Ubukhulu be-torque ehlanzekile - izinkinga nezixazululo

1. Amandla P asetshenziswa ekugcineni kogongolo olunobude obungamamitha amabili. Ungakanani ubukhulu be- torque ? I-axis yokujikeleza endaweni A.

Kwaziwa:

Amandla (F) = 10 N

Ubude be-AB (r _AB ) = 2 m

I-Force F iqonde ngqo emsebeni.

Ingalo ye-lever (l ) = r _AB sin 90 ^o = (2 m)(1) = 2 m

Okufunwayo: I-torque ezungeze i-axis yokujikeleza

Isixazululo:

I-torque:

τ = F l = (10 N)(2 m) = 20 N m

Uphawu lokuhlanganisa ngoba umsebe ujikeleza ujikeleza ngokuphambene newashi.

[irp]

2. Ubude bomsebe u -AB bungama-2 m kanti ubukhulu bamandla u-F bungama-10 N. Bungakanani ubukhulu be-torque? I-axis yokujikeleza endaweni A.

Kwaziwa:

Amandla (F) = 10 N

Ubude be-AB (r _AB ) = 2 m

Ingalo yesibambo (l ) = r _AB sin 60 ^o = (2 m)(0.5 √3 ) = √3 m

Okufunwayo: I-torque ezungeze i-axis yokujikeleza

Isixazululo:

I-torque:

τ = F l = (10 N)( √3 m) = 10 √3 N m

Uphawu lokuhlanganisa ngoba amandla u-F abangela ukuthi umsebe ujikeleze ukujikeleza okuphikisana newashi.

[irp]

3. Ubude bomsebe bungama-2 m. Ubukhulu be-F ₁ bungama-10 N kanti ubukhulu be-F ₂ bungama-15 N. Thola i-torque ephelele phakathi nendawo yomsebe.

I-axis yokujikeleza enkabeni yomsebe.

Kwaziwa:

Amandla 1 (F ₁ ) = 10 N

Ibanga eliphakathi kuka-F ₁ kanye nesikhungo somsebe (r ₁ ) = 1 m

Ingalo yesibambo 1 (l ₁ ) = r ₁ sin 90 ^o = (1 m)(1) = 1 m

I-Force F ₁ iqonde ngqo emsebeni.

Amandla 2 (F ₂ ) = 15 N

Ibanga eliphakathi kuka-F ₂ kanye nesikhungo somsebe (r ₂ ) = 1 m

I-Force F ₂ iqonde ngqo emsebeni.

Ingalo yesibambo 2 (l ₂ ) = r ₁ sin 90 ^o = (1 m)(1) = 1 m

Okufunwayo: I -torque engenalutho ezungeze i-axis yokujikeleza

Isixazululo:

I-torque 1:

τ ₁ = F ₁ l ₁ = (10 N)( 1 m) = 10 N m

Uphawu lokuhlanganisa ngoba amandla ka-F ₁ abangela ukuthi umsebe ujikeleze ukujikeleza okuphikisana newashi.

I-torque 2:

τ ₂ = F ₂ l ₂ = (15 N)( 1 m) = -15 N

Uphawu lokususa ngoba amandla u-F ₂ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque ephelele:

Σ τ = τ ₁ – τ ₂ = 10 – 15 = – 5 N m

Uphawu lokususa luwukuthi umsebe ujikeleza ngokwewashi.

[irp]

4. Ubude bomsebe u-AB bungama -2 m, ubukhulu be-F ₁ bungama-10 N kanti ubukhulu be-F ₂ bungama- 10 N. Thola i-torque ephelele phakathi nendawo yomsebe.

I-axis yokujikeleza enkabeni yomsebe.

Kwaziwa:

Amandla 1 (F ₁ ) = 10 Nn

Ibanga eliphakathi kuka-F ₁ kanye nesikhungo somsebe (r ₁ ) = 1 m

Ingalo yesibambo 1 (l ₁ ) = r ₁ sin 60 ^o = (1 m)(0.5 √3 ) = 0.5 √3 m

Amandla 2 (F ₂ ) = 10 N

Ibanga eliphakathi kuka-F ₂ kanye nesikhungo somsebe (r ₂ ) = 1 m

I-Force F ₂ iqonde ngqo emsebeni.

Ingalo yesibambo 2 (l ₂ ) = r ₂ sin 90 ^o = (1 m)(1) = 1 m

Okufunwayo: I-torque ephelele mayelana ne-axis yokujikeleza

Isixazululo:

I-torque 1:

τ ₁ = F ₁ l ₁ = (10 N)( 0.5 √3 m) = 5 √3 = 8.7 Nm

Uphawu lokuhlanganisa ngoba amandla u-F ₁ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque 2:

τ ₂ = F ₂ l ₂ = (10 N)( 1 m) = -10 N m

Uphawu lokususa ngoba amandla u-F ₂ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque ephelele:

Σ τ = τ ₁ – τ ₂ = 8.7 – 10 = – 1.3 N m

Uphawu lokususa ngoba amandla anetha abangela ukuthi umsebe ujikeleze ngokwewashi.

