Ithiyori kaTorricelli - izinkinga nezixazululo

Ithiyori kaTorricelli - izinkinga nezixazululo

1. Ipayipi elinokuphakama okungamasentimitha ayi-100 eligcwele amanzi. Umgodi u-Q utholakala kumasentimitha ayi-10 ngaphezu komhlabathi. Liyini ibanga elivundlile (x)?

Kwaziwa:

Ibanga phakathi komgodi kanye nobuso bamanzi (h) = 100 cm – 10 cm = 90 cm = 0.9 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Okufunayo: Ibanga lika-x

Isixazululo:

Isivinini sokugeleza kwamanzi emgodini

v= ijubane, g = ukusheshisa ngenxa yamandla adonsela phansi, h = ibanga phakathi komgodi kanye nobuso bamanzi

Isivinini sokugeleza kwamanzi emgodini:

Isikhathi emoyeni

Ukunyakaza kwamanzi esuka emgodini eya emhlabathini yikona ukunyakaza kwe-projectile. Ukunyakaza okubonakalayo kungaqondwa ngokuhlaziya izingxenye ezivundlile neziqondile zokunyakaza ngokwehlukana. Ukunyakaza kuka-x kwenzeka ngesivinini esingaguquki kanti ukunyakaza kuka-y kwenzeka ngokusheshisa okungaguquki kwamandla adonsela phansi.

Kule nkinga, ukunyakaza okuqondile kuhlaziywe njengokunyakaza kokuwa okukhululekile.

Bala isikhathi emoyeni usebenzisa i-equation ye- ukunyakaza kokuwa kwamahhala.

Kwaziwa:

Ukuphakama kwembobo (y) = 10 cm = 0.1 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Kufunwa: Isikhawu sesikhathi (t)

Isixazululo:

y = 1/2 gt²

0.1 = 1/2 (10) t²

0.1 = 5 t²

t² = 0.1/5

t² = 0.02

t = √0.02 imizuzwana

Ibanga elivundlile (x):

Kwaziwa:

Ijubane lokuqala (v)_o =v_ox) = 3√2 m/s

Isikhathi emoyeni (t)= √0.02 imizuzwana

Kufunwa: Ibanga elivundlile (x)

Isixazululo:

v = x / t

x = vt = (3√2)(√0.02) = (3)(1.41)(0.14) = 0.59 = 0.6 amamitha

2. Ithangi eliqukethe amanzi anokuphakama kwemitha eli-1. Ephuzwini P, kukhona umgodi. Liyini ijubane lokugeleza kwamanzi emgodini. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s².

Kwaziwa:

Ibanga phakathi komgodi kanye nobuso bamanzi (h) = 100 cm – 80 cm = 20 cm = 0.2 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Okufunayo: Isivinini sokugeleza kwamanzi emgodini (v)

Isixazululo:

Isivinini sokugeleza kwamanzi emgodini:

3. Okukhuluibhavu iqukethe amanzi futhi kukhona umpompi njengoba kuboniswe esithombeni esingezansi. Uma g = 10 ms^-2, bese ijubane lamanzi eliphuma empompini li...

Kwaziwa:

Ukuphakama (h) = 85 cm – 40 cm = 45 cm = 0.45 amamitha

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Okufunayo: Isivinini samanzi (v)

Isixazululo:

TIthiyori ka-orricelli ithi ijubane lamanzi ngomgodi oqhelelene no-h ebusweni bamanzi lilingana ne- isivinini se ukuwa kwamahhalaIng amanzi avela ekuphakameni okungu-h.

Ijubane lamanzi libalwa kusetshenziswa ifomula yokunyakaza kokuwa kwamahhalaa v_t² = 2 gh

v_t² = 2 gh = 2(10)(0.45) = 9

v_t = √9 = 3 m/s

4. A kubhavu kugcwele amanzi futhi odongeni kukhona imbobo (bheka isithombe esingezansi). Isivinini samanzi aphuma emgodini… (g = 10 ms^-2)

Kwaziwa:

Ukuphakama (h) = 1.5 m – 0.25 m = 1.25 amamitha

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Kufunwa: Sisivinini samanzi (V)

Isixazululo:

v_t² = 2 gh = 2(10)(1.25) = 25

v_t = √25 = 5 m/s

5. Ithangi eliqukethe amanzi afinyelela kumitha eli-1 (g = 10 ms^-2) futhi odongeni kukhona imbobo evuzayo (bheka isithombe esingezansi). Isivinini samanzi aphuma emgodini...

