) + 10 = 10 + 20

2(v)_A) + 10 = 30

2(v)_A) = 30 - 10

2(v)_A= = 20

v_A = 20 / 2

v_A = 10 m/s

6. Zvinhu A naB zvinofamba zvakatwasuka, sezvakaratidzwa mumufananidzo uri pazasi. Kana kuroverana kwacho kwakanyatsopfava uye kumhanya kwechinhu B mushure mekuroverana kwacho kuri 15 m / s¹, chii chinonzi kumhanya kwechinhu A mushure mekubonderana.

Zvinozivikanwa:

Huremu hwechinhu A (m)_A) = 5 kg

Huremu hwechinhu B (m)_B) = 2 kg

Kumhanya kwechinhu A usati wasangana (v_A) = 12 m/s

Kumhanya kwechinhu B usati wasangana (v_B) = 10 m/s

Kumhanya kwechinhu B mushure mekubonderana (v_B') = 15 m/s

Zvinhu zvose, zvisati zvaitika uye zvapera, zvinofamba kurudyi kuitira kuti kumhanya kwazvo kuratidze kuti zvakanaka.

Zvaidiwa: Kumhanya kwechinhu A mushure mekubonderana (v_A')

Solution:

m_A v_A +m_B v_B = m_A v_A' + m_B v_B'

(5)(12) + (2)(10) = (5)v_A' + (2)(15)

60 + 20 = (5)v_A'+ 30

80 = (5)v_A'+ 30

80 – 30 = (5)v_A'

50 = (5)v_A'

v_A' = 50/5

v_A' = 10 m/s

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