Ukucindezeleka I-modulus kaYoung – Izinkinga Nezixazululo

Ukucindezeleka I-modulus kaYoung – Izinkinga Nezixazululo

1. Intambo ye-nylon inobubanzi obungu-2 mm, idonswa ngamandla angu-100 N. Thola ukucindezeleka!

Kwaziwa:

Amandla (F) = 100 N

Ububanzi (d) = 2 mm = 0.002 m

Irediyasi (r) = 1 mm = 0.001 m

Okufunwayo: Ukucindezeleka

Isixazululo:

Indawo:

A = π r 2

A = (3.14)(0.001 m) 2 = 0.00000314 m 2

A = 3.14 x 10 -6 m 2

Ukucindezeleka:

Ukucindezeleka, ukucindezeleka, izinkinga zesampula ze-modulus kaYoung ngezixazululo 1

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2. Intambo enobude bokuqala obuyi-100 cm idonswa ngamandla. Ushintsho lobude bentambo luyi-2 mm. Thola ukuthi ingcindezi ingakanani!

Kwaziwa:

Ubude bokuqala (l 0 ) = 100 cm = 1 m

Ushintsho lobude (Δl) = 2 mm = 0.002 m

Okufunwayo: Ubunzima

Isixazululo:

Isitimela :

Ukucindezeleka, ukucindezeleka, izinkinga zesampula ze-modulus kaYoung ngezixazululo 2

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3. Intambo engu-4 mm ububanzi inobude bokuqala obuyi-2 m. Intambo idonswa ngamandla angu-200 N. Uma ubude bokugcina bentwasahlobo buyi-2.02 m, thola: (a) ukucindezeleka (b) ukucindezeleka (c) i-modulus kaYoung

Kwaziwa:

Ububanzi (d) = 4 mm = 0.004 m

Irediyasi (r) = 2 mm = 0.002 m

Indawo (A) = π r 2 = (3.14)(0.002 m) 2

Indawo ( A) = 0.00001256 m2 = 12.56 x 10 -6 m2

Amandla (F) = 200 N

Ubude bokuqala bentwasahlobo (l 0 ) = 2 m

Ushintsho lobude (Δl) = 2.02 – 2 = 0.02 m

Okufunwayo: (a) Ukucindezeleka (b) Ukucindezeleka c) I-modulus kaYoung

Isixazululo:

(a) Ukucindezeleka

Ukucindezeleka, ukucindezeleka, izinkinga zesampula ze-modulus kaYoung ngezixazululo 3

(b) Ubunzima

Ukucindezeleka, ukucindezeleka, izinkinga zesampula ze-modulus kaYoung ngezixazululo 4

(c) I-modulus kaYoung

Ukucindezeleka, ukucindezeleka, izinkinga zesampula ze-modulus kaYoung ngezixazululo 5

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4. Intambo inobubanzi obungu-1 cm kanye nobude bokuqala obungu-2 m. Intambo idonswa ngamandla angu-200 N. Thola ushintsho kubude bentambo! I-modulus kaYoung yentambo = 5 x 10 9 N/m 2

Kwaziwa:

Imodulus kaYoung (E) = 5 x 10 9 N/m 2

Ubude bokuqala (l 0 ) = 2 m

Amandla (F) = 200 N

Ububanzi (d) = 1 cm = 0.01 m

Irediyasi (r) = 0.5 cm = 0.005 m = 5 x 10 -3 m

Indawo (A) = π r 2 = (3.14)(5 x 10 -3 m) 2 = (3.14)(25 x 10 -6 m 2 )

Indawo (A) = 78.5 x 10 -6 m 2 = 7.85 x 10 -5 m 2

Okufunwayo : Ushintsho lobude (Δl)

Isixazululo:

Ifomula ye-modulus kaYoung:

Ukucindezeleka, ukucindezeleka, izinkinga zesampula ze-modulus kaYoung ngezixazululo 6

Ushintsho lobude :

Ukucindezeleka, ukucindezeleka, izinkinga zesampula ze-modulus kaYoung ngezixazululo 7

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5. Ikhonkrithi inokuphakama kwamamitha ama-5 futhi inendawo yeyunithi engu-3 m 3 esekela isisindo esingu-30,000 kg. Thola (a) Ukucindezeleka (b) Ukucindezeleka (c) Ushintsho ekuphakameni! Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2 . Imodulus kaYoung yekhonkrithi = 20 x 10 9 N/m 2

Kwaziwa:

I-modulus ka-Young yekhonkrithi = 20 x 10 9 N/m 2

Ukuphakama kokuqala (l 0 ) = amamitha angu-5

Indawo yeyunithi (A) = 3 m 2

Isisindo (w) = mg = (30,000)(10) = 300,000 N

Okufunwayo: (a) Ukucindezeleka (b) Ukucindezeleka (c) Ushintsho ekuphakameni!

Isixazululo:

(a) Ukucindezeleka

Ukucindezeleka, ukucindezeleka, izinkinga zesampula ze-modulus kaYoung ngezixazululo 8

(b) Ubunzima

Ukucindezeleka, ukucindezeleka, izinkinga zesampula ze-modulus kaYoung ngezixazululo 9

(c) Ushintsho ekuphakameni

Ukucindezeleka, ukucindezeleka, izinkinga zesampula ze-modulus kaYoung ngezixazululo 10

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  1. Umthetho kaHooke
  2. Ukucindezeleka, ukucindezeleka, i-modulus kaYoung

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