Kwaziwa:

Ukuphakama (h) = 1 m – 0.20 m = 0.8 amamitha

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Kufunwa: Sisivinini samanzi (V)

Isixazululo:

v_t² = 2 gh = 2(10)(0.8) = 16

v_t = √16 = 4 m/s

1. Ichaza ukuthini inkolelo-mbono kaTorricelli?
   • Impendulo: Ithiyori kaTorricelli ihlobanisa ijubane loketshezi oluphuma emgodini kuya ekuphakameni kwekholomu yoketshezi ngaphezu komgodi, kucatshangelwa ukuthi luzinzile, alubonakali (alukho uqweqwe), kanye nokugeleza okungacindezeleki.
2. I-theorem kaTorricelli ivezwa kanjani ngokwezibalo?
   • Impendulo: Ithiyori ivezwa njenge v=√2gh​, lapho $v$ ijubane le-efflux, $g$ ukusheshisa okubangelwa amandla adonsela phansi, futhi $h$ ukuphakama kwekholomu yoketshezi ngaphezu kwe-orifice.
3. I-theorem kaTorricelli yasungulwa ngaphansi kwaziphi izinkolelo-mbono?
   • Impendulo: Ithiyori icabanga ukuthi uketshezi alucindezeleki futhi aluna-viscous, ukugeleza kuzinzile, futhi akukho mandla engeziwe angeziwe noma athathwe oketshezini.
4. Uma isitsha sinezimbobo ezimbili ekujuleni okuhlukile, ijubane loketshezi oluphuma ezimbobeni lizoqhathaniswa kanjani?
   • Impendulo: Uketshezi oluphuma emgodini oseduze nesisekelo luzoba nesivinini esikhulu kunoketshezi oluvela emgodini ophakeme. Lokhu kungenxa yokuthi ingcindezi (futhi ngaleyo ndlela amandla angaba khona) inkulu ekujuleni okujulile.
5. Kungani ijubane le-efflux lingaxhomekile esimweni noma endaweni enqamulelayo yesitsha?
   • Impendulo: Ithiyori kaTorricelli ibheka kuphela amandla angaba khona ngenxa yokuphakama kwekholomu yoketshezi ngaphezu kwe-orifice. Ukuma kwesitsha akushintshi lokhu kuphakama, ngakho-ke ijubane le-efflux lihlala lifana.
6. Ijubane langempela loketshezi oluphuma emgodini lihluke kanjani esibikezelweni esenziwe yi-theorem kaTorricelli ezimweni zangempela?
   • Impendulo: Ezimweni zangempela, izici ezifana nokujiya koketshezi, ukuxokozela, kanye nesimo se-orifice kungathinta isivinini sangempela, okuvame ukwenza kube ngaphansi kwalokho okubikezelwa yi-theorem kaTorricelli.
7. Buyini ubudlelwano phakathi kwethiyori kaTorricelli nokulondolozwa kwamandla?
   • Impendulo: Ithiyori kaTorricelli isuselwa ekulondolozweni kwamandla omshini. Ilinganisa amandla angaba khona ebusweni boketshezi namandla e-kinetic asemgodini.
8. Uma kukhona i-orifice phezulu kakhulu kwesitsha esigcwele uketshezi, i-theorem kaTorricelli iyichaza kanjani ijubane lokuphuma kwamanzi?
   • Impendulo: Ukuphakama $h$ ngaphezu kwe-orifice kungaba ngu-zero, ngakho-ke ngokusho kwe-theorem kaTorricelli, isivinini se-efflux singaba ngu-zero.
9. Ukuba khona komfutho womoya kuthinta kanjani izibikezelo zethiyori kaTorricelli?
   • Impendulo: I-theorem kaTorricelli ithatha ukuthi isitsha sivulekele umkhathi, ngakho-ke, ingcindezi yomkhathi isebenza ngokulinganayo ebusweni boketshezi. Lokhu kucindezela kuyakhanselwa uma kucatshangelwa umehluko wokucindezela phakathi kokuphakama koketshezi, ngakho-ke i-theorem ihlala isebenza.
10. Kwenzekani ngesivinini sokuphuma kwamanzi njengoba uketshezi olusesitsheni luncipha?

• Impendulo: Njengoba izinga loketshezi lehla, ukuphakama $h$ ngaphezu kwe-orifice kwehla. Ngokusho kwe-theorem kaTorricelli, isivinini se-efflux sizokwehla njengoba v=√2gh​.

Le mibuzo nezimpendulo zihlola izisekelo, imiphumela, kanye nokusetshenziswa kwethiyori kaTorricelli ku-fluid dynamics.