[irp]

5. Ubude bomsebe buyi-10 m, ubukhulu be-F ₁ buyi-10 N, ubukhulu be-F ₂ buyi-10 N kanti ubukhulu be-F ₃ buyi-15 N. Ibanga eliphakathi kwephuzu A nephuzu C liyi-7.5 m. I-Force F ₂ itholakala enkabeni yomsebe. Thola i-torque ehlanzekile mayelana nephuzu C elitholakala ku-2.5 m ukusuka ephuzu B.

I-axis yokujikeleza itholakala endaweni C

Kwaziwa:

Amandla 1 (F ₁ ) = 10 N

Ibanga eliphakathi kuka-F ₁ nephuzu C (r ₁ ) = 2.5 m

I-Force F ₁ iqonde ngqo emsebeni.

Ingalo yesibambo 1 (l ₁ ) = r ₁ sin 90 ^o = ( 2.5 m)( 1 ) = 2.5 m

Amandla 2 (F ₂ ) = 10 N

Ibanga eliphakathi kuka-F ₂ nephuzu C (r ₂ ) = 2.5 m

Amandla F ₂ aqonde ngqo emsebeni.

Ingalo yesibambo 2 (l ₂ ) = r ₂ sin 90 ^o = ( 2.5 m)(1) = 2.5 m

Amandla 3 (F ₃ ) = 15 N

Ibanga eliphakathi kuka-F ₃ nephuzu C (r ₃ ) = 7.5 m

Amandla F ₃ aqonde ngqo emsebeni.

Ingalo yesibambo 3 (l ₃ ) = r ₃ sin 90 ^o = (7.5 m)(1) = 7.5 m

Okufunwayo: I-torque ephelele mayelana ne-axis yokujikeleza

Isixazululo:

I-torque 1:

τ ₁ = F ₁ l ₁ = (10 N)( 2.5 m) = 25 N m

Uphawu lokuhlanganisa ngoba amandla u-F ₁ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque 2:

τ ₂ = F ₂ l ₂ = (10 N)( 2.5 m) = 25 N m

Uphawu lwe -plus ngoba amandla u-F ₂ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque 3:

τ ₃ = F ₃ l ₃ = (15 N)( 7.5 m) = -112..5 N m

Uphawu lokususa ngoba amandla u-F ₃ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque ephelele:

Σ τ = τ ₁ + τ ₂ – τ ₃ = 25 + 25 – 112.5 = – 62.5 N m

Uphawu lokususa ngoba amandla anetha abangela ukuthi umsebe ujikeleze ngokwewashi.

[irp]

6. Ubude bomsebe buyi-10 m, ubukhulu buyi-F₁ ingu-10 N, ubukhulu buka-F₂ ingu-10 N kanye nobukhulu buka-F₃ ingu-10 N. Thola i-torque enetha mayelana nephuzu A, elitholakala ngamamitha angu-5 ukusuka endaweni ephakemeukusetshenziswa kwamandla F₁.

I-axis yokujikeleza endaweni A.

Kwaziwa:

Amandla 1 (F ₁ ) = 10 N

Ibanga eliphakathi kuka-F ₁ nephuzu A (r ₁ ) = 5 m

Ingalo yesibambo 1 (l ₁ ) = r ₁ sin 60 ^o = (5 m)(0.5 √3 ) = 2.5 √3 m

Amandla 2 (F ₂ ) = 10 N

Ibanga eliphakathi kuka-F ₂ nephuzu A (r ₂ ) = 0

Amandla F ₂ aqonde ngqo emsebeni.

Ingalo yesibambo 2 (l ₂ ) = r ₂ sin 90 ^o = (0)(1) = 0

Amandla 3 (F ₃ ) = 10 N

Ibanga eliphakathi kuka-F ₃ nephuzu A (r ₃ ) = 10 m

Ingalo yesibambo 3 (l ₃ ) = r ₃ sin 30 ^o = (10 m)(0.5) = 5 m

Okufunwayo: i-torque ehlanzekile ezungeze i-axis yokujikeleza

Isixazululo:

I-torque 1:

τ ₁ = F ₁ l ₁ = (10 N)( 2.5 √3 m ) = 25√3 = 43.3 N m

Uphawu lokuhlanganisa ngoba amandla u-F ₁ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque 2:

τ ₂ = F ₂ l ₂ = (10 N)(0) = 0

I-torque 3:

τ ₃ = F ₃ l ₃ = (10 N)( 5 m) = -50 N m

Uphawu lokususa ngoba amandla u-F ₃ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque ephelele:

Σ τ = τ ₁ + τ ₂ – τ ₃ = 43.3 + 0 – 50 = – 6.7 N m

Uphawu lokususa ngoba amandla anetha abangela ukuthi umsebe ujikeleze ngokwewashi.