Spanning, rek en Young-modulus – Problemen en oplossingen

Spanning, rek en Young-modulus – Problemen en oplossingen

1. A nylon string has a diameter of 2 mm, pulled by a force of 100 N. Determine the stress!

Bekend:

Dwingen (F) = 100 N

Diameter (d) = 2 mm = 0.002 m

Radius (r) = 1 mm = 0.001 m

Gewild : De stress

oplossing:

Gebied:

A = π r2

A = (3.14)(0.001 m)2 = 0.00000314 m2

A = 3.14x10-6 m2

The stress :

Stress, strain, Young's modulus sample problems with solutions 1

Zie ook  Druk van vaste stoffen – problemen en oplossingen

2. A cord has original length of 100 cm is pulled by a force. The change in length of the cord is 2 mm. Determine the strain!

Bekend:

Oorspronkelijke lengte (l0) = 100 cm = 1 m

The change in length (Δl) = 2 mm = 0.002 m

Gewild : De druk

oplossing:

De strein :

Stress, strain, Young's modulus sample problems with solutions 2

Zie ook  Diffractieroosters – problemen en oplossingen

3. A string 4 mm in diameter has original length 2 m. The string is pulled by a force of 200 N. If the final length of the spring is 2.02 m, determine : (a) stress (b) strain (c) Young’s modulus

Bekend:

Diameter (d) = 4 mm = 0.004 m

Radius (r) = 2 mm = 0.002 m

Area (A) = π r2 = (3.14)(0.002 m)2

Area (A) = 0.00001256 m2 = 12.56 x 10-6 m2

Kracht (F) = 200 N

Original length of spring (l0) = 2 meter

The change in length (Δl) = 2.02 – 2 = 0.02 m

Gewild : (a) The stress (b) The strain c) Young’s modulus

oplossing:

(a) The shaarlok

Stress, strain, Young's modulus sample problems with solutions 3

(b) The Strain

Stress, strain, Young's modulus sample problems with solutions 4

(C) Young's modulus

Stress, strain, Young's modulus sample problems with solutions 5

Zie ook  Distance and displacement - problems and solutions

4. A string has a diameter of 1 cm and the original length of 2 m. The string is pulled by a force of 200 N. Determine the change in length of the string! Young’s modulus of the string = 5 x 109 N / m2

Bekend:

Young’s modulus (E) = 5 x 109 N / m2

Oorspronkelijke lengte (l0) = 2 meter

Kracht (F) = 200 N

Diameter (d) = 1 cm = 0.01 m

Radius (r) = 0.5 cm = 0.005 m = 5 x 10-3 m

Area (A) = π r2 = (3.14)(5 x 10-3 m)2 = (3.14)(25 x 10-6 m2)

Area (A) = 78.5 x 10-6 m2 = 7.85 x 10-5 m2

gezocht : The change in length (Δl)

oplossing:

Young’s modulus formula :

Stress, strain, Young's modulus sample problems with solutions 6

De verandering in lengte :

Stress, strain, Young's modulus sample problems with solutions 7

Zie ook  Hoekversnelling en lineaire versnelling – problemen en oplossingen

5. A concrete has a height of 5 meters and has unit area of 3 m3 ondersteunt een massa of 30,000 kg. Determine (a) The stress (b) The strain (c) The change in height! Versnelling als gevolg van zwaartekracht (g) = 10 m/s2. Young’s modulus of concrete = 20 x 109 N / m2

Bekend:

Young’s modulus of concrete = 20 x 109 N / m2

Initial height (l0) = 5 meter

Unit area (A) = 3 m2

Gewicht (w) = mg = (30,000)(10) = 300,000 N

Gewild : (a) The stress (b) The strain (c) The change in height!

oplossing:

(a) The stress

Stress, strain, Young's modulus sample problems with solutions 8

(b) The Strain

Stress, strain, Young's modulus sample problems with solutions 9

(c) The change in height

Stress, strain, Young's modulus sample problems with solutions 10

Zie ook  Weerstandschakelingen – problemen en oplossingen

  1. de wet van Hooke
  2. Stress, strain, Young’s modulus

Laat een bericht achter