1. A 0.2-kg ball, attached to the end of a horizontal cord, is revolved in a circle of radius 1 meter and ball’s maximum speed is 10 rpm. What is the magnitude of the sentripetal na pagbilis and the magnitude of the tension force?
Kilala:
Masa (m) = 0.2 kg
Radius (r) = 1 m
Angular na bilis (ω) = 10 rev/min = 10 rev/60 s = 0.17 rev/s = (0.17)(6.28 rad)/s = 1 rad/s
Bilis (v) = r ω = (1 m)(1 rad/s) = 1 m/s
Hinahanap: as at ΣF
solusyon:
(a) The magnitude of the centripetal acceleration
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(b) The magnitude of the tension force
ΣF = ma
T = m as
T = (0.2 kg)(1 m/s)2)
T = 0.2 kg m/s2
T = 0.2 N
2. A 1-kg ball at the end of a string is revolving uniformly in a horizontal circle of radius 1 m. The cord will break when the tension in it exceeds 100 N. What is the maximum speed the ball can have?
Kilala:
Mass (m) = 1 kg
Radius (r) = 1 meter
Tension force (T) = puwersang sentripetal (ΣF) = 100 N
Wanted: v maximum
solusyon:

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- Masa at bigat
- Normal na pwersa
- Ikalawang batas ng galaw ni Newton
- Pwersa ng friction
- Motion on a horizontal surface without friction force
- The motion of two bodies with the same acceleration on the rough horizontal surface with a friction force
- Motion on an inclined plane without friction force
- Paggalaw sa magaspang na hilig na eroplano na may puwersa ng friction
- Paggalaw sa isang elevator
- Ang paggalaw ng mga katawan ay konektado sa pamamagitan ng mga kordon at pulley
- Dalawang katawan na may parehong magnitude ng acceleration
- Pag-ikot ng patag na kurba – dinamika ng pabilog na galaw
- Pag-ikot sa isang naka-bankong kurba – dinamika ng pabilog na galaw
- Pare-parehong galaw sa isang pahalang na bilog
- Puwersang sentripetal sa pare-parehong pabilog na galaw